RBI Assistant Prelims Online Test Series 1, RBI Assistant Mock Test
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RBI Assistant Prelims Online Test Series 1, RBI Assistant Mock Test. Take CAknowledge Free Online Test Series 1 for RBI Exams. RBI Assistant Pre. Exam Free Online Quiz 2019. To Analyse your preparation, one should attempt the test series on a regular basis to score more in the examination. Start FREE mock test and get top rank among all applicants whoever are participating in the exam. You can subscribe our test series for RBI Assistant Exam from here. RBI Assistant Pre Question and Answers in English and Hindi Series 1. Here we are providing RBI Assistant Pre. Full Mock Test Paper in English. RBI Assistant Pre Mock Test Series 1st 2019. Now Test your self for RBI Assistant Pre. Exam by using below quiz…
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Question 1 of 50
1. Question
A can do a piece of work in 10 days and B can do the same work in 12 days. A and B worked together for 2 days. How many more days are required to complete the remaining work if they work together?
Correct
A can do 1/10 of the work in a day.
B can do 1/12 of the work in a 1 day.
Both of them together can do (1/10 + 1/12) part of work in 1 day = (6 + 5)/60 = 11/60
They take 60/11 days to complete the work together.
Given that they already worked for 2 days.
The number of days required to complete remaining work => 60/11 – 2 = 38/11 = 3 (5/11) days.Incorrect
A can do 1/10 of the work in a day.
B can do 1/12 of the work in a 1 day.
Both of them together can do (1/10 + 1/12) part of work in 1 day = (6 + 5)/60 = 11/60
They take 60/11 days to complete the work together.
Given that they already worked for 2 days.
The number of days required to complete remaining work => 60/11 – 2 = 38/11 = 3 (5/11) days. -
Question 2 of 50
2. Question
A dishonest dealer professes to sell goods at the cost price but uses a weight of 800 grams per kg, what is his percent?
Correct
800 — 200
100 — ? => 25%Incorrect
800 — 200
100 — ? => 25% -
Question 3 of 50
3. Question
The average weight of a group of persons increased from 48 kg to 51 kg, when two persons weighing 78 kg and 93 kg join the group. Find the initial number of members in the group?
Correct
Let the initial number of members in the group be n.
Initial total weight of all the members in the group = n(48)
From the data,
48n + 78 + 93 = 51(n + 2) => 51n – 48n = 69 => n = 23
Therefore there were 23 members in the group initially.Incorrect
Let the initial number of members in the group be n.
Initial total weight of all the members in the group = n(48)
From the data,
48n + 78 + 93 = 51(n + 2) => 51n – 48n = 69 => n = 23
Therefore there were 23 members in the group initially. -
Question 4 of 50
4. Question
A, B and C completed a piece of work, A worked for 6 days, B for 9 days and C for 4 days. Their daily wages were in the ratio of 3:4:5. Find the daily wages of C, if their total earning was Rs.1480?
Correct
3x 4x 5x
6 9 4
18x + 36x + 20x = 1480
74x = 1480 => x = 20
5x = 100 Rs.Incorrect
3x 4x 5x
6 9 4
18x + 36x + 20x = 1480
74x = 1480 => x = 20
5x = 100 Rs. -
Question 5 of 50
5. Question
96 is divided into two parts in such a way that seventh part of first and ninth part of second are equal. Find the smallest part?
Correct
x/7 = y/9 => x:y = 7:9
7/16 * 96 = 42Incorrect
x/7 = y/9 => x:y = 7:9
7/16 * 96 = 42 -
Question 6 of 50
6. Question
In a series of six consecutive even numbers, the sum of the second and sixth numbers is 24. What is the fourth number?
Correct
Let the numbers be x, x + 2, x + 4, x + 6, x + 8 and x + 10.
Given (x + 2) + (x + 10) = 24
=> 2x + 12 = 24 => x = 6
The fourth number = x + 6 = 6 + 6 = 12.Incorrect
Let the numbers be x, x + 2, x + 4, x + 6, x + 8 and x + 10.
Given (x + 2) + (x + 10) = 24
=> 2x + 12 = 24 => x = 6
The fourth number = x + 6 = 6 + 6 = 12. -
Question 7 of 50
7. Question
The radius of a cylinder is 2 r units and height is 3 r units. Find the curved surface?
