RRB ALP Online Test Series 2, RRB ALP Mock Test, RRB Quiz Series 2

1/20 + 1/30 – 1/40 = 7/120
120/7 = 17 1/7

Let us say the ratio of the quantities of cheaper and dearer varieties = x : y
By the rule of allegation, x/y = (87.5 – 7.50) / (7.50 – 6) = 5/6

D = 100 + 150 = 250
S = 36 * 5/18 = 10 mps
T = 250/10 = 25 sec

Speed = 72 * 5/18 = 20 m/sec
Total distance covered = 110 + 132 = 242 m.
Required time = 242/20 = 12.1 sec.

They are moving in opposite directions, relative speed is equal to the sum of their speeds.
Relative speed = (54 + 72)*5/18 = 7*5 = 35 mps.
The time required = d/s = 100/35 = 20/7 sec.

Let the price of the article, four years age be Rs. 100 in the 1st year, price of the article = 100 + 30 = Rs. 130. In the 2nd year, price = 130 – 20% of 130 = 130 – 26 = Rs. 104.
In the 3rd year, price = 104 + 10% of 104 = 104 + 10.4 = Rs. 114.40.
But present price of the article is Rs. 2288
for 114.4 —> 100 ; 2288 —> ?
Required price = (2288 * 100)/114.4 = 20 * 100 = Rs. 2000.

Aman : Rakhi : Sagar = (70000 * 36) : (105000 * 30) : (140000 * 24)
= 12:15:16

One day’s work of A and B = 1/9 + 1/8 = (2+1)/18 = 1/6 So, the time taken to complete the work is 6 days.

Let C.P. of each article be Re. 1.
Then, C.P. of 50 articles = Rs. 50;
S.P. of 50 articles = Rs. 40.
Loss % = 10/50 * 100 = 20%

Let the present ages of X and Y be 5x and 6x years respectively.
Then, (5x + 7)/(6x + 7) = 6/7
7(5x + 7) = 6(6x + 7) => x = 7
X’s present age = 5x = 35 years.

x/18 + 12/24 = 1
x = 9

20 * 10 * 5 = 1000

S.I. = (1200 * 10 * 1)/100 = Rs. 120
C.I. = [1200 * (1 + 5/100)2 – 1200] = Rs. 123 Difference = (123 – 120) = Rs. 3.

Speed = 78 * 5/18 = 65/3 m/sec.
Time = 1 min = 60 sec.
Let the length of the train be x meters.
Then, (800 + x)/60 = 65/3
x = 500 m.

Ratio of their shares = 22500 : 35000 = 9:14
Deepak’s share = 13800 * 14/23 = Rs. 8400.

C.I. when interest is compounded yearly
= [5000 * (1 + 4/100) * (1 + (1/2 * 4)/100]
= 5000 * 26/25 * 51/50 = Rs. 5304
C.I. when interest is compounded half-yearly
= [5000 * (1 + 2/100)2]
= (5000 * 51/50 * 51/50 * 51/50) = Rs. 5306.04 Difference = (5306.04 – 5304) = Rs. 2.04.

Let the sum lent to C be Rs. x. Then,
(2500 * 7 * 4) / 100 + (x * 7 * 4) / 100 = 1120
7/25 x = (1120 – 700) => x = 1500

Let the number be x. Then,

A = 5000(51/50)³
= 5306.04
5000
———–
306.04

2c = ¼ + 1/6 – 1/3 = 1/12
c = 1/24 => 24 days

(A + B + C)’s 1 day work = 1/6;

We can initially arrange the six boys in 6! ways.
Having done this, now three are seven places and six girls to be arranged. This can be done in ⁷P₆ ways.
Hence required number of ways = 6! * ⁷P₆

x² + 5x – 3x – 15 = 0
x(x + 5) – 3(x + 5) = 0
(x – 3)(x + 5) = 0
=> x = 3 or x = -5.

SP per metre = 18000/400 = Rs. 45 Loss per metre = Rs. 5 CP per metre = 45 + 5 = Rs. 50

60(x + 1) = 64x
X = 15
60 * 16 = 960 km

Let the present ages of Giri and Hari be 5x and 8x years respectively.
(5x + 12) / (8x + 12) = 11/14
70x + 168 = 88x + 132 => x= 2
Difference in their ages will be the same at all times.
This difference = Difference of their present ages
= 8x – 5x = 3x = 6 years.

