## LIC ADO Online Test Series 2, LIC ADO Mock Test Series 2, LIC ADO Quiz

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LIC ADO Online Test Series 2, LIC ADO Mock Test Series 2, LIC ADO Quiz.Take this *LIC ADO Mock Test* | Free Online Test and find out how much you score before you appear for your next interview and written test**.** LIC ADO English Language Online Test in English **Series 2nd**. Take LIC ADO Online Quiz. The LIC ADO Full online mock test paper is free for all students. LIC ADO Question and Answers in English and Hindi **Series 2**.Most of the organizations are opting for computer based online mode of examination. So, a student needs to practice the question papers in online mod before appearing for the exam. Here we are providing** LIC ADO Full Mock Test Paper in English. LIC ADO **Mock Test **Series 2nd** 2019. Now Test your self for LIC ADO Exam by using below quiz…

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- Question 1 of 50
##### 1. Question

The length of a rectangular floor is more than its breadth by 200%. If Rs. 324 is required to paint the floor at the rate of Rs. 3 per sq m, then what would be the length of the floor?

CorrectLet the length and the breadth of the floor be l m and b m respectively.

l = b + 200% of b = l + 2b = 3b

Area of the floor = 324/3 = 108 sq m

l b = 108 i.e., l * l/3 = 108

l^{2}= 324 => l = 18.IncorrectLet the length and the breadth of the floor be l m and b m respectively.

l = b + 200% of b = l + 2b = 3b

Area of the floor = 324/3 = 108 sq m

l b = 108 i.e., l * l/3 = 108

l^{2}= 324 => l = 18. - Question 2 of 50
##### 2. Question

Find the least number with which 16200 should be multiplied, to make it a perfect cube.

Correct16200 = 2

^{3}* 3^{4}* 5^{2}

A perfect cube has a property of having the indices of all its prime factors divisible by 3.

Required number = 3^{2}* 5 = 45.Incorrect16200 = 2

^{3}* 3^{4}* 5^{2}

A perfect cube has a property of having the indices of all its prime factors divisible by 3.

Required number = 3^{2}* 5 = 45. - Question 3 of 50
##### 3. Question

Calculate the number of bricks, each measuring 25 cm * 15 cm * 8 cm required to construct a wall of dimensions 10 m * 4 m * 5 m when 10% of its volume is occupied by mortar?

Correct10 * 4/100 * 5 * 90/100 = 25/100 * 15/100 * 8/100 * x

10 * 20 * 90 = 15 * 2 * x => x = 6000Incorrect10 * 4/100 * 5 * 90/100 = 25/100 * 15/100 * 8/100 * x

10 * 20 * 90 = 15 * 2 * x => x = 6000 - Question 4 of 50
##### 4. Question

Two cylinders are of the same height. Their radii are in the ratio 1: 3. If the volume of the first cylinder is 40 cc. Find the volume of the second cylinder?

Correctr

_{1}= x r_{2}= 3x

Π * x^{2}* h = 40

Π9 x^{2}h = 40 * 9 = 360Incorrectr

_{1}= x r_{2}= 3x

Π * x^{2}* h = 40

Π9 x^{2}h = 40 * 9 = 360 - Question 5 of 50
##### 5. Question

Two pipes can fill a tank in 18 minutes and 15 minutes. An outlet pipe can empty the tank in 45 minutes. If all the pipes are opened when the tank is empty, then how many minutes will it take to fill the tank?

CorrectPart of the filled by all the three pipes in one minute

= 1/18 + 1/15 – 1/45 = (5 + 6 – 2)/90 = 9/90 = 1/10

So, the tank becomes full in 10 minutes.IncorrectPart of the filled by all the three pipes in one minute

= 1/18 + 1/15 – 1/45 = (5 + 6 – 2)/90 = 9/90 = 1/10

So, the tank becomes full in 10 minutes. - Question 6 of 50
##### 6. Question

(64 + 9 + 9) / (2 * 20 + 1) = ?

Correct(64 + 9 + 9) / (2 * 20 + 1) = 82/41 = 2

Incorrect(64 + 9 + 9) / (2 * 20 + 1) = 82/41 = 2

- Question 7 of 50
##### 7. Question

The difference between simple and compound interest on Rs. 1200 for one year at 10% per annum reckoned half-yearly is?