Correct
2 * π * 2r * 3r = 12 πr2
Incorrect
2 * π * 2r * 3r = 12 πr2
-
Question 8 of 50
8. Question
The weights of three boys are in the ratio 4 : 5 : 6. If the sum of the weights of the heaviest and the lightest boy is 45 kg more than the weight of the third boy, what is the weight of the lightest boy?
Correct
Let the weights of the three boys be 4k, 5k and 6k respectively.
4k + 6k = 5k + 45
=> 5k = 45 => k = 9
Therefore the weight of the lightest boy
= 4k = 4(9) = 36 kg.Incorrect
Let the weights of the three boys be 4k, 5k and 6k respectively.
4k + 6k = 5k + 45
=> 5k = 45 => k = 9
Therefore the weight of the lightest boy
= 4k = 4(9) = 36 kg. -
Question 9 of 50
9. Question
Rs.800 amounts to Rs.920 in 3 years at simple interest. If the interest is increased by 3%, it would amount to how much?
Correct
(800*3*3)/100 = 72
920 + 72 = 992Incorrect
(800*3*3)/100 = 72
920 + 72 = 992 -
Question 10 of 50
10. Question
Two trains of length 100 m and 200 m are 100 m apart. They start moving towards each other on parallel tracks, at speeds 54 kmph and 72 kmph. After how much time will the trains meet?
Correct
They are moving in opposite directions, relative speed is equal to the sum of their speeds.
Relative speed = (54 + 72)*5/18 = 7*5 = 35 mps.
The time required = d/s = 100/35 = 20/7 sec.Incorrect
They are moving in opposite directions, relative speed is equal to the sum of their speeds.
Relative speed = (54 + 72)*5/18 = 7*5 = 35 mps.
The time required = d/s = 100/35 = 20/7 sec. -
Question 11 of 50
11. Question
I bought two books; for Rs.480. I sold one at a loss of 15% and other at a gain of 19% and then I found each book was sold at the same price. Find the cost of the book sold at a loss?
Correct
x*(85/100) = (480 – x)119/100
x = 280Incorrect
x*(85/100) = (480 – x)119/100
x = 280 -
Question 12 of 50
12. Question
If A lends Rs.3500 to B at 10% per annum and B lends the same sum to C at 11.5% per annum then the gain of B in a period of 3 years is?
Correct
(3500*1.5*3)/100 => 157.50
Incorrect
(3500*1.5*3)/100 => 157.50
-
Question 13 of 50
13. Question
A dishonest dealer professes to sell his goods at Cost Price but still gets 20% profit by using a false weight. What weight does he substitute for a kilogram?
Correct
If the cost price is Rs.100, then to get a profit of 20%, the selling price should be Rs.120.
If 120kg are to be sold, and the dealer gives only 100kg, to get a profit of 20%.
How many grams he has to give instead of one kilogram(1000 gm).
120 gm —— 100 gm
1000 gm —— ?
(1000 * 100)/120 = 2500/3 = 833 1/3 grams.Incorrect
If the cost price is Rs.100, then to get a profit of 20%, the selling price should be Rs.120.
If 120kg are to be sold, and the dealer gives only 100kg, to get a profit of 20%.
How many grams he has to give instead of one kilogram(1000 gm).
120 gm —— 100 gm
1000 gm —— ?
(1000 * 100)/120 = 2500/3 = 833 1/3 grams. -
Question 14 of 50
14. Question
106 * 106 – 94 * 94 = ?
Correct
106 * 106 – 94 * 94 = (106)2 – (94)2
= (106 + 94)(106 – 94) = (200 * 12) = 2400Incorrect
106 * 106 – 94 * 94 = (106)2 – (94)2
= (106 + 94)(106 – 94) = (200 * 12) = 2400 -
Question 15 of 50
15. Question
[(62.25/2.5) + (12.5/0.5)] / [(0.75 * 9) + (3.5 * 3.5)] = ?
