The present ages of three people in a family are in the ratio 3:5:7. If the sum of their ages before 5 years was 60, find the age of the youngest.
A 12
B 18
C 6
D 15
Correct Option - D
ExplainationLet their present ages be 3x,5x and 7x. Sum of their ages before 5 years = 3x-5+5x-5+7x-5 = 15x-15 = 60 Solving, x=5 Age of the youngest = 3x = 15