CorrectS.I. = (1200 * 10 * 1)/100 = Rs. 120

C.I. = [1200 * (1 + 5/100)2 – 1200] = Rs. 123 Difference = (123 – 120) = Rs. 3.IncorrectS.I. = (1200 * 10 * 1)/100 = Rs. 120

C.I. = [1200 * (1 + 5/100)2 – 1200] = Rs. 123 Difference = (123 – 120) = Rs. 3. - Question 8 of 50
##### 8. Question

(24 * 5 * 7 * 9) / ? = 216

Correct? = (24 * 5 * 7 * 9) / 216 = 35

Incorrect? = (24 * 5 * 7 * 9) / 216 = 35

- Question 9 of 50
##### 9. Question

A goods train runs at the speed of 72 km/hr and crosses a 250 m long platform in 26 sec. What is the length of the goods train?

CorrectSpeed = 72 * 5/18 = 20 m/sec.

Time = 26 sec.

Let the length of the train be x meters.

Then, (x + 250)/26 = 20

x = 270 m.IncorrectSpeed = 72 * 5/18 = 20 m/sec.

Time = 26 sec.

Let the length of the train be x meters.

Then, (x + 250)/26 = 20

x = 270 m. - Question 10 of 50
##### 10. Question

The average height of 35 boys in a class was calculated as 180cm. It has later found that the height of one of the boys in the class was wrongly written as 166 cm whereas his actual height was 106 cm. Find the actual average height of the boys in the class (Round off your answer to two decimal places).

CorrectCalculated average height of 35 boys = 180 cm.

Wrong total height of 35 boys = 180 * 35 cm. This was as a result of an actual height of 106 cm being wrongly written as 166 cm. Correct total height of 35 boys = 180 * 35 cm – 166 cm + 106 cm

= 180 * 35 cm – 166 cm + 106 cm/35 = 180 cm – 60 /35 cm

= 180 cm – 1.71 cm = 178.29 cm.IncorrectCalculated average height of 35 boys = 180 cm.

Wrong total height of 35 boys = 180 * 35 cm. This was as a result of an actual height of 106 cm being wrongly written as 166 cm. Correct total height of 35 boys = 180 * 35 cm – 166 cm + 106 cm

= 180 * 35 cm – 166 cm + 106 cm/35 = 180 cm – 60 /35 cm

= 180 cm – 1.71 cm = 178.29 cm. - Question 11 of 50
##### 11. Question

In a colony of 70 residents, the ratio of the number of men and women is 4:3. Among the women, the ratio of the educated to the uneducated is 1:4. If the ratio of the number of education to uneducated persons is 8:27, then find the ratio of the number of educated and uneducated men in the colony?

CorrectNumber of men in the colony = 4/7 (70) = 40

Number of women in the colony = 3/7 (70) = 30

Number of educated women in the colony = 1/5 (30) = 6

Number of uneducated women in the colony = 4/5 (30) = 24

Number of educated persons in the colony = 8/35 (70) = 16

As 6 females are educated, remaining 10 educated persons must be men.

Number of uneducated men in the colony = 40 – 10 = 30

Number of educated men and uneducated men are in the ratio 10:30 => 1:3IncorrectNumber of men in the colony = 4/7 (70) = 40

Number of women in the colony = 3/7 (70) = 30

Number of educated women in the colony = 1/5 (30) = 6

Number of uneducated women in the colony = 4/5 (30) = 24

Number of educated persons in the colony = 8/35 (70) = 16

As 6 females are educated, remaining 10 educated persons must be men.

Number of uneducated men in the colony = 40 – 10 = 30

Number of educated men and uneducated men are in the ratio 10:30 => 1:3 - Question 12 of 50
##### 12. Question

64309 – 8703 + 798 – 437 = ?

Correct64309 – 8703 + 798 – 437 => 65107 – 9140 = 55967

Incorrect64309 – 8703 + 798 – 437 => 65107 – 9140 = 55967

- Question 13 of 50
##### 13. Question

When the numerator of a fraction is decreased by 25% and its denominator is decreased by 20%, the new fraction obtained is 3/4. Find the original fraction?

CorrectLet the fraction be x/y.

When the numerator decreased by 25% and the denominator decreased by 20%.

(x * 3/4)/(y * 4/5) = 3/4 => x/y = 3/4 * (4/5)/(3/4) = 4/5IncorrectLet the fraction be x/y.

When the numerator decreased by 25% and the denominator decreased by 20%.

(x * 3/4)/(y * 4/5) = 3/4 => x/y = 3/4 * (4/5)/(3/4) = 4/5 - Question 14 of 50
##### 14. Question

Find the one which does not belong to that group ?

