MAT Online Test Series 1  MAT Mock Test  MAT Sample Papers 
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MAT Online Test in English – Series 1, MAT Free Online Test Series 1. MAT Free Mock Test Exam 2019. MAT Exam Free Online Quiz 2019, MAT Full Online Mock Test Series 1st in English. MAT Free Mock Test Series in English. MAT Free Mock Test Series 1. MAT English Language Online Test in English Series 1st. Take MAT Online Quiz. The MAT Full online mock test paper is free for all students. MAT Question and Answers in English and Hindi Series 1. Here we are providing MAT Full Mock Test Paper in English. MAT Mock Test Series 1st 2019. Now Test your self for MAT Exam by using below quiz…
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Question 1 of 50
1. Question
Find the H.C.F of 12, 16, 18 and 24?
Correct
Incorrect

Question 2 of 50
2. Question
How much 60% of 50 is greater than 40% of 30?
Correct
(60/100) * 50 – (40/100) * 30
30 – 12 = 18Incorrect
(60/100) * 50 – (40/100) * 30
30 – 12 = 18 
Question 3 of 50
3. Question
A jogger running at 9 km/hr along side a railway track is 240 m ahead of the engine of a 120 m long train running at 45 km/hr in the same direction. In how much time will the train pass the jogger?
Correct
Speed of train relative to jogger = 45 – 9 = 36 km/hr.
= 36 * 5/18 = 10 m/sec.
Distance to be covered = 240 + 120 = 360 m.
Time taken = 360/10 = 36 sec.Incorrect
Speed of train relative to jogger = 45 – 9 = 36 km/hr.
= 36 * 5/18 = 10 m/sec.
Distance to be covered = 240 + 120 = 360 m.
Time taken = 360/10 = 36 sec. 
Question 4 of 50
4. Question
Two trains of length 100 m and 200 m are 100 m apart. They start moving towards each other on parallel tracks, at speeds 54 kmph and 72 kmph. After how much time will the trains meet?
Correct
They are moving in opposite directions, relative speed is equal to the sum of their speeds.
Relative speed = (54 + 72)*5/18 = 7*5 = 35 mps.
The time required = d/s = 100/35 = 20/7 sec.Incorrect
They are moving in opposite directions, relative speed is equal to the sum of their speeds.
Relative speed = (54 + 72)*5/18 = 7*5 = 35 mps.
The time required = d/s = 100/35 = 20/7 sec. 
Question 5 of 50
5. Question
What should be the least number to be added to the 51234 number to make it divisible by 9?
Correct
The least number to be added to the numbers to make them divisible by 9 is equal to the difference of the least multiple of 9 greater than the sum of the digits and sum of the digits.
Sum of digits = 15.
Nearest multiple of 9 greater than sum of digits = 18.
Hence 3 has to be added.Incorrect
The least number to be added to the numbers to make them divisible by 9 is equal to the difference of the least multiple of 9 greater than the sum of the digits and sum of the digits.
Sum of digits = 15.
Nearest multiple of 9 greater than sum of digits = 18.
Hence 3 has to be added. 
Question 6 of 50
6. Question
Product of two coprime numbers is 117. Their L.C.M should be:
Correct
H.C.F of coprime numbers is 1.
So, L.C.M = 117/1 = 117.Incorrect
H.C.F of coprime numbers is 1.
So, L.C.M = 117/1 = 117. 
Question 7 of 50
7. Question
10 camels cost as much as 24 horses, 16 horses cost as much as 4 oxen and 6 oxen as much as 4 elephants. If the cost of 10 elephants is Rs.170000, find the cost of a camel?
Correct
Cost of the camel = P
10 camels = 24 horses
16 horses = 4 oxen
6 oxen = 4 elephants
10 elephants = Rs.170000
P = Rs.[(24 * 4 * 4 * 170000)/(10 * 16 * 6 * 10)]
P = Rs.(65280000/9600) => P = Rs.6800Incorrect
Cost of the camel = P
10 camels = 24 horses
16 horses = 4 oxen
6 oxen = 4 elephants
10 elephants = Rs.170000
P = Rs.[(24 * 4 * 4 * 170000)/(10 * 16 * 6 * 10)]
P = Rs.(65280000/9600) => P = Rs.6800 
Question 8 of 50
8. Question
In a partnership between A, B and C. A’s capital is Rs.5000. If his share of a profit of Rs.800 is Rs.200 and C’s share is Rs.130, what is B’s capital?
