IBPS SO Prelims Quantitative Aptitude Free Online Mock Test - 1
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Quantitative Aptitude Questions for IBPS SO Prelims Online Test, IBPS SO Free Mock Test Series. IBPS Free Mock Test for IT Officer. The below online test on IBPS Specialist Officer Recruitment will help you for preperation of the post of IT Officer, Agricultural Field Officer, Rajbhasha Adhikari, Law Officer, HR/Personnel Officer, Marketing Officer. IBPS Quantitative Aptitude Online Test in English. IBPS SO Quantitative Aptitude Quiz 2019. The IBPS Full online mock test paper is free for all students. IBPS Mock test for Quantitative Aptitude Subject Via Online Mode. Here we are providing Quantitative Aptitude Question for IBPS SO Exam in English. IBPS SO IT Officer Mock Test Series 2019. Now Test your self for IBPS Exam by using below quiz…
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Question 1 of 50
1. Question
267, 244, 219, 190, ?, 100 The following series are based on a certain pattern. Find the number represented by question mark (?) in the following series:
Correct
Incorrect
-
Question 2 of 50
2. Question
265, 264, 272, 245, 309, ? The following series are based on a certain pattern. Find the number represented by question mark (?) in the following series:
Correct
-13, +23, -33, +43, -53
Incorrect
-13, +23, -33, +43, -53
-
Question 3 of 50
3. Question
0.5, 2, 7, 29, 146, ? The following series are based on a certain pattern. Find the number represented by question mark (?) in the following series:
Correct
*2 + 1, *3 + 1, *4 + 1, *5 + 1
Incorrect
*2 + 1, *3 + 1, *4 + 1, *5 + 1
-
Question 4 of 50
4. Question
0.5, 2, 5, 12.5, 34.25, ? The following series are based on a certain pattern. Find the number represented by question mark (?) in the following series:
Correct
*1 + 1.5, *1.5 + 2, *2 + 2.5, *2.5 + 3, *3 + 3.5
Incorrect
*1 + 1.5, *1.5 + 2, *2 + 2.5, *2.5 + 3, *3 + 3.5
-
Question 5 of 50
5. Question
512, ?, 256, 64, 8, 0.5 The following series are based on a certain pattern. Find the number represented by question mark (?) in the following series:
Correct
*1, *1/2, *1/4, *1/8, *1/16
Incorrect
*1, *1/2, *1/4, *1/8, *1/16
-
Question 6 of 50
6. Question
√? + √1335 * 24 – 13.96 = 895 What approximate value should come in place of question mark (?) in the below given questions?
Correct
√? +36*24 -14=895
√? +850=895
√?=45
X=45*45=2025.Incorrect
√? +36*24 -14=895
√? +850=895
√?=45
X=45*45=2025. -
Question 7 of 50
7. Question
(42.03% of 495.04 + 58.02% of 1200 ) / 9 = ? What approximate value should come in place of question mark (?) in the below given questions?
Correct
(208+696)/9=100.44
Incorrect
(208+696)/9=100.44
-
Question 8 of 50
8. Question
(9117.88 – 8021.85 + 903.92) * 12 = 1500 * ? What approximate value should come in place of question mark (?) in the below given questions?
Correct
(9118-8022+904) *12 =1500* ?
(2000*12 /1500) = x
X=15.
Incorrect
(9118-8022+904) *12 =1500* ?
(2000*12 /1500) = x
X=15.
-
Question 9 of 50
9. Question
{(4/7*15/4) / (3.5 -1.2) }2 = ? What approximate value should come in place of question mark (?) in the below given questions?
Correct
[(60/28)/2.3]2 =x
X={15/16}2 ==> 0.87.Incorrect
[(60/28)/2.3]2 =x
X={15/16}2 ==> 0.87. -
Question 10 of 50
10. Question
If x=3.5 , y=4.5 , then {(y-x) (y-x)/y+x}*xy = ? What approximate value should come in place of question mark (?) in the below given questions?