CorrectStar, Moon, Comet and Planet are natural celestial bodies, while Rocket is man made.

IncorrectStar, Moon, Comet and Planet are natural celestial bodies, while Rocket is man made.

- Question 15 of 50
##### 15. Question

(22 * 495 + 891 * 44) / (33 * 176 + 55 * 264) = ?

Correct(22 * 495 + 891 * 44) / (33 * 176 + 55 * 264) = (22 * 33 * 15 + 9 * 99 * 2 * 22) / (33 * 22 * 8 + 5 * 11 * 22 * 12)

= (22 * 33 * 15 + 22 * 33 * 54) / (33 * 22 * 8 + 33 * 22 * 20) = [22 * 33(15 + 54)] / [33 * 22(8 + 20)] = 69/28Incorrect(22 * 495 + 891 * 44) / (33 * 176 + 55 * 264) = (22 * 33 * 15 + 9 * 99 * 2 * 22) / (33 * 22 * 8 + 5 * 11 * 22 * 12)

= (22 * 33 * 15 + 22 * 33 * 54) / (33 * 22 * 8 + 33 * 22 * 20) = [22 * 33(15 + 54)] / [33 * 22(8 + 20)] = 69/28 - Question 16 of 50
##### 16. Question

A train passes a man standing on the platform. If the train is 170 meters long and its speed is 72 kmph, how much time it took in doing so?

CorrectD = 170

S = 72 * 5/18 = 20 mps

T = 170/20 = 8 ½ secIncorrectD = 170

S = 72 * 5/18 = 20 mps

T = 170/20 = 8 ½ sec - Question 17 of 50
##### 17. Question

On dividing a number by 68, we get 269 as quotient and 0 as remainder. On dividing the same number by 67, what will be the remainder?

CorrectNumber = 269 * 68 + 0 = 18292

67) 18292 (273

18291

——–

1

Required number = 1.IncorrectNumber = 269 * 68 + 0 = 18292

67) 18292 (273

18291

——–

1

Required number = 1. - Question 18 of 50
##### 18. Question

The least number of four digits which is divisible by 15, 25, 40 and 75 is:

CorrectGreatest number of 4 digits is 9999. L.C.M of 15, 25, 40 and 75 is 600.

On dividing 9999 by 600, the remainder is 399. Required number = 9999 – 399 = 9600IncorrectGreatest number of 4 digits is 9999. L.C.M of 15, 25, 40 and 75 is 600.

On dividing 9999 by 600, the remainder is 399. Required number = 9999 – 399 = 9600 - Question 19 of 50
##### 19. Question

A man swims downstream 30 km and upstream 18 km taking 3 hours each time, what is the speed of the man in still water?

Correct30 — 3 DS = 10

? —- 1

18 —- 3 US = 6

? —- 1 M = ?

M = (10 + 6)/2 = 8Incorrect30 — 3 DS = 10

? —- 1

18 —- 3 US = 6

? —- 1 M = ?

M = (10 + 6)/2 = 8 - Question 20 of 50
##### 20. Question

Express 25 mps in kmph?

Correct25 * 18/5 = 90 kmph

Incorrect25 * 18/5 = 90 kmph

- Question 21 of 50
##### 21. Question

A can do a piece of work in 4 hours; B and C together can do it in 3 hours, which A and C together can do it in 2 hours. How long will B alone take to do it?

CorrectA’s 1 hour work = 1/4;

(B + C)’s 1 hour work = 1/3;

(A + C)’s 1 hour work = 1/2

(A + B + C)’s 1 hour work = (1/4 + 1/3) = 7/12

B’s 1 hour work = (7/12 + 1/2) = 1/12

B alone will take 12 hours to do the work.IncorrectA’s 1 hour work = 1/4;

(B + C)’s 1 hour work = 1/3;

(A + C)’s 1 hour work = 1/2

(A + B + C)’s 1 hour work = (1/4 + 1/3) = 7/12

B’s 1 hour work = (7/12 + 1/2) = 1/12

B alone will take 12 hours to do the work. - Question 22 of 50
##### 22. Question

Rs.4500 amounts to Rs.5544 in two years at compound interest, compounded annually. If the rate of the interest for the first year is 12%, find the rate of interest for the second year?

CorrectLet the rate of interest during the second year be R%. Given,

4500 * {(100 + 12)/100} * {(100 + R)/100} = 5544

R = 10%IncorrectLet the rate of interest during the second year be R%. Given,

4500 * {(100 + 12)/100} * {(100 + R)/100} = 5544

R = 10% - Question 23 of 50
##### 23. Question

A question paper consists of five problems, each problem having three internal choices. In how many ways can a candidate attempt one or more problems?