Correct
[(62.25/2.5) + (12.5/0.5)] / [(0.75 * 9) + (3.5 * 3.5)]
= [(6225/250) + (125/5)] / (6.75 + 12.25)
= (249/10 + 25) / 19 = 499/190 = 2 119/190Incorrect
[(62.25/2.5) + (12.5/0.5)] / [(0.75 * 9) + (3.5 * 3.5)]
= [(6225/250) + (125/5)] / (6.75 + 12.25)
= (249/10 + 25) / 19 = 499/190 = 2 119/190 -
Question 16 of 50
16. Question
The cash difference between the selling prices of an article at a profit of 4% and 6% is Rs. 3. The ratio of the two selling prices is:
Correct
Let C.P. of the article be Rs. x.
Then, required ratio = 104% of x / 106% of x
= 104/106 = 52/53 = 52:53Incorrect
Let C.P. of the article be Rs. x.
Then, required ratio = 104% of x / 106% of x
= 104/106 = 52/53 = 52:53 -
Question 17 of 50
17. Question
The sides of a cube are in the ratio 1:2 the ratio of their volume is?
Correct
Incorrect
-
Question 18 of 50
18. Question
A tap can fill a tank in 6 hours. After half the tank is filled three more similar taps are opened. What is the total time taken to fill the tank completely?
Correct
Time taken by one tap to fill the tank = 3 hrs.
Part filled by the taps in 1 hour = 4 * 1/6 = 2/3
Remaining part = 1 – 1/2 = 1/2
2/3 : 1/2 :: 1 : x
x = 1/2 * 1 * 3/2 = 3/4 hrs. i.e., 45 min
So, total time taken = 3 hrs 45 min.Incorrect
Time taken by one tap to fill the tank = 3 hrs.
Part filled by the taps in 1 hour = 4 * 1/6 = 2/3
Remaining part = 1 – 1/2 = 1/2
2/3 : 1/2 :: 1 : x
x = 1/2 * 1 * 3/2 = 3/4 hrs. i.e., 45 min
So, total time taken = 3 hrs 45 min. -
Question 19 of 50
19. Question
A 300 m long train crosses a platform in 39 sec while it crosses a signal pole in 18 sec. What is the length of the platform?
Correct
Speed = 300/18 = 50/3 m/sec.
Let the length of the platform be x meters.
Then, (x + 300)/39 = 50/3
3x + 900 = 1950 => x = 350 m.Incorrect
Speed = 300/18 = 50/3 m/sec.
Let the length of the platform be x meters.
Then, (x + 300)/39 = 50/3
3x + 900 = 1950 => x = 350 m. -
Question 20 of 50
20. Question
Find the one which does not belong to that group ?
Correct
30 = 33 + 3, 630 = 54 + 5, 10 = 23 + 2, 520 = 83 + 8 and 130 = 53 + 5.
30, 10, 130 and 520 can be expressed as n3 + n but not 630.Incorrect
30 = 33 + 3, 630 = 54 + 5, 10 = 23 + 2, 520 = 83 + 8 and 130 = 53 + 5.
30, 10, 130 and 520 can be expressed as n3 + n but not 630. -
Question 21 of 50
21. Question
The ratio of the volumes of a cube to that of the sphere which will fit inside the cube is?
Correct
a3 : a3/8 * 4/3 π => 6: π
Incorrect
a3 : a3/8 * 4/3 π => 6: π
-
Question 22 of 50
22. Question
I. a2 – 2a – 8 = 0,
II. b2 = 9 to solve both the equations to find the values of a and b?Correct
I. (a – 4)(a + 2) = 0
=> a = 4, -2
II. b2 = 9
=> b = ± 3
-2 -3, 4 > 3, 4 > -3,
No relation can be established between a and b.Incorrect
I. (a – 4)(a + 2) = 0
=> a = 4, -2
II. b2 = 9
=> b = ± 3
-2 -3, 4 > 3, 4 > -3,
No relation can be established between a and b. -
Question 23 of 50
23. Question
The average age of three boys is 15 years and their ages are in proportion 3:5:7. What is the age in years of the youngest boy?
Correct
3x + 5x + 7x = 45
x =3
3x = 9Incorrect
3x + 5x + 7x = 45
x =3
3x = 9 -
Question 24 of 50
24. Question
The sum of money at compound interest amounts to thrice itself in 3 years. In how many years will it be 9 times itself?
