## DCCB Online Test Series 1, DCCB Mock Test in English Series 1

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DCCB Online Test Series 1, DCCB Mock Test in English Series 1. DCCB Staff Assistant Mock Test 2019 -19. Free DCCB Online Test for competitive examination, entrance examination and campus interview. Take various tests and find out how much you score before you appear for your next interview and written test.. RRB Online Test for All Subjects, DCCB Free Mock Test Series in English. DCCB Free Mock Test **Series 1.** DCCB English Language Online Test in English **Series 1st**. DCCB Quantitative Aptitude Quiz 2019, DCCB Reasoning Ability Free Online Test. Take DCCB Online Quiz. The DCCB Full online mock test paper is free for all students. DCCB Question and Answers in English and Hindi **Series 1**. Here we are providing** DCCB Full Mock Test Paper in English. DCCB **Mock Test **Series 1st** 2019. Now Test your self for DCCB Exam by using below quiz…

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- Question 1 of 50
##### 1. Question

Ravi purchased a refrigerator and a mobile phone for Rs. 15000 and Rs. 8000 respectively. He sold the refrigerator at a loss of 4 percent and the mobile phone at a profit of 10 percent. Overall he make a.

CorrectLet the SP of the refrigerator and the mobile phone be Rs. r and Rs. m respectively.

r = 15000(1 – 4/100) = 15000 – 600

m = 8000(1 + 10/100) = 8000 + 800

Total SP – Total CP = r + m – (15000 + 8000) = -600 + 800 = Rs. 200

As this is positive, an overall profit of Rs. 200 was made.IncorrectLet the SP of the refrigerator and the mobile phone be Rs. r and Rs. m respectively.

r = 15000(1 – 4/100) = 15000 – 600

m = 8000(1 + 10/100) = 8000 + 800

Total SP – Total CP = r + m – (15000 + 8000) = -600 + 800 = Rs. 200

As this is positive, an overall profit of Rs. 200 was made. - Question 2 of 50
##### 2. Question

Walking 7/6 of his usual rate, a boy reaches his school 4 min early. Find his usual time to reach the school?

CorrectSpeed Ratio = 1:7/6 = 6:7

Time Ratio = 7:6

1 ——– 7

4 ——— ? → 28 mIncorrectSpeed Ratio = 1:7/6 = 6:7

Time Ratio = 7:6

1 ——– 7

4 ——— ? → 28 m - Question 3 of 50
##### 3. Question

(98 / 7 / 2) / ? = 14

Correct? = (98 / 7 / 2) / 14 = 1/2

Incorrect? = (98 / 7 / 2) / 14 = 1/2

- Question 4 of 50
##### 4. Question

A rectangular field has area equal to 150 sq m and perimeter 50 m. Its length and breadth must be?

Correctlb = 150

2(l + b) = 50 => l + b = 25

l – b = 5

l = 15 b = 10Incorrectlb = 150

2(l + b) = 50 => l + b = 25

l – b = 5

l = 15 b = 10 - Question 5 of 50
##### 5. Question

How many minimum number’s of whole square slabs are required for paving the floor 12.96 meters long and 3.84 meters side?

CorrectHCF of 384, 1296 = 48

48 * 48 * x = 384 * 1296

x = 216IncorrectHCF of 384, 1296 = 48

48 * 48 * x = 384 * 1296

x = 216 - Question 6 of 50
##### 6. Question

A motorcyclist goes from Bombay to Pune, a distance of 192 kms at an average of 32 kmph speed. Another man starts from Bombay by car 2 ½ hours after the first, and reaches Pune ½ hour earlier. What is the ratio of the speed of the motorcycle and the car?

CorrectT = 192/32 = 6 h

T = 6 – 3 = 3

Time Ratio = 6:3 = 2:1

Speed Ratio = 1:2IncorrectT = 192/32 = 6 h

T = 6 – 3 = 3

Time Ratio = 6:3 = 2:1

Speed Ratio = 1:2 - Question 7 of 50
##### 7. Question

By mixing two brands of tea and selling the mixture at the rate of Rs. 177 per kg. a shopkeeper makes a profit of 18%. If to every 2 kg of one brand costing Rs. 200 per kg, 3 kg of the other brand is added, then how much per kg does the other brand cost?

CorrectLet the cost of the brand be Rs. X per kg.