CorrectGiven that, the question paper consists of five problems. For each problem, one or two or three or none of the choices can be attempted.

Hence, the required number of ways = 4^{5}– 1.

= 2^{10}– 1 = 1024 – 1 = 1023IncorrectGiven that, the question paper consists of five problems. For each problem, one or two or three or none of the choices can be attempted.

Hence, the required number of ways = 4^{5}– 1.

= 2^{10}– 1 = 1024 – 1 = 1023 - Question 24 of 50
##### 24. Question

If a : b = 4 : 1, then find (a – 3b)/(2a – b).

Correcta : b = 4 : 1

a/b = 4/1 => a = 4b

(a – 3b)/(2a – b) = (4b – 3b)/[2(4b) – b]

= b/(8b – b) = b/7b => 1/7Incorrecta : b = 4 : 1

a/b = 4/1 => a = 4b

(a – 3b)/(2a – b) = (4b – 3b)/[2(4b) – b]

= b/(8b – b) = b/7b => 1/7 - Question 25 of 50
##### 25. Question

A box contains nine bulbs out of which 4 are defective. If four bulbs are chosen at random, find the probability that all the four bulbs are defective.

CorrectOut of nine, five are good and four are defective. Required probability = ⁴C₄/⁹C₄ = 1/126

IncorrectOut of nine, five are good and four are defective. Required probability = ⁴C₄/⁹C₄ = 1/126

- Question 26 of 50
##### 26. Question

The average of 35 students in a class is 16 years. The average age of 21 students is 14. What is the average age of remaining 14 students?

CorrectSum of the ages of 14 students

= (16 * 35) – (14 * 21) = 560 – 294 = 266

Required average = (266/14) = 19 years.IncorrectSum of the ages of 14 students

= (16 * 35) – (14 * 21) = 560 – 294 = 266

Required average = (266/14) = 19 years. - Question 27 of 50
##### 27. Question

The salary of a worker is first increased by 30% and afterwards reduced by 30%. What is net change in his salary?

Correct(30 * 30)/100 = 9% decrease

Incorrect(30 * 30)/100 = 9% decrease

- Question 28 of 50
##### 28. Question

A man can row a boat at 20 kmph in still water. If the speed of the stream is 6 kmph, what is the time taken to row a distance of 60 km downstream?

CorrectSpeed downstream = 20 + 6 = 26 kmph.

Time required to cover 60 km downstream = d/s = 60/26 = 30/13 hours.IncorrectSpeed downstream = 20 + 6 = 26 kmph.

Time required to cover 60 km downstream = d/s = 60/26 = 30/13 hours. - Question 29 of 50
##### 29. Question

A is twice as good a workman as B and they took 7 days together to do the work B alone can do it in.

CorrectWC = 2:1

2x + x = 1/7

x = 1/21 => 21 daysIncorrectWC = 2:1

2x + x = 1/7

x = 1/21 => 21 days - Question 30 of 50
##### 30. Question

After decreasing 24% in the price of an article costs Rs.912. Find the actual cost of an article?

CorrectCP* (76/100) = 912

CP= 12 * 100 => CP = 1200IncorrectCP* (76/100) = 912

CP= 12 * 100 => CP = 1200 - Question 31 of 50
##### 31. Question

The smallest ratio out of 1:1, 2:1, 1:3 and 3:1 is?

CorrectIncorrect - Question 32 of 50
##### 32. Question

Sachin is younger than Rahul by 4 years. If their ages are in the respective ratio of 7:9, how old is Sachin?

CorrectLet Rahul’s age be x years.

Then, Sachin’s age = (x – 7) years.

(x – 7)/x = 7/9

2x = 63 => x = 31.5

Hence, Sachin’s age = (x – 7) = 24.5 years.IncorrectLet Rahul’s age be x years.

Then, Sachin’s age = (x – 7) years.

(x – 7)/x = 7/9

2x = 63 => x = 31.5

Hence, Sachin’s age = (x – 7) = 24.5 years. - Question 33 of 50
##### 33. Question

A is faster than B. A and B each walk 24 km. The sum of their speeds is 7 km/hr and the sum of times taken by them is 14 hours. Then, A’s speed is equal to?

CorrectLet A’s speed = x km/hr. Then, B’s speed = (7 – x) km/ hr.

