## IPPB Pre Quiz Series 4, IPPB Pre Online Test Series 4th, IPPB Mock Test

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IPPB Pre Quiz Series 4, IPPB Pre online test series 4th, IPPB mock test. RRB Exam Online Test 2019, IPPB Prelims Free Mock Test Exam 2019. IPPB Prelims Exam Free Online Quiz 2019, IPPB Prelims Full Online Mock Test **Series 4th** in English. RRB Online Test for All Subjects, IPPB Prelims Free Mock Test Series in English. IPPB Prelims Free Mock Test **Series 4.** IPPB Prelims English Language Online Test in English **Series 4th**. IPPB Prelims Quantitative Aptitude Quiz 2019, IPPB Prelims Reasoning Ability Free Online Test. Take IPPB Prelims Online Quiz. The IPPB Prelims Full online mock test paper is free for all students. IPPB Prelims Question and Answers in English and Hindi **Series 4**. Here we are providing** IPPB Prelims Full Mock Test Paper in English. IPPB Prelims **Mock Test **Series 4th** 2019. Now Test your self for IPPB Prelims Exam by using below quiz…

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- Question 1 of 50
##### 1. Question

A question paper consists of five problems, each problem having three internal choices. In how many ways can a candidate attempt one or more problems?

CorrectGiven that, the question paper consists of five problems. For each problem, one or two or three or none of the choices can be attempted.

Hence, the required number of ways = 4^{5}– 1.

= 2^{10}– 1 = 1024 – 1 = 1023IncorrectGiven that, the question paper consists of five problems. For each problem, one or two or three or none of the choices can be attempted.

Hence, the required number of ways = 4^{5}– 1.

= 2^{10}– 1 = 1024 – 1 = 1023 - Question 2 of 50
##### 2. Question

A train running at the speed of 60 km/hr crosses a pole in 9 sec. What is the length of the train?

CorrectSpeed = 60 * 5/18 = 50/3 m/sec

Length of the train = speed * time = 50/3 * 9 = 150 mIncorrectSpeed = 60 * 5/18 = 50/3 m/sec

Length of the train = speed * time = 50/3 * 9 = 150 m - Question 3 of 50
##### 3. Question

What is the least number, which is perfect square but contains 2700 as its factor?

Correct900 * 3 * 3 = 8100

Incorrect900 * 3 * 3 = 8100

- Question 4 of 50
##### 4. Question

Find the one which does not belong to that group ?

CorrectCrocodile, Turtle, Allegator and Frog are amphibians, while Chameleon is a terrestrial animal.

IncorrectCrocodile, Turtle, Allegator and Frog are amphibians, while Chameleon is a terrestrial animal.

- Question 5 of 50
##### 5. Question

Simplify the following:

(169/121)^{-3/2}* 27/2 * (13/22)^{-1}Correct(169/121)

^{-3/2}* 27/2 * (13/22)^{-1}

(13^{2}/11^{2})^{-3/2}* 27/2 * 22/13 = 13^{-3}/11^{-3}* 27/2 * 22/13

= 13^{-4}11^{4}3^{3}Incorrect(169/121)

^{-3/2}* 27/2 * (13/22)^{-1}

(13^{2}/11^{2})^{-3/2}* 27/2 * 22/13 = 13^{-3}/11^{-3}* 27/2 * 22/13

= 13^{-4}11^{4}3^{3} - Question 6 of 50
##### 6. Question

40 is subtracted from 60% of a number, the result is 50. Find the number?

Correct(60/100) * X – 40 = 50

6X = 900

X = 150Incorrect(60/100) * X – 40 = 50

6X = 900

X = 150 - Question 7 of 50
##### 7. Question

Two trains are running in opposite directions with the same speed. If the length of each train is 120 m and they cross each other in 12 sec, then the speed of each train is?

CorrectLet the speed of each train be x m/sec.

Then, relative speed of the two trains = 2x m/sec.

So, 2x = (120 + 120)/12 => x = 10

Speed of each train = 10 m/sec.

