CAT MCQ Series 5 | Free CAT Quiz | CAT Free Mock Test Series
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CAT Online Test Series 5 | Free CAT Quiz Series 5 | CAT Free Mock Test. Common Admission Test (CAT) is one of the most challenging and competitive MBA entrance test in our country. Check your level of preparation for CAT with free All India Mock test 2019. CAT Exam Online Test 2019, CAT Free Mock Test Exam 2019. CAT Exam Free Online Quiz 2019, CAT Full Online Mock Test Series 5th in English. CAT Online Test for All Subjects, CAT Free Mock Test Series in English. CAT Free Mock Test Series 5. CAT English Language Online Test in English Series 5th. Here we are providing CAT Full Mock Test Paper in English. CAT Mock Test Series 5th 2019. Now Test your self for CAT Exam by using below quiz…
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Question 1 of 50
1. Question
The total age of A and B is 12 years more than the total age of B and C. C is how many years younger than A?
Correct
(A + B) – (B + C) = 12
A – C = 12Incorrect
(A + B) – (B + C) = 12
A – C = 12 -
Question 2 of 50
2. Question
At the end of three years what will be the compound interest at the rate of 10% p.a. on an amount of Rs.20000?
Correct
A = 20000(11/10)3
= 26620
= 20000
———-
6620Incorrect
A = 20000(11/10)3
= 26620
= 20000
———-
6620 -
Question 3 of 50
3. Question
Ajay and Vijay have some marbles with them. Ajay told Vijay “if you give me ‘x’ marbles, both of us will have equal number of marbles”. Vijay then told Ajay “if you give me twice as many marbles, I will have 30 more marbles than you would”. Find ‘x’?
Correct
If Vijay gives ‘x’ marbles to Ajay then Vijay and Ajay would have V – x and A + x marbles.
V – x = A + x — (1)
If Ajay gives 2x marbles to Vijay then Ajay and Vijay would have A – 2x and V + 2x marbles.
V + 2x – (A – 2x) = 30 => V – A + 4x = 30 — (2)
From (1) we have V – A = 2x
Substituting V – A = 2x in (2)
6x = 30 => x = 5.Incorrect
If Vijay gives ‘x’ marbles to Ajay then Vijay and Ajay would have V – x and A + x marbles.
V – x = A + x — (1)
If Ajay gives 2x marbles to Vijay then Ajay and Vijay would have A – 2x and V + 2x marbles.
V + 2x – (A – 2x) = 30 => V – A + 4x = 30 — (2)
From (1) we have V – A = 2x
Substituting V – A = 2x in (2)
6x = 30 => x = 5. -
Question 4 of 50
4. Question
Which one of the following is the least number of four digits divisible by 71?
Correct
1000/71 = 14 6/71
1000 + 71 – 6 = 1065Incorrect
1000/71 = 14 6/71
1000 + 71 – 6 = 1065 -
Question 5 of 50
5. Question
If the cost price of 12 pens is equal to the selling price of 8 pens, the gain percent is:
Correct
Let C.P. of each pen be Re. 1.
Then, C.P. of 8 pens = Rs. 8; S.P. of 8 pens = Rs. 12.
Gain % = 4/8 * 100 = 50%Incorrect
Let C.P. of each pen be Re. 1.
Then, C.P. of 8 pens = Rs. 8; S.P. of 8 pens = Rs. 12.
Gain % = 4/8 * 100 = 50% -
Question 6 of 50
6. Question
How many figures are required to number the pages the pages of a book containing 365 pages?
Correct
1 to 9 = 9 * 1 = 9
10 to 99 = 90 * 2 = 180
100 to 365 = 266 * 3 = 798
= ———–
= 987Incorrect
1 to 9 = 9 * 1 = 9
10 to 99 = 90 * 2 = 180
100 to 365 = 266 * 3 = 798
= ———–
= 987 -
Question 7 of 50
7. Question
A cylinder and a cone have a same height and same radius of the base. The ratio between the volumes of the cylinder and cone is?
