## RRB SSE Online Test Series 1 | RRB Mock Test Series 1

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**RRB SSE Online Test Series 1 | RRB Mock Test Series 1, Online Preparation: **RRB Senior Section Engineer, Junior Engineer, Non-Technical Exam Free Online Test Series. Free *RRB Online Test* for various competitive examination, entrance examination and campus interview. check out Online mock test series for RRB Senior Section Engineer. RRB Online Test for All Subjects, RRB SSE Free Mock Test Series in English. RRB SSE Free Mock Test **Series 1.** RRB SSE English Language Online Test in English **Series 1st**. RRB SSE Quantitative Aptitude Quiz 2019, RRB SSE Reasoning Ability Free Online Test. Take RRB SSE Online Quiz. The RRB SSE Full online mock test paper is free for all students. RRB SSE Question and Answers in English and Hindi **Series 1**. Here we are providing** RRB SSE Full Mock Test Paper in English. RRB SSE **Mock Test **Series 1st** 2019. Now Test your self for RRB SSE Exam by using below quiz…

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- Question 1 of 50
##### 1. Question

How many numbers up to 500 are divisible by 23?

Correct500/23 = 21 17/23 => 21 Numbers

Incorrect500/23 = 21 17/23 => 21 Numbers

- Question 2 of 50
##### 2. Question

Find the one which does not belong to that group ?

CorrectThe sum of the digits in 508, 328, 706 and 148 is 13, but not in 608.

IncorrectThe sum of the digits in 508, 328, 706 and 148 is 13, but not in 608.

- Question 3 of 50
##### 3. Question

If x = √196 + √200, then x/2 + 2/x is?

Correctx = 14 + 10√2

x/2 = 7 + 5√2

2/x = (7 – 5√2) / (7 + 5√2)(7 – 5√2) = 5√2 – 7

x/2 + 2/x = 10√2 = 2√50Incorrectx = 14 + 10√2

x/2 = 7 + 5√2

2/x = (7 – 5√2) / (7 + 5√2)(7 – 5√2) = 5√2 – 7

x/2 + 2/x = 10√2 = 2√50 - Question 4 of 50
##### 4. Question

A man can swim in still water at 4.5 km/h, but takes twice as long to swim upstream than downstream. The speed of the stream is?

CorrectM = 4.5

S = x

DS = 4.5 + x

US = 4.5 + x

4.5 + x = (4.5 – x)2

4.5 + x = 9 -2x

3x = 4.5

x = 1.5IncorrectM = 4.5

S = x

DS = 4.5 + x

US = 4.5 + x

4.5 + x = (4.5 – x)2

4.5 + x = 9 -2x

3x = 4.5

x = 1.5 - Question 5 of 50
##### 5. Question

Divide Rs.32000 in the ratio 3:5?

Correct3/8 * 32000 = 12000

5/8 * 32000 = 20000Incorrect3/8 * 32000 = 12000

5/8 * 32000 = 20000 - Question 6 of 50
##### 6. Question

A, B and C are partners. A receives 2/3 of profits, B and C dividing the remainder equally. A’s income is increased by Rs.200 when the rate to profit rises from 5 to 7 percent. Find the Capital of B?

CorrectA:B:C = 2/3:1/6:1/6 = 4:1:1

x * 2/100 * 2/3 = 200

B capital = 15000*1/6 = 2500IncorrectA:B:C = 2/3:1/6:1/6 = 4:1:1

x * 2/100 * 2/3 = 200

B capital = 15000*1/6 = 2500 - Question 7 of 50
##### 7. Question

If a man walks to his office at ¾ of his usual rate, he reaches office 1/3 of an hour late than usual. What is his usual time to reach office?