LCM = 180
180) 10000 (55
9900
———
100
10000 + 180 – 100 = 10080

A:B:C = 5:6:4
Let the total profit = 100 – 30 = 70
5/15 * 70 = 70/3
A share = 70/3 + 30 = 160/3
B + C share = 100 – 160/3 = 140/3
A-(B+C) = 160/3 – 140/3 = 20/3
20/3 —- 200
100 —- ? => 3000

?² = 3/7 * 4/9 * 2/5 * 7560

4⁵⁰ = (2²)⁵⁰ = 2¹⁰⁰ => 16²⁵ = (2⁴)²⁵ = 2¹⁰⁰

Let the total amount be Rs. p.
Let shares of A and B be Rs. x and Rs. y respectively.
C’s share was Rs. 14
we have, x + y + 14 = p —– (1)
From the given data, x = (p/2) – 4 —– (2)
Remaining amount = p – (p/2 – 4) => p/2 + 4.
y = 1/2(p/2 + 4) + 8 => p/4 + 10 —– (3)
From (1), (2) and (3)
p/2 – 4 + p/4 + 10 + 14 = p
3p/4 + 20 = p
p/4 = 20 => p = Rs. 80.

Speed = 45 * 5/18 = 25/2 m/sec
Total distance covered = 360 + 140 = 500 m
Required time = 500 * 2/25 = 40 sec

Let the quantities of A and B mixed be 3x kg and 7x kg.
Cost of 3x kg of A = 9(3x) = Rs. 27x
Cost of 7x kg of B = 15(7x) = Rs. 105x
Cost of 10x kg of the mixture = 27x + 105x = Rs. 132x
Cost of 5 kg of the mixture = 132x/10x (5) = Rs. 66
Profit made in selling 5 kg of the mixture = 25/100 (cost of 5 kg of the mixture) = 25/100 * 66 = Rs. 16.50

Kim’s wages : David’s wages = Kim’s 1 day work : David’s 1 day work = 1/3 : 1/2 = 2:3
Kim’s share = 2/5 * 150 = Rs. 60

40*(40/100) = 16 — 64
? — 12 => Rs.3

Given Exp. = 35 + 15 * 3/2
= 35 + 45/2 = 35 + 22.5 = 57.5

Amount = [25000 * (1 + 12/100)³]

Let the present ages of Mahesh, Nilesh and Ramesh be m, n and r respectively.
m/n = 5/x —— (1)
m = r – 18 —— (2)
r + 9 = 47 —— (3)
m – n = r —– (4)
(3) => r = 47 – 9 = 38 years
(2) => m = 38 -18 = 20 years
(1) => 20/n = 5/x => n = 4x
(4) => 4x – 20 = 38
=> 4x = 58 => x = 14.5

Work done by P alone in one day = 1/6th of the total work done by Q alone in one day = 1/3(of that done by P in one day) = 1/3(1/6 of the total) = 1/18 of the total.
Work done by P and Q, working together in one day = 1/6 + 1/18 = 4/18 = 2/9 of the total
They would take 9/2 days = 4 (1/2) days to complete the work working together.

C.P. of 1 toy = 375/12 = Rs. 31.25
S.P of 1 toy = Rs. 33
Profit = 1.75/31.25 * 100 = 28/5 = 5.6%

45 * 5/18 = 10
25:20 => 5:4

Since the difference between the divisors and the respective remainders is not constant, back substitution is the convenient method. None of the given numbers is satisfying the condition.

Let A worked for x days.
x/21 + 4/28 = 1 => x/21 = 6/7 => x = 18
A worked for 18 days. So, A can complete the remaining work in 18 – 4 = 14 days.

Rate of consumption of each man = 1050/(150 * 30) = 7/30 kg/day
Let us say 70 men take x days to consume 150 kg.
Quantity consumed by each item in x days = 7x/30 kg.
Quantity consumed by 70 men in x days = (7x/30)(70)kg
(7x/30)(70) = 980
x = (980 * 30)/490 => x = 60 days

d = 3d d = d
a√2 = 3d a√2 = d
a = 3d/√2 a = d/√2 => 3: 1

a : b = 4 : 1
a/b = 4/1 => a = 4b
(a – 3b)/(2a – b) = (4b – 3b)/[2(4b) – b]
= b/(8b – b) = b/7b => 1/7

x * 1/3 * 3/4 =21 => x = 84