So, 24/x + 24/(7 – x) = 14

x^{2}– 98x + 168 = 0

(x – 3)(x – 4) = 0 => x = 3 or 4.

Since, A is faster than B, so A’s speed = 4 km/hr and B’s speed = 3 km/hr.IncorrectLet A’s speed = x km/hr. Then, B’s speed = (7 – x) km/ hr.

So, 24/x + 24/(7 – x) = 14

x^{2}– 98x + 168 = 0

(x – 3)(x – 4) = 0 => x = 3 or 4.

Since, A is faster than B, so A’s speed = 4 km/hr and B’s speed = 3 km/hr. - Question 34 of 50
##### 34. Question

A train 800 m long is running at a speed of 78 km/hr. If it crosses a tunnel in 1 min, then the length of the tunnel is?

CorrectSpeed = 78 * 5/18 = 65/3 m/sec.

Time = 1 min = 60 sec.

Let the length of the train be x meters.

Then, (800 + x)/60 = 65/3

x = 500 m.IncorrectSpeed = 78 * 5/18 = 65/3 m/sec.

Time = 1 min = 60 sec.

Let the length of the train be x meters.

Then, (800 + x)/60 = 65/3

x = 500 m. - Question 35 of 50
##### 35. Question

A man can do a job in 15 days. His father takes 20 days and his son finishes it in 25 days. How long will they take to complete the job if they all work together?

Correct1 day work of the three persons = (1/15 + 1/20 + 1/25) = 47/300

So, all three together will complete the work in 300/47 = 6.4 days.-Incorrect1 day work of the three persons = (1/15 + 1/20 + 1/25) = 47/300

So, all three together will complete the work in 300/47 = 6.4 days.- - Question 36 of 50
##### 36. Question

A person purchases 90 clocks and sells 40 clocks at a gain of 10% and 50 clocks at a gain of 20%. If he sold all of them at a uniform profit of 15%, then he would have got Rs. 40 less. The cost price of each clock is:

CorrectLet C.P. of clock be Rs. x.

Then, C.P. of 90 clocks = Rs. 90x.

[(110% of 40x) + (120% of 50x)] – (115% of 90x) = 40

44x + 60x – 103.5x = 40

0.5x = 40 => x = 80IncorrectLet C.P. of clock be Rs. x.

Then, C.P. of 90 clocks = Rs. 90x.

[(110% of 40x) + (120% of 50x)] – (115% of 90x) = 40

44x + 60x – 103.5x = 40

0.5x = 40 => x = 80 - Question 37 of 50
##### 37. Question

Income and expenditure of a person are in the ratio 5 : 4. If the income of the person is Rs. 18000, then find his savings.

CorrectLet the income and the expenditure of the person be Rs. 5x and Rs. 4x respectively.

Income, 5x = 18000 => x = 3600

Savings = Income – expenditure = 5x – 4x = x

So, savings = Rs. 3600.IncorrectLet the income and the expenditure of the person be Rs. 5x and Rs. 4x respectively.

Income, 5x = 18000 => x = 3600

Savings = Income – expenditure = 5x – 4x = x

So, savings = Rs. 3600. - Question 38 of 50
##### 38. Question

What is the unit digit in 7

^{105}?CorrectUnit digit in 7

^{105}= unit digit in [(7^{4})^{26}* 7]

But, unit digit in (7^{4})^{26}= 1

unit digit in 7^{105}= (1 * 7) = 7IncorrectUnit digit in 7

^{105}= unit digit in [(7^{4})^{26}* 7]

But, unit digit in (7^{4})^{26}= 1

unit digit in 7^{105}= (1 * 7) = 7 - Question 39 of 50
##### 39. Question

What percent of 125 is 16?

CorrectLet the required percentage be x%.

x% of 125 = 16 => x/100 * 125 = 16

=> x = 1600/125 = 64/5 = 12 4/5IncorrectLet the required percentage be x%.

x% of 125 = 16 => x/100 * 125 = 16

=> x = 1600/125 = 64/5 = 12 4/5 - Question 40 of 50
##### 40. Question

Rs. 6000 is lent out in two parts. One part is lent at 7% p.a simple interest and the other is lent at 10% p.a simple interest. The total interest at the end of one year was Rs. 450. Find the ratio of the amounts lent at the lower rate and higher rate of interest?