Correct
{(1*1)/8*15.75}= x
X= 15.75/8=2.Incorrect
{(1*1)/8*15.75}= x
X= 15.75/8=2. -
Question 11 of 50
11. Question
(87.65% of 7159.89 – 68.99% of 8939.89) * 6.06 = (?)2 What approximate value should come in place of question mark (?) in the below given questions?
Correct
(6300 – 6168) * 6 =x 2
132 * 6 = x 2
792= x 2
ie x=28.Incorrect
(6300 – 6168) * 6 =x 2
132 * 6 = x 2
792= x 2
ie x=28. -
Question 12 of 50
12. Question
35 5/7% of 6510 + 77 7/9% of 5886 = ?% of 6126 + 50% of 5638 What approximate value should come in place of question mark (?) in the below given questions?
Correct
250/7% of 6510 + 700/9 % of 5886 =?% of 6126 + 50% of 5638
2325 + 4578 – 2819 = x/100 *6126 +2819
(4084 *100 ) /6126 = x
X=66.66.Incorrect
250/7% of 6510 + 700/9 % of 5886 =?% of 6126 + 50% of 5638
2325 + 4578 – 2819 = x/100 *6126 +2819
(4084 *100 ) /6126 = x
X=66.66. -
Question 13 of 50
13. Question
854.926 – 562.005 – 115.98 = 22.6% of (?) What approximate value should come in place of question mark (?) in the below given questions?
Correct
855 – 562 – 116 = 22.6% of x
177 =23/100 * x
X=770Incorrect
855 – 562 – 116 = 22.6% of x
177 =23/100 * x
X=770 -
Question 14 of 50
14. Question
(750/45) / 11/781 * 114/95 = ? What approximate value should come in place of question mark (?) in the below given questions?
Correct
750/45 * 781/11* 114/95
=(10*71*36 )/ 19
=1420.Incorrect
750/45 * 781/11* 114/95
=(10*71*36 )/ 19
=1420. -
Question 15 of 50
15. Question
15.332 – 12.942 + 22.062 – 35.65 = ? What approximate value should come in place of question mark (?) in the below given questions?
Correct
15 2 -132 + 222 -35.65 = x
225-169+484-35.65 = x
X= 504.Incorrect
15 2 -132 + 222 -35.65 = x
225-169+484-35.65 = x
X= 504. -
Question 16 of 50
16. Question
I. 3×2 – 5x – 12 = 0
II. 4y2 – 9y – 9 = 0
In the following questions, two equations numbered are given in variables x and y. You have to solve both the equations and find out the relationship between x and y. Then give answer accordingly-Correct
x = -4/3, 3
y = -3/4, 3
Put all values on number line and analyze the relationship
-4/3………..-3/4……3Incorrect
x = -4/3, 3
y = -3/4, 3
Put all values on number line and analyze the relationship
-4/3………..-3/4……3 -
Question 17 of 50
17. Question
I. 2×2 + 11x + 14 = 0
II. 3y2 – 7y – 6 = 0
In the following questions, two equations numbered are given in variables x and y. You have to solve both the equations and find out the relationship between x and y. Then give answer accordingly-Correct
x = -7/2, -2
y = -2/3, 3
Put all values on number line and analyze the relationship
-7/2………-2………..-2/3…………3Incorrect
x = -7/2, -2
y = -2/3, 3
Put all values on number line and analyze the relationship
-7/2………-2………..-2/3…………3 -
Question 18 of 50
18. Question
I. 3×2 + 19x + 20 = 0
II. 4y2 – 13y – 12 = 0
In the following questions, two equations numbered are given in variables x and y. You have to solve both the equations and find out the relationship between x and y. Then give answer accordingly-Correct
x = -5, -4/3
y = -3/4, 4
Put all values on number line and analyze the relationship
-5………-4/3……….-3/4………4Incorrect
x = -5, -4/3
y = -3/4, 4
Put all values on number line and analyze the relationship
-5………-4/3……….-3/4………4 -
Question 19 of 50
19. Question
I. 4×2 – 9x – 9 = 0
II. 4y2 + 15y + 9 = 0
In the following questions, two equations numbered are given in variables x and y. You have to solve both the equations and find out the relationship between x and y. Then give answer accordingly-Correct
x = -3/4, 3
y = -3, -3/4
Put all values on number line and analyze the relationship
-3……………-3/4…………3Incorrect
x = -3/4, 3
y = -3, -3/4
Put all values on number line and analyze the relationship
-3……………-3/4…………3 -
Question 20 of 50
20. Question
I. 2×2 – 3x – 9 = 0
II. 4y2 + 23y + 15 = 0
In the following questions, two equations numbered are given in variables x and y. You have to solve both the equations and find out the relationship between x and y. Then give answer accordingly-Correct
x = -3/2, 3
y = -5, -3/4
Put all values on number line and analyze the relationship
-5……….-3/4…….-3/2………3Incorrect
x = -3/2, 3
y = -5, -3/4
Put all values on number line and analyze the relationship
-5……….-3/4…….-3/2………3 -
Question 21 of 50
21. Question
In two alloys A and B the ratio of zinc to copper is 4:5 and 2:7 respectively. Eighteen kg of the alloy A and 45 kg of the alloy B are mixed together to form a new alloy. what will be the ratio of Zinc and copper in the new alloy?
