## IPPB Mains Online Test Series 5, IPPB Test Series, IPPB Mock Test

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**IPPB Mains Online Test Series 5, IPPB Test Series, IPPB Mock Test**. RRB Exam Online Test 2019, IPPB Mains Free Mock Test Exam 2019. IPPB Mains Exam Free Online Quiz 2019, IPPB Mains Full Online Mock Test **Series 5th** in English. RRB Online Test for All Subjects, IPPB Mains Free Mock Test Series in English. IPPB Mains Free Mock Test **Series 5.** IPPB Mains English Language Online Test in English **Series 5th**. IPPB Mains Quantitative Aptitude Quiz 2019, IPPB Mains Reasoning Ability Free Online Test. Take IPPB Mains Online Quiz. The IPPB Mains Full online mock test paper is free for all students. IPPB Mains Question and Answers in English and Hindi **Series 5**. Here we are providing** IPPB Mains Full Mock Test Paper in English. IPPB Mains **Mock Test **Series 5th** 2019. Now Test your self for IPPB Mains Exam by using below quiz…

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- Question 1 of 50
##### 1. Question

Sushil got thrice as many marks in English as in Science. His total marks in English, Science and Maths are 162. If the ratio of his marks in English and Maths is 3:5, find his marks in Science?

CorrectS:E = 1:3

E:M = 3:5

————

S:E:M = 3:9:15

3/27 * 162 = 18IncorrectS:E = 1:3

E:M = 3:5

————

S:E:M = 3:9:15

3/27 * 162 = 18 - Question 2 of 50
##### 2. Question

From a pack of cards two cards are drawn one after the other, with replacement. The probability that the first is a red card and the second is a king is -.

CorrectLet E

_{1}be the event of drawing a red card.

Let E_{2}be the event of drawing a king .

P(E_{1}∩ E_{2}) = P(E_{1}) . P(E_{2})

(As E_{1}and E_{2}are independent)

= 1/2 * 1/13 = 1/26IncorrectLet E

_{1}be the event of drawing a red card.

Let E_{2}be the event of drawing a king .

P(E_{1}∩ E_{2}) = P(E_{1}) . P(E_{2})

(As E_{1}and E_{2}are independent)

= 1/2 * 1/13 = 1/26 - Question 3 of 50
##### 3. Question

The area of a square field 3136 sq m, if the length of cost of drawing barbed wire 3 m around the field at the rate of Rs.1.50 per meter. Two gates of 1 m width each are to be left for entrance. What is the total cost?

Correcta

^{2}= 3136 => a = 56

56 * 4 * 3 = 672 – 6 = 666 * 1.5 = 999Incorrecta

^{2}= 3136 => a = 56

56 * 4 * 3 = 672 – 6 = 666 * 1.5 = 999 - Question 4 of 50
##### 4. Question

A, B and C start at the same time in the same direction to run around a circular stadium. A completes a round in 252 seconds, B in 308 seconds and C in 198 seconds, all starting at the same point. After what time will they meet again at the starting point?

CorrectL.C.M of 252, 308 and 198 = 2772

So, A, B and C will again meet at the starting point in 2772 sec, i.e., 46 min 12 sec.IncorrectL.C.M of 252, 308 and 198 = 2772

So, A, B and C will again meet at the starting point in 2772 sec, i.e., 46 min 12 sec. - Question 5 of 50
##### 5. Question

There is food for 760 men for 22 days. How many more men should join after two days so that the same food may last for 19 days more?