Correct
Incorrect
-
Question 8 of 50
8. Question
Kim can do a work in 3 days while David can do the same work in 2 days. Both of them finish the work together and get Rs. 150. What is the share of Kim?
Correct
Kim’s wages : David’s wages = Kim’s 1 day work : David’s 1 day work = 1/3 : 1/2 = 2:3
Kim’s share = 2/5 * 150 = Rs. 60Incorrect
Kim’s wages : David’s wages = Kim’s 1 day work : David’s 1 day work = 1/3 : 1/2 = 2:3
Kim’s share = 2/5 * 150 = Rs. 60 -
Question 9 of 50
9. Question
The least number of four digits which is divisible by 15, 25, 40 and 75 is:
Correct
Greatest number of 4 digits is 9999. L.C.M of 15, 25, 40 and 75 is 600.
On dividing 9999 by 600, the remainder is 399. Required number = 9999 – 399 = 9600Incorrect
Greatest number of 4 digits is 9999. L.C.M of 15, 25, 40 and 75 is 600.
On dividing 9999 by 600, the remainder is 399. Required number = 9999 – 399 = 9600 -
Question 10 of 50
10. Question
The sale price sarees listed for Rs.400 after successive discount is 10% and 5% is?
Correct
400*(90/100)*(95/100) = 342
Incorrect
400*(90/100)*(95/100) = 342
-
Question 11 of 50
11. Question
Visitors to show were charged Rs.15 each on the first day. Rs.7.50 on the second day, Rs.2.50 on the third day and total attendance on the three days were in ratio 2:5:13 respectively. The average charge per person for the whole show is?
Correct
2: 5: 13
2x 5x 13x
15 7.5 2.5
30x + 37.5x + 32.5x = 100x/20x
Average = 5Incorrect
2: 5: 13
2x 5x 13x
15 7.5 2.5
30x + 37.5x + 32.5x = 100x/20x
Average = 5 -
Question 12 of 50
12. Question
A train running at a speed of 36 kmph crosses an electric pole in 12 seconds. In how much time will it cross a 350 m long platform?
Correct
Let the length of the train be x m.
When a train crosses an electric pole, the distance covered is its own length.
So, x = 12 * 36 * 5 /18 m = 120 m.
Time taken to cross the platform = (120 +350)/ 36 * 5/18 = 47 min.Incorrect
Let the length of the train be x m.
When a train crosses an electric pole, the distance covered is its own length.
So, x = 12 * 36 * 5 /18 m = 120 m.
Time taken to cross the platform = (120 +350)/ 36 * 5/18 = 47 min. -
Question 13 of 50
13. Question
9 men and 12 boys finish a job in 12 days, 12 men and 12 boys finish it in 10 days. 10 men and 10 boys shall finish it in how many days?
Correct
9M + 12B —– 12 days
12M + 12B ——- 10 days
10M + 10B ——-?
108M + 144B = 120M +120B
24B = 12M => 1M = 2B
18B + 12B = 30B —- 12 days
20B + 10B = 30B —–? => 12 daysIncorrect
9M + 12B —– 12 days
12M + 12B ——- 10 days
10M + 10B ——-?
108M + 144B = 120M +120B
24B = 12M => 1M = 2B
18B + 12B = 30B —- 12 days
20B + 10B = 30B —–? => 12 days -
Question 14 of 50
14. Question
22004 – 29303 + 101299 – 59532 = ?
Correct
22004 – 29303 + 101299 – 59532
123303 – 888.35 = 34468 = 34500Incorrect
22004 – 29303 + 101299 – 59532
123303 – 888.35 = 34468 = 34500 -
Question 15 of 50
15. Question
A cricketer has a certain average for 10 innings. In the eleventh inning, he scored 108 runs, there by increasing his average by 6 runs. His new average is:
Correct
Let average for 10 innings be x. Then,
(10x + 108)/11 = x + 6
= 11x + 66 = 10x + 108
= x = 42.
