## CAT Online Test Series 2, CAT Free Mock Test | Free CAT Quiz series 2

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**CAT Online Test Series 2, CAT Free Mock Test | Free CAT Quiz series 2.** Common Admission Test (CAT) is one of the most challenging and competitive MBA entrance test in our country. Check your level of preparation for *CAT* with free All India *Mock test* 2019. CAT Exam Online Test 2019, CAT Free Mock Test Exam 2019. CAT Exam Free Online Quiz 2019, CAT Full Online Mock Test **Series 2nd** in English. CAT Online Test for All Subjects, CAT Free Mock Test Series in English. CAT Free Mock Test **Series 2.** CAT English Language Online Test in English **Series 2nd**. Here we are providing** CAT Full Mock Test Paper in English. CAT **Mock Test **Series 2nd** 2019. Now Test your self for CAT Exam by using below quiz…

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- Question 1 of 50
##### 1. Question

Two pipes A and B can fill a tank in 4 and 5 hours respectively. If they are turned up alternately for one hour each, the time taken to fill the tank is?

Correct1/4 + 1/5 = 9/20

20/9 = 2 2/9

9/20 * 2 = 9/10 —- 4 hours

WR = 1 – 9/10 = 1/10

1 h —- 1/4

? —– 1/10

2/5 * 60 = 24 = 4 hrs 24 minIncorrect1/4 + 1/5 = 9/20

20/9 = 2 2/9

9/20 * 2 = 9/10 —- 4 hours

WR = 1 – 9/10 = 1/10

1 h —- 1/4

? —– 1/10

2/5 * 60 = 24 = 4 hrs 24 min - Question 2 of 50
##### 2. Question

Simple interest on a sum at 4% per annum for 2 years is Rs.80. The C.I. on the same sum for the same period is?

CorrectSI = 40 + 40

CI = 40 + 40 + 1.6 = 81.6IncorrectSI = 40 + 40

CI = 40 + 40 + 1.6 = 81.6 - Question 3 of 50
##### 3. Question

There are two circles of different radii. The are of a square is 784 sq cm and its side is twice the radius of the larger circle. The radius of the larger circle is seven – third that of the smaller circle. Find the circumference of the smaller circle.

CorrectLet the radii of the larger and the smaller circles be l cm and s cm respectively. Let the side of the square be a cm.

a^{2}= 784 = (4)(196) = (2^{2}).(14^{2})

a = (2)(14) = 28

a = 2l, l = a/2 = 14

l = (7/3)s

Therefore s = (3/7)(l) = 6 Circumference of the smaller circle = 2∏s = 12∏ cm.IncorrectLet the radii of the larger and the smaller circles be l cm and s cm respectively. Let the side of the square be a cm.

a^{2}= 784 = (4)(196) = (2^{2}).(14^{2})

a = (2)(14) = 28

a = 2l, l = a/2 = 14

l = (7/3)s

Therefore s = (3/7)(l) = 6 Circumference of the smaller circle = 2∏s = 12∏ cm. - Question 4 of 50
##### 4. Question

32% of 425 – ?% of 250 = 36

Correct32/100 * 425 – x/100 * 250 = 36

=> x/100 * 250 = 136 – 36 = 100

=> x = (100 * 100)/250 = 40Incorrect32/100 * 425 – x/100 * 250 = 36

=> x/100 * 250 = 136 – 36 = 100

=> x = (100 * 100)/250 = 40 - Question 5 of 50
##### 5. Question

A question paper consists of five problems, each problem having three internal choices. In how many ways can a candidate attempt one or more problems?

CorrectGiven that, the question paper consists of five problems. For each problem, one or two or three or none of the choices can be attempted.

Hence, the required number of ways = 4^{5}– 1.

= 2^{10}– 1 = 1024 – 1 = 1023IncorrectGiven that, the question paper consists of five problems. For each problem, one or two or three or none of the choices can be attempted.

Hence, the required number of ways = 4^{5}– 1.

= 2^{10}– 1 = 1024 – 1 = 1023 - Question 6 of 50
##### 6. Question

In an exam, Amar scored 64 percent, Bhavan scored 36 percent and Chetan 44 percent. The maximum score awarded in the exam is 800. Find the average mark scored by all the three boys?