CorrectLet the amount lent at 7% be Rs. x

Amount lent at 10% is Rs. (6000 – x)

Total interest for one year on the two sums lent

= 7/100 x + 10/100 (6000 – x) = 600 – 3x/100

=> 600 – 3/100 x = 450 => x = 5000

Amount lent at 10% = 1000

Required ratio = 5000 : 1000 = 5 : 1IncorrectLet the amount lent at 7% be Rs. x

Amount lent at 10% is Rs. (6000 – x)

Total interest for one year on the two sums lent

= 7/100 x + 10/100 (6000 – x) = 600 – 3x/100

=> 600 – 3/100 x = 450 => x = 5000

Amount lent at 10% = 1000

Required ratio = 5000 : 1000 = 5 : 1 - Question 41 of 50
##### 41. Question

√3584 * 52.034 = ?

Correct√3600 * 52 = ?

=> ? = 60 * 52 = 3120Incorrect√3600 * 52 = ?

=> ? = 60 * 52 = 3120 - Question 42 of 50
##### 42. Question

Sum of two consecutive even terms lacks by 98 from their product. Find the sum of these numbers?

Correctx(x + 2) – (x + x + 2) = 98

Incorrectx(x + 2) – (x + x + 2) = 98

- Question 43 of 50
##### 43. Question

The length of the bridge, which a train 130 metres long and travelling at 45 km/hr can cross in 30 seconds, is:

CorrectSpeed = [45 X 5/18] m/sec = [25/2] m/sec Time = 30 sec Let the length of bridge be x metres. Then, (130 + x)/30 = 25/2 => 2(130 + x) = 750 => x = 245 m.

IncorrectSpeed = [45 X 5/18] m/sec = [25/2] m/sec Time = 30 sec Let the length of bridge be x metres. Then, (130 + x)/30 = 25/2 => 2(130 + x) = 750 => x = 245 m.

- Question 44 of 50
##### 44. Question

Find the one which does not belong to that group ?

Correct20 = 4

^{2}+ 4, 42 = 6^{2}+ 6, 58 = 7^{2}+ 9, 72 = 8^{2}+ 8 and 90 = 9^{2}+ 9.

20, 42, 72 and 90 can be expressed in n^{2}+ n form but not 58.Incorrect20 = 4

^{2}+ 4, 42 = 6^{2}+ 6, 58 = 7^{2}+ 9, 72 = 8^{2}+ 8 and 90 = 9^{2}+ 9.

20, 42, 72 and 90 can be expressed in n^{2}+ n form but not 58. - Question 45 of 50
##### 45. Question

21345 * 45 = 4270 * ?

Correct? = (21345 * 45) / 4270

? = 225Incorrect? = (21345 * 45) / 4270

? = 225 - Question 46 of 50
##### 46. Question

The sum of three numbers is 98. If the ratio of the first to the second is 2:3. And that of the second to the third is 5:8, then the second number is:

CorrectLet the three parts A, B, C.

Then, A:B = 2:3 and B:C = 5:8

= (5 * 3/5) : (8 * 3/5) = 3:24/5

A:B:C = 2:3:24/5

= 10:15:24 => B = 98 * 15/49 = 30.IncorrectLet the three parts A, B, C.

Then, A:B = 2:3 and B:C = 5:8

= (5 * 3/5) : (8 * 3/5) = 3:24/5

A:B:C = 2:3:24/5

= 10:15:24 => B = 98 * 15/49 = 30. - Question 47 of 50
##### 47. Question

Rahim bought 65 books for Rs.1150 from one shop and 50 books for Rs.920 from another. What is the average price he paid per book ?

CorrectAverage price per book = (1150 + 920) / (65 + 50) = 2070 / 115 = Rs.18

IncorrectAverage price per book = (1150 + 920) / (65 + 50) = 2070 / 115 = Rs.18

- Question 48 of 50
##### 48. Question

The radius of a cylindrical vessel is 7cm and height is 3cm. Find the whole surface of the cylinder?

Correctr = 7 h = 3

2πr(h + r) = 2 * 22/7 * 7(10) = 440Incorrectr = 7 h = 3

2πr(h + r) = 2 * 22/7 * 7(10) = 440 - Question 49 of 50
##### 49. Question

7 2/5 of 110 / ? = 844

Correct? = 844 – 7 2/5 of 110 = 844 – 37 * 22 = 30

Incorrect? = 844 – 7 2/5 of 110 = 844 – 37 * 22 = 30

- Question 50 of 50
##### 50. Question

A can do a piece of work in 12 days. When he had worked for 2 days B joins him. If the complete work was finished in 8 days. In how many days B alone can finish the work?

Correct8/12 + 6/x = 1

X = 18 daysIncorrect8/12 + 6/x = 1

X = 18 days