C.P. of 5 kg = (2 * 200 + 3 * x) = Rs. (400 + 3x)

S.P of 5 kg = Rs. (5 * 177) = Rs. 885

[885 – (400 + 3x)]/(400 + 3x) * 100 = 18

24250 – 150x = 3600 + 27x

177x = 20650 => x = 116 2/3

So, cost of the other brand = Rs. 116.66.IncorrectLet the cost of the brand be Rs. X per kg.

C.P. of 5 kg = (2 * 200 + 3 * x) = Rs. (400 + 3x)

S.P of 5 kg = Rs. (5 * 177) = Rs. 885

[885 – (400 + 3x)]/(400 + 3x) * 100 = 18

24250 – 150x = 3600 + 27x

177x = 20650 => x = 116 2/3

So, cost of the other brand = Rs. 116.66. - Question 8 of 50
##### 8. Question

Two trains 121 meters and 165 meters in length respectively are running in opposite directions, one at the rate of 80 km and the other at the rate of 65 kmph. In what time will they be completely clear of each other from the moment they meet?

CorrectT = (121 + 165)/ (80 + 65) * 18/5

T = 7.15IncorrectT = (121 + 165)/ (80 + 65) * 18/5

T = 7.15 - Question 9 of 50
##### 9. Question

What is the ratio between perimeters of two squares one having 3 times the diagonal then the other?

Correctd = 3d d = d

a√2 = 3d a√2 = d

a = 3d/√2 a = d/√2 => 3: 1Incorrectd = 3d d = d

a√2 = 3d a√2 = d

a = 3d/√2 a = d/√2 => 3: 1 - Question 10 of 50
##### 10. Question

A and B invests Rs.10000 each, A investing for 8 months and B investing for all the 12 months in the year. If the total profit at the end of the year is Rs.25000, find their shares?

CorrectThe ratio of their profits A:B = 8:12 = 2:3

Share of A in the total profit = 2/5 * 25000 = Rs.10000 Share of A in the total profit = 3/5 * 25000 = Rs.15000IncorrectThe ratio of their profits A:B = 8:12 = 2:3

Share of A in the total profit = 2/5 * 25000 = Rs.10000 Share of A in the total profit = 3/5 * 25000 = Rs.15000 - Question 11 of 50
##### 11. Question

The sum of a number and its reciprocal is one-eighth of 34. What is the product of the number and its square root?

CorrectLet the number be x. Then,

x + 1/x = 34/8

8x^{2}– 34x + 8 = 0

4x^{2}– 17x + 4 = 0

(4x – 1)(x – 4) = 0

x = 4

required number = 4 * √4 = 4 * 2 = 8.IncorrectLet the number be x. Then,

x + 1/x = 34/8

8x^{2}– 34x + 8 = 0

4x^{2}– 17x + 4 = 0

(4x – 1)(x – 4) = 0

x = 4

required number = 4 * √4 = 4 * 2 = 8. - Question 12 of 50
##### 12. Question

Mohan’s salary was first increased by 20% and then decreased by 20%. If his present salary is Rs. 7200, then what was his original salary?

CorrectLet Mohan’s salary be Rs.100.

When increased by 20%, Mohan’s salary = Rs.120

Again when decreased by 20%, Mohan’s salary = 120 – 24 = Rs. 96.

But present salary is Rs. 7200

for, 96 —> 100 ; 7200 —> ?

Required salary is 7200/96 * 100 = Rs. 7500IncorrectLet Mohan’s salary be Rs.100.

When increased by 20%, Mohan’s salary = Rs.120

Again when decreased by 20%, Mohan’s salary = 120 – 24 = Rs. 96.

But present salary is Rs. 7200

for, 96 —> 100 ; 7200 —> ?

Required salary is 7200/96 * 100 = Rs. 7500 - Question 13 of 50
##### 13. Question

If the L.C.M of two numbers is 750 and their product is 18750, find the H.C.F of the numbers.

CorrectH.C.F = (Product of the numbers) / (Their L.C.M) = 18750/750 = 25.

IncorrectH.C.F = (Product of the numbers) / (Their L.C.M) = 18750/750 = 25.