New average = (x + 6) = 48 runs.Incorrect
Let average for 10 innings be x. Then,
(10x + 108)/11 = x + 6
= 11x + 66 = 10x + 108
= x = 42.
New average = (x + 6) = 48 runs. -
Question 16 of 50
16. Question
A cycle is bought for Rs.900 and sold for Rs.1080, find the gain percent?
Correct
900 —- 180
100 —- ? => 20%Incorrect
900 —- 180
100 —- ? => 20% -
Question 17 of 50
17. Question
One root of the quadratic equation x2 – 12x + a = 0, is thrice the other. Find the value of a?
Correct
Let the roots of the quadratic equation be x and 3x.
Sum of roots = -(-12) = 12
a + 3a = 4a = 12 => a = 3
Product of the roots = 3a2 = 3(3)2 = 27.Incorrect
Let the roots of the quadratic equation be x and 3x.
Sum of roots = -(-12) = 12
a + 3a = 4a = 12 => a = 3
Product of the roots = 3a2 = 3(3)2 = 27. -
Question 18 of 50
18. Question
The average age of three boys is 15 years and their ages are in proportion 3:5:7. What is the age in years of the youngest boy?
Correct
3x + 5x + 7x = 45
x =3
3x = 9Incorrect
3x + 5x + 7x = 45
x =3
3x = 9 -
Question 19 of 50
19. Question
Rs.590 is divided amongst A, B, C so that 5 times A’s share, six times B’s share and eight times C’s share are all equal. Find C’s share?
Correct
A+B+C = 590
5A = 6B = 8C = x
A:B:C = 1/5:1/6:1/8
= 24:20:15
15/59 * 590 = Rs.150Incorrect
A+B+C = 590
5A = 6B = 8C = x
A:B:C = 1/5:1/6:1/8
= 24:20:15
15/59 * 590 = Rs.150 -
Question 20 of 50
20. Question
Find the one which does not belong to that group ?
Correct
Tiruvanantapuram, Hyderabad, Bangalore and Bhubaneswar are state capitals, while Calicut is not a state capital.
Incorrect
Tiruvanantapuram, Hyderabad, Bangalore and Bhubaneswar are state capitals, while Calicut is not a state capital.
-
Question 21 of 50
21. Question
If one-third of one fourth of a number is 15, then three-tenth of that number is:
Correct
Let the number be x. Then,
1/3 of 1/4 of x = 15
x = 15 * 12 = 180
So, required number = (3/10 * 180) = 54.Incorrect
Let the number be x. Then,
1/3 of 1/4 of x = 15
x = 15 * 12 = 180
So, required number = (3/10 * 180) = 54. -
Question 22 of 50
22. Question
A train crosses a platform of 120 m in 15 sec, same train crosses another platform of length 180 m in 18 sec. then find the length of the train?
Correct
Length of the train be ‘X’
X + 120/15 = X + 180/18
6X + 720 = 5X + 900
X = 180mIncorrect
Length of the train be ‘X’
X + 120/15 = X + 180/18
6X + 720 = 5X + 900
X = 180m -
Question 23 of 50
23. Question
A train passes a station platform in 36 sec and a man standing on the platform in 20 sec. If the speed of the train is 54 km/hr. What is the length of the platform?
Correct
Speed = 54 * 5/18 = 15 m/sec.
Length of the train = 15 * 20 = 300 m.
Let the length of the platform be x m . Then,
(x + 300)/36 = 15 => x = 240 m.Incorrect
Speed = 54 * 5/18 = 15 m/sec.
Length of the train = 15 * 20 = 300 m.
Let the length of the platform be x m . Then,
(x + 300)/36 = 15 => x = 240 m. -
Question 24 of 50
24. Question
How many numbers up to 200 are divisible by 2 and 3 both?
Correct
200/6 = 33 2/6 => 33 Numbers
Incorrect
200/6 = 33 2/6 => 33 Numbers
-
Question 25 of 50
25. Question
A garrison of 400 men had a provision for 31 days. After 28 days 280 persons re-enforcement leave the garrison. Find the number of days for which the remaining ration will be sufficient?