= 10 * 18/5 =- 36 km/hr.IncorrectLet the speed of each train be x m/sec.

Then, relative speed of the two trains = 2x m/sec.

So, 2x = (120 + 120)/12 => x = 10

Speed of each train = 10 m/sec.

= 10 * 18/5 =- 36 km/hr. - Question 8 of 50
##### 8. Question

50 men can complete a work in 65 days.Five days after started the work, 20 men left the group. In how many days can the remaining work be completed?

CorrectAfter 5 days, the following situation prevails.

50 men can complete the work in 60 days.

30 men can complete the work in ? days.

M_{1}D_{1}= M_{2}D_{2}

=> 50 * 60 = 30 * D_{2}

=> D_{2}= (50 * 60)/30 = 100 days.IncorrectAfter 5 days, the following situation prevails.

50 men can complete the work in 60 days.

30 men can complete the work in ? days.

M_{1}D_{1}= M_{2}D_{2}

=> 50 * 60 = 30 * D_{2}

=> D_{2}= (50 * 60)/30 = 100 days. - Question 9 of 50
##### 9. Question

The least square number which divides 8, 12 and 18 is?

CorrectLCM = 72

72 * 2 = 144IncorrectLCM = 72

72 * 2 = 144 - Question 10 of 50
##### 10. Question

How much time will take for an amount of Rs. 450 to yield Rs. 81 as interest at 4.5% per annum of simple interest?

CorrectTime = (100 * 81) / (450 * 4.5) = 4 years

IncorrectTime = (100 * 81) / (450 * 4.5) = 4 years

- Question 11 of 50
##### 11. Question

A gets 3 times as much money as B gets, B gets only Rs.25 more then what C gets. The three gets Rs.675 in all. Find the share of B?

CorrectA+B+C = 675

A = 3B

3B+B+B-25 = 675

5B = 700

B = 140IncorrectA+B+C = 675

A = 3B

3B+B+B-25 = 675

5B = 700

B = 140 - Question 12 of 50
##### 12. Question

Twenty four men can do a work in 35 days. How many men are required to complete the work in 21 days?

CorrectWe have M

_{1}D_{1}= M_{2}D_{2}

So, 24 * 35 = M_{2}* 21 => M_{2}= 40.IncorrectWe have M

_{1}D_{1}= M_{2}D_{2}

So, 24 * 35 = M_{2}* 21 => M_{2}= 40. - Question 13 of 50
##### 13. Question

A rope of which a calf is tied is increased from 12 m to 23 m, how much additional grassy ground shall it graze?

Correctπ (23

^{2}– 12^{2}) = 1210Incorrectπ (23

^{2}– 12^{2}) = 1210 - Question 14 of 50
##### 14. Question

A train 240 m in length crosses a telegraph post in 16 seconds. The speed of the train is?

CorrectS = 240/16 * 18/5 = 54 kmph

IncorrectS = 240/16 * 18/5 = 54 kmph

- Question 15 of 50
##### 15. Question

A is twice as fast as B. If B alone can do a piece of work in 30 days, in what time can A and B together complete the work?

CorrectA can do the work in 30/2 i.e., 15 days.

A and B’s one day’s work = 1/15 + 1/30 = (2 + 1)/30 = 1/10

So A and B together can do the work in 10 days.IncorrectA can do the work in 30/2 i.e., 15 days.

A and B’s one day’s work = 1/15 + 1/30 = (2 + 1)/30 = 1/10

So A and B together can do the work in 10 days. - Question 16 of 50
##### 16. Question

Robert is traveling on his cycle and has calculated to reach point A at 2 p.m. if he travels at 10 km/hr; he will reach there at 12 noon if he travels at 15 km/hr. At what speed must he travel to reach A at 1 p.m.?

CorrectLet the distance traveled be x km.

Then, x/10 – x/15 = 2

3x – 2x = 60 => x = 60 km.

Time taken to travel 60 km at 10 km/hr = 60/10 = 6 hrs.

