Aptitude Time and Distance Online Test, Free Aptitude Quiz
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Aptitude Time and Distance Online Test, Free Aptitude Quiz, Online Aptitude Time and Distance Test. Aptitude Time and Distance Question and Answers 2019. Aptitude Time and Distance Quiz. Aptitude Time and Distance Free Mock Test 2019. Aptitude Time and Distance Question and Answers in PDF. The Aptitude Time and Distance online mock test paper is free for all students.The below Aptitude questions and answers can improve your skills in order to face the Interview, Competitive examination, Govt Exams and various entrance test with full confidence. Aptitude online test is very useful for exam preparation and getting for Rank. Aptitude Time and Distance Question and Answers in Hindi and English. Aptitude Time and Distance Mock test for topic via Online Mode. Here we are providing Aptitude Time and Distance Mock Test in Hindi. Now Test your self for “Aptitude Time and Distance Online Test in Hindi” Exam by using below quiz…
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Question 1 of 15
1. Question
A person crosses a 600 m long street in 5 minutes. What is his speed in km per hour?
Correct
Incorrect
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Question 2 of 15
2. Question
An aeroplane covers a certain distance at a speed of 240 kmph in 5 hours. To cover the same distance in 1 2/3, it must travel at a speed of:
Correct
Distance = (240 x 5) = 1200 km.
Speed = Distance/Time
Speed = 1200/(5/3) km/hr. [We can write 1 2/3 hours as 5/3 hours]
Incorrect
Distance = (240 x 5) = 1200 km.
Speed = Distance/Time
Speed = 1200/(5/3) km/hr. [We can write 1 2/3 hours as 5/3 hours]
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Question 3 of 15
3. Question
If a person walks at 14 km/hr instead of 10 km/hr, he would have walked 20 km more. The actual distance travelled by him is:
Correct
Let the actual distance travelled be x km.
Then, X/10 = X+20/14
⇒ 14x = 10x + 200
⇒ 4x = 200
⇒ x = 50 km.Incorrect
Let the actual distance travelled be x km.
Then, X/10 = X+20/14
⇒ 14x = 10x + 200
⇒ 4x = 200
⇒ x = 50 km. -
Question 4 of 15
4. Question
A train can travel 50% faster than a car. Both start from point A at the same time and reach point B 75 kms away from A at the same time. On the way, however, the train lost about 12.5 minutes while stopping at the stations. The speed of the car is:
Correct
Incorrect
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Question 5 of 15
5. Question
Excluding stoppages, the speed of a bus is 54 kmph and including stoppages, it is 45 kmph. For how many minutes does the bus stop per hour?
Correct
Due to stoppages, it covers 9 km less.
Time taken to cover 9 km = (9/54 × 60) min = 10 min.Incorrect
Due to stoppages, it covers 9 km less.
Time taken to cover 9 km = (9/54 × 60) min = 10 min. -
Question 6 of 15
6. Question
In a flight of 600 km, an aircraft was slowed down due to bad weather. Its average speed for the trip was reduced by 200 km/hr and the time of flight increased by 30 minutes. The duration of the flight is:
Correct
Incorrect
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Question 7 of 15
7. Question
A man complete a journey in 10 hours. He travels first half of the journey at the rate of 21 km/hr and second half at the rate of 24 km/hr. Find the total journey in km.
Correct
Incorrect
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Question 8 of 15
8. Question
The ratio between the speeds of two trains is 7 : 8. If the second train runs 400 km in 4 hours, then the speed of the first train is:
Correct
Incorrect
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Question 9 of 15
9. Question
A man on tour travels first 160 km at 64 km/hr and the next 160 km at 80 km/hr. The average speed for the first 320 km of the tour is:
Correct
Incorrect
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Question 10 of 15
10. Question
A car travelling with 5/7 of its actual speed covers 42 km in 1 hr 40 min 48 sec. Find the actual speed of the car.