Correct760 —- 22

760 —- 20

x —– 19

x*19 = 760*20

x = 800

760

——-

40Incorrect760 —- 22

760 —- 20

x —– 19

x*19 = 760*20

x = 800

760

——-

40 - Question 6 of 50
##### 6. Question

If A:B = 2:3, B:C = 4:5 and C:D = 6:7, then A:B:C:D is:

CorrectA:B = 2:3, B:C = 4:5 = (4 * 3/4):(5 * 3/4) = 3:15/4

and C:D = 6:7 = (6 * 15/24):(7 * 15/24) = 15/4:35/8 A:B:C:D = 2:3:15/4:35/8 = 16:24:30:35IncorrectA:B = 2:3, B:C = 4:5 = (4 * 3/4):(5 * 3/4) = 3:15/4

and C:D = 6:7 = (6 * 15/24):(7 * 15/24) = 15/4:35/8 A:B:C:D = 2:3:15/4:35/8 = 16:24:30:35 - Question 7 of 50
##### 7. Question

Ravi can do a piece of work in 30 days while Prakash can do it in 40 days. In how many days will they finish it together?

Correct1/30 + 1/40 = 7/120

120/7 = 17 1/7 daysIncorrect1/30 + 1/40 = 7/120

120/7 = 17 1/7 days - Question 8 of 50
##### 8. Question

The average height of 35 boys in a class was calculated as 180cm. It has later found that the height of one of the boys in the class was wrongly written as 166 cm whereas his actual height was 106 cm. Find the actual average height of the boys in the class (Round off your answer to two decimal places).

CorrectCalculated average height of 35 boys = 180 cm.

Wrong total height of 35 boys = 180 * 35 cm. This was as a result of an actual height of 106 cm being wrongly written as 166 cm. Correct total height of 35 boys = 180 * 35 cm – 166 cm + 106 cm

= 180 * 35 cm – 166 cm + 106 cm/35 = 180 cm – 60 /35 cm

= 180 cm – 1.71 cm = 178.29 cm.IncorrectCalculated average height of 35 boys = 180 cm.

Wrong total height of 35 boys = 180 * 35 cm. This was as a result of an actual height of 106 cm being wrongly written as 166 cm. Correct total height of 35 boys = 180 * 35 cm – 166 cm + 106 cm

= 180 * 35 cm – 166 cm + 106 cm/35 = 180 cm – 60 /35 cm

= 180 cm – 1.71 cm = 178.29 cm. - Question 9 of 50
##### 9. Question

A certain sum of money doubles itself in 10 years in how much many years will it trible itself at the same rate?

Correct100 —- 100 — 10

100 — 10

——————–

300 —- 20 yearsIncorrect100 —- 100 — 10

100 — 10

——————–

300 —- 20 years - Question 10 of 50
##### 10. Question

Find the amount on Rs.8000 in 9 months at 20% per annum, if the interest being compounded quarterly?

CorrectA = 8000(21/20)

^{3}= 9261IncorrectA = 8000(21/20)

^{3}= 9261 - Question 11 of 50
##### 11. Question

A can do half the work in one day where as B can do it full. B can also do half the work of C in one day. Ratio in their efficiency will be?

CorrectWC of A: B = 1:2

B: C = 1:2

———————

A: B: C = 1:2:4IncorrectWC of A: B = 1:2

B: C = 1:2

———————

A: B: C = 1:2:4 - Question 12 of 50
##### 12. Question

If Rs. 782 be divided into three parts, proportional to 1/2:2/3:3/4, then the first part is:

CorrectGiven ratio = 1/2:2/3:3/4 = 6:8:9

1st part = 782 * 6/23 = Rs. 204.IncorrectGiven ratio = 1/2:2/3:3/4 = 6:8:9

1st part = 782 * 6/23 = Rs. 204. - Question 13 of 50
##### 13. Question

A, B and C enter into a partnership. They invest Rs. 40,000, Rs. 80,000 and Rs. 1,20,000 respectively. At the end of the first year, B withdraws Rs. 40,000, while at the end of the second year, C withdraws Rs. 80,000. IN what ratio will the profit be shared at the end of 3 years?

CorrectA:B:C = (40000 * 36) : (80000 * 12 + 40000 * 24) : (120000 * 24 + 40000 * 12)

= 144:192:336 = 3:4:7IncorrectA:B:C = (40000 * 36) : (80000 * 12 + 40000 * 24) : (120000 * 24 + 40000 * 12)

= 144:192:336 = 3:4:7 - Question 14 of 50
##### 14. Question

22004 – 29303 + 101299 – 59532 = ?