Correct
200 + 130 = 330
800 – 330 = 470
200 — 5000
470 — ? => 11750Incorrect
200 + 130 = 330
800 – 330 = 470
200 — 5000
470 — ? => 11750 
Question 9 of 50
9. Question
The average of 9 observations was 9, that of the 1^{st} of 5 being 10 and that of the last 5 being 8. What was the 5^{th} observation?
Correct
1 to 9 = 9 * 9 = 81
1 to 5 = 5 * 10 = 50
5 to 9 = 5 * 8 = 40
5^{th} = 50 + 40 = 90 – 81 = 9Incorrect
1 to 9 = 9 * 9 = 81
1 to 5 = 5 * 10 = 50
5 to 9 = 5 * 8 = 40
5^{th} = 50 + 40 = 90 – 81 = 9 
Question 10 of 50
10. Question
The difference between a number and its threefifth is 50. What is the number?
Correct
Let the number be x. Then,
x – 3/5 x = 50 => 2/5 x = 50
x = (50 * 5)/2 = 125.Incorrect
Let the number be x. Then,
x – 3/5 x = 50 => 2/5 x = 50
x = (50 * 5)/2 = 125. 
Question 11 of 50
11. Question
Albert buys 4 horses and 9 cows for Rs. 13,400. If he sells the horses at 10% profit and the cows at 20% profit, then he earns a total profit of Rs. 1880. The cost of a horse is:
Correct
Let C.P. of each horse be Rs. x and C.P. of each cow be Rs. y.
Then, 4x + 9y = 13400 — (i)
And, 10% of 4x + 20% of 9y = 1880
2/5 x + 9/5 y = 1880 => 2x + 9y = 9400 — (ii)
Solving (i) and (ii), we get : x = 2000 and y = 600.
Cost price of each horse = Rs. 2000.Incorrect
Let C.P. of each horse be Rs. x and C.P. of each cow be Rs. y.
Then, 4x + 9y = 13400 — (i)
And, 10% of 4x + 20% of 9y = 1880
2/5 x + 9/5 y = 1880 => 2x + 9y = 9400 — (ii)
Solving (i) and (ii), we get : x = 2000 and y = 600.
Cost price of each horse = Rs. 2000. 
Question 12 of 50
12. Question
The length of a rectangular floor is more than its breadth by 200%. If Rs. 324 is required to paint the floor at the rate of Rs. 3 per sq m, then what would be the length of the floor?
Correct
Let the length and the breadth of the floor be l m and b m respectively.
l = b + 200% of b = l + 2b = 3b
Area of the floor = 324/3 = 108 sq m
l b = 108 i.e., l * l/3 = 108
l^{2} = 324 => l = 18.Incorrect
Let the length and the breadth of the floor be l m and b m respectively.
l = b + 200% of b = l + 2b = 3b
Area of the floor = 324/3 = 108 sq m
l b = 108 i.e., l * l/3 = 108
l^{2} = 324 => l = 18. 
Question 13 of 50
13. Question
When 5% is lost in grinding wheat, a country has to import 20 million bags; but when only 2% is lost, it has to import only 15 million bags. Find the quantity of wheat, which grows in the country?
Correct
5% – 2% = 3%
3% — 5
100% — ? => 166 2/3Incorrect
5% – 2% = 3%
3% — 5
100% — ? => 166 2/3 
Question 14 of 50
14. Question
Eight men, ten women and six boys together can complete a piece of work in eight days. In how many days can 20 women complete the same work if 20 men can complete it in 12 days?
Correct
Let the number of units which can be completed by each man, each women and each boy be m/day, w/day and b/day respectively.
Work = 8(8m + 10w +6b)units = 12(20m)
10w +6b = 22m
b is unknown.
We cannot find the relation between m and w.
We cannot answer the question.Incorrect
Let the number of units which can be completed by each man, each women and each boy be m/day, w/day and b/day respectively.
Work = 8(8m + 10w +6b)units = 12(20m)
10w +6b = 22m
b is unknown.
We cannot find the relation between m and w.
We cannot answer the question. 
Question 15 of 50
15. Question
A and B began business with Rs.3000 and Rs.4000 after 8 months, A withdraws Rs.1000 and B advances Rs.1000 more. At the end of the year, their profits amounted to Rs.630 find the share of A.
Correct
(3*8 + 2*4):(4*8 + 5*4)
8:13
8/21 * 630 = 240Incorrect
(3*8 + 2*4):(4*8 + 5*4)
8:13
8/21 * 630 = 240 
Question 16 of 50
16. Question
(64 + 9 + 9) / (2 * 20 + 1) = ?
Correct
(64 + 9 + 9) / (2 * 20 + 1) = 82/41 = 2
Incorrect
(64 + 9 + 9) / (2 * 20 + 1) = 82/41 = 2