CorrectSpeed Ratio = 1:3/4 = 4:3

Time Ratio = 3:4

1 ——– 1/3

3 ——— ? è 1 hourIncorrectSpeed Ratio = 1:3/4 = 4:3

Time Ratio = 3:4

1 ——– 1/3

3 ——— ? è 1 hour - Question 8 of 50
##### 8. Question

If the L.C.M of two numbers is 750 and their product is 18750, find the H.C.F of the numbers.

CorrectH.C.F = (Product of the numbers) / (Their L.C.M) = 18750/750 = 25.

IncorrectH.C.F = (Product of the numbers) / (Their L.C.M) = 18750/750 = 25.

- Question 9 of 50
##### 9. Question

Pipes A and B can fill a tank in 5 and 6 hours respectively. Pipe C can empty it in 12 hours. If all the three pipes are opened together, then the tank will be filled in?

CorrectNet part filled in 1 hour = 1/5 + 1/6 – 1/12 = 17/60

The tank will be full in 60/17 hrs, i.e., 3 9/17 hrs.IncorrectNet part filled in 1 hour = 1/5 + 1/6 – 1/12 = 17/60

The tank will be full in 60/17 hrs, i.e., 3 9/17 hrs. - Question 10 of 50
##### 10. Question

Find the one which does not belong to that group ?

CorrectExcept Japanian, all others are appropriate usage of citizenship.

IncorrectExcept Japanian, all others are appropriate usage of citizenship.

- Question 11 of 50
##### 11. Question

How much interest can a person get on Rs. 8200 at 17.5% p.a. simple interest for a period of two years and six months?

CorrectI = (8200 * 2.5 * 17.5)/100 = (8200 * 5 * 35)/(100 * 2 * 2) = Rs. 3587.50

IncorrectI = (8200 * 2.5 * 17.5)/100 = (8200 * 5 * 35)/(100 * 2 * 2) = Rs. 3587.50

- Question 12 of 50
##### 12. Question

P alone can complete a piece of work in 6 days. Work done by Q alone in one day is equal to one-third of the work done by P alone in one day. In how many days can the work be completed if P and Q work together?

CorrectWork done by P alone in one day = 1/6th of the total work done by Q alone in one day = 1/3(of that done by P in one day) = 1/3(1/6 of the total) = 1/18 of the total.

Work done by P and Q, working together in one day = 1/6 + 1/18 = 4/18 = 2/9 of the total

They would take 9/2 days = 4 (1/2) days to complete the work working together.IncorrectWork done by P alone in one day = 1/6th of the total work done by Q alone in one day = 1/3(of that done by P in one day) = 1/3(1/6 of the total) = 1/18 of the total.

Work done by P and Q, working together in one day = 1/6 + 1/18 = 4/18 = 2/9 of the total

They would take 9/2 days = 4 (1/2) days to complete the work working together. - Question 13 of 50
##### 13. Question

Simplify: y

^{p(q – r)}. y^{q(r – p)}. y^{r(p – q)}Correcty

^{p(q – r)}. y^{q(r – p)}. y^{r(p – q)}

= y^{pq – pr + qr – qp + rp – rq}

= y^{p0}= 1.Incorrecty

^{p(q – r)}. y^{q(r – p)}. y^{r(p – q)}

= y^{pq – pr + qr – qp + rp – rq}

= y^{p0}= 1. - Question 14 of 50
##### 14. Question

A 300 m long train crosses a platform in 39 sec while it crosses a signal pole in 18 sec. What is the length of the platform?

CorrectSpeed = 300/18 = 50/3 m/sec.

Let the length of the platform be x meters.

Then, (x + 300)/39 = 50/3

3x + 900 = 1950 => x = 350 m.IncorrectSpeed = 300/18 = 50/3 m/sec.

Let the length of the platform be x meters.

Then, (x + 300)/39 = 50/3

3x + 900 = 1950 => x = 350 m. - Question 15 of 50
##### 15. Question

A tank 3 m long, 2 m wide and 1.5 m deep is dug in a field 20 m long and 14 m wide. If the earth dug out is evenly spread out over the field, the level of the field will raise by nearly?

