## IPPB Pre Online Test Series 5, IPPB Prelims Mock Test Series 5th

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IPPB Pre Online Test Series 5, IPPB Prelims Mock Test Series 5th, IPPB Prelims Free Mock Test Exam 2019. IPPB Prelims Exam Free Online Quiz 2019. IPPB Prelims Full Online Mock Test **Series 5th** in English.candidates who want to make sure whether their preparation level is up to date then they take this online test series without paying anything. CAknowledge provide **IPPB Online Test Series 2019 **in order to let you excel in the examination. The IPPB Prelims Full online mock test paper is free for all students. IPPB Prelims Question and Answers in English and Hindi **Series 5**. Here we are providing** IPPB Prelims Full Mock Test Paper in English. IPPB Prelims **Mock Test **Series 5th** 2019. Now Test your self for IPPB Prelims Exam by using below quiz…

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- Question 1 of 50
##### 1. Question

Sreedhar and Sravan together can do a work in 25 days. With the help of Pavan, they completed the work in 8 days and earned Rs. 225. What is the share of Sravan, if Sreedhar alone can do the work in 75 days?

CorrectSravan’s one day’s work = 1/25 – 1/75 = 2/75

Sravan worked for 8 days. So, his 8 days work = 8 * 2/75 = 16/75

Sravan completed 16/75th of total work.

So, his share is 16/75 * 225 = Rs. 48.IncorrectSravan’s one day’s work = 1/25 – 1/75 = 2/75

Sravan worked for 8 days. So, his 8 days work = 8 * 2/75 = 16/75

Sravan completed 16/75th of total work.

So, his share is 16/75 * 225 = Rs. 48. - Question 2 of 50
##### 2. Question

A train running at the speed of 60 km/hr crosses a pole in 9 seconds. What is the length of the train?

CorrectSpeed=(60 * 5/18) m/sec = (50/3) m/sec Length of the train = (Speed x Time) = (50/3 * 9) m = 150 m.

IncorrectSpeed=(60 * 5/18) m/sec = (50/3) m/sec Length of the train = (Speed x Time) = (50/3 * 9) m = 150 m.

- Question 3 of 50
##### 3. Question

A letter lock consists of three rings each marked with six different letters. The number of distinct unsuccessful attempts to open the lock is at the most -.

CorrectSince each ring consists of six different letters, the total number of attempts possible with the three rings is = 6 * 6 * 6 = 216. Of these attempts, one of them is a successful attempt.

Maximum number of unsuccessful attempts = 216 – 1 = 215.IncorrectSince each ring consists of six different letters, the total number of attempts possible with the three rings is = 6 * 6 * 6 = 216. Of these attempts, one of them is a successful attempt.

Maximum number of unsuccessful attempts = 216 – 1 = 215. - Question 4 of 50
##### 4. Question

Sum of two numbers is 80. Greater number exceeds by 5 from four times of the smaller. Find the numbers?

Correctx + y = 80

x – 4y = 5

x = 65 y = 15Incorrectx + y = 80

x – 4y = 5

x = 65 y = 15 - Question 5 of 50
##### 5. Question

The ratio of the earnings of P and Q is 9:10. If the earnings of P increases by one-fourth and the earnings of Q decreases by one-fourth, then find the new ratio of their earnings?

CorrectLet the earnings of P and Q be 9x and 10x respectively.

New ratio = [9x + 1/4 (9x)]/[10x – 1/4 (10x)]

=> 9*(1 + 1/4)/10*(1 – 1/4)

=> 9/10 * (5/4)/(3/4) = 3/2IncorrectLet the earnings of P and Q be 9x and 10x respectively.

New ratio = [9x + 1/4 (9x)]/[10x – 1/4 (10x)]

=> 9*(1 + 1/4)/10*(1 – 1/4)

=> 9/10 * (5/4)/(3/4) = 3/2 - Question 6 of 50
##### 6. Question

A building contractor employs 20 male, 15 female and 5 child workers. To a male worker he pays Rs.25 per day, to a female worker Rs.20 per day and a child worker Rs.8 per day. The average wage per day paid by the contractor is?

Correct20 15 5

25 20 8

500 + 300 + 40 = 840/40 = 21Incorrect20 15 5

25 20 8

500 + 300 + 40 = 840/40 = 21 - Question 7 of 50
##### 7. Question

Find the number which multiplied by 15 is increased by 196.