Correct
400 — 31
400 — 3
120 — ?
400*3 = 120*x => x =10 daysIncorrect
400 — 31
400 — 3
120 — ?
400*3 = 120*x => x =10 days -
Question 26 of 50
26. Question
The product of two numbers is 2028 and their H.C.F is 13. The number of such pairs is:
Correct
Let the numbers be 13a and 13b.
Then, 13a * 13b = 2028 => ab = 12.
Now, co-primes with product 12 are (1, 12) and (3, 4).
So, the required numbers are (13 * 1, 13 * 12) and (13 * 3, 13 * 4).
Clearly, there are 2 such pairs.Incorrect
Let the numbers be 13a and 13b.
Then, 13a * 13b = 2028 => ab = 12.
Now, co-primes with product 12 are (1, 12) and (3, 4).
So, the required numbers are (13 * 1, 13 * 12) and (13 * 3, 13 * 4).
Clearly, there are 2 such pairs. -
Question 27 of 50
27. Question
Eighteen years ago, a father was three times as old as his son. Now the father is only twice as old his son. Then the sum of the present ages of the son and the father is:
Correct
Let the present ages of the father and son be 2x and x years respectively.
Then, (2x – 18) = 3(x – 18) => x = 36
Required sum = (2x + x) = 108 years.Incorrect
Let the present ages of the father and son be 2x and x years respectively.
Then, (2x – 18) = 3(x – 18) => x = 36
Required sum = (2x + x) = 108 years. -
Question 28 of 50
28. Question
A sum of money is borrowed and paid back in two annual installments of Rs. 882 each allowing 5% C.I. The sum borrowed was?
Correct
Principal = (P.W. of Rs. 882 due 1 year hence) + (P.W. of Rs. 882 due 2 years hence)
= [882/(1 + 5/100) + 882/(1 + 5/100)2]
= (882 * 20)/21 + (882 * 400)/441 = Rs. 1640.Incorrect
Principal = (P.W. of Rs. 882 due 1 year hence) + (P.W. of Rs. 882 due 2 years hence)
= [882/(1 + 5/100) + 882/(1 + 5/100)2]
= (882 * 20)/21 + (882 * 400)/441 = Rs. 1640. -
Question 29 of 50
29. Question
On multiplying a number by 7, the product is a number each of whose digits is 3. The smallest such number is:
Correct
By hit and trail, we find that
47619 * 7 = 333333.
7) 333333 (47619
333333
—————-
0Incorrect
By hit and trail, we find that
47619 * 7 = 333333.
7) 333333 (47619
333333
—————-
0 -
Question 30 of 50
30. Question
In how many years will a sum of money doubles itself at 5% per annum on simple interest?
Correct
P = (P*5*R)/100
R = 20%Incorrect
P = (P*5*R)/100
R = 20% -
Question 31 of 50
31. Question
A, B and C invests Rs.2000, Rs.3000 and Rs.4000 in a business. After one year A removed his money; B and C continued the business for one more year. If the net profit after 2 years be Rs.3200, then A’s share in the profit is?
Correct
2*12 : 3*12 : 4*24
1: 3: 4
1/8 * 3200 = 400Incorrect
2*12 : 3*12 : 4*24
1: 3: 4
1/8 * 3200 = 400 -
Question 32 of 50
32. Question
Two pipes A and B can separately fill a tank in 12 and 15 minutes respectively. A third pipe C can drain off 45 liters of water per minute. If all the pipes are opened, the tank can be filled in 15 minutes. What is the capacity of the tank?
Correct
1/12 + 1/15 – 1/x = 1/15
x = 12
12 * 45 = 540Incorrect
1/12 + 1/15 – 1/x = 1/15
x = 12
12 * 45 = 540 -
Question 33 of 50
33. Question
If x = 3 – √7, then find the value of x + 1/x.