Correct
100 —- 300 — 3
900 — 3
—-
6 yearsIncorrect
100 —- 300 — 3
900 — 3
—-
6 years -
Question 25 of 50
25. Question
Thirty men can do a work in 24 days. In how many days can 20 men can do the work, given that the time spent per day is increased by one-third of the previous time?
Correct
Let the number of hours working per day initially be x. we have M1 D1 H1= M2 D2 H2
30 * 24 * x = 20 * d2 * (4x)/3 => d2 = (30 * 24 * 3)/(24 * 4) = 27 days.Incorrect
Let the number of hours working per day initially be x. we have M1 D1 H1= M2 D2 H2
30 * 24 * x = 20 * d2 * (4x)/3 => d2 = (30 * 24 * 3)/(24 * 4) = 27 days. -
Question 26 of 50
26. Question
Find the ratio of the curved surfaces of two cylinders of same heights if their radii are in the ratio 1:2.
Correct
Incorrect
-
Question 27 of 50
27. Question
Ramesh can finish a work in 20 days and Sushil in 25 days. They both work together for 5 days and then Sushil goes away. In how many days will Ramesh complete the remaining work?
Correct
(5 + x)/20 + 5/25 = 1 => x = 11 days
Incorrect
(5 + x)/20 + 5/25 = 1 => x = 11 days
-
Question 28 of 50
28. Question
A, B and C play a cricket match. The ratio of the runs scored by them in the match is A:B = 2:3 and B:C = 2:5. If the total runs scored by all of them are 75, the runs scored by B are?
Correct
A:B = 2:3
B:C = 2:5
A:B:C = 4:6:15
6/25 * 75 = 18Incorrect
A:B = 2:3
B:C = 2:5
A:B:C = 4:6:15
6/25 * 75 = 18 -
Question 29 of 50
29. Question
A train running at a speed of 36 kmph crosses an electric pole in 12 seconds. In how much time will it cross a 350 m long platform?
Correct
Let the length of the train be x m.
When a train crosses an electric pole, the distance covered is its own length.
So, x = 12 * 36 * 5 /18 m = 120 m.
Time taken to cross the platform = (120 +350)/ 36 * 5/18 = 47 min.Incorrect
Let the length of the train be x m.
When a train crosses an electric pole, the distance covered is its own length.
So, x = 12 * 36 * 5 /18 m = 120 m.
Time taken to cross the platform = (120 +350)/ 36 * 5/18 = 47 min. -
Question 30 of 50
30. Question
A started a business with an investment of Rs. 70000 and after 6 months B joined him investing Rs. 120000. If the profit at the end of a year is Rs. 52000, then the share of B is?
Correct
Ratio of investments of A and B is (70000 * 12) : (120000 * 6) = 7 : 6
Total profit = Rs. 52000
Share of B = 6/13 (52000) = Rs. 24000Incorrect
Ratio of investments of A and B is (70000 * 12) : (120000 * 6) = 7 : 6
Total profit = Rs. 52000
Share of B = 6/13 (52000) = Rs. 24000 -
Question 31 of 50
31. Question
Find the smallest number which should be multiplied with 520 to make it a perfect square.
Correct
520 = 26 * 20 = 2 * 13 * 22 * 5 = 23 * 13 * 5
Required smallest number = 2 * 13 * 5 = 130
130 is the smallest number which should be multiplied with 520 to make it a perfect square.Incorrect
520 = 26 * 20 = 2 * 13 * 22 * 5 = 23 * 13 * 5
Required smallest number = 2 * 13 * 5 = 130
130 is the smallest number which should be multiplied with 520 to make it a perfect square. -
Question 32 of 50
32. Question
If y exceeds x by 25%, then x is less than y by?
Correct
X=100 y=125
125——–25
100——–? => 20%Incorrect
X=100 y=125
125——–25
100——–? => 20% -
Question 33 of 50
33. Question
The average temperature for Monday, Tuesday, Wednesday and Thursday was 48 degrees and for Tuesday, Wednesday, Thursday and Friday was 46 degrees. If the temperature on Monday was 42 degrees. Find the temperature on Friday?
Correct
M + Tu + W + Th = 4 * 48 = 192
Tu + W + Th + F = 4 * 46 = 184
M = 42
Tu + W + Th = 192 -42 = 150
F = 184 – 150 = 34Incorrect
M + Tu + W + Th = 4 * 48 = 192
Tu + W + Th + F = 4 * 46 = 184
M = 42
Tu + W + Th = 192 -42 = 150
F = 184 – 150 = 34 -
Question 34 of 50
34. Question
{20 – [7 – (3 -2)] + 1/3 (4.2)} / 1.4 = ?
