RRB JE Mock Test series 2, RRB JE Online Test in English Series 2

200 + 130 = 330
800 – 330 = 470
200 —- 5000
470 —- ? => 11750

S.I. = (15500 – 12500) = Rs. 3000\
Rate = (100 * 3000) / (12500 * 4) = 6%

Speed = 45 * 5/18 = 25/2 m/sec
Total distance covered = 360 + 140 = 500 m
Required time = 500 * 2/25 = 40 sec

0.003 * ? * 0.0003 = 0.00000027
3/1000 * ? * 3/10000 = 3/1000 * 3/1000 * 3/100
? = 3/10 = 0.3

Ratio of their shares = 22500 : 35000 = 9:14
Deepak’s share = 13800 * 14/23 = Rs. 8400.

LCM = 180
180) 10000 (55
9900
———
100
10000 + 180 – 100 = 10080

Let the number be x. Then,
1/3 of 1/4 of x = 15
x = 15 * 12 = 180
So, required number = (3/10 * 180) = 54.

LCM = 48 + 3 = 51

Speed of the first train = 120/10 = 12 m/sec.
Speed of the second train = 120/5 = 8 m/sec.
Relative speed = 12 + 8 = 20 m/sec.
Required time = (120 + 120)/20 = 12 sec.

a³ : a³/8 * 4/3 π => 6: π

70 * (10/100) = 7
Wine Water
87 1/2% 12 1/2%
87 1/2% ——- 63
12 1/2% ——-? => 9-7=2

Let P, Q and R represent their respective monthly incomes. Then, we have:
P + Q = (5050 * 2) = 10100 — (i)
Q + R = (6250 * 2) = 12500 — (ii)
P + R = (5200 * 2) = 10400 — (iii)
Adding (i), (ii) and (iii), we get:
2(P + Q + R) = 33000 = P + Q + R = 16500 — (iv)
Subtracting (ii) from (iv), we get, P = 4000.
P’s monthly income = Rs. 4000.

Cost price = Rs.500
profit = 20% of 500 = Rs.100
Selling price = Cost price + Profit
= 500 + 100 = 600

S = 4
M = x
DS = x + 4
US = x – 4
6/(x + 4) + 6/(x – 4) = 2
x = 8

2: 5: 13
2x                  5x           13x
15                  7.5          2.5
30x + 37.5x + 32.5x = 100x/20x
Average = 5

100/7 = 14 2/7 => 14 Numbers

Let B = 100
A = 50
C * (150/100) = 50
3C = 100
C = 33.3 then ‘C’ Cheapest

Let the greater and the smaller number be g and s respectively.
gs = 2560
g + s exceeds g – s by 64 i.e., g + s – (g – s) = 64
i.e., 2s = 64 => s = 32.
g = 2560/s = 80.

Since A and B move in the same direction along the circle, so they will first meet each other when there is a difference of one round between the two.
Relative speed of A and B = 6 – 1 = 5 rounds per hour.
Time taken to complete one round at this speed = 1/5 hr = 12 min.

r₁: r₂ = 1: 3
Πr₁²: Πr₂²
r₁²: r₂² = 1: 9

They should share the profits in the ratio of their investments.
The ratio of the investments made by A and B =
6000 : 8000 => 3:4

105 – 57 = 48
57 – 25 = 32
105 – 25 = 80
The H.C.F of 32, 48 and 80 is 16.

Let the amount lent out at 8% p.a. be Rs. A
=> (A * 8)/100 + [(10000 – A) * 10]/100 = 890
=> A = Rs. 5500.

Suppose A, B and C take x, x/2 and x/3 respectively to finish the work.
Then, (1/x + 2/x + 3/x) = 1/2
6/x = 1/2 => x = 12
So, B takes 6 hours to finish the work.