Correct22004 – 29303 + 101299 – 59532

123303 – 888.35 = 34468 = 34500Incorrect22004 – 29303 + 101299 – 59532

123303 – 888.35 = 34468 = 34500 - Question 15 of 50
##### 15. Question

The average of 11 numbers is 10.9. If the average of first six is 10.5 and that of the last six is 11.4 the sixth number is?

Correct1 to 11 = 11 * 10.9 = 119.9

1 to 6 = 6 * 10.5 = 63

6 to 11 = 6 * 11.4 = 68.4

63 + 68.4 = 131.4 – 119.9 = 11.5

6^{th}number = 11.5Incorrect1 to 11 = 11 * 10.9 = 119.9

1 to 6 = 6 * 10.5 = 63

6 to 11 = 6 * 11.4 = 68.4

63 + 68.4 = 131.4 – 119.9 = 11.5

6^{th}number = 11.5 - Question 16 of 50
##### 16. Question

The ratio of the number of boys and girls in a college is 7:8. If the percentage increase in the number of boys and girls be 20% and 10% respectively. What will be the new ratio?

CorrectOriginally, let the number of boys and girls in the college be 7x and 8x respectively.

Their increased number is (120% of 7x) and (110% of 8x).

i.e., (120/100 * 7x) and (110/100 * 8x)

i.e., 42x/5 and 44x/5

Required ratio = 42x/5 : 44x/5 = 21:22IncorrectOriginally, let the number of boys and girls in the college be 7x and 8x respectively.

Their increased number is (120% of 7x) and (110% of 8x).

i.e., (120/100 * 7x) and (110/100 * 8x)

i.e., 42x/5 and 44x/5

Required ratio = 42x/5 : 44x/5 = 21:22 - Question 17 of 50
##### 17. Question

The greatest number of five digits which is divisible by 32, 36, 40, 42 and 48 is:

CorrectLCM = 10080

10080) 99999 (8

90720

———

9279

99999 – 9279 = 90720IncorrectLCM = 10080

10080) 99999 (8

90720

———

9279

99999 – 9279 = 90720 - Question 18 of 50
##### 18. Question

If 30% of a number exceeds 20% of it by 18, then find the number?

CorrectLet the number be x.

30% of x = 30/100 * x = 3x/10

20% of x = 20/100 * x = x/5 = 2x/10.

Given that 3x/10 – 2x/10 = 18 => x = 180.

Required number is 180.IncorrectLet the number be x.

30% of x = 30/100 * x = 3x/10

20% of x = 20/100 * x = x/5 = 2x/10.

Given that 3x/10 – 2x/10 = 18 => x = 180.

Required number is 180. - Question 19 of 50
##### 19. Question

The ratio of two natural numbers is 5:6. If a certain number is added to both the numbers, the ratio becomes 7:8. If the larger number exceeds the smaller number by 10, find the number added?

CorrectLet the two numbers be 5x and 6x.

Let the number added to both so that their ratio becomes 7:8 be k.

(5x + k)/(6x + k) = 7/8

42x = 7k => k = 2x.

6x – 5x = 10 => x = 10

k = 2x = 20.IncorrectLet the two numbers be 5x and 6x.

Let the number added to both so that their ratio becomes 7:8 be k.

(5x + k)/(6x + k) = 7/8

42x = 7k => k = 2x.

6x – 5x = 10 => x = 10

k = 2x = 20. - Question 20 of 50
##### 20. Question

25% of 30% of 45% is equal to?

Correct(25/100) * (30/100) * (45/100)

1/4 * 3/10 * 9/20

27/800 = 0.03375Incorrect(25/100) * (30/100) * (45/100)

1/4 * 3/10 * 9/20

27/800 = 0.03375 - Question 21 of 50
##### 21. Question

A train of 24 carriages, each of 60 meters length, when an engine also of 60 meters length is running at a speed of 60 kmph. In what time will the train cross a bridge 1.5 km long?