CorrectLet the number be x. Then,

15x – x = 196

x = 14IncorrectLet the number be x. Then,

15x – x = 196

x = 14 - Question 8 of 50
##### 8. Question

If the arithmetic mean of seventy five numbers is calculated, it is 35. If each number is increased by 5, then mean of new number is:

CorrectA.M. of 75 numbers = 35

Sum of 75 numbers = 75 * 35 = 2625

Total increase = 75 * 5 = 375

Increased sum = 2625 + 375 = 3000

Increased average = 3000/75 = 40.IncorrectA.M. of 75 numbers = 35

Sum of 75 numbers = 75 * 35 = 2625

Total increase = 75 * 5 = 375

Increased sum = 2625 + 375 = 3000

Increased average = 3000/75 = 40. - Question 9 of 50
##### 9. Question

25 2/5 + 8 4/5 + 4/5 = ?

Correct25 2/5 + 8 4/5 + 4/5 = 34 4/5 ≡ 35

Incorrect25 2/5 + 8 4/5 + 4/5 = 34 4/5 ≡ 35

- Question 10 of 50
##### 10. Question

150 men consume 1050 kg of rice in 30 days. In how many days will 70 men consume 980 kg of rice?

CorrectRate of consumption of each man = 1050/(150 * 30) = 7/30 kg/day

Let us say 70 men take x days to consume 150 kg.

Quantity consumed by each item in x days = 7x/30 kg.

Quantity consumed by 70 men in x days = (7x/30)(70)kg

(7x/30)(70) = 980

x = (980 * 30)/490 => x = 60 daysIncorrectRate of consumption of each man = 1050/(150 * 30) = 7/30 kg/day

Let us say 70 men take x days to consume 150 kg.

Quantity consumed by each item in x days = 7x/30 kg.

Quantity consumed by 70 men in x days = (7x/30)(70)kg

(7x/30)(70) = 980

x = (980 * 30)/490 => x = 60 days - Question 11 of 50
##### 11. Question

(64 + 9 + 9) / (2 * 20 + 1) = ?

Correct(64 + 9 + 9) / (2 * 20 + 1) = 82/41 = 2

Incorrect(64 + 9 + 9) / (2 * 20 + 1) = 82/41 = 2

- Question 12 of 50
##### 12. Question

108 * 107 * 96 = ? (to the nearest hundred)

Correct108 * 107 * 96 ≡ 1109400

Incorrect108 * 107 * 96 ≡ 1109400

- Question 13 of 50
##### 13. Question

The area of a base of a cone is 30 cm

^{2}. If the height of the cone is 6cm, find its volume?Correctπr

^{2}= 30 h = 6

1/3 * 30 * 6 = 60Incorrectπr

^{2}= 30 h = 6

1/3 * 30 * 6 = 60 - Question 14 of 50
##### 14. Question

The product of two numbers is 2028 and their H.C.F is 13. The number of such pairs is:

CorrectLet the numbers be 13a and 13b.

Then, 13a * 13b = 2028 => ab = 12.

Now, co-primes with product 12 are (1, 12) and (3, 4).

So, the required numbers are (13 * 1, 13 * 12) and (13 * 3, 13 * 4).

Clearly, there are 2 such pairs.IncorrectLet the numbers be 13a and 13b.

Then, 13a * 13b = 2028 => ab = 12.

Now, co-primes with product 12 are (1, 12) and (3, 4).

So, the required numbers are (13 * 1, 13 * 12) and (13 * 3, 13 * 4).

Clearly, there are 2 such pairs. - Question 15 of 50
##### 15. Question

Arun purchased 30 kg of wheat at the rate of Rs. 11.50 per kg and 20 kg of wheat at the rate of 14.25 per kg. He mixed the two and sold the mixture. Approximately what price per kg should be sell the mixture to make 30% profit?

CorrectC.P. of 50 kg wheat = (30 * 11.50 + 20 * 14.25) = Rs. 630.

S.P. of 50 kg wheat = 130% of Rs. 630 = 130/100 * 630 = Rs. 819.

S.P. per kg = 819/50 = Rs. 16.38 = 16.30.IncorrectC.P. of 50 kg wheat = (30 * 11.50 + 20 * 14.25) = Rs. 630.