Correct
Incorrect
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Question 11 of 15
11. Question
In covering a distance of 30 km, Abhay takes 2 hours more than Sameer. If Abhay doubles his speed, then he would take 1 hour less than Sameer. Abhay’s speed is:
Correct
Let Abhay’s speed be x km/hr.
Then, 30/x – 30/2x = 3
⇒ 6x = 30
⇒ x = 5 km/hr.Incorrect
Let Abhay’s speed be x km/hr.
Then, 30/x – 30/2x = 3
⇒ 6x = 30
⇒ x = 5 km/hr. -
Question 12 of 15
12. Question
Robert is travelling on his cycle and has calculated to reach point A at 2 P.M. if he travels at 10 kmph, he will reach there at 12 noon if he travels at 15 kmph. At what speed must he travel to reach A at 1 P.M.?
Correct
Let the distance travelled by x km.
Then, x/10 – x/15 = 2
⇒ 3x – 2x = 60
⇒ x = 60 km.
Time taken to travel 60 km at 10 km/hr = (60/10) hrs = 6 hrs.
So, Robert started 6 hours before 2 P.M. i.e., at 8 A.M.
Required speed = (60/5) kmph. = 12 kmph.Incorrect
Let the distance travelled by x km.
Then, x/10 – x/15 = 2
⇒ 3x – 2x = 60
⇒ x = 60 km.
Time taken to travel 60 km at 10 km/hr = (60/10) hrs = 6 hrs.
So, Robert started 6 hours before 2 P.M. i.e., at 8 A.M.
Required speed = (60/5) kmph. = 12 kmph. -
Question 13 of 15
13. Question
It takes eight hours for a 600 km journey, if 120 km is done by train and the rest by car. It takes 20 minutes more, if 200 km is done by train and the rest by car. The ratio of the speed of the train to that of the cars is:
Correct
Let the speed of the train be x km/hr and that of the car be y km/hr.
Solving (i) and (ii), we get: x = 60 and y = 80.
∴ Ratio of speeds = 60 : 80 = 3 : 4.Incorrect
Let the speed of the train be x km/hr and that of the car be y km/hr.
Solving (i) and (ii), we get: x = 60 and y = 80.
∴ Ratio of speeds = 60 : 80 = 3 : 4. -
Question 14 of 15
14. Question
A farmer travelled a distance of 61 km in 9 hours. He travelled partly on foot @ 4 km/hr and partly on bicycle @ 9 km/hr. The distance travelled on foot is:
Correct
Let the distance travelled on foot be x km.
Then, distance travelled on bicycle = (61 -x) km.
So, x/4 + (61-x)/9 = 9
⇒ 9x + 4(61 -x) = 9 x 36
⇒ 5x = 80
⇒ x = 16 km.Incorrect
Let the distance travelled on foot be x km.
Then, distance travelled on bicycle = (61 -x) km.
So, x/4 + (61-x)/9 = 9
⇒ 9x + 4(61 -x) = 9 x 36
⇒ 5x = 80
⇒ x = 16 km. -
Question 15 of 15
15. Question
A man covered a certain distance at some speed. Had he moved 3 kmph faster, he would have taken 40 minutes less. If he had moved 2 kmph slower, he would have taken 40 minutes more. The distance (in km) is:
Correct
Let distance = x km and usual rate = y kmph.
Then, x/y – x/y+3 = 30/60 ⇒ 2y(y+3) = 9x…..(i)
And, x/y-2 – x/y = 40/60 ⇒ y(y-2) = 3x…..(ii)
On dividing (i) by (ii), we get: x = 40.Incorrect
Let distance = x km and usual rate = y kmph.
Then, x/y – x/y+3 = 30/60 ⇒ 2y(y+3) = 9x…..(i)
And, x/y-2 – x/y = 40/60 ⇒ y(y-2) = 3x…..(ii)
On dividing (i) by (ii), we get: x = 40.