CorrectD = 25 * 60 + 1500 = 3000 m

T = 3000/60 * 18/5 = 180 sec = 3 minsIncorrectD = 25 * 60 + 1500 = 3000 m

T = 3000/60 * 18/5 = 180 sec = 3 mins - Question 22 of 50
##### 22. Question

A alone can do a piece of work in 6 days and B alone in 8 days. A and B undertook to do it for Rs. 3200. With the help of C, they completed the work in 3 days. How much is to be paid to C?

CorrectC’s 1 day’s work = 1/3 – (1/6 + 1/8) = 1/3 – 7/24 = 1/24

A’s wages : B’s wages : C’s wages

1/6 : 1/8 : 1/24 = 4:3:1

C’s share = 1/8 * 3200 = Rs. 400IncorrectC’s 1 day’s work = 1/3 – (1/6 + 1/8) = 1/3 – 7/24 = 1/24

A’s wages : B’s wages : C’s wages

1/6 : 1/8 : 1/24 = 4:3:1

C’s share = 1/8 * 3200 = Rs. 400 - Question 23 of 50
##### 23. Question

Find the compound interest accrued on an amount of Rs.14,800 at 13.5% p.a at the end of two years. (Round off your answer to nearest integer)

CorrectCI = 14800{ [ 1 + 13.5/100]

^{2}– 1 }

= 14800 { [1 + 27/200]^{2}– 1

= 14800 { 2 + 27/200}{27/200}

= (74)[2 + 27/200](27) =

1998[2 + 27/200] = 3996 + 269.73 = Rs. 4266IncorrectCI = 14800{ [ 1 + 13.5/100]

^{2}– 1 }

= 14800 { [1 + 27/200]^{2}– 1

= 14800 { 2 + 27/200}{27/200}

= (74)[2 + 27/200](27) =

1998[2 + 27/200] = 3996 + 269.73 = Rs. 4266 - Question 24 of 50
##### 24. Question

10 men and 15 women together can complete a work in 6 days. It takes 100 days for one man alone to complete the same work. How many days will be required for one woman alone to complete the same work?

Correct1 man’s 1 day work = 1/100

(10 men + 15 women)’s 1 day work = 1/6

15 women’s 1 day work = (1/6 – 10/100) = 1/15

1 woman’s 1 day work = 1/225

1 woman alone can complete the work in 225 days.Incorrect1 man’s 1 day work = 1/100

(10 men + 15 women)’s 1 day work = 1/6

15 women’s 1 day work = (1/6 – 10/100) = 1/15

1 woman’s 1 day work = 1/225

1 woman alone can complete the work in 225 days. - Question 25 of 50
##### 25. Question

The sides of a cube are in the ratio 1:2 the ratio of their volume is?

CorrectIncorrect - Question 26 of 50
##### 26. Question

A rectangular farm has to be fenced one long side, one short side and the diagonal. If the cost of fencing is Rs.10 per meter. The area of farm is 1200 m2 and the short side is 30 m long. How much would the job cost?

Correctl * 30 = 1200 → l = 40

40 + 30 + 50 = 120

120 * 10 = 1200Incorrectl * 30 = 1200 → l = 40

40 + 30 + 50 = 120

120 * 10 = 1200 - Question 27 of 50
##### 27. Question

A is 30% more efficient than B. How much time will they, working together, take to complete a job which A alone could have done in 23 days?

CorrectRatio of times taken by A and B = 100:130 = 10:13

Suppose B takes x days to do the work.

x = (23 * 13)/10 = 299/10

A’s 1 day work = 1/23; B’s 1 day work = 10/299

(A + B)’s 1 day work = (1/23 + 10/299) = 1/13

A and B together can complete the job in 13 days.IncorrectRatio of times taken by A and B = 100:130 = 10:13

Suppose B takes x days to do the work.

x = (23 * 13)/10 = 299/10

A’s 1 day work = 1/23; B’s 1 day work = 10/299

(A + B)’s 1 day work = (1/23 + 10/299) = 1/13

A and B together can complete the job in 13 days. - Question 28 of 50
##### 28. Question

Find the one which does not belong to that group ?