S.P. of 50 kg wheat = 130% of Rs. 630 = 130/100 * 630 = Rs. 819.

S.P. per kg = 819/50 = Rs. 16.38 = 16.30. - Question 16 of 50
##### 16. Question

(1.9 * 0.021) / (0.095 * 0.105) = ?

Correct(1.9 * 0.021) / (0.095 * 0.105) = (19 * 21 * 100) / (95 * 105) = 4.

Incorrect(1.9 * 0.021) / (0.095 * 0.105) = (19 * 21 * 100) / (95 * 105) = 4.

- Question 17 of 50
##### 17. Question

A cistern is filled by a tap in 3 1/2 hours. Due to leak in the bottom of the cistern, it takes half an hour longer to fill the cistern. If the cistern is full how long will it take the leak to empty it?

Correct2/7 – 1/x = 1/4

x = 28Incorrect2/7 – 1/x = 1/4

x = 28 - Question 18 of 50
##### 18. Question

Find the least number by which (5

^{9})(3^{6})(17) has to be multiplied to obtain a perfect square?CorrectFor any perfect square the index of the power of each of its prime factors is even. in the given number the power of 5 and 17 have odd indices, while 3 has an even index.

The least number = (5)(17) = 85.IncorrectFor any perfect square the index of the power of each of its prime factors is even. in the given number the power of 5 and 17 have odd indices, while 3 has an even index.

The least number = (5)(17) = 85. - Question 19 of 50
##### 19. Question

What is the least number to be subtracted from 11, 15, 21 and 30 each so that the resultant numbers become proportional?

CorrectLet the least number to be subtracted be ‘x’, then 11 – x, 15 – x, 21 – x and 30 – x are in proportion.

<=> (11 – x):(15 – x) = (21 – x):(30 -x)(21 – x)

From the options, when x = 3

=> 8 * 27 = 12 * 18 => then x = 3. => (11 – x)(30 – x) = (15 – x)(21 – x)IncorrectLet the least number to be subtracted be ‘x’, then 11 – x, 15 – x, 21 – x and 30 – x are in proportion.

<=> (11 – x):(15 – x) = (21 – x):(30 -x)(21 – x)

From the options, when x = 3

=> 8 * 27 = 12 * 18 => then x = 3. => (11 – x)(30 – x) = (15 – x)(21 – x) - Question 20 of 50
##### 20. Question

In how many ways can three consonants and two vowels be selected from the letters of the word “TRIANGLE”?

CorrectThe word contains five consonants. Three vowels, three consonants can be selected from five consonants in ⁵C₃ ways, two vowels can be selected from three vowels in ³C₂ ways.

3 consonants and 2 vowels can be selected in ⁵C₂ . ³C₂ ways i.e., 10 * 3 = 30 ways.IncorrectThe word contains five consonants. Three vowels, three consonants can be selected from five consonants in ⁵C₃ ways, two vowels can be selected from three vowels in ³C₂ ways.

3 consonants and 2 vowels can be selected in ⁵C₂ . ³C₂ ways i.e., 10 * 3 = 30 ways. - Question 21 of 50
##### 21. Question

Two pipes can fill a tank in 20 and 24 minutes respectively and a waste pipe can empty 3 gallons per minute. All the three pipes working together can fill the tank in 15 minutes. The capacity of the tank is?

CorrectWork done by the waste pipe in 1 minute = 1/15 – (1/20 + 1/24) = – 1/40

Volume of 1/40 part = 3 gallons\

Volume of whole = 3 * 40 = 120 gallons.IncorrectWork done by the waste pipe in 1 minute = 1/15 – (1/20 + 1/24) = – 1/40

Volume of 1/40 part = 3 gallons\

Volume of whole = 3 * 40 = 120 gallons. - Question 22 of 50
##### 22. Question

If the sum and difference of two numbers are 20 and 8 respectively, then the difference of their square is:

CorrectLet the numbers be x and y.

Then, x + y = 20 and x – y = 8

x^{2}– y^{2}= (x + y)(x – y) = 20 * 8 = 160.IncorrectLet the numbers be x and y.

Then, x + y = 20 and x – y = 8

x^{2}– y^{2}= (x + y)(x – y) = 20 * 8 = 160. - Question 23 of 50
##### 23. Question

In a partnership between A, B and C. A’s capital is Rs.5000. If his share of a profit of Rs.800 is Rs.200 and C’s share is Rs.130, what is B’s capital?