CorrectAverage mark scored by all the three boys =

[64/100 (800) + 36/100 (800) + 44/100 (800)] / 3 = 384IncorrectAverage mark scored by all the three boys =

[64/100 (800) + 36/100 (800) + 44/100 (800)] / 3 = 384 - Question 7 of 50
##### 7. Question

Anil spends 40% of his income on rent, 30% of the remaining on medicines and 20% of the remaining on education. If he saves Rs. 840 every month, then find his monthly salary?

CorrectLet’s Anil’s salary be Rs. 100.

Money spent on Rent = 40% of 100 = Rs. 40.

Money spent on medical grounds = 30% of (100 – 40) = 3/10 * 60 = Rs. 18.

Money spent on education = 20% of (60 – 18) = 1/5 * 42 = Rs. 8.40

Anil saves 100 – (40 + 18 + 8.40) i.e., Rs. 33.60

for 33.6 —> 100 ; 840 —> ?

Required salary = 840/33.6 * 100 = Rs. 2500IncorrectLet’s Anil’s salary be Rs. 100.

Money spent on Rent = 40% of 100 = Rs. 40.

Money spent on medical grounds = 30% of (100 – 40) = 3/10 * 60 = Rs. 18.

Money spent on education = 20% of (60 – 18) = 1/5 * 42 = Rs. 8.40

Anil saves 100 – (40 + 18 + 8.40) i.e., Rs. 33.60

for 33.6 —> 100 ; 840 —> ?

Required salary = 840/33.6 * 100 = Rs. 2500 - Question 8 of 50
##### 8. Question

There were two candidates in an election. Winner candidate received 62% of votes and won the election by 288 votes. Find the number of votes casted to the winning candidate?

CorrectW = 62% L = 38%

62% – 38% = 24%

24% ——– 288

62% ——– ? => 744IncorrectW = 62% L = 38%

62% – 38% = 24%

24% ——– 288

62% ——– ? => 744 - Question 9 of 50
##### 9. Question

What is the difference between the local values of 3 in the number 53403?

Correct3000 – 3 = 2997

Incorrect3000 – 3 = 2997

- Question 10 of 50
##### 10. Question

A 70 cm long wire is to be cut into two pieces so that one piece will be 2/5th of the other, how many centimeters will the shorter piece be?

Correct1: 2/5 = 5: 2

2/7 * 70 = 20Incorrect1: 2/5 = 5: 2

2/7 * 70 = 20 - Question 11 of 50
##### 11. Question

A can do a piece of work in 30 days. He works at it for 5 days and then B finishes it in 20 days. In what time can A and B together it?

Correct5/30 + 20/x = 1

x = 24

1/30 + 1/24 = 3/40

40/3 = 13 1/3 daysIncorrect5/30 + 20/x = 1

x = 24

1/30 + 1/24 = 3/40

40/3 = 13 1/3 days - Question 12 of 50
##### 12. Question

If one-third of one fourth of a number is 15, then three-tenth of that number is:

CorrectLet the number be x. Then,

1/3 of 1/4 of x = 15

x = 15 * 12 = 180

So, required number = (3/10 * 180) = 54.IncorrectLet the number be x. Then,

1/3 of 1/4 of x = 15

x = 15 * 12 = 180

So, required number = (3/10 * 180) = 54. - Question 13 of 50
##### 13. Question

Find the roots of quadratic equation: 3x

^{2}– 7x – 6 = 0?Correct3x

^{2}– 9x + 2x – 6 = 0

3x(x – 3) + 2(x – 3) = 0

(x – 3)(3x + 2) = 0 => x = 3, -2/3Incorrect3x

^{2}– 9x + 2x – 6 = 0

3x(x – 3) + 2(x – 3) = 0

(x – 3)(3x + 2) = 0 => x = 3, -2/3 - Question 14 of 50
##### 14. Question

The average weight of a group of boys is 30 kg. After a boy of weight 35 kg joins the group, the average weight of the group goes up by 1 kg. Find the number of boys in the group originally ?

CorrectLet the number off boys in the group originally be x.