Let the sides of the rectangle be l and b respectively.
From the given data,
(√l² + b²) = (1 + 108 1/3 %)lb
=> l² + b² = (1 + 325/3 * 1/100)lb
= (1 + 13/12)lb
= 25/12 lb
=> (l² + b²)/lb = 25/12
12(l² + b²) = 25lb
Adding 24lb on both sides
12l² + 12b² + 24lb = 49lb
12(l² + b² + 2lb) = 49lb
but 2(l + b) = 28 => l + b = 14
12(l + b)² = 49lb
=> 12(14)² = 49lb
=> lb = 48
Since l + b = 14, l = 8 and b = 6
l – b = 8 – 6 = 2m.

10% of x = 20% of y
10x/100 = 20y/100 => x/10 = y/5
x/y = 10/5 = 2/1
x:y = 2:1.

T = (121 + 165)/ (80 + 65) * 18/5
T = 7.15

Let the roots of the equation 2a and 3a respectively.
2a + 3a = 5a = -(- 5/2) = 5/2 => a = 1/2
Product of the roots: 6a2 = b/2 => b = 12a2
a = 1/2, b = 3.

36 * 48 / 64 + 36/12 = 27 + 3 = 30

Drawing two balls of same color from seven green balls can be done in ⁷C₂ ways.
Similarly from eight white balls two can be drawn in ⁸C₂ ways.
P = ⁷C₂/¹⁵C₂ + ⁸C₂/¹⁵C₂ = 7/15

1/2 * 15 * 20 = 150

5% – 2% = 3%
3% —- 5
100% —- ? => 166 2/3

Let the sum be Rs. x.
(x * 18 * 2)/100 – (x * 12 * 2)/100 = 840 => 36x/100 – 24x/100 =840
=> 12x/100 = 840 => x = 7000.

We need to know the S.I., principal and time to find the rate. Since the principal is not given, so data is inadequate.

They are moving in opposite directions, relative speed is equal to the sum of their speeds.
Relative speed = (54 + 72)*5/18 = 7*5 = 35 mps.
The time required = d/s = 100/35 = 20/7 sec.

[(3.572)³ + (2.428)³] / [(3.572)² – (3.572) * (2.428) + (2.428)²]
= {(3.572)² – (3.572) * (2.428) + (2.428)²}{3.752 + 2.428} / [(3.572)² – (3.572) * (2.428) + (2.428)²]
= 3.752 + 2.428 = 6

Let the two consecutive positive integers be x and x + 1
x² + (x + 1)² – x(x + 1) = 91
x² + x – 90 = 0
(x + 10)(x – 9) = 0 => x = -10 or 9.
As x is positive x = 9
Hence the two consecutive positive integers are 9 and 10.

RS = 40 – 22 = 18 * 5/18 = 5 mps
T = 60 sec
D = 5 * 60 = 300 m
125
——–
175 m

Volume of the wire (in Cylindrical shape) is equal to the volume of the sphere.
π(16)² * h = (4/3)π (12)³ => h = 9 cm

The word contains five consonants. Three vowels, three consonants can be selected from five consonants in ⁵C₃ ways, two vowels can be selected from three vowels in ³C₂ ways.
3 consonants and 2 vowels can be selected in ⁵C₂ . ³C₂ ways i.e., 10 * 3 = 30 ways.

Assume X soldiers join the fort. 1200 soldiers have provision for 1200(days for which provisions last them)(rate of consumption of each soldier)
= 1200(30)(3) kg
Also provisions available for (1200 + x) soldiers is (1200 + x)(25)(2.5) kg
As the same provisions are available
=> 1200(30)(3) = (1200 + x)(25)(2.5)
x = [1200(30)(3)]/[(25)(2.5)] – 1200
x = 528

105 * 99 * 299 = 105 * 100 * 300 = 315000

A’s one day’s work = 1/30
B’s one day’s work = 1/45
(A + B)’s one day’s work = 1/30 + 1/45 = 1/18
The part of the work completed in 3 days = 3 (1/18) = 1/6.

441 = P(21/20)²
P = 400

3²: 4² = 9:16

30 * 25 = 750
425
———–
325
25 + 7.50 = 32.5
325/32.5 = 10

Let CP of an article = RS. 100
MP= Rs. 120
Discount = 20%
SP = M[(100 – d%)/100] = 120(80/100) = Rs. 96
Clearly, the trader gets 4% loss.