Correct
{20 – [7 – (3 -2)] + 1/3 (4.2)} / 1.4
=> [20 – (7 – 1) + 1.4] / 1.4
=> (20 – 6 + 1.4)/1.4 = 10 + 1 = 11Incorrect
{20 – [7 – (3 -2)] + 1/3 (4.2)} / 1.4
=> [20 – (7 – 1) + 1.4] / 1.4
=> (20 – 6 + 1.4)/1.4 = 10 + 1 = 11 -
Question 35 of 50
35. Question
The sum of the present ages of two persons A and B is 60. If the age of A is twice that of B, find the sum of their ages 5 years hence?
Correct
A + B = 60, A = 2B
2B + B = 60 => B = 20 then A = 40.
5 years, their ages will be 45 and 25.
Sum of their ages = 45 + 25 = 70.Incorrect
A + B = 60, A = 2B
2B + B = 60 => B = 20 then A = 40.
5 years, their ages will be 45 and 25.
Sum of their ages = 45 + 25 = 70. -
Question 36 of 50
36. Question
A and B can do a piece of work in 7 days. With the help of C they finish the work in 5 days. C alone can do that piece of work in?
Correct
C = 1/5 – 1/6 = 1/30 => 30 days
Incorrect
C = 1/5 – 1/6 = 1/30 => 30 days
-
Question 37 of 50
37. Question
A, B and C can do a work in 90, 30 and 45 days respectively. If they work together, in how many days will they complete the work?
Correct
One days’s work of A, B and C = 1/90 + 1/30 + 1/45
= (1 + 3 + 2)/90 = 1/15
A, B and C together can do the work in 15 days.Incorrect
One days’s work of A, B and C = 1/90 + 1/30 + 1/45
= (1 + 3 + 2)/90 = 1/15
A, B and C together can do the work in 15 days. -
Question 38 of 50
38. Question
A two-digit number is such that the product of the digits is 8. When 18 is added to the number, then the digits are reversed. The number is:
Correct
Let the ten’s and unit’s digit be x and 8/x respectively.
Then,
(10x + 8/x) + 18 = 10 * 8/x + x
9x2 + 18x – 72 = 0
x2 + 2x – 8 = 0
(x + 4)(x – 2) = 0
x = 2
So, ten’s digit = 2 and unit’s digit = 4.
Hence, required number = 24.Incorrect
Let the ten’s and unit’s digit be x and 8/x respectively.
Then,
(10x + 8/x) + 18 = 10 * 8/x + x
9x2 + 18x – 72 = 0
x2 + 2x – 8 = 0
(x + 4)(x – 2) = 0
x = 2
So, ten’s digit = 2 and unit’s digit = 4.
Hence, required number = 24. -
Question 39 of 50
39. Question
Rajan got married 8 years ago. His present age is 6/5 times his age at the time of his marriage. Rajan’s sister was 10 years younger to him at the time of his marriage. The age of Rajan’s sister is:
Correct
Let Rajan’s present age be x years.
Then, his age at the time of marriage = (x – 8) years.
x = 6/5 (x – 8)
5x = 6x – 48 => x = 48
Rajan’s sister’s age at the time of his marriage = (x – 8) – 10 = 30 years.
Rajan’s sister’s present age = (30 + 8) = 38 years.Incorrect
Let Rajan’s present age be x years.
Then, his age at the time of marriage = (x – 8) years.
x = 6/5 (x – 8)
5x = 6x – 48 => x = 48
Rajan’s sister’s age at the time of his marriage = (x – 8) – 10 = 30 years.
Rajan’s sister’s present age = (30 + 8) = 38 years. -
Question 40 of 50
40. Question
The least number which when diminished by 7 is divisible by 21, 28, 36 and 45 is?
Correct
LCM = 1260
1260 + 7 = 1267Incorrect
LCM = 1260
1260 + 7 = 1267 -
Question 41 of 50
41. Question
By selling an article at Rs.800, a shopkeeper makes a profit of 25%. At what price should he sell the article so as to make a loss of 25%?
