Aptitude Profit and Loss Online Test, Free Aptitude Quiz
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Aptitude Profit and Loss Online Test, Free Aptitude Quiz, Online Aptitude Profit and Loss Test. Aptitude Profit and Loss Question and Answers 2019. Aptitude Profit and Loss Quiz. Aptitude Profit and Loss Free Mock Test 2019. Aptitude Profit and Loss Question and Answers in PDF. The Aptitude Profit and Loss online mock test paper is free for all students.The below Aptitude questions and answers can improve your skills in order to face the Interview, Competitive examination, Govt Exams and various entrance test with full confidence. Aptitude online test is very useful for exam preparation and getting for Rank. Aptitude Profit and Loss Question and Answers in Hindi and English. Aptitude Profit and Loss Mock test for topic via Online Mode. Here we are providing Aptitude Profit and Loss Mock Test in Hindi. Now Test your self for “Aptitude Profit and Loss Online Test in Hindi” Exam by using below quiz…
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Question 1 of 20
1. Question
Alfred buys an old scooter for Rs. 4700 and spends Rs. 800 on its repairs. If he sells the scooter for Rs. 5800, his gain percent is:
Correct
Cost Price (C.P.) = Rs. (4700 + 800) = Rs. 5500.
Selling Price (S.P.) = Rs. 5800.
Gain = (S.P.) – (C.P.) = Rs.(5800 – 5500) = Rs. 300.
Gain % = (300/5500 x 100)% =
Incorrect
Cost Price (C.P.) = Rs. (4700 + 800) = Rs. 5500.
Selling Price (S.P.) = Rs. 5800.
Gain = (S.P.) – (C.P.) = Rs.(5800 – 5500) = Rs. 300.
Gain % = (300/5500 x 100)% = -
Question 2 of 20
2. Question
The cost price of 20 articles is the same as the selling price of x articles. If the profit is 25%, then the value of x is:
Correct
Let C.P. of each article be Re. 1 C.P. of x articles = Rs. x.
S.P. of x articles = Rs. 20.
Profit = Rs. (20 – x).
∴ 20-x/x × 100 = 25
⇒ 2000 – 100x = 25x
125x = 2000
⇒ x = 16.Incorrect
Let C.P. of each article be Re. 1 C.P. of x articles = Rs. x.
S.P. of x articles = Rs. 20.
Profit = Rs. (20 – x).
∴ 20-x/x × 100 = 25
⇒ 2000 – 100x = 25x
125x = 2000
⇒ x = 16. -
Question 3 of 20
3. Question
If selling price is doubled, the profit triples. Find the profit percent.
Correct
Let C.P. be Rs. x and S.P. be Rs. y.
Then, 3(y – x) = (2y – x) y = 2x.
Profit = Rs. (y – x) = Rs. (2x – x) = Rs. x.
∴ Profit % = (x/x × 100) % = 100%Incorrect
Let C.P. be Rs. x and S.P. be Rs. y.
Then, 3(y – x) = (2y – x) y = 2x.
Profit = Rs. (y – x) = Rs. (2x – x) = Rs. x.
∴ Profit % = (x/x × 100) % = 100% -
Question 4 of 20
4. Question
In a certain store, the profit is 320% of the cost. If the cost increases by 25% but the selling price remains constant, approximately what percentage of the selling price is the profit?
Correct
Let C.P.= Rs. 100. Then, Profit = Rs. 320, S.P. = Rs. 420.
New C.P. = 125% of Rs. 100 = Rs. 125
New S.P. = Rs. 420.
Profit = Rs. (420 – 125) = Rs. 295.
∴ Required percentage = (295/420 × 100) % = 1475/21 % = 70% (approximately).Incorrect
Let C.P.= Rs. 100. Then, Profit = Rs. 320, S.P. = Rs. 420.
New C.P. = 125% of Rs. 100 = Rs. 125
New S.P. = Rs. 420.
Profit = Rs. (420 – 125) = Rs. 295.