- Question 14 of 50
##### 14. Question

The product of two natural numbers is 17. Then, the sum of the reciprocals of their squares is:

CorrectLet the numbers be a and b. Then,

ab = 17, a = 1 and b = 17

So, 1/a^{2}+ 1/b^{2}= (a^{2}+ b^{2})/a^{2}b^{2}

= (1^{2}+ 17^{2})/(1 * 17)^{2}= 290/289IncorrectLet the numbers be a and b. Then,

ab = 17, a = 1 and b = 17

So, 1/a^{2}+ 1/b^{2}= (a^{2}+ b^{2})/a^{2}b^{2}

= (1^{2}+ 17^{2})/(1 * 17)^{2}= 290/289 - Question 15 of 50
##### 15. Question

A sum of Rs. 125000 amounts to Rs. 15500 in 4 years at the rate of simple interest. What is the rate of interest?

CorrectS.I. = (15500 – 12500) = Rs. 3000\

Rate = (100 * 3000) / (12500 * 4) = 6%IncorrectS.I. = (15500 – 12500) = Rs. 3000\

Rate = (100 * 3000) / (12500 * 4) = 6% - Question 16 of 50
##### 16. Question

1000 men have provisions for 15 days. If 200 more men join them, for how many days will the provisions last now?

Correct1000*15 = 1200*x

x = 12.5Incorrect1000*15 = 1200*x

x = 12.5 - Question 17 of 50
##### 17. Question

How many figures are required for numbering the pages of a book containing 1000 pages?

Correct1 to 9 = 9 * 1 = 9

10 to 99 = 90 * 2 = 180

100 to 999 = 900 * 3 =2700

1000 = 4

———–

2893Incorrect1 to 9 = 9 * 1 = 9

10 to 99 = 90 * 2 = 180

100 to 999 = 900 * 3 =2700

1000 = 4

———–

2893 - Question 18 of 50
##### 18. Question

The sum of three consecutive multiples of 3 is 72. What is the largest number?

CorrectLet the numbers be 3x, 3x + 3 and 3x + 6.

Then,

3x + (3x + 3) + (3x + 6) = 72

9x = 63

x = 7

Largest number = 3x + 6 = 27.IncorrectLet the numbers be 3x, 3x + 3 and 3x + 6.

Then,

3x + (3x + 3) + (3x + 6) = 72

9x = 63

x = 7

Largest number = 3x + 6 = 27. - Question 19 of 50
##### 19. Question

Solve for m if 3(√3)

^{m+4}= (√3)^{2m+7}Correct3(√3)

^{m+4 }= 3(3^{½})^{m+4 }= 3^{1+(m+4)/2}

(√3)^{2}^{m+7 }= (3^{½})^{2}^{m+7 }= 3^{(2m+7)/2}

As 3(√3)^{m+4 }= (√3)^{2}^{m+7}=>^{ }3^{1+(m+4)/2 }= 3^{(2m+7)/2}

Equating the powers of 3 on both sides, m = -1.Incorrect3(√3)

^{m+4 }= 3(3^{½})^{m+4 }= 3^{1+(m+4)/2}

(√3)^{2}^{m+7 }= (3^{½})^{2}^{m+7 }= 3^{(2m+7)/2}

As 3(√3)^{m+4 }= (√3)^{2}^{m+7}=>^{ }3^{1+(m+4)/2 }= 3^{(2m+7)/2}

Equating the powers of 3 on both sides, m = -1. - Question 20 of 50
##### 20. Question

The difference between simple and compound interest on Rs. 1200 for one year at 10% per annum reckoned half-yearly is?

CorrectS.I. = (1200 * 10 * 1)/100 = Rs. 120

C.I. = [1200 * (1 + 5/100)^{2}– 1200] = Rs. 123 Difference = (123 – 120) = Rs. 3.IncorrectS.I. = (1200 * 10 * 1)/100 = Rs. 120

C.I. = [1200 * (1 + 5/100)^{2}– 1200] = Rs. 123 Difference = (123 – 120) = Rs. 3. - Question 21 of 50
##### 21. Question

A sum amount to Rs.1344 in two years at simple interest. What will be the compound interest on the same sum at the same rate of interest for the same period?

CorrectIncorrect - Question 22 of 50
##### 22. Question

Four bells begin to toll together respectively at the intervals of 8, 10, 12 and 16 seconds. After how many seconds will they toll together again?

CorrectLCM = 240

IncorrectLCM = 240

- Question 23 of 50
##### 23. Question

Sum of two numbers is 80. Greater number exceeds by 5 from four times of the smaller. Find the numbers?

Correctx + y = 80

x – 4y = 5

x = 65 y = 15Incorrectx + y = 80

x – 4y = 5

x = 65 y = 15 - Question 24 of 50
##### 24. Question

Sum of two numbers is 15. Two times of the first exceeds by 5 from the three times of the other. Then the numbers will be?