Correct
Total Quantity of Zinc=4/9*18 + 2/9*45=8+10==>18
Total Quantity of Copper=5/9*18 + 7/9*45=10+35==>45
Ratio=18:45=2:5.Incorrect
Total Quantity of Zinc=4/9*18 + 2/9*45=8+10==>18
Total Quantity of Copper=5/9*18 + 7/9*45=10+35==>45
Ratio=18:45=2:5. -
Question 22 of 50
22. Question
If the manufacturer gains 10 %, the wholesale dealer 15 % and the retailer 25 %, then find the cost of production of a table if the retail price was Rs 1265
Correct
(125/100 *115/100*110/100 )*P =1265
(253/160) * P =1265
P=Rs800.Incorrect
(125/100 *115/100*110/100 )*P =1265
(253/160) * P =1265
P=Rs800. -
Question 23 of 50
23. Question
A began a business with Rs. 65,000. He was joined afterwards by B with Rs. 40,000. For how much period does B work, if the profits at the end of the year are divided in the ratio of 13 : 4?
Correct
(65000*12)/(40000*x)=13/4
X= 3/2x=1/4
X=6.
Incorrect
(65000*12)/(40000*x)=13/4
X= 3/2x=1/4
X=6.
-
Question 24 of 50
24. Question
After three successive equal percentage rise in the salary the sum of 100 rupees turned into 140 rupees and 49 paise. Find the percentage rise in the salary.
Correct
12% of 100 ==>112
12% of 112 ==>125.44
12% of 125.44 ==> 140.49.Incorrect
12% of 100 ==>112
12% of 112 ==>125.44
12% of 125.44 ==> 140.49. -
Question 25 of 50
25. Question
A dishonest milk man mixed 1 liter of water for every 3 liters of milk and thus made up 36 liters of milk. If he now adds 15 liters of milk to mixture, find the ratio of milk and water in the new mixture:
Correct
Quantity of milk and water in the 36 liter mixture;
27 liter milk and 9 liter water.
Now, 15 liters milk is added then milk becomes 42 liters.
Now, ratio = 42:9 = 14:3.Incorrect
Quantity of milk and water in the 36 liter mixture;
27 liter milk and 9 liter water.
Now, 15 liters milk is added then milk becomes 42 liters.
Now, ratio = 42:9 = 14:3. -
Question 26 of 50
26. Question
From a pack of 52 cards, two cards are drawn together at random. What is the probability of both the cards being kings?
Correct
P=n(e)/n(s)
=[(4*3)/(2*1)]/ [(52*51)/(2*1)]
=6/1326=1/221.
Incorrect
P=n(e)/n(s)
=[(4*3)/(2*1)]/ [(52*51)/(2*1)]
=6/1326=1/221.
-
Question 27 of 50
27. Question
The average weight of 6 persons increases by 3 kg when a new person comes in place of one of them weighing 45 kg. What might be the weight of the new person ?
Correct
Total weight increased = (6 x 3) kg = 18 kg.