Total weight of the boys = 30x

After the boy weighing 35 kg joins the group, total weight of boys = 30x + 35

So 30x + 35 + 31(x + 1) = > x = 4.IncorrectLet the number off boys in the group originally be x.

Total weight of the boys = 30x

After the boy weighing 35 kg joins the group, total weight of boys = 30x + 35

So 30x + 35 + 31(x + 1) = > x = 4. - Question 15 of 50
##### 15. Question

A pump can fill a tank with water in 2 hours. Because of a leak, it took 2 1/3 hours to fill the tank. The leak can drain all the water of the tank in?

CorrectWork done by the tank in 1 hour = (1/2 – 1/3) = 1/14 Leak will empty the tank in 14 hrs.

IncorrectWork done by the tank in 1 hour = (1/2 – 1/3) = 1/14 Leak will empty the tank in 14 hrs.

- Question 16 of 50
##### 16. Question

150 men consume 1050 kg of rice in 30 days. In how many days will 70 men consume 980 kg of rice?

CorrectRate of consumption of each man = 1050/(150 * 30) = 7/30 kg/day

Let us say 70 men take x days to consume 150 kg.

Quantity consumed by each item in x days = (7x/30) kg

Quantity consumed by 70 men in x days = (7/30 x)(70) kg

= (7/30 x) * (70) = 960

x = 60 days.IncorrectRate of consumption of each man = 1050/(150 * 30) = 7/30 kg/day

Let us say 70 men take x days to consume 150 kg.

Quantity consumed by each item in x days = (7x/30) kg

Quantity consumed by 70 men in x days = (7/30 x)(70) kg

= (7/30 x) * (70) = 960

x = 60 days. - Question 17 of 50
##### 17. Question

The fourth proportional to 5, 8, 15 is:

CorrectLet the fourth proportional to 5, 8, 15 be x.

Then, 5:8 :: 15:x

x = (8 * 15)/5 = 24.IncorrectLet the fourth proportional to 5, 8, 15 be x.

Then, 5:8 :: 15:x

x = (8 * 15)/5 = 24. - Question 18 of 50
##### 18. Question

The probability that a number selected at random from the first 50 natural numbers is a composite number is -.

CorrectThe number of exhaustive events = ⁵⁰C₁ = 50.

We have 15 primes from 1 to 50.

Number of favourable cases are 34.

Required probability = 34/50 = 17/25.IncorrectThe number of exhaustive events = ⁵⁰C₁ = 50.

We have 15 primes from 1 to 50.

Number of favourable cases are 34.

Required probability = 34/50 = 17/25. - Question 19 of 50
##### 19. Question

The edges of three iron cubes are 6cm; 8cm; 10cm respectively. A new cube was made by melting them. Find the edge of the new cube?

Correct6

^{3}+ 8^{3}+ 10^{3}= a^{3}=> a = 12Incorrect6

^{3}+ 8^{3}+ 10^{3}= a^{3}=> a = 12 - Question 20 of 50
##### 20. Question

If the sum of a number and its square is 182, what is the number?

CorrectLet the number be x. Then,

x + x^{2}= 182

(x + 14)(x – 13) = 0

x = 13IncorrectLet the number be x. Then,

x + x^{2}= 182

(x + 14)(x – 13) = 0

x = 13 - Question 21 of 50
##### 21. Question

By selling 50 meters of cloth. I gain the selling price of 15 meters. Find the gain percent?

CorrectSP = CP + g

50 SP = 50 CP + 15 SP

35 SP = 50 CP

35 — 15 CP gain

100 — ? => 42 6/7%IncorrectSP = CP + g

50 SP = 50 CP + 15 SP

35 SP = 50 CP

35 — 15 CP gain

100 — ? => 42 6/7% - Question 22 of 50
##### 22. Question

Find the average of the first 20 natural numbers?

CorrectAverage of the first ‘n’ natural numbers = (n + 1)/2

We get (20 + 1)/2 = 10.5IncorrectAverage of the first ‘n’ natural numbers = (n + 1)/2

We get (20 + 1)/2 = 10.5 - Question 23 of 50
##### 23. Question

Pipes A and B can fill a tank in 5 and 6 hours respectively. Pipe C can empty it in 12 hours. If all the three pipes are opened together, then the tank will be filled in?