CorrectIncorrect - Question 16 of 50
##### 16. Question

106 * 106 – 94 * 94 = ?

Correct106 * 106 – 94 * 94 = (106)

^{2}– (94)^{2}

= (106 + 94)(106 – 94) = (200 * 12) = 2400Incorrect106 * 106 – 94 * 94 = (106)

^{2}– (94)^{2}

= (106 + 94)(106 – 94) = (200 * 12) = 2400 - Question 17 of 50
##### 17. Question

In a colony of 70 residents, the ratio of the number of men and women is 4:3. Among the women, the ratio of the educated to the uneducated is 1:4. If the ratio of the number of education to uneducated persons is 8:27, then find the ratio of the number of educated and uneducated men in the colony?

CorrectNumber of men in the colony = 4/7 (70) = 40

Number of women in the colony = 3/7 (70) = 30

Number of educated women in the colony = 1/5 (30) = 6

Number of uneducated women in the colony = 4/5 (30) = 24

Number of educated persons in the colony = 8/35 (70) = 16

As 6 females are educated, remaining 10 educated persons must be men.

Number of uneducated men in the colony = 40 – 10 = 30

Number of educated men and uneducated men are in the ratio 10:30 => 1:3IncorrectNumber of men in the colony = 4/7 (70) = 40

Number of women in the colony = 3/7 (70) = 30

Number of educated women in the colony = 1/5 (30) = 6

Number of uneducated women in the colony = 4/5 (30) = 24

Number of educated persons in the colony = 8/35 (70) = 16

As 6 females are educated, remaining 10 educated persons must be men.

Number of uneducated men in the colony = 40 – 10 = 30

Number of educated men and uneducated men are in the ratio 10:30 => 1:3 - Question 18 of 50
##### 18. Question

3251 + 587 + 369 – ? = 3007

CorrectLet 4207 – x = 3007

Then, x = 4207 – 3007 = 1200IncorrectLet 4207 – x = 3007

Then, x = 4207 – 3007 = 1200 - Question 19 of 50
##### 19. Question

3 men or 6 women can do a piece of work in 20 days. In how many days will 12 men and 8 women do the same work?

Correct3M = 6W —- 20 days

12M + 8W —–?

24W + 8 W = 32W —?

6W —- 20 32 —–?

6 * 20 = 32 * x => x = 15/4 daysIncorrect3M = 6W —- 20 days

12M + 8W —–?

24W + 8 W = 32W —?

6W —- 20 32 —–?

6 * 20 = 32 * x => x = 15/4 days - Question 20 of 50
##### 20. Question

A certain sum becomes Rs. 20720 in four years and 24080 in six years at simple interest. Find sum and rate of interest?

CorrectLet the interest for one year be x.

As amount = Principal + Interest, we have

P + 4x = 20720 — (1) ; P + 6x = 24080 — (2)

Solving the equations (1) and (2), we can get

P = Rs. 14000 and x = Rs. 1680

Interest for one year on Rs. 14000 is Rs. 1680

So, R = (100 * 1680)/(14000 * 1) = 12% p.a.IncorrectLet the interest for one year be x.

As amount = Principal + Interest, we have

P + 4x = 20720 — (1) ; P + 6x = 24080 — (2)

Solving the equations (1) and (2), we can get

P = Rs. 14000 and x = Rs. 1680

Interest for one year on Rs. 14000 is Rs. 1680

So, R = (100 * 1680)/(14000 * 1) = 12% p.a. - Question 21 of 50
##### 21. Question

If Rs.3250 be divided among Ram, Shyam and Mohan in the ratio of 1/2:1/3:1/4 then the share of each are?