Correct200 + 130 = 330

800 – 330 = 470

200 —- 5000

470 —- ? => 11750Incorrect200 + 130 = 330

800 – 330 = 470

200 —- 5000

470 —- ? => 11750 - Question 24 of 50
##### 24. Question

25 * 25 / 25 + 15 * 40 = ?

Correct(25 * 25)/25 + 15 * 40 = 25 + 600 = 625.

Incorrect(25 * 25)/25 + 15 * 40 = 25 + 600 = 625.

- Question 25 of 50
##### 25. Question

The sum of the ages of 5 children born at the intervals of 3 years each is 50 years. What is the age of the youngest child?

CorrectLet the ages of the children be x, (x + 3), (x + 6), (x + 9) and (x +12) years.

Then, x + (x + 3) + (x + 6) + (x + 9) + (x + 12) = 50

5x = 20 => x = 4.

Age of youngest child = x = 4 years.IncorrectLet the ages of the children be x, (x + 3), (x + 6), (x + 9) and (x +12) years.

Then, x + (x + 3) + (x + 6) + (x + 9) + (x + 12) = 50

5x = 20 => x = 4.

Age of youngest child = x = 4 years. - Question 26 of 50
##### 26. Question

Which of the following number is divisible by 4 and 9?

CorrectFor a number to be divisible by 4, the number formed by the last two digits of that number must be divisible by 4.

For a number to be divisible by 9, the sum of its digits must be divisible by 9.

Among the choices, choices (a) and (b) are divisible by 4 but of the first two choices, only choice (b) is divisible by 9.

Hence choice (b) is divisible by both 4 and 9.IncorrectFor a number to be divisible by 4, the number formed by the last two digits of that number must be divisible by 4.

For a number to be divisible by 9, the sum of its digits must be divisible by 9.

Among the choices, choices (a) and (b) are divisible by 4 but of the first two choices, only choice (b) is divisible by 9.

Hence choice (b) is divisible by both 4 and 9. - Question 27 of 50
##### 27. Question

A man engaged a servant on the condition that he would pay him Rs.900 and a uniform after one year service. He served only for 9 months and received uniform and Rs.650, find the price of the uniform?

Correct9/12 = 3/4 * 900 = 675

= 650

= ————-

= 25

1/4 ——– 25

1 ——— ? => Rs.100Incorrect9/12 = 3/4 * 900 = 675

= 650

= ————-

= 25

1/4 ——– 25

1 ——— ? => Rs.100 - Question 28 of 50
##### 28. Question

How much interest can a person get on Rs. 8200 at 17.5% p.a. simple interest for a period of two years and six months?

CorrectI = (8200 * 2.5 * 17.5)/100 = (8200 * 5 * 35)/(100 * 2 * 2) = Rs. 3587.50

IncorrectI = (8200 * 2.5 * 17.5)/100 = (8200 * 5 * 35)/(100 * 2 * 2) = Rs. 3587.50

- Question 29 of 50
##### 29. Question

What percentage of numbers from 1 to 70 have squares that end in the digit 1?

CorrectClearly, the numbers which have 1 or 9 in the unit’s digit, have squares that end in the digit 1. Such numbers from 1 to 70 are 1, 9, 11, 19, 21, 29, 31, 39, 41, 49, 51, 59, 61, 69.

Number of such numbers = 14.

Required percentage = (14/70 * 100) = 20%

Learn more problems on : PercentagesIncorrectClearly, the numbers which have 1 or 9 in the unit’s digit, have squares that end in the digit 1. Such numbers from 1 to 70 are 1, 9, 11, 19, 21, 29, 31, 39, 41, 49, 51, 59, 61, 69.

Number of such numbers = 14.

Required percentage = (14/70 * 100) = 20%

Learn more problems on : Percentages - Question 30 of 50
##### 30. Question

A delegation of 5 members has to be formed from 3 ladies and 5 gentlemen. In how many ways the delegation can be formed, if 2 particular ladies are always included in the delegation?

CorrectThere are three ladies and five gentlemen and a committee of 5 members to be formed.

Number of ways such that two ladies are always included in the committee = ⁶C₃ = (6 * 5 * 4)/6 = 20.IncorrectThere are three ladies and five gentlemen and a committee of 5 members to be formed.