CorrectNet part filled in 1 hour = 1/5 + 1/6 – 1/12 = 17/60

The tank will be full in 60/17 hrs, i.e., 3 9/17 hrs.IncorrectNet part filled in 1 hour = 1/5 + 1/6 – 1/12 = 17/60

The tank will be full in 60/17 hrs, i.e., 3 9/17 hrs. - Question 24 of 50
##### 24. Question

If the sum of the two numbers is 22 and the sum of their squares is 404, then the product of the numbers is:

CorrectLet the numbers be x and y.

Then, (x + y) = 22 and x^{2}+ y^{2}= 404

Now,

2xy = (x + y)^{2}– (x^{2}+ y^{2})

2xy= 22^{2}– 404 = 484 – 404 = 80

xy = 40IncorrectLet the numbers be x and y.

Then, (x + y) = 22 and x^{2}+ y^{2}= 404

Now,

2xy = (x + y)^{2}– (x^{2}+ y^{2})

2xy= 22^{2}– 404 = 484 – 404 = 80

xy = 40 - Question 25 of 50
##### 25. Question

A started a business with an investment of Rs. 70000 and after 6 months B joined him investing Rs. 120000. If the profit at the end of a year is Rs. 52000, then the share of B is?

CorrectRatio of investments of A and B is (70000 * 12) : (120000 * 6) = 7 : 6

Total profit = Rs. 52000

Share of B = 6/13 (52000) = Rs. 24000IncorrectRatio of investments of A and B is (70000 * 12) : (120000 * 6) = 7 : 6

Total profit = Rs. 52000

Share of B = 6/13 (52000) = Rs. 24000 - Question 26 of 50
##### 26. Question

A 300 meter long train crosses a platform in 39 seconds while it crosses a signal pole in 18 seconds. What is the length of the platform?

CorrectSpeed = [300 / 18] m/sec = 50/3 m/sec.

Let the length of the platform be x meters.

Then, x + 300 / 39 = 50/3

3(x + 300) = 1950 → x = 350m.IncorrectSpeed = [300 / 18] m/sec = 50/3 m/sec.

Let the length of the platform be x meters.

Then, x + 300 / 39 = 50/3

3(x + 300) = 1950 → x = 350m. - Question 27 of 50
##### 27. Question

The average of 10 numbers is 23. If each number is increased by 4, what will the new average be?

CorrectSum of the 10 numbers = 230

If each number is increased by 4, the total increase =

4 * 10 = 40

The new sum = 230 + 40 = 270 The new average = 270/10 = 27.IncorrectSum of the 10 numbers = 230

If each number is increased by 4, the total increase =

4 * 10 = 40

The new sum = 230 + 40 = 270 The new average = 270/10 = 27. - Question 28 of 50
##### 28. Question

Raj invested an amount of Rs.17400 for two years. Find the rate of compound interest that will fetch him an amount of Rs.1783.50 at the end of two years?

CorrectLet the rate of interest be R% p.a.

17400[1 + R/100]^{2}= 17400 + 1783.50

[1 + R/100]^{2}= (17400 + 1783.50)/17400

= 1 + 1025/10000 = 1 + 41/400

= 441/400 = [21/20]^{2}

[1 + R/100] = 21/20

R/100 = 1/20

Therefore R = 5IncorrectLet the rate of interest be R% p.a.

17400[1 + R/100]^{2}= 17400 + 1783.50

[1 + R/100]^{2}= (17400 + 1783.50)/17400

= 1 + 1025/10000 = 1 + 41/400

= 441/400 = [21/20]^{2}

[1 + R/100] = 21/20

R/100 = 1/20

Therefore R = 5 - Question 29 of 50
##### 29. Question

A train of 24 carriages, each of 60 meters length, when an engine also of 60 meters length is running at a speed of 60 kmph. In what time will the train cross a bridge 1.5 km long?

CorrectD = 25 * 60 + 1500 = 3000 m

T = 3000/60 * 18/5 = 180 sec = 3 minsIncorrectD = 25 * 60 + 1500 = 3000 m

T = 3000/60 * 18/5 = 180 sec = 3 mins - Question 30 of 50
##### 30. Question

A dealer purchases 15 articles for Rs. 25 and sells 12 articles for Rs. 30. Find the profit percentage?