Correct
SP = 800
Profit = 25%
CP = (SP)*[100/(100+P)]
= 800 * [100/125]
= 640
Loss = 25% = 25% of 640 = Rs.160
SP = CP – Loss = 640 – 160 = Rs.480Incorrect
SP = 800
Profit = 25%
CP = (SP)*[100/(100+P)]
= 800 * [100/125]
= 640
Loss = 25% = 25% of 640 = Rs.160
SP = CP – Loss = 640 – 160 = Rs.480 -
Question 42 of 50
42. Question
Anil can do a work in 15 days while Sunil can do it in 25 days. How long will they take if both work together?
Correct
1/15 + 1/25 = 8/75
75/8 = 9 3/8 daysIncorrect
1/15 + 1/25 = 8/75
75/8 = 9 3/8 days -
Question 43 of 50
43. Question
If x;Y = 5:2, then (8x + 9y):(8x + 2y) is :
Correct
Let x = 5k and y = 2k.
Then, (8x + 9y)/(8x + 2y)
= [(8 * 5k) + (9 * 2k)] / [(8 * 5k) + (2 * 2k)] = 58k/44k = 29/22
(8x + 9y):(8x + 2y) = 29:22Incorrect
Let x = 5k and y = 2k.
Then, (8x + 9y)/(8x + 2y)
= [(8 * 5k) + (9 * 2k)] / [(8 * 5k) + (2 * 2k)] = 58k/44k = 29/22
(8x + 9y):(8x + 2y) = 29:22 -
Question 44 of 50
44. Question
All the water in container A which was filled to its brim was poured into two containers B and C. The quantity of water in container B was 62.5% less than the capacity of container A. If 148 liters was now transferred from C to B, then both the containers would have equal quantities of water. What was the initial quantity of water in container A?
Correct
B has 62.5% or (5/8) of the water in A. Therefore, let the quantity of water in container A(initially) be 8k.
Quantity of water in B = 8k – 5k = 3k.
Quantity of water in container C = 8k – 3k = 5k
Container: A B C
Quantity of water: 8k 3k 5k
It is given that if 148 liters was transferred from container C to container B, then both the containers would have equal quantities of water.
5k – 148 = 3k + 148 => 2k = 296 => k = 148
The initial quantity of water in A = 8k = 8 * 148 = 1184 liters.Incorrect
B has 62.5% or (5/8) of the water in A. Therefore, let the quantity of water in container A(initially) be 8k.
Quantity of water in B = 8k – 5k = 3k.
Quantity of water in container C = 8k – 3k = 5k
Container: A B C
Quantity of water: 8k 3k 5k
It is given that if 148 liters was transferred from container C to container B, then both the containers would have equal quantities of water.
5k – 148 = 3k + 148 => 2k = 296 => k = 148
The initial quantity of water in A = 8k = 8 * 148 = 1184 liters. -
Question 45 of 50
45. Question
A bank offers 5% C.I. calculated on half-yearly basis . A customer deposits Rs. 1600 each on 1st January and 1st July of a year. At the end of the year, the amount he would have gained by way of interest is?
Correct
Amount = [1600 * (1 + 5/(2 * 100)2 + 1600 * (1 + 5/(2 * 100)]
= [1600 * 41/40(41/40 + 1)
= [(1600 * 41 * 81)/(40 * 40)] = Rs. 3321.
C.I. = 3321 – 3200 = Rs. 121.Incorrect
Amount = [1600 * (1 + 5/(2 * 100)2 + 1600 * (1 + 5/(2 * 100)]
= [1600 * 41/40(41/40 + 1)
= [(1600 * 41 * 81)/(40 * 40)] = Rs. 3321.
C.I. = 3321 – 3200 = Rs. 121. -
Question 46 of 50
46. Question
150 men consume 1050 kg of rice in 30 days. In how many days will 70 men consume 980 kg of rice?
Correct
Rate of consumption of each man = 1050/(150 * 30) = 7/30 kg/day
Let us say 70 men take x days to consume 150 kg.
Quantity consumed by each item in x days = (7x/30) kg
Quantity consumed by 70 men in x days = (7/30 x)(70) kg
= (7/30 x) * (70) = 960
x = 60 days.Incorrect
Rate of consumption of each man = 1050/(150 * 30) = 7/30 kg/day
Let us say 70 men take x days to consume 150 kg.