So, Robert started 6 hours before 2. p.m. i.e., at 8 a.m.

Required speed = 60/5 = 12 kmph.

Learn more problems on : Time and DistanceIncorrectLet the distance traveled be x km.

Then, x/10 – x/15 = 2

3x – 2x = 60 => x = 60 km.

Time taken to travel 60 km at 10 km/hr = 60/10 = 6 hrs.

So, Robert started 6 hours before 2. p.m. i.e., at 8 a.m.

Required speed = 60/5 = 12 kmph.

Learn more problems on : Time and Distance - Question 17 of 50
##### 17. Question

A number when divided by 221 gives a remainder 43, what remainder will be obtained by dividing the same number 17?

Correct221 + 43 = 264/17 = 9 (Remainder)

Incorrect221 + 43 = 264/17 = 9 (Remainder)

- Question 18 of 50
##### 18. Question

What is the rate percent when the simple interest on Rs.800 amount to Rs.160 in 4 Years?

Correct160 = (180*4*R)/100

R = 5%Incorrect160 = (180*4*R)/100

R = 5% - Question 19 of 50
##### 19. Question

Three number are in the ratio 5:6:7. The sum of its largest and smallest numbers equals the sum of the third number and 48. Find the third number?

CorrectLet the numbers be 5x, 6x and 7x.

Largest number = 7x

Smallest number = 5x

Third number = 6x

7x + 5x = 6x + 48

6x = 48

Third number is: 48.IncorrectLet the numbers be 5x, 6x and 7x.

Largest number = 7x

Smallest number = 5x

Third number = 6x

7x + 5x = 6x + 48

6x = 48

Third number is: 48. - Question 20 of 50
##### 20. Question

A manufacturer sells a pair of glasses to a wholesale dealer at a profit of 18%. The wholesaler sells the same to retailer at a profit of 20%. The retailer in turn sells them to a customer for Rs. 30.09, there by earning a profit of 25%. The cost price for the manufacturer is:

CorrectLet the cost price for the manufacturer be Rs. x. Then, 125% of 120% of 118% of x = 30.09.

125/100 * 120/100 * 118/100 * x = 3009/100

177/100 x = 3009/100 => x = 17IncorrectLet the cost price for the manufacturer be Rs. x. Then, 125% of 120% of 118% of x = 30.09.

125/100 * 120/100 * 118/100 * x = 3009/100

177/100 x = 3009/100 => x = 17 - Question 21 of 50
##### 21. Question

Simple interest on a sum at 4% per annum for 2 years is Rs.80. The C.I. on the same sum for the same period is?

CorrectSI = 40 + 40

CI = 40 + 40 + 1.6 = 81.6IncorrectSI = 40 + 40

CI = 40 + 40 + 1.6 = 81.6 - Question 22 of 50
##### 22. Question

Sreenivas sells a table to Shiva at 10% profit and Shiva sells it to Mahesh at 10% loss. At what price did Sreenivas purchase the table if Mahesh paid Rs. 2178?

CorrectLet the cost price of table for Sreenivas be Rs. x and given that, cost price of table for Mahesh = Rs. 2178.

=> (90%) of (110%) of x = Rs. 2178.

=> (90/100)(110/100)x = 2178

=> x = (2178 * 100)/(9 * 11)

=> x = Rs. 2200IncorrectLet the cost price of table for Sreenivas be Rs. x and given that, cost price of table for Mahesh = Rs. 2178.

=> (90%) of (110%) of x = Rs. 2178.

=> (90/100)(110/100)x = 2178

=> x = (2178 * 100)/(9 * 11)

=> x = Rs. 2200 - Question 23 of 50
##### 23. Question

Find the ratio of the curved surfaces of two cylinders of same heights if their radii are in the ratio 1:2.

CorrectIncorrect - Question 24 of 50
##### 24. Question

Find the greatest number of four digits which when divided by 10, 15, 21 and 28 leaves 4, 9, 15 and 22 as remainders respectively?