Correct1/2:1/3:1/4 = 6:4:3

Ram = 6/13 * 3250 = 1500

Shyam = 4/13 * 3250 = 1000

Mohan = 3/13 * 3250 = 750Incorrect1/2:1/3:1/4 = 6:4:3

Ram = 6/13 * 3250 = 1500

Shyam = 4/13 * 3250 = 1000

Mohan = 3/13 * 3250 = 750 - Question 22 of 50
##### 22. Question

A box contains nine bulbs out of which 4 are defective. If four bulbs are chosen at random, find the probability that atleast one bulb is good.

CorrectRequired probability = 1 – 1/126 = 125/126

IncorrectRequired probability = 1 – 1/126 = 125/126

- Question 23 of 50
##### 23. Question

On dividing 2272 as well as 875 by 3-digit number N, we get the same remainder. The sum of the digits of N is:

CorrectClearly, (2272 – 875) = 1397, is exactly divisible by N.

Now. 1397 = 11 * 127

The required 3-digit number is 127, the sum of whose digit is 10.IncorrectClearly, (2272 – 875) = 1397, is exactly divisible by N.

Now. 1397 = 11 * 127

The required 3-digit number is 127, the sum of whose digit is 10. - Question 24 of 50
##### 24. Question

The average of 11 results is 50, if the average of first six results is 49 and that of the last six is 52. Find the sixth result?

Correct1 to 11 = 11 * 50 = 550

1 to 6 = 6 * 49 = 294

6 to 11 = 6 * 52 = 312

6^{th}= 294 + 312 – 550 = 56Incorrect1 to 11 = 11 * 50 = 550

1 to 6 = 6 * 49 = 294

6 to 11 = 6 * 52 = 312

6^{th}= 294 + 312 – 550 = 56 - Question 25 of 50
##### 25. Question

20% of 40 + ? % of 80 = 120

Correct20% of 40 + ? % of 80 = 120

=> 800/100 + ?/100 * 80 = 120

=> ? = 140Incorrect20% of 40 + ? % of 80 = 120

=> 800/100 + ?/100 * 80 = 120

=> ? = 140 - Question 26 of 50
##### 26. Question

A box contains 3 blue marbles, 4 red, 6 green marbles and 2 yellow marbles. If two marbles are drawn at random, what is the probability that at least one is green?

CorrectGiven that there are three blue marbles, four red marbles, six green marbles and two yellow marbles.

Probability that at least one green marble can be picked in the random draw of two marbles = Probability that one is green + Probability that both are green

= (⁶C₁ * ⁹C₁)/¹⁵C₂ + ⁶C₂/¹⁵C₂

= (6 * 9 * 2)/(15 * 14) + (6 * 5)/(15 * 14) = 36/70 + 1/7

= 46/70 = 23/35IncorrectGiven that there are three blue marbles, four red marbles, six green marbles and two yellow marbles.

Probability that at least one green marble can be picked in the random draw of two marbles = Probability that one is green + Probability that both are green

= (⁶C₁ * ⁹C₁)/¹⁵C₂ + ⁶C₂/¹⁵C₂

= (6 * 9 * 2)/(15 * 14) + (6 * 5)/(15 * 14) = 36/70 + 1/7

= 46/70 = 23/35 - Question 27 of 50
##### 27. Question

Sum of two numbers is 80. Greater number exceeds by 5 from four times of the smaller. Find the numbers?

Correctx + y = 80

x – 4y = 5

x = 65 y = 15Incorrectx + y = 80

x – 4y = 5

x = 65 y = 15 - Question 28 of 50
##### 28. Question

The ratio of the prices of three articles X, Y and Z is 8 : 5 : 3. If the prices of X , Y and Z are increased by 25%, 20% and 33 1/3% respectively, then what would be the ratio of the new prices of X, Y and Z?

CorrectLet the prices of X, Y and Z be 8k, 5k and 3k respectively.

After increase

Price of X = 8k * 125/100 = 10k

Price of Y = 5k * 120/100 = 6k

Price of Z = 3k * (133 1/3)/100 = 4k

Required ratio = 10k : 6k : 4k = 5 : 3 : 2.IncorrectLet the prices of X, Y and Z be 8k, 5k and 3k respectively.