∴ Required percentage = (295/420 × 100) % = 1475/21 % = 70% (approximately). -
Question 5 of 20
5. Question
A vendor bought toffees at 6 for a rupee. How many for a rupee must he sell to gain 20%?
Correct
C.P. of 6 toffees = Re. 1
S.P. of 6 toffees = 120% of Re. 1 = Rs. 6/5
For Rs. 6/5 , toffees sold = 6.
For Re. 1, toffees sold = (6 × 5/6) = 5.Incorrect
C.P. of 6 toffees = Re. 1
S.P. of 6 toffees = 120% of Re. 1 = Rs. 6/5
For Rs. 6/5 , toffees sold = 6.
For Re. 1, toffees sold = (6 × 5/6) = 5. -
Question 6 of 20
6. Question
The percentage profit earned by selling an article for Rs. 1920 is equal to the percentage loss incurred by selling the same article for Rs. 1280. At what price should the article be sold to make 25% profit?
Correct
Let C.P. be Rs. x.
Then, 1920-x/x × 100 = x-1280/x × 100
⇒ 1920 – x = x – 1280
⇒ 2x = 3200
⇒ x = 1600
∴ Required S.P. = 125% of Rs. 1600 = Rs. (125/100 × 1600) = Rs 2000.Incorrect
Let C.P. be Rs. x.
Then, 1920-x/x × 100 = x-1280/x × 100
⇒ 1920 – x = x – 1280
⇒ 2x = 3200
⇒ x = 1600
∴ Required S.P. = 125% of Rs. 1600 = Rs. (125/100 × 1600) = Rs 2000. -
Question 7 of 20
7. Question
A shopkeeper expects a gain of 22.5% on his cost price. If in a week, his sale was of Rs. 392, what was his profit?
Correct
C.P. = Rs. (100/122.5 × 392) = Rs. (1000/1225 × 392) = Rs. 320
Profit = Rs. (392 – 320) = Rs. 72.Incorrect
C.P. = Rs. (100/122.5 × 392) = Rs. (1000/1225 × 392) = Rs. 320
Profit = Rs. (392 – 320) = Rs. 72. -
Question 8 of 20
8. Question
A man buys a cycle for Rs. 1400 and sells it at a loss of 15%. What is the selling price of the cycle?
Correct
S.P. = 85% of Rs. 1400 = Rs. (85/100 x 1400) = Rs. 1190
Incorrect
S.P. = 85% of Rs. 1400 = Rs. (85/100 x 1400) = Rs. 1190
-
Question 9 of 20
9. Question
Sam purchased 20 dozens of toys at the rate of Rs. 375 per dozen. He sold each one of them at the rate of Rs. 33. What was his percentage profit?
Correct
Cost Price of 1 toy = Rs. (375/12) = Rs. 31.25
Selling Price of 1 toy = Rs. 33
So, Gain = Rs. (33 – 31.25) = Rs. 1.75
Profit % = (1.75/31.25 × 100) % = 28/5 % = 5.6%Incorrect
Cost Price of 1 toy = Rs. (375/12) = Rs. 31.25
Selling Price of 1 toy = Rs. 33
So, Gain = Rs. (33 – 31.25) = Rs. 1.75
Profit % = (1.75/31.25 × 100) % = 28/5 % = 5.6% -
Question 10 of 20
10. Question
Some articles were bought at 6 articles for Rs. 5 and sold at 5 articles for Rs. 6. Gain percent is:
Correct
Suppose, number of articles bought = L.C.M. of 6 and 5 = 30.
C.P. of 30 articles = Rs. (5/6 x 30) = Rs. 25.
S.P. of 30 articles = Rs. (6/5 x 30) = Rs. 36.
∴ Gain % = (11/25 x 100) % = 44%.Incorrect
Suppose, number of articles bought = L.C.M. of 6 and 5 = 30.
C.P. of 30 articles = Rs. (5/6 x 30) = Rs. 25.
S.P. of 30 articles = Rs. (6/5 x 30) = Rs. 36.