Correct
x = 3 – √7
1/x = 1/(3 – √7) = (3 + √7)/(3 – √7)(3 + √7)
= (3 + √7)/2 => x + 1/x (9 – √7)/2Incorrect
x = 3 – √7
1/x = 1/(3 – √7) = (3 + √7)/(3 – √7)(3 + √7)
= (3 + √7)/2 => x + 1/x (9 – √7)/2 -
Question 34 of 50
34. Question
Three consecutive odd integers are in increasing order such that the sum of the last two integers is 13 more than the first integer. Find the three integers?
Correct
Let the three consecutive odd integers be x, x + 2 and x + 4 respectively.
x + 4 + x + 2 = x + 13 => x = 7
Hence three consecutive odd integers are 7, 9 and 11.Incorrect
Let the three consecutive odd integers be x, x + 2 and x + 4 respectively.
x + 4 + x + 2 = x + 13 => x = 7
Hence three consecutive odd integers are 7, 9 and 11. -
Question 35 of 50
35. Question
The C.I. on a certain sum for 2 years Rs.41 and the simple interest is Rs.40. What is the rate percent?
Correct
SI = 20 + 20
CI = 20 + 21
20 —- 1
100 —- ? => 5%Incorrect
SI = 20 + 20
CI = 20 + 21
20 —- 1
100 —- ? => 5% -
Question 36 of 50
36. Question
A gardener wants to plant trees in his garden in rows in such a way that the number of trees in each row to be the same. If there are 24 rows the number of trees in each row is 42 if there are 12 more rows find the number of trees in each row?
Correct
Required number of trees
= 24/36 * 42 = 28.Incorrect
Required number of trees
= 24/36 * 42 = 28. -
Question 37 of 50
37. Question
The smallest fraction, which each of 6/7, 5/14, 10/21 will divide exactly is:
Correct
Required fraction = L.C.M of 6/7, 5/14, 10/21
= (L.C.M of 6, 5, 10) / (H.C.F of 7, 14, 21) = 30/7Incorrect
Required fraction = L.C.M of 6/7, 5/14, 10/21
= (L.C.M of 6, 5, 10) / (H.C.F of 7, 14, 21) = 30/7 -
Question 38 of 50
38. Question
Two trains are moving at 50 kmph and 70 kmph in opposite directions. Their lengths are 150 m and 100 m respectively. The time they will take to pass each other completely is?
Correct
70 + 50 = 120 * 5/18 = 100/3 mps
D = 150 + 100 = 250 m
T = 250 * 3/100 = 15/2 = 7 ½ secIncorrect
70 + 50 = 120 * 5/18 = 100/3 mps
D = 150 + 100 = 250 m
T = 250 * 3/100 = 15/2 = 7 ½ sec -
Question 39 of 50
39. Question
Find the one which does not belong to that group ?
Correct
All are organs of our body which are in pairs except fingers.
Incorrect
All are organs of our body which are in pairs except fingers.
-
Question 40 of 50
40. Question
A man was employed on the promise that he will be paid the highest wages per day. The contract money to be paid was Rs. 1189. Finally he was paid only Rs. 1073. For how many days did he actually work?
Correct
HCF of 1189, 1073 = 29
1073/29 = 37Incorrect
HCF of 1189, 1073 = 29
1073/29 = 37 -
Question 41 of 50
41. Question
7 + 5 – (3/2 * 1/4) of 2/7 + 7/2 * 1/6 equals -.
Correct
7 + 5 – (3/2 * 1/4) of 2/7 + 7/2 * 1/16
= 7 + 5 – (3/2 * 1/4) * 2/7 + 7/2 * 1/16 = 7 + 5 – 3/28 + 7/32
= 12 + 3/28 + 7/32 = 12 + (7 * 7 – 3 * 8)/224
= 12 + 25/224 = 12 25/224Incorrect
7 + 5 – (3/2 * 1/4) of 2/7 + 7/2 * 1/16
= 7 + 5 – (3/2 * 1/4) * 2/7 + 7/2 * 1/16 = 7 + 5 – 3/28 + 7/32
= 12 + 3/28 + 7/32 = 12 + (7 * 7 – 3 * 8)/224
= 12 + 25/224 = 12 25/224 -
Question 42 of 50
42. Question
Two trains, one from Howrah to Patna and the other from Patna to Howrah, start simultaneously. After they meet, the trains reach their destinations after 9 hours and 16 hours respectively. The ratio of their speeds is?