After increase

Price of X = 8k * 125/100 = 10k

Price of Y = 5k * 120/100 = 6k

Price of Z = 3k * (133 1/3)/100 = 4k

Required ratio = 10k : 6k : 4k = 5 : 3 : 2. - Question 29 of 50
##### 29. Question

A train running at the speed of 60 km/hr crosses a pole in 9 sec. What is the length of the train?

CorrectSpeed = 60 * 5/18 = 50/3 m/sec

Length of the train = speed * time = 50/3 * 9 = 150 mIncorrectSpeed = 60 * 5/18 = 50/3 m/sec

Length of the train = speed * time = 50/3 * 9 = 150 m - Question 30 of 50
##### 30. Question

Two cars P and Q start at the same time from A and B which are 120 km apart. If the two cars travel in opposite directions, they meet after one hour and if they travel in same direction (from A towards B), then P meets Q after 6 hours. What is the speed of car P?

CorrectLet their speed be x km/hr and y km/he respectively.

Then, 120/(x + y) = 1 => x + y = 120 — (i)

Now, when they move in same direction:

(Distance traveled by P in 6 hrs) – (Distance traveled by Q in 6 hrs) = 120 km

6x – 6y = 120 => x – y = 20 — (ii)

Sloving (i) and (ii), we get x = 70, y = 50

P’s speed = 70 km/hr.IncorrectLet their speed be x km/hr and y km/he respectively.

Then, 120/(x + y) = 1 => x + y = 120 — (i)

Now, when they move in same direction:

(Distance traveled by P in 6 hrs) – (Distance traveled by Q in 6 hrs) = 120 km

6x – 6y = 120 => x – y = 20 — (ii)

Sloving (i) and (ii), we get x = 70, y = 50

P’s speed = 70 km/hr. - Question 31 of 50
##### 31. Question

The current of a stream runs at the rate of 4 kmph. A boat goes 6 km and back to the starting point in 2 hours, then find the speed of the boat in still water?

CorrectS = 4

M = x

DS = x + 4

US = x – 4

6/(x + 4) + 6/(x – 4) = 2

x = 8IncorrectS = 4

M = x

DS = x + 4

US = x – 4

6/(x + 4) + 6/(x – 4) = 2

x = 8 - Question 32 of 50
##### 32. Question

26.98% of 6002 + 45.01% of 4199 = ?

Correct27% of 6000 + 45% of 4200 = ?

=> ? = 27/100 * 6000 + 45/100 * 4200

=> ? = 1620 + 1890 = 3510 = 3500Incorrect27% of 6000 + 45% of 4200 = ?

=> ? = 27/100 * 6000 + 45/100 * 4200

=> ? = 1620 + 1890 = 3510 = 3500 - Question 33 of 50
##### 33. Question

A can do a piece of work in 15 days and B in 20 days. They began the work together but 5 days before the completion of the work, A leaves. The work was completed in?

Correct(x – 5)/15 + x/20 = 1

x = 11 3/7 daysIncorrect(x – 5)/15 + x/20 = 1

x = 11 3/7 days - Question 34 of 50
##### 34. Question

A shopkeeper sells 20% of his stock at 10% profit ans sells the remaining at a loss of 5%. He incurred an overall loss of Rs. 400. Find the total worth of the stock?

CorrectLet the total worth of the stock be Rs. x.

The SP of 20% of the stock = 1/5 * x * 1.1 = 11x/50

The SP of 80% of the stock = 4/5 * x * 0.95 = 19x/25 = 38x/50

Total SP = 11x/50 + 38x/50 = 49x/50

Overall loss = x – 49x/50 = x/50

x/50 = 400 => x = 20000IncorrectLet the total worth of the stock be Rs. x.