CorrectTiruvanantapuram, Hyderabad, Bangalore and Bhubaneswar are state capitals, while Calicut is not a state capital.

IncorrectTiruvanantapuram, Hyderabad, Bangalore and Bhubaneswar are state capitals, while Calicut is not a state capital.

- Question 29 of 50
##### 29. Question

Find the one which does not belong to that group ?

Correct41, 43, 47 and 53 are prime numbers, but not 57.

Incorrect41, 43, 47 and 53 are prime numbers, but not 57.

- Question 30 of 50
##### 30. Question

Ram sold two bicycles, each for Rs.990. If he made 10% profit on the first and 10% loss on the second, what is the total cost of both bicycles?

Correct(10*10)/100 = 1%loss

100 — 99

? — 1980 => Rs.2000Incorrect(10*10)/100 = 1%loss

100 — 99

? — 1980 => Rs.2000 - Question 31 of 50
##### 31. Question

Anita, Indu and Geeta can do a piece of work in 18 days, 27 days and 36 days respectively. They start working together. After working for 4 days. Anita goes away and Indu leaves 7 days before the work is finished. Only Geeta remains at work from beginning to end. In how many days was the whole work done?

Correct4/18 + (x -7)/27 + x/36 = 1

x = 16 daysIncorrect4/18 + (x -7)/27 + x/36 = 1

x = 16 days - Question 32 of 50
##### 32. Question

A dishonest dealer professes to sell his goods at Cost Price but still gets 20% profit by using a false weight. What weight does he substitute for a kilogram?

CorrectIf the cost price is Rs.100, then to get a profit of 20%, the selling price should be Rs.120.

If 120kg are to be sold, and the dealer gives only 100kg, to get a profit of 20%.

How many grams he has to give instead of one kilogram(1000 gm).

120 gm —— 100 gm

1000 gm —— ?

(1000 * 100)/120 = 2500/3 = 833 1/3 grams.IncorrectIf the cost price is Rs.100, then to get a profit of 20%, the selling price should be Rs.120.

If 120kg are to be sold, and the dealer gives only 100kg, to get a profit of 20%.

How many grams he has to give instead of one kilogram(1000 gm).

120 gm —— 100 gm

1000 gm —— ?

(1000 * 100)/120 = 2500/3 = 833 1/3 grams. - Question 33 of 50
##### 33. Question

A cistern is normally filled in 8 hours but takes two hours longer to fill because of a leak in its bottom. If the cistern is full, the leak will empty it in?

Correct1/8 – 1/x = 1/10

x = 40Incorrect1/8 – 1/x = 1/10

x = 40 - Question 34 of 50
##### 34. Question

A thief is noticed by a policeman from a distance of 200 m. The thief starts running and the policeman chases him. The thief and the policeman run at the rate of 10 km and 11 km per hour respectively. What is the distance between them after 6 minutes?

CorrectRelative speed of the thief and policeman = 11 – 10 = 1 km/hr.

Distance covered in 6 minutes = 1/60 * 6 = 1/10 km = 100 m.

Distance between the thief and policeman = 200 – 100 = 100 m.IncorrectRelative speed of the thief and policeman = 11 – 10 = 1 km/hr.

Distance covered in 6 minutes = 1/60 * 6 = 1/10 km = 100 m.

Distance between the thief and policeman = 200 – 100 = 100 m. - Question 35 of 50
##### 35. Question

Pipe A can fill a tank in 16 minutes and pipe B cam empty it in 24 minutes. If both the pipes are opened together after how many minutes should pipe B be closed, so that the tank is filled in 30 minutes?