CorrectL.C.M of 15 and 12 = 60

CP of 60 articles = Rs. 100 (25 * 4)

SP of 60 articles = Rs. 150 (30 * 5)

Profit percentage = (150 – 100)/100 * 100 = 50%IncorrectL.C.M of 15 and 12 = 60

CP of 60 articles = Rs. 100 (25 * 4)

SP of 60 articles = Rs. 150 (30 * 5)

Profit percentage = (150 – 100)/100 * 100 = 50% - Question 31 of 50
##### 31. Question

The difference between simple interest and C.I. at the same rate for Rs.5000 for 2 years in Rs.72. The rate of interest is?

Correct5000 = 72(100/R)

^{2}

5 R^{2}= 720 => R = 12Incorrect5000 = 72(100/R)

^{2}

5 R^{2}= 720 => R = 12 - Question 32 of 50
##### 32. Question

Anna left for city A from city B at 5.20 a.m. She traveled at the speed of 80 km/hr for 2 hrs 15 min. After that the speed was reduced to 60 km/hr. If the distance between two cities is 350 kms, at what time did Anna reach city A?

CorrectDistance covered in 2 hrs 15 min i.e., 2 1/4 hrs = 80 * 9/4 = 180 hrs.

Time taken to cover remaining distance = (350 – 180)/60 = 17/6 hrs

= 2 5/6 = 2 hrs 50 min

Total time taken = (2 hrs 15 min + 2 hrs 50 min) = 5 hrs 5 min.

So, Anna reached city A at 10.25 a.m.IncorrectDistance covered in 2 hrs 15 min i.e., 2 1/4 hrs = 80 * 9/4 = 180 hrs.

Time taken to cover remaining distance = (350 – 180)/60 = 17/6 hrs

= 2 5/6 = 2 hrs 50 min

Total time taken = (2 hrs 15 min + 2 hrs 50 min) = 5 hrs 5 min.

So, Anna reached city A at 10.25 a.m. - Question 33 of 50
##### 33. Question

What percent of 125 is 16?

CorrectLet the required percentage be x%.

x% of 125 = 16 => x/100 * 125 = 16

=> x = 1600/125 = 64/5 = 12 4/5IncorrectLet the required percentage be x%.

x% of 125 = 16 => x/100 * 125 = 16

=> x = 1600/125 = 64/5 = 12 4/5 - Question 34 of 50
##### 34. Question

Two men and three women working 7 hours a day finish a work in 5 days. Four men and four women working 3 hours a day complete the work in 7 days. The number of days in which only 7 men working 4 hours a day will finish the work is?

Correct2M + 3W —– 35 h

4M + 4W ——- 21 h

7M ——-? d

70M + 105W = 84M +84M

21W = 14M => 2M = 3W

4 * 35 = 7 * x => x = 20 hours

20/4 = 5 daysIncorrect2M + 3W —– 35 h

4M + 4W ——- 21 h

7M ——-? d

70M + 105W = 84M +84M

21W = 14M => 2M = 3W

4 * 35 = 7 * x => x = 20 hours

20/4 = 5 days - Question 35 of 50
##### 35. Question

The average age 9 members of a committee are the same as it was 2 years ago, because an old number has been replaced by a younger number. Find how much younger is the new member than the old number?

Correct9 * 2 = 18 years

Incorrect9 * 2 = 18 years

- Question 36 of 50
##### 36. Question

(5 – 7)

^{2}* (6 – 9)^{2}/ (2^{3})^{-2}= ?Correct(5 – 7)

^{2}* (6 – 9)^{2}/ (2^{3})^{-2}= (-2)^{2}* (-3)^{2}* 1/(2^{3})^{-2}

= 4 * 9 * 64 = 2304.Incorrect(5 – 7)

^{2}* (6 – 9)^{2}/ (2^{3})^{-2}= (-2)^{2}* (-3)^{2}* 1/(2^{3})^{-2}

= 4 * 9 * 64 = 2304. - Question 37 of 50
##### 37. Question

If the height of a cone is increased by 100% then its volume is increased by?