Quantity consumed by each item in x days = (7x/30) kg
Quantity consumed by 70 men in x days = (7/30 x)(70) kg
= (7/30 x) * (70) = 960
x = 60 days. -
Question 47 of 50
47. Question
A shopkeeper sold an article offering a discount of 5% and earned a profit of 23.5%. What would have been the percentage of profit earned if no discount was offered?
Correct
Let C.P. be Rs. 100.
Then, S.P. = Rs. 123.50
Let marked price be Rs. x. Then, 95/100 x = 123.50
x = 12350/95 = Rs. 130
Now, S.P. = Rs. 130, C.P. = Rs. 100
Profit % = 30%.Incorrect
Let C.P. be Rs. 100.
Then, S.P. = Rs. 123.50
Let marked price be Rs. x. Then, 95/100 x = 123.50
x = 12350/95 = Rs. 130
Now, S.P. = Rs. 130, C.P. = Rs. 100
Profit % = 30%. -
Question 48 of 50
48. Question
A mixture of 150 liters of wine and water contains 20% water. How much more water should be added so that water becomes 25% of the new mixture?
Correct
Number of liters of water in150 liters of the mixture = 20% of 150 = 20/100 * 150 = 30 liters.
P liters of water added to the mixture to make water 25% of the new mixture.
Total amount of water becomes (30 + P) and total volume of mixture is (150 + P).
(30 + P) = 25/100 * (150 + P)
120 + 4P = 150 + P => P = 10 liters.Incorrect
Number of liters of water in150 liters of the mixture = 20% of 150 = 20/100 * 150 = 30 liters.
P liters of water added to the mixture to make water 25% of the new mixture.
Total amount of water becomes (30 + P) and total volume of mixture is (150 + P).
(30 + P) = 25/100 * (150 + P)
120 + 4P = 150 + P => P = 10 liters. -
Question 49 of 50
49. Question
A train 125 m long passes a man, running at 5 km/hr in the same direction in which the train is going, in 10 seconds. The speed of the train is:
Correct
Speed of the train relative to man = (125/10) m/sec = (25/2) m/sec. [(25/2) * (18/5)] km/hr = 45 km/hr. Let the speed of the train be x km/hr. Then, relative speed = (x – 5) km/hr. x – 5 = 45 ==> x = 50 km/hr.
Incorrect
Speed of the train relative to man = (125/10) m/sec = (25/2) m/sec. [(25/2) * (18/5)] km/hr = 45 km/hr. Let the speed of the train be x km/hr. Then, relative speed = (x – 5) km/hr. x – 5 = 45 ==> x = 50 km/hr.
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Question 50 of 50
50. Question
X and Y started a business with capitals Rs. 20000 and Rs. 25000. After few months Z joined them with a capital of Rs. 30000. If the share of Z in the annual profit of Rs. 50000 is Rs. 14000, then after how many months from the beginning did Z join?
Correct
Investments of X, Y and Z respectively are Rs. 20000, Rs. 25000 and Rs. 30000
Let investment period of Z be x months.
Ratio of annual investments of X, Y and Z is (20000 * 12) : (25000 * 12) : (30000 * x)
= 240 : 300 : 30x = 8 : 10 : x
The share of Z in the annual profit of Rs. 50000 is Rs. 14000.
=> [x/ (18 + x)] 50000 = 14000 => [x/ (18 + x)] 25 = 7
=> 25x = 7x + (18 * 7) => x = 7 months.
Z joined the business after (12 – 7) months. i.e., 5 months.Incorrect
Investments of X, Y and Z respectively are Rs. 20000, Rs. 25000 and Rs. 30000
Let investment period of Z be x months.
Ratio of annual investments of X, Y and Z is (20000 * 12) : (25000 * 12) : (30000 * x)
= 240 : 300 : 30x = 8 : 10 : x
The share of Z in the annual profit of Rs. 50000 is Rs. 14000.
=> [x/ (18 + x)] 50000 = 14000 => [x/ (18 + x)] 25 = 7
=> 25x = 7x + (18 * 7) => x = 7 months.
Z joined the business after (12 – 7) months. i.e., 5 months.