The SP of 20% of the stock = 1/5 * x * 1.1 = 11x/50

The SP of 80% of the stock = 4/5 * x * 0.95 = 19x/25 = 38x/50

Total SP = 11x/50 + 38x/50 = 49x/50

Overall loss = x – 49x/50 = x/50

x/50 = 400 => x = 20000 - Question 35 of 50
##### 35. Question

A sum amount to Rs.1344 in two years at simple interest. What will be the compound interest on the same sum at the same rate of interest for the same period?

CorrectIncorrect - Question 36 of 50
##### 36. Question

Three pipes of same capacity can fill a tank in 8 hours. If there are only two pipes of same capacity, the tank can be filled in.

CorrectThe part of the tank filled by three pipes in one hour = 1/8

=> The part of the tank filled by two pipes in 1 hour = 2/3 * 1/8 = 1/12.

The tank can be filled in 12 hours.IncorrectThe part of the tank filled by three pipes in one hour = 1/8

=> The part of the tank filled by two pipes in 1 hour = 2/3 * 1/8 = 1/12.

The tank can be filled in 12 hours. - Question 37 of 50
##### 37. Question

The ratio of the number of boys and girls in a college is 7:8. If the percentage increase in the number of boys and girls be 20% and 10% respectively. What will be the new ratio?

CorrectOriginally, let the number of boys and girls in the college be 7x and 8x respectively.

Their increased number is (120% of 7x) and (110% of 8x).

i.e., (120/100 * 7x) and (110/100 * 8x)

i.e., 42x/5 and 44x/5

Required ratio = 42x/5 : 44x/5 = 21:22IncorrectOriginally, let the number of boys and girls in the college be 7x and 8x respectively.

Their increased number is (120% of 7x) and (110% of 8x).

i.e., (120/100 * 7x) and (110/100 * 8x)

i.e., 42x/5 and 44x/5

Required ratio = 42x/5 : 44x/5 = 21:22 - Question 38 of 50
##### 38. Question

6 2/3 * 9 3/5 * 2 1/3 + 1 1/3 = ?

Correct6 2/3 * 9 3/5 * 2 1/3 + 1 1/3 = 20/3 * 48/5 * 7/3 + 4/3

= 448/3 + 4/3 = 452/3 = 150 2/3Incorrect6 2/3 * 9 3/5 * 2 1/3 + 1 1/3 = 20/3 * 48/5 * 7/3 + 4/3

= 448/3 + 4/3 = 452/3 = 150 2/3 - Question 39 of 50
##### 39. Question

Find the one which does not belong to that group ?

CorrectExcept Real, all others are rhyming words.

IncorrectExcept Real, all others are rhyming words.

- Question 40 of 50
##### 40. Question

In a kilometer race, A beats B by 50 meters or 10 seconds. What time does A take to complete the race?

CorrectTime taken by B run 1000 meters = (1000 * 10)/50 = 200 sec.

Time taken by A = 200 – 10 = 190 sec.IncorrectTime taken by B run 1000 meters = (1000 * 10)/50 = 200 sec.

Time taken by A = 200 – 10 = 190 sec. - Question 41 of 50
##### 41. Question

The area of sector of a circle whose radius is 12 metro and whose angle at the center is 42° is?

Correct42/360 * 22/7 * 12 * 12 = 52.8 m

^{2}Incorrect42/360 * 22/7 * 12 * 12 = 52.8 m

^{2} - Question 42 of 50
##### 42. Question

A man can row upstream at 25 kmph and downstream at 35 kmph, and then find the speed of the man in still water?

CorrectUS = 25

DS = 35

M = (35 + 25)/2 = 30IncorrectUS = 25

DS = 35

M = (35 + 25)/2 = 30 - Question 43 of 50
##### 43. Question

How many seconds will a 500 m long train take to cross a man walking with a speed of 3 km/hr in the direction of the moving train if the speed of the train is 63 km/hr?

CorrectSpeed of train relative to man = 63 – 3 = 60 km/hr.

= 60 * 5/18 = 50/3 m/sec.