Correctx + y = 15

2x – 3y = 5

x = 10 y = 5Incorrectx + y = 15

2x – 3y = 5

x = 10 y = 5 - Question 25 of 50
##### 25. Question

The average of the marks of 12 students in a class is 36. If the marks of each student are doubled, find the new average?

CorrectSum of the marks for the 12 students = 12 * 36 = 432. The marks of each student are doubled, the sum also will be doubled.

The new sum = 432 * 2 = 864. So, the new average = 864/12 = 72.IncorrectSum of the marks for the 12 students = 12 * 36 = 432. The marks of each student are doubled, the sum also will be doubled.

The new sum = 432 * 2 = 864. So, the new average = 864/12 = 72. - Question 26 of 50
##### 26. Question

H.C.F of 4 * 27 * 3125, 8 * 9 * 25 * 7 and 16 * 81 * 5 * 11 * 49 is:

Correct4 * 27 * 3125 = 2

^{2}* 3^{3}* 5^{5};

8 * 9 * 25 * 7 = 2^{3}* 3^{2}* 5^{2}* 7;

16 * 81 * 5 * 11 * 49 = 2^{4}* 3^{4}* 5 * 7^{2}* 11

H.C.F = 2^{2}* 3^{2}* 5 = 180.Incorrect4 * 27 * 3125 = 2

^{2}* 3^{3}* 5^{5};

8 * 9 * 25 * 7 = 2^{3}* 3^{2}* 5^{2}* 7;

16 * 81 * 5 * 11 * 49 = 2^{4}* 3^{4}* 5 * 7^{2}* 11

H.C.F = 2^{2}* 3^{2}* 5 = 180. - Question 27 of 50
##### 27. Question

The time taken by a man to row his boat upstream is twice the time taken by him to row the same distance downstream. If the speed of the boat in still water is 42 kmph, find the speed of the stream?

CorrectThe ratio of the times taken is 2:1.

The ratio of the speed of the boat in still water to the speed of the stream = (2+1)/(2-1) = 3/1 = 3:1

Speed of the stream = 42/3 = 14 kmph.IncorrectThe ratio of the times taken is 2:1.

The ratio of the speed of the boat in still water to the speed of the stream = (2+1)/(2-1) = 3/1 = 3:1

Speed of the stream = 42/3 = 14 kmph. - Question 28 of 50
##### 28. Question

The edges of cuboid are 4 cm; 5 cm and 6 cm. Find its surface area?

Correct2(4*5 + 5*6 + 4*6) = 148

Incorrect2(4*5 + 5*6 + 4*6) = 148

- Question 29 of 50
##### 29. Question

Find the amount on Rs.8000 in 9 months at 20% per annum, if the interest being compounded quarterly?

CorrectA = 8000(21/20)

^{3}= 9261IncorrectA = 8000(21/20)

^{3}= 9261 - Question 30 of 50
##### 30. Question

If A lends Rs.3500 to B at 10% per annum and B lends the same sum to C at 11.5% per annum then the gain of B in a period of 3 years is?

Correct(3500*1.5*3)/100 => 157.50

Incorrect(3500*1.5*3)/100 => 157.50

- Question 31 of 50
##### 31. Question

Find the one which does not belong to that group ?

Correct36 = 6

^{2}, 49 = 7^{2}, 64 = 8^{2}, 81 = 9^{2}and 100 = 10^{2}.

36, 64, 81 and 100 are squares of composite numbers, but not 49.Incorrect36 = 6

^{2}, 49 = 7^{2}, 64 = 8^{2}, 81 = 9^{2}and 100 = 10^{2}.

36, 64, 81 and 100 are squares of composite numbers, but not 49. - Question 32 of 50
##### 32. Question

A and B can do a piece of work in 3 days, B and C in 4 days, C and A in 6 days. How long will C take to do it?

Correct2c = ¼ + 1/6 – 1/3 = 1/12

c = 1/24 => 24 daysIncorrect2c = ¼ + 1/6 – 1/3 = 1/12

c = 1/24 => 24 days - Question 33 of 50
##### 33. Question

31.2 * 14.5 * 9.6 = ?

CorrectIncorrect - Question 34 of 50
##### 34. Question

Difference between two numbers is 5, six times of the smaller lacks by 6 from the four times of the greater. Find the numbers?