∴ Gain % = (11/25 x 100) % = 44%. -
Question 11 of 20
11. Question
On selling 17 balls at Rs. 720, there is a loss equal to the cost price of 5 balls. The cost price of a ball is:
Correct
(C.P. of 17 balls) – (S.P. of 17 balls) = (C.P. of 5 balls)
⇒ C.P. of 12 balls = S.P. of 17 balls = Rs.720.
⇒ C.P. of 1 ball = Rs. (720/12) = Rs. 60.Incorrect
(C.P. of 17 balls) – (S.P. of 17 balls) = (C.P. of 5 balls)
⇒ C.P. of 12 balls = S.P. of 17 balls = Rs.720.
⇒ C.P. of 1 ball = Rs. (720/12) = Rs. 60. -
Question 12 of 20
12. Question
When a plot is sold for Rs. 18,700, the owner loses 15%. At what price must that plot be sold in order to gain 15%?
Correct
85 : 18700 = 115 : x
x = (18700×115 / 85) = 25300.
Hence, S.P. = Rs. 25,300.Incorrect
85 : 18700 = 115 : x
x = (18700×115 / 85) = 25300.
Hence, S.P. = Rs. 25,300. -
Question 13 of 20
13. Question
100 oranges are bought at the rate of Rs. 350 and sold at the rate of Rs. 48 per dozen. The percentage of profit or loss is:
Correct
Incorrect
-
Question 14 of 20
14. Question
A shopkeeper sells one transistor for Rs. 840 at a gain of 20% and another for Rs. 960 at a loss of 4%. His total gain or loss percent is:
Correct
Incorrect
-
Question 15 of 20
15. Question
A trader mixes 26 kg of rice at Rs. 20 per kg with 30 kg of rice of other variety at Rs. 36 per kg and sells the mixture at Rs. 30 per kg. His profit percent is:
Correct
C.P. of 56 kg rice = Rs. (26 x 20 + 30 x 36) = Rs. (520 + 1080) = Rs. 1600.
S.P. of 56 kg rice = Rs. (56 x 30) = Rs. 1680.
∴ Gain = (80/1600 × 100) % = 5%.Incorrect
C.P. of 56 kg rice = Rs. (26 x 20 + 30 x 36) = Rs. (520 + 1080) = Rs. 1600.
S.P. of 56 kg rice = Rs. (56 x 30) = Rs. 1680.
∴ Gain = (80/1600 × 100) % = 5%. -
Question 16 of 20
16. Question
A shopkeeper sells some articles at the profit of 25% on the original price. What is the exact amount of profit? To find the answer, which of the following information given in Statements I and II is/are necessary?
I. Sale price of the article
II. Number of articles soldCorrect
Gain = 25% of C.P.
In order to find gain, we must know the sale price of each article and the number of articles sold.
∴ Correct answer is (D).Incorrect
Gain = 25% of C.P.
In order to find gain, we must know the sale price of each article and the number of articles sold.
∴ Correct answer is (D). -
Question 17 of 20
17. Question
A shopkeeper sells some toys at Rs. 250 each. What percent profit does he make? To find the answer, which of the following information given in Statements I and II is/are necessary?
I. Number of toys sold.
II. Cost price of each toy.Correct
S.P. = Rs. 250 each.
To find gain percent, we must know the C.P. of each.
∴ Correct answer is (B).Incorrect
S.P. = Rs. 250 each.
To find gain percent, we must know the C.P. of each.
∴ Correct answer is (B). -
Question 18 of 20
18. Question
Each of the questions given below consists of a question followed by three statements. You have to study the question and the statements and decide which of the statement(s) is/are necessary to answer the question.
By selling an article what is the profit percent gained?