Number of ways such that two ladies are always included in the committee = ⁶C₃ = (6 * 5 * 4)/6 = 20. - Question 31 of 50
##### 31. Question

109.13 * 34.14 – 108.12 * 33 = ?

Correct109 * 34 – 108 * 33

= 3706 – 3564 = 142Incorrect109 * 34 – 108 * 33

= 3706 – 3564 = 142 - Question 32 of 50
##### 32. Question

12 3/4 * (1 2/17 / 8 1/6) / 5 4/3 = ?

CorrectBy applying BODMAS rule.

51/4 * (19/17 / 49/6) / 19/3

= 51/4 * ( 19/17 * 6/49) * 3/19 = 27/98IncorrectBy applying BODMAS rule.

51/4 * (19/17 / 49/6) / 19/3

= 51/4 * ( 19/17 * 6/49) * 3/19 = 27/98 - Question 33 of 50
##### 33. Question

A sum of money becomes double itself in 8 years at simple interest. How many times will it become 10 years at the same rate?

CorrectP —- 2P —- 8 years

2 1/4 P —- 10 yearsIncorrectP —- 2P —- 8 years

2 1/4 P —- 10 years - Question 34 of 50
##### 34. Question

The sum of money at compound interest amounts to thrice itself in 3 years. In how many years will it be 9 times itself?

Correct100 —- 300 — 3

900 — 3

—-

6 yearsIncorrect100 —- 300 — 3

900 — 3

—-

6 years - Question 35 of 50
##### 35. Question

Find the simple interest on Rs.500 for 9 months at 6 paisa per month?

CorrectI = (500*9*6)/100 = 270

IncorrectI = (500*9*6)/100 = 270

- Question 36 of 50
##### 36. Question

A starts business with a capital of Rs.1200 B and C join with some investments after 3 and 6 months respectively. If the end of a year, the profit is divided in the ratio 2:3:5 respectively. What is B’s investment in the business?

Correct1200 * 12: x * 9 = 2:3

x = 2400Incorrect1200 * 12: x * 9 = 2:3

x = 2400 - Question 37 of 50
##### 37. Question

Three 6 faced dice are thrown together. The probability that exactly two dice show the same number on them is -.

CorrectUsing question number 11 and 12, we get the probability as

1 – (1/36 + 5/9) = 5/12IncorrectUsing question number 11 and 12, we get the probability as

1 – (1/36 + 5/9) = 5/12 - Question 38 of 50
##### 38. Question

Pipe A can fill a tank in 5 hours, pipe B in 10 hours and pipe C in 30 hours. If all the pipes are open, in how many hours will the tank be filled?

CorrectPart filled by A + B + C in 1 hour = 1/5 + 1/10 + 1/30 = 1/3

All the three pipes together will fill the tank in 3 hours.IncorrectPart filled by A + B + C in 1 hour = 1/5 + 1/10 + 1/30 = 1/3

All the three pipes together will fill the tank in 3 hours. - Question 39 of 50
##### 39. Question

Ravi invested certain amount for two rates of simple interests at 6% p.a. and 7% p.a. What is the ratio of Ravi’s investments if the interests from those investments are equal?

CorrectLet x be the investment of Ravi in 6% and y be in 7%

x(6)(n)/100 = y(7)(n)/100

=> x/y = 7/6

x : y = 7 : 6IncorrectLet x be the investment of Ravi in 6% and y be in 7%

x(6)(n)/100 = y(7)(n)/100

=> x/y = 7/6

x : y = 7 : 6 - Question 40 of 50
##### 40. Question

A train 125 m long passes a man, running at 5 km/hr in the same direction in which the train is going, in 10 sec. The speed of the train is?

CorrectSpeed of the train relative to man = 125/10 = 25/2 m/sec.

= 25/2 * 18/5 = 45 km/hr

Let the speed of the train be x km/hr. Then, relative speed = (x – 5) km/hr.

x – 5 = 45 => x = 50 km/hr.IncorrectSpeed of the train relative to man = 125/10 = 25/2 m/sec.

= 25/2 * 18/5 = 45 km/hr

Let the speed of the train be x km/hr. Then, relative speed = (x – 5) km/hr.

x – 5 = 45 => x = 50 km/hr. - Question 41 of 50
##### 41. Question

A candidate who gets 30% of the marks fails by 50 marks. But another candidate who gets 45% marks gets 25 marks more than necessary for passing. Find the number of marks for passing?