Correct

420) 9999 (23

= 9660

= ———

= 339

9999 – 339 = 9660 – 6 = 9654Incorrect

420) 9999 (23

= 9660

= ———

= 339

9999 – 339 = 9660 – 6 = 9654 - Question 25 of 50
##### 25. Question

If 70% of an equal to 40% of b, then ratio between a and b is?

Correct70 a = 40 b

a: b = 4: 7Incorrect70 a = 40 b

a: b = 4: 7 - Question 26 of 50
##### 26. Question

184 * 216 – 81 + 119 / 0.7 = ?

Correct184 * 216 – 81 + 119 / 0.7 = 184/216 – 81 + 170

Using the concept of digit roots we can say digit root of 180 = 1 + 8 + 4 = 13 = 1 + 3 = 4.

i.e. we keep adding the digits till we get the sum as a single digit number.

Digit root of 216 is 0

Digit root of 81 is 0.

Digit root of 170 is 1 + 7 + 0 = 8

Thus the digit root of the answer must be (4)(0) – 0 + 8 = 8.

(39439) digit root is 3 + 9 + 4 + 3 + 9 = 28 2 + 8 = 10 1 + 0 = 1.

Digit root is 1.

Similarly the digit root of 39394 is 1 digit root of 94934 is 2.

Where as the digit root of 33949 is 1. Thus none of them could be the answer, hence the answer is choice (5) or 184 * 216 – 81 + 170 = 39833.Incorrect184 * 216 – 81 + 119 / 0.7 = 184/216 – 81 + 170

Using the concept of digit roots we can say digit root of 180 = 1 + 8 + 4 = 13 = 1 + 3 = 4.

i.e. we keep adding the digits till we get the sum as a single digit number.

Digit root of 216 is 0

Digit root of 81 is 0.

Digit root of 170 is 1 + 7 + 0 = 8

Thus the digit root of the answer must be (4)(0) – 0 + 8 = 8.

(39439) digit root is 3 + 9 + 4 + 3 + 9 = 28 2 + 8 = 10 1 + 0 = 1.

Digit root is 1.

Similarly the digit root of 39394 is 1 digit root of 94934 is 2.

Where as the digit root of 33949 is 1. Thus none of them could be the answer, hence the answer is choice (5) or 184 * 216 – 81 + 170 = 39833. - Question 27 of 50
##### 27. Question

The number of ways in which six boys and six girls can be seated in a row for a photograph so that no two girls sit together is -.

CorrectWe can initially arrange the six boys in 6! ways.

Having done this, now three are seven places and six girls to be arranged. This can be done in ⁷P₆ ways.

Hence required number of ways = 6! * ⁷P₆IncorrectWe can initially arrange the six boys in 6! ways.

Having done this, now three are seven places and six girls to be arranged. This can be done in ⁷P₆ ways.

Hence required number of ways = 6! * ⁷P₆ - Question 28 of 50
##### 28. Question

A train crosses a platform of 120 m in 15 sec, same train crosses another platform of length 180 m in 18 sec. then find the length of the train?

CorrectLength of the train be ‘X’

X + 120/15 = X + 180/18

6X + 720 = 5X + 900

X = 180mIncorrectLength of the train be ‘X’

X + 120/15 = X + 180/18

6X + 720 = 5X + 900

X = 180m - Question 29 of 50
##### 29. Question

2

^{42}+ 4^{20}+ 16^{11}+ 64^{7}equalsCorrect2

^{42}+ 2^{40}+ 2^{44}+ 2^{42}

= 2^{40}(2^{2}+ 1 + 2^{4}+ 2^{2})

= 2^{40}* 25 = 2^{40}* 5^{2}Incorrect2

^{42}+ 2^{40}+ 2^{44}+ 2^{42}

= 2^{40}(2^{2}+ 1 + 2^{4}+ 2^{2})

= 2^{40}* 25 = 2^{40}* 5^{2} - Question 30 of 50
##### 30. Question

How many meters of carpet 50cm, wide will be required to cover the floor of a room 30m * 20m?