Weight of new person = (45 + 18) kg = 63 kg.Incorrect
Total weight increased = (6 x 3) kg = 18 kg.
Weight of new person = (45 + 18) kg = 63 kg. -
Question 28 of 50
28. Question
The ratio between the perimeter and the breadth of a rectangle is 5 : 1. If the area of the rectangle is 216 sq. cm, what is the length of the rectangle?
Correct
Answer: A
2(l+b)/b=5/1
2l + 2b = 5b
3b = 2l
b= (2/3)l
Area = 216
l * b = 216
l * (2/3)l =216
l2= 324
l = 18 cm.Incorrect
Answer: A
2(l+b)/b=5/1
2l + 2b = 5b
3b = 2l
b= (2/3)l
Area = 216
l * b = 216
l * (2/3)l =216
l2= 324
l = 18 cm. -
Question 29 of 50
29. Question
A starts business with Rs. 3500 and after 5 months, B joins with A as his partner. After a year, the profit is divided in the ratio 2 : 3. What is B’s contribution in the capital?
Correct
Let B’s capital be Rs. x.
Then (3500*12)/7x=2/3
14x=126000
X=Rs 9000.Incorrect
Let B’s capital be Rs. x.
Then (3500*12)/7x=2/3
14x=126000
X=Rs 9000. -
Question 30 of 50
30. Question
12 buckets of water fill a tank when the capacity of each tank is 13.5 liters. How many buckets will be needed to fill the same tank,if the capacity of each bucket is 9 liters?
Correct
Capacity of the tank =(12 x 13.5) liters =162 liters.
Capacity of each bucket =9 liters
Number of buckets needed = 162/9 =18.Incorrect
Capacity of the tank =(12 x 13.5) liters =162 liters.
Capacity of each bucket =9 liters
Number of buckets needed = 162/9 =18. -
Question 31 of 50
31. Question
Study the bar chart carefully to answer the given questions.
What is the difference between the number of passengers travelling from X to S and that from X to T?
Correct
12000 * (16-9)/100
=120*7=840.Incorrect
12000 * (16-9)/100
=120*7=840. -
Question 32 of 50
32. Question
Study the bar chart carefully to answer the given questions.
What is the average no of passengers travelling from X to R, Q and S together?
Correct
12000* (15+22+16)/3
=120*53/3=2120.
Incorrect
12000* (15+22+16)/3
=120*53/3=2120.
-
Question 33 of 50
33. Question
Study the bar chart carefully to answer the given questions.
The no of passengers travelling from X to S is what percent more than the no of passengers travelling to P?
Correct
[12000*12/100] 100
[12000*(16-12)/100] ?==> 100/3=33 1/3%.Incorrect
[12000*12/100] 100
[12000*(16-12)/100] ?==> 100/3=33 1/3%. -
Question 34 of 50
34. Question
Study the bar chart carefully to answer the given questions.
What will be the central angle for passengers travelling from X to S ?
Correct
360 == 100
? 16 ==>57.6Deg.Incorrect
360 == 100
? 16 ==>57.6Deg. -
Question 35 of 50
35. Question
Study the bar chart carefully to answer the given questions.
Passengers travelling from X to which station are the maximum in number?
Correct
From bar graph,
The maximum no of passengers are travelling to station Q.Incorrect
From bar graph,
The maximum no of passengers are travelling to station Q. -
Question 36 of 50
36. Question
What is the number of employees in Finance Department of offices A and D?
Correct
In A = 18 * 3/2 = 27
In D = 32 * 7/8 = 28
Required total = 27+28 = 55Incorrect
In A = 18 * 3/2 = 27
In D = 32 * 7/8 = 28
Required total = 27+28 = 55 -
Question 37 of 50
37. Question
What is the number of employees in Other Departments of offices D and E?
Correct
In D, in finance = 28, so in Others = 250 – (32+28) = 190
in E, in finance = 48 * 11/6 = 88, so in Others= 360 -(48+88) = 224
Required total = 190 + 224Incorrect
In D, in finance = 28, so in Others = 250 – (32+28) = 190
in E, in finance = 48 * 11/6 = 88, so in Others= 360 -(48+88) = 224
Required total = 190 + 224 -
Question 38 of 50
38. Question
In Office C, 25%, 20% and 50% people in HR, Finance and Others Department respectively are females. What is the number of males in these departments in office C?