Correct
Let us name the trains A and B.
Then, (A’s speed) : (B’s speed)
= √b : √a = √16 : √9 = 4:3Incorrect
Let us name the trains A and B.
Then, (A’s speed) : (B’s speed)
= √b : √a = √16 : √9 = 4:3 -
Question 43 of 50
43. Question
There are 18 stations between Hyderabad and Bangalore. How many second class tickets have to be printed, so that a passenger can travel from any station to any other station?
Correct
The total number of stations = 20
From 20 stations we have to choose any two stations and the direction of travel (i.e., Hyderabad to Bangalore is different from Bangalore to Hyderabad) in ²⁰P₂ ways.
²⁰P₂ = 20 * 19 = 380.Incorrect
The total number of stations = 20
From 20 stations we have to choose any two stations and the direction of travel (i.e., Hyderabad to Bangalore is different from Bangalore to Hyderabad) in ²⁰P₂ ways.
²⁰P₂ = 20 * 19 = 380. -
Question 44 of 50
44. Question
Find the number of factors of 300 excluding 1 and itself.
Correct
300 = 4.75 = 4.25.3 = 22.52.31
Number of factors of 300 = (2 + 1)(2 + 1)(1 + 1) = 18.
There are 16 factors of 300 excluding 1 and itself.Incorrect
300 = 4.75 = 4.25.3 = 22.52.31
Number of factors of 300 = (2 + 1)(2 + 1)(1 + 1) = 18.
There are 16 factors of 300 excluding 1 and itself. -
Question 45 of 50
45. Question
An article is bought for Rs.600 and sold for Rs.500, find the loss percent?
Correct
600 —- 100
100 —- ? => 16 2/3%Incorrect
600 —- 100
100 —- ? => 16 2/3% -
Question 46 of 50
46. Question
Out of first 20 natural numbers, one number is selected at random. The probability that it is either an even number or a prime number is -.
Correct
n(S) = 20
n(Even no) = 10 = n(E)
n(Prime no) = 8 = n(P)
P(EᴜP) = 10/20 + 8/20 – 1/20 = 17/20Incorrect
n(S) = 20
n(Even no) = 10 = n(E)
n(Prime no) = 8 = n(P)
P(EᴜP) = 10/20 + 8/20 – 1/20 = 17/20 -
Question 47 of 50
47. Question
By selling a house for Rs.45000, it was found that 1/8 of the outlay was gained, what ought the selling to price to have been in order to have lost 5 p.c?
Correct
CP + CP/8 = 45000
CP = 40000
SP = 40000*(95/100) = 38000Incorrect
CP + CP/8 = 45000
CP = 40000
SP = 40000*(95/100) = 38000 -
Question 48 of 50
48. Question
How many three letter words are formed using the letters of the word TIME?
Correct
The number of letters in the given word is four.
The number of three letter words that can be formed using these four letters is ⁴P₃ = 4 * 3 * 2 = 24.Incorrect
The number of letters in the given word is four.
The number of three letter words that can be formed using these four letters is ⁴P₃ = 4 * 3 * 2 = 24. -
Question 49 of 50
49. Question
If a: b = 3:4, b:c = 7:9, c:d = 5:7, find a:d?
Correct
a/d = (3/4)*(7/9)*(5/7) => 5/12
Incorrect
a/d = (3/4)*(7/9)*(5/7) => 5/12
-
Question 50 of 50
50. Question
A and B can do a piece of work in 7 days. With the help of C they finish the work in 5 days. C alone can do that piece of work in?
Correct
C = 1/5 – 1/6 = 1/30 => 30 days
Incorrect
C = 1/5 – 1/6 = 1/30 => 30 days