Correct50/100 * x = 30 * 20 => x = 1200

Incorrect50/100 * x = 30 * 20 => x = 1200

- Question 31 of 50
##### 31. Question

A, B and C invested Rs.6300, Rs.4200 and Rs.10500 respectively, in a partnership business. Find the share of A in profit of Rs.12100 after a year?

Correct6300:4200:10500

3:2:5

3/10 * 12100 = 3630Incorrect6300:4200:10500

3:2:5

3/10 * 12100 = 3630 - Question 32 of 50
##### 32. Question

A man could buy a certain number of notebooks for Rs.300. If each notebook cost is Rs.5 more, he could have bought 10 notebooks less for the same amount. Find the price of each notebook?

CorrectLet the price of each note book be Rs.x.

Let the number of note books which can be brought for Rs.300 each at a price of Rs.x be y.

Hence xy = 300

=> y = 300/x

(x + 5)(y – 10) = 300 => xy + 5y – 10x – 50 = xy

=>5(300/x) – 10x – 50 = 0 => -150 + x^{2}+ 5x = 0

multiplying both sides by -1/10x

=> x^{2}+ 15x – 10x – 150 = 0

=> x(x + 15) – 10(x + 15) = 0

=> x = 10 or -15

As x>0, x = 10.IncorrectLet the price of each note book be Rs.x.

Let the number of note books which can be brought for Rs.300 each at a price of Rs.x be y.

Hence xy = 300

=> y = 300/x

(x + 5)(y – 10) = 300 => xy + 5y – 10x – 50 = xy

=>5(300/x) – 10x – 50 = 0 => -150 + x^{2}+ 5x = 0

multiplying both sides by -1/10x

=> x^{2}+ 15x – 10x – 150 = 0

=> x(x + 15) – 10(x + 15) = 0

=> x = 10 or -15

As x>0, x = 10. - Question 33 of 50
##### 33. Question

A batsman makes a score of 64 runs in the 16th innings and thus increased his average by 3. Find his average after the 16th inning?

CorrectLet the average after the 16th inning be P.

So, the average after the 15th inning will be (P-3) Hence, 15(P-30) + 64 = 16P => P = 19.IncorrectLet the average after the 16th inning be P.

So, the average after the 15th inning will be (P-3) Hence, 15(P-30) + 64 = 16P => P = 19. - Question 34 of 50
##### 34. Question

(a

^{-3}b^{-2}/ a^{2}b^{2})^{-3}* (a^{3}b^{-4}/ a^{-3}b^{3}) / (a^{-2}b^{3}/a^{-4}b^{-3}) = ?Correct(a

^{-3}b^{-2}/ a^{2}b^{2})^{-3}* (a^{3}b^{-4}/ a^{-3}b^{3}) / (a^{-2}b^{3}/a^{-4}b^{-3})

= (a^{-5}b^{-4})^{-3}* a^{6}b^{-7}/ a^{2}b^{6}

= a^{15}b^{12}* a^{6}b^{-7}* a^{-2}b^{-6}

= a^{19}b^{-1}Incorrect(a

^{-3}b^{-2}/ a^{2}b^{2})^{-3}* (a^{3}b^{-4}/ a^{-3}b^{3}) / (a^{-2}b^{3}/a^{-4}b^{-3})

= (a^{-5}b^{-4})^{-3}* a^{6}b^{-7}/ a^{2}b^{6}

= a^{15}b^{12}* a^{6}b^{-7}* a^{-2}b^{-6}

= a^{19}b^{-1} - Question 35 of 50
##### 35. Question

A began business with Rs.45000 and was joined afterwards by B with Rs.5400. When did B join if the profits at the end of the year were divided in the ratio of 2:1?

Correct45*12 : 54*x = 2: 1

x = 5

12 -5 = 7Incorrect45*12 : 54*x = 2: 1

x = 5

12 -5 = 7 - Question 36 of 50
##### 36. Question

15% of 195 + 14% of 205 = ?