CorrectIncorrect - Question 38 of 50
##### 38. Question

The sum of two numbers is 528 and their H.C.F is 33. The number of pairs of numbers satisfying the above conditions is:

CorrectLet the required numbers be 33a and 33b.

Then, 33a + 33b = 528 => a + b = 16.

Now, co-primes with sum 16 are (1, 15), (3, 13), (5, 11) and (7, 9).

Required numbers are (33 * 1, 33 * 15), (33 * 3, 33 * 13), (33 * 5, 33 * 11), (33 * 7, 33 * 9).

The number of such pairs is 4.IncorrectLet the required numbers be 33a and 33b.

Then, 33a + 33b = 528 => a + b = 16.

Now, co-primes with sum 16 are (1, 15), (3, 13), (5, 11) and (7, 9).

Required numbers are (33 * 1, 33 * 15), (33 * 3, 33 * 13), (33 * 5, 33 * 11), (33 * 7, 33 * 9).

The number of such pairs is 4. - Question 39 of 50
##### 39. Question

I. x

^{2}– x – 42 = 0,

II. y^{2}– 17y + 72 = 0 to solve both the equations to find the values of x and y?CorrectI. x

^{2}– 7x + 6x – 42 = 0

=> (x – 7)(x + 6) = 0 => x = 7, -6

II. y^{2}– 8y – 9y + 72 = 0

=> (y – 8)(y – 9) = 0 => y = 8, 9

=> x < yIncorrectI. x

^{2}– 7x + 6x – 42 = 0

=> (x – 7)(x + 6) = 0 => x = 7, -6

II. y^{2}– 8y – 9y + 72 = 0

=> (y – 8)(y – 9) = 0 => y = 8, 9

=> x < y - Question 40 of 50
##### 40. Question

A person purchases 90 clocks and sells 40 clocks at a gain of 10% and 50 clocks at a gain of 20%. If he sold all of them at a uniform profit of 15%, then he would have got Rs. 40 less. The cost price of each clock is:

CorrectLet C.P. of clock be Rs. x.

Then, C.P. of 90 clocks = Rs. 90x.

[(110% of 40x) + (120% of 50x)] – (115% of 90x) = 40

44x + 60x – 103.5x = 40

0.5x = 40 => x = 80IncorrectLet C.P. of clock be Rs. x.

Then, C.P. of 90 clocks = Rs. 90x.

[(110% of 40x) + (120% of 50x)] – (115% of 90x) = 40

44x + 60x – 103.5x = 40

0.5x = 40 => x = 80 - Question 41 of 50
##### 41. Question

X men can do a work in 120 days. If there were 20 men less, the work would have taken 60 days more. What is the value of X?

CorrectWe have M

_{1}D_{1}= M_{2}D_{2}

120X = (X – 20)180

=> 2X = (X – 20) 3 => 2X = 3X – 60

=> X = 60IncorrectWe have M

_{1}D_{1}= M_{2}D_{2}

120X = (X – 20)180

=> 2X = (X – 20) 3 => 2X = 3X – 60

=> X = 60 - Question 42 of 50
##### 42. Question

How much is 80% of 40 is greater than 4/5 of 25?

Correct(80/100) * 40 – (4/5) * 25

32 – 20 = 12Incorrect(80/100) * 40 – (4/5) * 25

32 – 20 = 12 - Question 43 of 50
##### 43. Question

In how many ways can three consonants and two vowels be selected from the letters of the word “TRIANGLE”?

CorrectThe word contains five consonants. Three vowels, three consonants can be selected from five consonants in ⁵C₃ ways, two vowels can be selected from three vowels in ³C₂ ways.

3 consonants and 2 vowels can be selected in ⁵C₂ . ³C₂ ways i.e., 10 * 3 = 30 ways.IncorrectThe word contains five consonants. Three vowels, three consonants can be selected from five consonants in ⁵C₃ ways, two vowels can be selected from three vowels in ³C₂ ways.

3 consonants and 2 vowels can be selected in ⁵C₂ . ³C₂ ways i.e., 10 * 3 = 30 ways. - Question 44 of 50
##### 44. Question

A train moves fast a telegraph post and a bridge 264 m long in 8 sec and 20 sec respectively. What is the speed of the train?