Time taken to pass the man = 500 * 3/50 = 30 sec.IncorrectSpeed of train relative to man = 63 – 3 = 60 km/hr.

= 60 * 5/18 = 50/3 m/sec.

Time taken to pass the man = 500 * 3/50 = 30 sec. - Question 44 of 50
##### 44. Question

A can do a piece of work in 10 days and B can do it in 15 days and C can do it 20 days. They started the work together and A leaves after 2 days and B leaves after 4 days from the beginning. How long will work lost?

Correct2/10 + 4/15 + x/20 = 1

x = 32/3 = 10 2/3Incorrect2/10 + 4/15 + x/20 = 1

x = 32/3 = 10 2/3 - Question 45 of 50
##### 45. Question

A fair price shopkeeper takes 10% profit on his goods. He lost 20% goods during theft. His loss percent is:

CorrectSuppose he has 100 items. Let C.P. of each item be Re. 1.

Total cost = Rs. 100. Number of items left after theft = 80.

S.P. of each item = Rs. 1.10

Total sale = 1.10 * 80 = Rs. 88

Hence, loss % = 12/100 * 100 = 12%IncorrectSuppose he has 100 items. Let C.P. of each item be Re. 1.

Total cost = Rs. 100. Number of items left after theft = 80.

S.P. of each item = Rs. 1.10

Total sale = 1.10 * 80 = Rs. 88

Hence, loss % = 12/100 * 100 = 12% - Question 46 of 50
##### 46. Question

Find the principle on a certain sum of money at 5% per annum for 2 2/5 years if the amount being Rs.1120?

Correct1120 = P [1 + (5*12/5)/100]

P= 1000Incorrect1120 = P [1 + (5*12/5)/100]

P= 1000 - Question 47 of 50
##### 47. Question

The food in a camp lasts for 30 men for 40 days. If ten more men join, how many days will the food last?

Correctone man can consume the same food in 30*40 = 1200 days.

10 more men join, the total number of men = 40

The number of days the food will last = 1200/40 = 30 days.Incorrectone man can consume the same food in 30*40 = 1200 days.

10 more men join, the total number of men = 40

The number of days the food will last = 1200/40 = 30 days. - Question 48 of 50
##### 48. Question

Dacid obtained 76, 65, 82, 67 and 85 marks (out of 100) in English, Mathematics, Physics, Chemistry and Biology. What are his average marks?

CorrectAverage = (76 + 65 + 82 + 67 + 85)/5 = 375/5 = 75.

IncorrectAverage = (76 + 65 + 82 + 67 + 85)/5 = 375/5 = 75.

- Question 49 of 50
##### 49. Question

The areas of the two spheres are in the ratio 1: 4. The ratio of their volume is?

Correct4πr

_{1}^{2}: 4πr_{2}^{2}= 1 : 4

r_{1}: r_{2 }= 1 : 2

4/3 πr_{1}^{3 }: 4/3 πr_{2}^{3}

r_{1}^{3}: r_{2}^{3}= 1 : 8Incorrect4πr

_{1}^{2}: 4πr_{2}^{2}= 1 : 4

r_{1}: r_{2 }= 1 : 2

4/3 πr_{1}^{3 }: 4/3 πr_{2}^{3}

r_{1}^{3}: r_{2}^{3}= 1 : 8 - Question 50 of 50
##### 50. Question

Two-fifth of one-third of three-seventh of a number is 15. What is 40% of that number?

CorrectLet the number be x. Then,

2/5 of 1/3 of 3/7 of

x = 15 => x = (15 * 5/3 * 3 * 5/2) = 525/2

40% of 525/2 = (40/100 * 525/2) = 105IncorrectLet the number be x. Then,

2/5 of 1/3 of 3/7 of

x = 15 => x = (15 * 5/3 * 3 * 5/2) = 525/2

40% of 525/2 = (40/100 * 525/2) = 105

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