Correct
In C, in HR = 16, so males = 75/100 * 16 = 12
In C, in Finance = 16 * 5/8 = 10, so males = 80/100 * 10 = 8
In C, in Others = 280 – (16+10) = 254, so males = 50/100 * 254 = 127
Required number = 12+8+127 = 147Incorrect
In C, in HR = 16, so males = 75/100 * 16 = 12
In C, in Finance = 16 * 5/8 = 10, so males = 80/100 * 10 = 8
In C, in Others = 280 – (16+10) = 254, so males = 50/100 * 254 = 127
Required number = 12+8+127 = 147 -
Question 39 of 50
39. Question
What is the ratio of number of employees in Other Departments in offices A and D?
Correct
In A, in others = 270 – (18+27) = 225
in D, in others = 190
Required ratio = 225 : 190 = 45 : 38
Incorrect
In A, in others = 270 – (18+27) = 225
in D, in others = 190
Required ratio = 225 : 190 = 45 : 38
-
Question 40 of 50
40. Question
What is the total number of employees in Finance Department in all offices?
Correct
Required number 27+63+28+10+88 = 216
Incorrect
Required number 27+63+28+10+88 = 216
-
Question 41 of 50
41. Question
Two boats A and B starts from the two different places P and Q at the same time towards each other. If boat A is going downstream and other is going upstream, after how much time will they meet each other if their speeds are 15km/hr and 20km/hr respectively and if distance between the two places i.e P and Q is 210km?
Correct
Time = Distance /Relative speed
Relative speed =(15+D) +(20-D)=35
Therefore ,time at which they meet with each other = 210/35= 6 hoursIncorrect
Time = Distance /Relative speed
Relative speed =(15+D) +(20-D)=35
Therefore ,time at which they meet with each other = 210/35= 6 hours -
Question 42 of 50
42. Question
A company gives 5% of commission to a salesman upto the sale of 20,000 and a commission of 4% on the sales above 20,000. If the salesman deposited Rs.36,000 in the company after deducting his commission. Find his total sales (approx)?
Correct
Incorrect
-
Question 43 of 50
43. Question
Ram purchases 750 articles at a cost of 60 paise/article. He fixed the selling price such that if he sold only 600 articles ,he would made a profit of 40% on the incidental charge. However 120 articles got damaged and able to sell only 630 articles at this price. Find his actual profit % as the percentage of total incidental charge if unsold articles are useless.
Correct
Cost Price= 750 * 60/ 100 = Rs.450
Profit = 450 * 40 /100 = 180
If selling price of 600 articles is = Rs. 630
Then the selling priceof one article will be = Rs. 630/600
Selling Price of 630 articles = 630/600 * 630 = Rs. 661.5
Profit = 661.5 – 450 =Rs. 211.5
Profit % = 2115 / 4500 *100 = 47%Incorrect
Cost Price= 750 * 60/ 100 = Rs.450
Profit = 450 * 40 /100 = 180
If selling price of 600 articles is = Rs. 630
Then the selling priceof one article will be = Rs. 630/600
Selling Price of 630 articles = 630/600 * 630 = Rs. 661.5
Profit = 661.5 – 450 =Rs. 211.5
Profit % = 2115 / 4500 *100 = 47% -
Question 44 of 50
44. Question
A gold ring of 20 gm has gold and silver in the ratio 196:4 ,while another ring of 10 gm has in the ratio 8:2 .If both of them are molten and mixed together. Find the ratio of gold and silver in the resultant mixture?