CorrectLet the pipe B be closed after x minutes.

30/16 – x/24 = 1 => x/24 = 30/16 – 1 = 14/16

=> x = 14/16 * 24 = 21.IncorrectLet the pipe B be closed after x minutes.

30/16 – x/24 = 1 => x/24 = 30/16 – 1 = 14/16

=> x = 14/16 * 24 = 21. - Question 36 of 50
##### 36. Question

In an office, totally there are 6400 employees and 65% of the total employees are males. 25% of the males in the office are at-least 50 years old. Find the number of males aged below 50 years?

CorrectNumber of male employees = 6400 * 65/100 = 4160

Required number of male employees who are less than 50 years old = 4160 * (100 – 25)%

= 4160 * 75/100 = 3120.IncorrectNumber of male employees = 6400 * 65/100 = 4160

Required number of male employees who are less than 50 years old = 4160 * (100 – 25)%

= 4160 * 75/100 = 3120. - Question 37 of 50
##### 37. Question

[(3.572)

^{3}+ (2.428)^{3}] / [(3.572)^{2}– (3.572) * (2.428) + (2.428)^{2}] is equal to -.Correct[(3.572)

^{3}+ (2.428)^{3}] / [(3.572)^{2}– (3.572) * (2.428) + (2.428)^{2}]

= {(3.572)^{2}– (3.572) * (2.428) + (2.428)^{2}}{3.752 + 2.428} / [(3.572)^{2}– (3.572) * (2.428) + (2.428)^{2}]

= 3.752 + 2.428 = 6Incorrect[(3.572)

^{3}+ (2.428)^{3}] / [(3.572)^{2}– (3.572) * (2.428) + (2.428)^{2}]

= {(3.572)^{2}– (3.572) * (2.428) + (2.428)^{2}}{3.752 + 2.428} / [(3.572)^{2}– (3.572) * (2.428) + (2.428)^{2}]

= 3.752 + 2.428 = 6 - Question 38 of 50
##### 38. Question

Two persons A and B can complete a piece of work in 30 days and 45 days respectively. If they work together, what part of the work will be completed in 3 days?

CorrectIncorrect - Question 39 of 50
##### 39. Question

Simplify : 1 – {1 + (a

^{2}– 1)^{-1}}^{-1}Correct1 – {1 + (a

^{2}– 1)^{-1}}^{-1}= 1 – {1 + 1/a^{2}– 1}^{-1}= 1 – {a^{2}/ a^{2}– 1}^{-1}= 1 – (a^{2}– 1)/a^{2}= 1/a^{2}.Incorrect1 – {1 + (a

^{2}– 1)^{-1}}^{-1}= 1 – {1 + 1/a^{2}– 1}^{-1}= 1 – {a^{2}/ a^{2}– 1}^{-1}= 1 – (a^{2}– 1)/a^{2}= 1/a^{2}. - Question 40 of 50
##### 40. Question

40 is subtracted from 60% of a number, the result is 50. Find the number?

Correct(60/100) * X – 40 = 50

6X = 900

X = 150Incorrect(60/100) * X – 40 = 50

6X = 900

X = 150 - Question 41 of 50
##### 41. Question

Rs.160 contained in a box consists of one rupee, 50 paisa and 25 paisa coins in the ratio 4:5:6. What is the number of 25 paisa coins?

Correct4x 5x 6x

100 50 25

400x + 350x + 150x = 16000

x = 20

6x = 120Incorrect4x 5x 6x

100 50 25

400x + 350x + 150x = 16000

x = 20

6x = 120 - Question 42 of 50
##### 42. Question

The sale price of an article including the sales tax is Rs. 616. The rate of sales tax is 10%. If the shopkeeper has made a profit of 12%, then the cost price of the article is:

Correct110% of S.P. = 616

S.P. = (616 * 100)/110 = Rs. 560

C.P = (110 * 560)/112 = Rs. 500Incorrect110% of S.P. = 616

S.P. = (616 * 100)/110 = Rs. 560

C.P = (110 * 560)/112 = Rs. 500 - Question 43 of 50
##### 43. Question

How many meters of carpet 50cm, wide will be required to cover the floor of a room 30m * 20m?