I. 5% discount is given on list price.
II. If discount is not given, 20% profit is gained.
III. The cost price of the articles is Rs. 5000.Correct
I. Let the list price be Rs. x.
Then, S.P. = 95% of Rs. x = Rs. (x × 95/100) = Rs. (19x/20)
II. When S.P. = Rs. x and gain = 20%.
Then, C.P. = Rs. (100/120 × x) = Rs. 5x/6
∴ Gain = (19x/20 – 5x/6) = (57x-50x/60) = 7x/60
∴ Gain % = (7x/60 × 6/5x × 100) % = 14%.
Thus, I and II only give the answer.
∴ Correct answer is (A).Incorrect
I. Let the list price be Rs. x.
Then, S.P. = 95% of Rs. x = Rs. (x × 95/100) = Rs. (19x/20)
II. When S.P. = Rs. x and gain = 20%.
Then, C.P. = Rs. (100/120 × x) = Rs. 5x/6
∴ Gain = (19x/20 – 5x/6) = (57x-50x/60) = 7x/60
∴ Gain % = (7x/60 × 6/5x × 100) % = 14%.
Thus, I and II only give the answer.
∴ Correct answer is (A). -
Question 19 of 20
19. Question
Each of the questions given below consists of a question followed by three statements. You have to study the question and the statements and decide which of the statement(s) is/are necessary to answer the question.
What was the percentage of discount given?
I. 23.5% profit was earned by selling an almirah for Rs. 12,350.
II. If there were no discount, the earned profit would have been 30%.
III. The cost price of the almirah was Rs. 10,000.Correct
I. S.P. = Rs. 12350, Gain = 23.5%
∴ C.P. = Rs. (100/123.5 x 12350) = Rs. 10,000.
II. M.P. = 130% of C.P. = 130% of Rs. 10,000 = Rs. 13,000.
From I and II, discount = Rs. (13000 – 12350) = Rs. 650.
Discount % = (650/13000 x 100) % = 5%.
Thus, I and II give the answer.
II and III can not give the answer. Because we require profit percentage with discount and profit percentage without discount. So II and III are not sufficient.
Since III gives C.P. = Rs. 10,000, I and III give the answer.
Therefore, I and II [or] I and III give the answer.
∴ Correct answer is (E).Incorrect
I. S.P. = Rs. 12350, Gain = 23.5%
∴ C.P. = Rs. (100/123.5 x 12350) = Rs. 10,000.
II. M.P. = 130% of C.P. = 130% of Rs. 10,000 = Rs. 13,000.
From I and II, discount = Rs. (13000 – 12350) = Rs. 650.
Discount % = (650/13000 x 100) % = 5%.
Thus, I and II give the answer.
II and III can not give the answer. Because we require profit percentage with discount and profit percentage without discount. So II and III are not sufficient.
Since III gives C.P. = Rs. 10,000, I and III give the answer.
Therefore, I and II [or] I and III give the answer.
∴ Correct answer is (E). -
Question 20 of 20
20. Question
Each of these questions is followed by three statements. You have to study the question and all the three statements given to decide whether any information provided in the statement(s) is redundant and can be dispensed with while answering the given question.
What is the percent profit earned by the shopkeeper on selling the articles in his shop?
I. Labeled price of the articles sold was 130% of the cost price.
II. Cost price of each article was Rs. 550.
III. A discount of 10% on labeled price was offered.Correct
I. Let C.P. be Rs. x.
Then, M.P. = 130% of x = Rs. (13x/10) .
III. S.P. = 90% of M.P.
Thus, I and III give, S.P. = Rs. (90/100 x 13x/10) = Rs. (117x/100)
Gain = Rs. (117x/100 – x) = Rs. (17x/100)
Thus, from I and III, gain % can be obtained.
Clearly, II is redundant.Incorrect
I. Let C.P. be Rs. x.
Then, M.P. = 130% of x = Rs. (13x/10) .
III. S.P. = 90% of M.P.
Thus, I and III give, S.P. = Rs. (90/100 x 13x/10) = Rs. (117x/100)
Gain = Rs. (117x/100 – x) = Rs. (17x/100)
Thus, from I and III, gain % can be obtained.
Clearly, II is redundant.