Correct30% ———— 50

45% ———— 25

———————-

15% ————- 75

30% ————– ?

150 + 50 = 200 MarksIncorrect30% ———— 50

45% ———— 25

———————-

15% ————- 75

30% ————– ?

150 + 50 = 200 Marks - Question 42 of 50
##### 42. Question

The C.P of 10 pens is equal to the S.P of 12 pens. Find his gain % or loss%?

Correct10 CP = 12 SP

12 — 2 CP loss

100 — ? => 16 2/3%Incorrect10 CP = 12 SP

12 — 2 CP loss

100 — ? => 16 2/3% - Question 43 of 50
##### 43. Question

Two third of three- fifth of one fourth of a number is 24, what is 30% of that number?

Correctx * 2/3 * 3/5 * 1/4 = 24

x = 240

240 * 30/100 = 72Incorrectx * 2/3 * 3/5 * 1/4 = 24

x = 240

240 * 30/100 = 72 - Question 44 of 50
##### 44. Question

The sector of a circle has radius of 21 cm and central angle 135

^{o}. Find its perimeter?CorrectPerimeter of the sector = length of the arc + 2(radius)

= (135/360 * 2 * 22/7 * 21) + 2(21)

= 49.5 + 42 = 91.5 cmIncorrectPerimeter of the sector = length of the arc + 2(radius)

= (135/360 * 2 * 22/7 * 21) + 2(21)

= 49.5 + 42 = 91.5 cm - Question 45 of 50
##### 45. Question

In what time a sum of money double itself at 3% per annum simple interest?

CorrectP = (P*3*R)/100

R = 33 1/3%IncorrectP = (P*3*R)/100

R = 33 1/3% - Question 46 of 50
##### 46. Question

The simple form of the ratio 2/3:2/5 is?

Correct2/3 : 2/5 = 10:6 = 5:3

Incorrect2/3 : 2/5 = 10:6 = 5:3

- Question 47 of 50
##### 47. Question

If x;Y = 5:2, then (8x + 9y):(8x + 2y) is :

CorrectLet x = 5k and y = 2k.

Then, (8x + 9y)/(8x + 2y)

= [(8 * 5k) + (9 * 2k)] / [(8 * 5k) + (2 * 2k)] = 58k/44k = 29/22

(8x + 9y):(8x + 2y) = 29:22IncorrectLet x = 5k and y = 2k.

Then, (8x + 9y)/(8x + 2y)

= [(8 * 5k) + (9 * 2k)] / [(8 * 5k) + (2 * 2k)] = 58k/44k = 29/22

(8x + 9y):(8x + 2y) = 29:22 - Question 48 of 50
##### 48. Question

Income and expenditure of a person are in the ratio 5 : 4. If the income of the person is Rs. 18000, then find his savings.

CorrectLet the income and the expenditure of the person be Rs. 5x and Rs. 4x respectively.

Income, 5x = 18000 => x = 3600

Savings = Income – expenditure = 5x – 4x = x

So, savings = Rs. 3600.IncorrectLet the income and the expenditure of the person be Rs. 5x and Rs. 4x respectively.

Income, 5x = 18000 => x = 3600

Savings = Income – expenditure = 5x – 4x = x

So, savings = Rs. 3600. - Question 49 of 50
##### 49. Question

The ratio between the school ages of Neelam and Shaan is 5:6 respectively. If the ratio between the one-third age of Neelam and half of Shaan’s age of 5:9, then what is the school age of Shaan?

CorrectLet the school ages of Neelam and Shaan be 5x and 6x years respectively.

Then, (1/3 * 5x)/(1/2 * 6x) = 5/9

15 = 15

Thus, Shaan’s age cannot be determined.IncorrectLet the school ages of Neelam and Shaan be 5x and 6x years respectively.

Then, (1/3 * 5x)/(1/2 * 6x) = 5/9

15 = 15

Thus, Shaan’s age cannot be determined. - Question 50 of 50
##### 50. Question

A sum of money place at compound interest doubles itself in 4 years. In how many years will it amount to eight times itself?

Correct100 —- 200 —- 4

400 —- 4

800 —- 4

——

12 yearsIncorrect100 —- 200 —- 4

400 —- 4

800 —- 4

——

12 years