Correct50/100 * x = 30 * 20 => x = 1200

Incorrect50/100 * x = 30 * 20 => x = 1200

- Question 44 of 50
##### 44. Question

The ratio between the school ages of Neelam and Shaan is 5:6 respectively. If the ratio between the one-third age of Neelam and half of Shaan’s age of 5:9, then what is the school age of Shaan?

CorrectLet the school ages of Neelam and Shaan be 5x and 6x years respectively.

Then, (1/3 * 5x)/(1/2 * 6x) = 5/9

15 = 15

Thus, Shaan’s age cannot be determined.IncorrectLet the school ages of Neelam and Shaan be 5x and 6x years respectively.

Then, (1/3 * 5x)/(1/2 * 6x) = 5/9

15 = 15

Thus, Shaan’s age cannot be determined. - Question 45 of 50
##### 45. Question

The ratio of the cost price and the selling price is 4:5. The profit percent is:

CorrectLet C.P. = Rs. 4x. Then, S.P. = Rs. 5x

Gain = (5x – 4x) = Rs. x

Gain % = (x * 100)/ 4x = 25%.IncorrectLet C.P. = Rs. 4x. Then, S.P. = Rs. 5x

Gain = (5x – 4x) = Rs. x

Gain % = (x * 100)/ 4x = 25%. - Question 46 of 50
##### 46. Question

Out of 10 persons working on a project, 4 are graduates. If 3 are selected, what is the probability that there is at least one graduate among them?

CorrectP(at least one graduate) = 1 – P(no graduates) =

1 – ⁶C₃/¹⁰C₃ = 1 – (6 * 5 * 4)/(10 * 9 * 8) = 5/6IncorrectP(at least one graduate) = 1 – P(no graduates) =

1 – ⁶C₃/¹⁰C₃ = 1 – (6 * 5 * 4)/(10 * 9 * 8) = 5/6 - Question 47 of 50
##### 47. Question

The length of a rectangle is increased by 25% and its breadth is decreased by 20%. What is the effect on its area?

Correct100 * 100 = 10000

125 * 80 = 10000

No changeIncorrect100 * 100 = 10000

125 * 80 = 10000

No change - Question 48 of 50
##### 48. Question

A certain number when divided by 45 leaves a remainder 31, what is the remainder if the same number be divided by 15?

Correct45 + 31 = 76/15 = 1 (Remainder)

Incorrect45 + 31 = 76/15 = 1 (Remainder)

- Question 49 of 50
##### 49. Question

If x = √8 – √7, y = √6 – √5 and z = √10 – 3, which of the following is true?

Correctx = √8 – √7 = 1/(√8 + √7) and y = √6 – √5 = 1/(√6 + √5) and z = √10 – 3 = 1/(√10 + 3)

As (√8 + √7) > (√6 + √5), (√8 – √7) < (√6 – √5) As (√10 + 3) > (√8 + √7) > (√6 + √5)

z < x < y.Incorrectx = √8 – √7 = 1/(√8 + √7) and y = √6 – √5 = 1/(√6 + √5) and z = √10 – 3 = 1/(√10 + 3)

As (√8 + √7) > (√6 + √5), (√8 – √7) < (√6 – √5) As (√10 + 3) > (√8 + √7) > (√6 + √5)

z < x < y. - Question 50 of 50
##### 50. Question

Two pipes A and B can fill a cistern in 20 and 30 minutes respectively, and a third pipe C can empty it in 40 minutes. How long will it take to fill the cistern if all the three are opened at the same time?

Correct1/20 + 1/30 – 1/40 = 7/120

120/7 = 17 1/7Incorrect1/20 + 1/30 – 1/40 = 7/120

120/7 = 17 1/7