CorrectLet the length of the train be x m and its speed be y m/sec.

Then, x/y = 8 => x = 8y

(x + 264)/20 = y

y = 22

Speed = 22 m/sec = 22 * 18/5 = 79.2 km/hr.IncorrectLet the length of the train be x m and its speed be y m/sec.

Then, x/y = 8 => x = 8y

(x + 264)/20 = y

y = 22

Speed = 22 m/sec = 22 * 18/5 = 79.2 km/hr. - Question 45 of 50
##### 45. Question

Manoj borrowed Rs.3450 from Anwar at 6% p.a. simple interest for three years. He then added some more money to the borrowed sum and lent it to Ramu for the same time at 9% p.a. simple interest. If Manoj gains Rs.824.85 by way of interest on the borrowed sum as well as his own amount from the whole transaction, then what is the sum lent by him to Ramu?

CorrectLet the sum lent by Manoj to Ramu be Rs.P.

Amount gained by Manoj = P. 3.9 /100 = 3450.3.6/100 = Rs.824.85

27P = 62100 = 82485

P = (82485 + 62100)/27 = 3055 + 2300 = Rs.5355IncorrectLet the sum lent by Manoj to Ramu be Rs.P.

Amount gained by Manoj = P. 3.9 /100 = 3450.3.6/100 = Rs.824.85

27P = 62100 = 82485

P = (82485 + 62100)/27 = 3055 + 2300 = Rs.5355 - Question 46 of 50
##### 46. Question

A man buys two articles for Rs.1980 each and he gains 10% on the first and loses 10% on the next. Find his total gain or loss percent?

CorrectIncorrect - Question 47 of 50
##### 47. Question

A train 110 meters long is running with a speed of 60 kmph. In what time will it pass a man who is running at 6 kmph in the direction opposite to that in which the train is going?

CorrectSpeed of train relative to man = (60 + 6) km/hr = 66 km/hr

[66 * 5/18] m/sec = [55/3] m/sec.

Time taken to pass the man = [110 * 3/55] sec = 6 secIncorrectSpeed of train relative to man = (60 + 6) km/hr = 66 km/hr

[66 * 5/18] m/sec = [55/3] m/sec.

Time taken to pass the man = [110 * 3/55] sec = 6 sec - Question 48 of 50
##### 48. Question

150 men consume 1050 kg of rice in 30 days. In how many days will 70 men consume 980 kg of rice?

CorrectRate of consumption of each man = 1050/(150 * 30) = 7/30 kg/day

Let us say 70 men take x days to consume 150 kg.

Quantity consumed by each item in x days = 7x/30 kg.

Quantity consumed by 70 men in x days = (7x/30)(70)kg

(7x/30)(70) = 980

x = (980 * 30)/490 => x = 60 daysIncorrectRate of consumption of each man = 1050/(150 * 30) = 7/30 kg/day

Let us say 70 men take x days to consume 150 kg.

Quantity consumed by each item in x days = 7x/30 kg.

Quantity consumed by 70 men in x days = (7x/30)(70)kg

(7x/30)(70) = 980

x = (980 * 30)/490 => x = 60 days - Question 49 of 50
##### 49. Question

Ravi invested certain amount for two rates of simple interests at 6% p.a. and 7% p.a. What is the ratio of Ravi’s investments if the interests from those investments are equal?

CorrectLet x be the investment of Ravi in 6% and y be in 7%

x(6)(n)/100 = y(7)(n)/100

=> x/y = 7/6

x : y = 7 : 6IncorrectLet x be the investment of Ravi in 6% and y be in 7%

x(6)(n)/100 = y(7)(n)/100

=> x/y = 7/6

x : y = 7 : 6 - Question 50 of 50
##### 50. Question

Find the one which does not belong to that group ?

CorrectTiruvanantapuram, Hyderabad, Bangalore and Bhubaneswar are state capitals, while Calicut is not a state capital.

IncorrectTiruvanantapuram, Hyderabad, Bangalore and Bhubaneswar are state capitals, while Calicut is not a state capital.