Correct15/100 * 195 + 14/100 * 205 = 15/100 * 200 + 14/100 * 200

= 30 + 28 = 58Incorrect15/100 * 195 + 14/100 * 205 = 15/100 * 200 + 14/100 * 200

= 30 + 28 = 58 - Question 37 of 50
##### 37. Question

Find the one which does not belong to that group ?

CorrectExcept Regiment, all others are caders of army officers.

IncorrectExcept Regiment, all others are caders of army officers.

- Question 38 of 50
##### 38. Question

The parameter of a square is double the perimeter of a rectangle. The area of the rectangle is 480 sq cm. Find the area of the square.

CorrectLet the side of the square be a cm. Let the length and the breadth of the rectangle be l cm and b cm respectively.

4a = 2(l + b)

2a = l + b

l . b = 480

We cannot find ( l + b) only with the help of l . b. Therefore a cannot be found .

Area of the square cannot be found.IncorrectLet the side of the square be a cm. Let the length and the breadth of the rectangle be l cm and b cm respectively.

4a = 2(l + b)

2a = l + b

l . b = 480

We cannot find ( l + b) only with the help of l . b. Therefore a cannot be found .

Area of the square cannot be found. - Question 39 of 50
##### 39. Question

Find the number which multiplied by 15 is increased by 196.

CorrectLet the number be x. Then,

15x – x = 196

x = 14IncorrectLet the number be x. Then,

15x – x = 196

x = 14 - Question 40 of 50
##### 40. Question

Find the one which does not belong to that group ?

Correct42624, 37573, 74347 and 93339 are palindromes but not 84284.

Incorrect42624, 37573, 74347 and 93339 are palindromes but not 84284.

- Question 41 of 50
##### 41. Question

{20 – [7 – (3 -2)] + 1/3 (4.2)} / 1.4 = ?

Correct{20 – [7 – (3 -2)] + 1/3 (4.2)} / 1.4

=> [20 – (7 – 1) + 1.4] / 1.4

=> (20 – 6 + 1.4)/1.4 = 10 + 1 = 11Incorrect{20 – [7 – (3 -2)] + 1/3 (4.2)} / 1.4

=> [20 – (7 – 1) + 1.4] / 1.4

=> (20 – 6 + 1.4)/1.4 = 10 + 1 = 11 - Question 42 of 50
##### 42. Question

The average of 11 results is 50, if the average of first six results is 49 and that of the last six is 52. Find the sixth result?

Correct1 to 11 = 11 * 50 = 550

1 to 6 = 6 * 49 = 294

6 to 11 = 6 * 52 = 312

6^{th}= 294 + 312 – 550 = 56Incorrect1 to 11 = 11 * 50 = 550

1 to 6 = 6 * 49 = 294

6 to 11 = 6 * 52 = 312

6^{th}= 294 + 312 – 550 = 56 - Question 43 of 50
##### 43. Question

Divide Rs.118000 among three persons A, B and C such that the ratio of the shares of A and B is 3:4 and that of B:C is 5:6?

CorrectCompound ratio of A:B:C

A:B = 3:4

B:C = 5:6

———-

A:B:C = 15:20:24

We can divide Rs.118000 in this ratio.

Share of A = 15/59 * 118000 = 30000

Share of B = 20/59 * 118000 = 40000

Share of C = 24/59 * 118000 = 48000IncorrectCompound ratio of A:B:C

A:B = 3:4

B:C = 5:6

———-

A:B:C = 15:20:24

We can divide Rs.118000 in this ratio.

Share of A = 15/59 * 118000 = 30000

Share of B = 20/59 * 118000 = 40000

Share of C = 24/59 * 118000 = 48000 - Question 44 of 50
##### 44. Question

In a mixture of milk and water, the proportion of milk by weight was 80%. If, in a 180 gm mixture, 36 gms of pure milk is added, what would be the percentage of milk in the mixture formed?