Correct
Amt. of gold in the first gold ring = (196/196+4)*20 = 19.6 gm
Amt. of silver in the first silver ring = (4/196+4)* 20 = 0.4 gm
Amt. of gold in the second gold ring = (8/ 8+2)* 10 = 8 gm
Amt. of silver in the second silver ring =(2/ 8+2) *10 = 2 gm
Therefore , ratio of gold : silver = (19.6+8) / (0.4 + 2) = 23/2Incorrect
Amt. of gold in the first gold ring = (196/196+4)*20 = 19.6 gm
Amt. of silver in the first silver ring = (4/196+4)* 20 = 0.4 gm
Amt. of gold in the second gold ring = (8/ 8+2)* 10 = 8 gm
Amt. of silver in the second silver ring =(2/ 8+2) *10 = 2 gm
Therefore , ratio of gold : silver = (19.6+8) / (0.4 + 2) = 23/2 -
Question 45 of 50
45. Question
If a discount 20% on the marked price of an food item, the shopkeeper gets a profit of 40%. Find his percentage profit if he offers a discount of 40% on the same article ?
Correct
(100 + %first profit ) [100- % 2nd discount/ 100 -% 1st discount ] – 100
= (100 +40)[100-40/100-20] -100
=140(60/80) -100
=105-100
= 5%Incorrect
(100 + %first profit ) [100- % 2nd discount/ 100 -% 1st discount ] – 100
= (100 +40)[100-40/100-20] -100
=140(60/80) -100
=105-100
= 5% -
Question 46 of 50
46. Question
In how many ways the letters of the word “EQUATION” can be arranged if it always starts with letter “E” and ends with letter “T”
Correct
For this ,lets fix the letter E at the first position= 1! Way and fix T at the last position = 1! Way .
Now, remaining rest empty positions ie. 6 so we can arrange it in 6 different ways = 6! Ways
Hence , 1* 6! * 1= 720Incorrect
For this ,lets fix the letter E at the first position= 1! Way and fix T at the last position = 1! Way .
Now, remaining rest empty positions ie. 6 so we can arrange it in 6 different ways = 6! Ways
Hence , 1* 6! * 1= 720 -
Question 47 of 50
47. Question
A , B and C hired a meadow jointly for the whole year. A puts 80 cows for 10 months, B puts 100 cows for 6 months and C puts 120 cows for 3 months. If A paid Rs. 400 as rent. Find the total rent for the meadow ?
Correct
Find the ratio first ,
80*10 : 100 * 6 : 120 * 3
800 : 600 : 360
20 : 15 : 9
Therefore , Total rent of the meadow = 400/ 20 *44 =Rs. 880Incorrect
Find the ratio first ,
80*10 : 100 * 6 : 120 * 3
800 : 600 : 360
20 : 15 : 9
Therefore , Total rent of the meadow = 400/ 20 *44 =Rs. 880 -
Question 48 of 50
48. Question
A tank has two pipes. The first pipe can fill it in 45 minutes and the second pipe can empty it in 1 hour. In what time will the empty tank be filled if the pipes be opened one at a time in alternate minutes?
Correct
In 2 minutes -> +4 filled and -3 emptied = 1 litre filled
1 litre in 2 mins.
176 litres -> 176 * 2 = 352 mins.
Remaining 4 litres will be filled in 1 minute = 352 + 1= 353 minutes = 5 hrs 53 mins.Incorrect
In 2 minutes -> +4 filled and -3 emptied = 1 litre filled
1 litre in 2 mins.
176 litres -> 176 * 2 = 352 mins.
Remaining 4 litres will be filled in 1 minute = 352 + 1= 353 minutes = 5 hrs 53 mins. -
Question 49 of 50
49. Question
A bag contains 3 black and 5 red balls . A ball is drawn out of it and replaced in the bag. Two draws of two balls each are made ,the ball being replaced after the first draw. What is the chance that the balls were black in the first draw and red in the second draw?
Correct
Req. Probability = 3C2/8C2 * 5C2/ 8C2 = 15 / 392
Incorrect
Req. Probability = 3C2/8C2 * 5C2/ 8C2 = 15 / 392
-
Question 50 of 50
50. Question
The difference between the simple interest received from two different banks on Rs. 700 for 3 years is Rs. 3. What is the difference between their rate of interest ( in p.a ) ?
Correct
(3/ 700) *( 100 /3) = 1/7 = 0.143%
Incorrect
(3/ 700) *( 100 /3) = 1/7 = 0.143%
