A bag contains 4 pink and 5 blue beads. Another bag contains 3 pink and 6 blue beads. Two beads are drawn, one from each bag. Find the probability that one is pink and the other is blue.
A
13/27
B
1/2
C
7/11
D
14/27
Correct Option - A
Explaination
n(S) = 9C1*9C1 = 81
No. of ways of selecting a pink and a blue bead
= [n(Pink from bag 1)*n(Blue from bag 2)]+
[n(Blue from bag 1)*n(Pink from bag 2)]
n(E) = (4*6)+(5*3)
= 39
P(E) = 13/27