Correctx – y = 5

4x – 6y = 6

x = 12 y = 7Incorrectx – y = 5

4x – 6y = 6

x = 12 y = 7 - Question 35 of 50
##### 35. Question

A fair price shopkeeper takes 10% profit on his goods. He lost 20% goods during theft. His loss percent is:

CorrectSuppose he has 100 items. Let C.P. of each item be Re. 1.

Total cost = Rs. 100. Number of items left after theft = 80.

S.P. of each item = Rs. 1.10

Total sale = 1.10 * 80 = Rs. 88

Hence, loss % = 12/100 * 100 = 12%IncorrectSuppose he has 100 items. Let C.P. of each item be Re. 1.

Total cost = Rs. 100. Number of items left after theft = 80.

S.P. of each item = Rs. 1.10

Total sale = 1.10 * 80 = Rs. 88

Hence, loss % = 12/100 * 100 = 12% - Question 36 of 50
##### 36. Question

Simplify : 1 – {1 + (a

^{2}– 1)^{-1}}^{-1}Correct1 – {1 + (a

^{2}– 1)^{-1}}^{-1}= 1 – {1 + 1/a^{2}– 1}^{-1}= 1 – {a^{2}/ a^{2}– 1}^{-1}= 1 – (a^{2}– 1)/a^{2}= 1/a^{2}.Incorrect1 – {1 + (a

^{2}– 1)^{-1}}^{-1}= 1 – {1 + 1/a^{2}– 1}^{-1}= 1 – {a^{2}/ a^{2}– 1}^{-1}= 1 – (a^{2}– 1)/a^{2}= 1/a^{2}. - Question 37 of 50
##### 37. Question

The product of two successive numbers is 4556. Which of the following is the larger of the two numbers?

CorrectLet the two successive numbers be n, n + 1.

It is given that n(n + 1) = 4556.

=> n^{2}+ n – 4556 = 0

=> n^{2}+ 68n – 67n – 4556 = 0

=> n(n + 68) – 67(n + 68) = 0

=> n = 67 and (n + 1) = 68.IncorrectLet the two successive numbers be n, n + 1.

It is given that n(n + 1) = 4556.

=> n^{2}+ n – 4556 = 0

=> n^{2}+ 68n – 67n – 4556 = 0

=> n(n + 68) – 67(n + 68) = 0

=> n = 67 and (n + 1) = 68. - Question 38 of 50
##### 38. Question

Surface area of two spheres are in the ratio 1:4 what is the ratio of their volumes?

CorrectIncorrect - Question 39 of 50
##### 39. Question

The radius of a cylinder is 2 r units and height is 3 r units. Find the curved surface?

Correct2 * π * 2r * 3r = 12 πr

^{2}Incorrect2 * π * 2r * 3r = 12 πr

^{2} - Question 40 of 50
##### 40. Question

There is a 30% increase in the price of an article in the first year, a 20% decrease in the second year and a 10% increase in the next year. If the final price of the article is Rs. 2288, then what was the price of the article initially?

CorrectLet the price of the article, four years age be Rs. 100 in the 1st year, price of the article = 100 + 30 = Rs. 130. In the 2nd year, price = 130 – 20% of 130 = 130 – 26 = Rs. 104.

In the 3rd year, price = 104 + 10% of 104 = 104 + 10.4 = Rs. 114.40.

But present price of the article is Rs. 2288

for 114.4 —> 100 ; 2288 —> ?

Required price = (2288 * 100)/114.4 = 20 * 100 = Rs. 2000.IncorrectLet the price of the article, four years age be Rs. 100 in the 1st year, price of the article = 100 + 30 = Rs. 130. In the 2nd year, price = 130 – 20% of 130 = 130 – 26 = Rs. 104.

In the 3rd year, price = 104 + 10% of 104 = 104 + 10.4 = Rs. 114.40.

But present price of the article is Rs. 2288

for 114.4 —> 100 ; 2288 —> ?

Required price = (2288 * 100)/114.4 = 20 * 100 = Rs. 2000. - Question 41 of 50
##### 41. Question

Find the one which does not belong to that group ?

CorrectThe sum of the digits in 508, 328, 706 and 148 is 13, but not in 608.

IncorrectThe sum of the digits in 508, 328, 706 and 148 is 13, but not in 608.

- Question 42 of 50
##### 42. Question

The average salary per head of the entire staff of an office including the officers and clerks is Rs.90. The average salary of officers is Rs.600 and that of the clerks is Rs.84. If the number of officers is 2, find the number of officers in the office?