CorrectPercentage of milk in the mixture formed = [80/100 (180) + 36] / (180 + 36) * 100% = (144 + 36)/216 * 100% = 5/6 * 100% = 83.33%.

IncorrectPercentage of milk in the mixture formed = [80/100 (180) + 36] / (180 + 36) * 100% = (144 + 36)/216 * 100% = 5/6 * 100% = 83.33%.

- Question 45 of 50
##### 45. Question

In a pair of fractions, fraction A is twice the fraction B and the product of two fractions is 2/25. What is the value of fraction A?

CorrectA = 2B => B = 1/2 A, so, AB = 2/25

1/2 A^{2}= 2/25

A^{2}= 4/25

A = 2/5IncorrectA = 2B => B = 1/2 A, so, AB = 2/25

1/2 A^{2}= 2/25

A^{2}= 4/25

A = 2/5 - Question 46 of 50
##### 46. Question

In an election only two candidates contested. A candidate secured 70% of the valid votes and won by a majority of 172 votes. Find the total number of valid votes?

CorrectLet the total number of valid votes be x.

70% of x = 70/100 * x = 7x/10

Number of votes secured by the other candidate = x – 7x/100 = 3x/10

Given, 7x/10 – 3x/10 = 172 => 4x/10 = 172

=> 4x = 1720 => x = 430.IncorrectLet the total number of valid votes be x.

70% of x = 70/100 * x = 7x/10

Number of votes secured by the other candidate = x – 7x/100 = 3x/10

Given, 7x/10 – 3x/10 = 172 => 4x/10 = 172

=> 4x = 1720 => x = 430. - Question 47 of 50
##### 47. Question

Sum of two numbers is 80. Greater number exceeds by 5 from four times of the smaller. Find the numbers?

Correctx + y = 80

x – 4y = 5

x = 65 y = 15Incorrectx + y = 80

x – 4y = 5

x = 65 y = 15 - Question 48 of 50
##### 48. Question

(0.9 * 0.9 – 0.8 * 0.8)/1.7 = ?

CorrectAs numerator is of the form a

^{2}– b^{2}= (a + b) (a – b), so the given expression simplifying becomes

(0.9^{2}– 0.8^{2})/(0.9 + 0.8) (0.9 + 0.8) (0.9 – 0.8)/0.9 + 0.8 = 0.1IncorrectAs numerator is of the form a

^{2}– b^{2}= (a + b) (a – b), so the given expression simplifying becomes

(0.9^{2}– 0.8^{2})/(0.9 + 0.8) (0.9 + 0.8) (0.9 – 0.8)/0.9 + 0.8 = 0.1 - Question 49 of 50
##### 49. Question

An automobile financier claims to be lending money at S.I., but he includes the interest every six months for calculating the principal. If he is charging an interest of 10%, the effective rate of interest becomes?

CorrectLet the sum be Rs. 100. Then,

S.I. for first 6 months = (100 * 10 *1) / (100 * 2) = Rs. 5

S.I. for last 6 months = (105 * 10 * 1) / (100 * 2) = Rs. 5.25

So, amount at the end of 1 year = (100 + 5 + 5.25) = Rs. 110.25

Effective rate = (110.25 – 100) = 10.25%.IncorrectLet the sum be Rs. 100. Then,

S.I. for first 6 months = (100 * 10 *1) / (100 * 2) = Rs. 5

S.I. for last 6 months = (105 * 10 * 1) / (100 * 2) = Rs. 5.25

So, amount at the end of 1 year = (100 + 5 + 5.25) = Rs. 110.25

Effective rate = (110.25 – 100) = 10.25%. - Question 50 of 50
##### 50. Question

The ratio of two numbers is 2:3 and the sum of their cubes is 945. The difference of number is?

Correct2x 3x

8x cube + 27x cube = 945

35x cube = 945

x cube = 27 => x = 3Incorrect2x 3x

8x cube + 27x cube = 945

35x cube = 945

x cube = 27 => x = 3