CorrectIncorrect - Question 43 of 50
##### 43. Question

If A:B = 1/2: 1/3 B:C = 1/2:1/3 then A:B:C?

CorrectA:B = 1/2:1/3 = 3:2

B:C = 1/2:1/3 = 3:2

——————–

A:B:C = 9:6:4IncorrectA:B = 1/2:1/3 = 3:2

B:C = 1/2:1/3 = 3:2

——————–

A:B:C = 9:6:4 - Question 44 of 50
##### 44. Question

If Rs.7500 are borrowed at C.I at the rate of 4% per annum, then after 2 years the amount to be paid is?

CorrectA = 7500(26/25)

^{2}= 8112IncorrectA = 7500(26/25)

^{2}= 8112 - Question 45 of 50
##### 45. Question

A 1200 m long train crosses a tree in 120 sec, how much time will I take to pass a platform 700 m long?

CorrectL = S*T

S= 1200/120

S= 10 m/Sec.

Total length (D)= 1900 m

T = D/S

T = 1900/10

T = 190 SecIncorrectL = S*T

S= 1200/120

S= 10 m/Sec.

Total length (D)= 1900 m

T = D/S

T = 1900/10

T = 190 Sec - Question 46 of 50
##### 46. Question

By selling 150 mangoes, a fruit-seller gains the selling price of 30 mangoes. Find the gain percent?

CorrectSP = CP + g

150 SP = 150 CP + 30 SP

120 SP = 150 CP

120 — 30 CP

100 — ? => 25%IncorrectSP = CP + g

150 SP = 150 CP + 30 SP

120 SP = 150 CP

120 — 30 CP

100 — ? => 25% - Question 47 of 50
##### 47. Question

A building contractor employs 20 male, 15 female and 5 child workers. To a male worker he pays Rs.25 per day, to a female worker Rs.20 per day and a child worker Rs.8 per day. The average wage per day paid by the contractor is?

Correct20 15 5

25 20 8

500 + 300 + 40 = 840/40 = 21Incorrect20 15 5

25 20 8

500 + 300 + 40 = 840/40 = 21 - Question 48 of 50
##### 48. Question

A, B and C started a business with capitals of Rs. 8000, Rs. 10000 and Rs. 12000 respectively. At the end of the year, the profit share of B is Rs. 1500. The difference between the profit shares of A and C is?

CorrectRatio of investments of A, B and C is 8000 : 10000 : 12000 = 4 : 5 : 6

And also given that, profit share of B is Rs. 1500

=> 5 parts out of 15 parts is Rs. 1500

Now, required difference is 6 – 4 = 2 parts

Required difference = 2/5 (1500) = Rs. 600IncorrectRatio of investments of A, B and C is 8000 : 10000 : 12000 = 4 : 5 : 6

And also given that, profit share of B is Rs. 1500

=> 5 parts out of 15 parts is Rs. 1500

Now, required difference is 6 – 4 = 2 parts

Required difference = 2/5 (1500) = Rs. 600 - Question 49 of 50
##### 49. Question

A train leaves Mumabai at 9 am at a speed of 40 kmph. After one hour, another train leaves Mumbai in the same direction as that of the first train at a speed of 50 kmph. When and at what distance from Mumbai do the two trains meet?

CorrectWhen the second train leaves Mumbai the first train covers 40 * 1 = 40 km

So, the distance between first train and second train is 40 km at 10.00am

Time taken by the trains to meet

= Distance / relative speed = 40 / (50 -40) = 4 hours

So, the two trains meet at 2 p.m. The two trains meet 4 * 50 = 200 km away from Mumbai.

Learn more problems on : Time and DistanceIncorrectWhen the second train leaves Mumbai the first train covers 40 * 1 = 40 km

So, the distance between first train and second train is 40 km at 10.00am

Time taken by the trains to meet

= Distance / relative speed = 40 / (50 -40) = 4 hours

So, the two trains meet at 2 p.m. The two trains meet 4 * 50 = 200 km away from Mumbai.

Learn more problems on : Time and Distance - Question 50 of 50
##### 50. Question

The difference between the two digit number and the number obtained by interchanging its digits is 54. The difference between the digits is?

Correct(10x + y) – (10y + x) = 54

x – y = 6Incorrect(10x + y) – (10y + x) = 54

x – y = 6