Question 17 of 50
17. Question
30 men can do a work in 40 days. When should 20 men leave the work so that the entire work is completed in 40 days after they leave the work?
Correct
Total work to be done = 30 * 40 = 1200
Let 20 men leave the work after ‘P’ days, so that the remaining work is completed in 40 days after they leave the work.
40P + (20 * 40) = 1200
40P = 400 => P = 10 daysIncorrect
Total work to be done = 30 * 40 = 1200
Let 20 men leave the work after ‘P’ days, so that the remaining work is completed in 40 days after they leave the work.
40P + (20 * 40) = 1200
40P = 400 => P = 10 days 
Question 18 of 50
18. Question
How many times the keys of a typewriter have to be pressed in order to write first 400 counting numbers?
Correct
1 to 9 = 9 * 1 = 9
10 to 99 = 90 * 2 = 180
100 to 400 = 301 * 3 = 903
———–
1092Incorrect
1 to 9 = 9 * 1 = 9
10 to 99 = 90 * 2 = 180
100 to 400 = 301 * 3 = 903
———–
1092 
Question 19 of 50
19. Question
The H.C.F of two numbers is 8. Which of the following can never be their L.C.M?
Correct
H.C.F of two numbers divides their L.C.M exactly. Clearly, 8 is not a factor of 60.
Incorrect
H.C.F of two numbers divides their L.C.M exactly. Clearly, 8 is not a factor of 60.

Question 20 of 50
20. Question
The subduplicate ratio of 1:4 is
Correct
√1:√4 = 1:2
Incorrect
√1:√4 = 1:2

Question 21 of 50
21. Question
Two men Amar and Bhavan have the ratio of their monthly incomes as 6:5. The ratio of their monthly expenditures is 3:2. If Bhavan saves onefourth of his income, find the ratio of their monthly savings?
Correct
Let the monthly incomes of Amar and Bhavan be 6x and 5x respectively.
Let the monthly expenditures of Amar and Bhavan be 3y and 2y respectively.
Savings of Bhavan every month = 1/4 (5x)
=(his income) – (his expenditure) = 5x – 2y
=> 5x = 20x – 8y => y = 15x/8
Ratio of savings of Amar and Bhavan
= 6x – 3y : 1/4 (5x) = 6x – 3(15x/8) : 5x/4
= 3x/8 : 5x/4 => 3:10Incorrect
Let the monthly incomes of Amar and Bhavan be 6x and 5x respectively.
Let the monthly expenditures of Amar and Bhavan be 3y and 2y respectively.
Savings of Bhavan every month = 1/4 (5x)
=(his income) – (his expenditure) = 5x – 2y
=> 5x = 20x – 8y => y = 15x/8
Ratio of savings of Amar and Bhavan
= 6x – 3y : 1/4 (5x) = 6x – 3(15x/8) : 5x/4
= 3x/8 : 5x/4 => 3:10 
Question 22 of 50
22. Question
The curved surface of a sphere is 64 π cm^{2}. Find its radius?
Correct
4 πr^{2 }= 64 => r = 4
Incorrect
4 πr^{2 }= 64 => r = 4

Question 23 of 50
23. Question
A train 540 meters long is running with a speed of 54 kmph. The time taken by it to cross a tunnel 180 meters long is?
Correct
D = 540 + 180 = 720
S = 54 * 5/18 = 15 mps
T = 720/15 = 48 secIncorrect
D = 540 + 180 = 720
S = 54 * 5/18 = 15 mps
T = 720/15 = 48 sec 
Question 24 of 50
24. Question
A, B and C started a business with capitals of Rs. 8000, Rs. 10000 and Rs. 12000 respectively. At the end of the year, the profit share of B is Rs. 1500. The difference between the profit shares of A and C is?
Correct
Ratio of investments of A, B and C is 8000 : 10000 : 12000 = 4 : 5 : 6
And also given that, profit share of B is Rs. 1500
=> 5 parts out of 15 parts is Rs. 1500
Now, required difference is 6 – 4 = 2 parts
Required difference = 2/5 (1500) = Rs. 600Incorrect
Ratio of investments of A, B and C is 8000 : 10000 : 12000 = 4 : 5 : 6
And also given that, profit share of B is Rs. 1500
=> 5 parts out of 15 parts is Rs. 1500
Now, required difference is 6 – 4 = 2 parts
Required difference = 2/5 (1500) = Rs. 600 
Question 25 of 50
25. Question
Ravi invested certain amount for two rates of simple interests at 6% p.a. and 7% p.a. What is the ratio of Ravi’s investments if the interests from those investments are equal?
Correct
Let x be the investment of Ravi in 6% and y be in 7%
x(6)(n)/100 = y(7)(n)/100
=> x/y = 7/6
x : y = 7 : 6Incorrect
Let x be the investment of Ravi in 6% and y be in 7%
x(6)(n)/100 = y(7)(n)/100
=> x/y = 7/6
x : y = 7 : 6 
Question 26 of 50
26. Question
A motorcyclist goes from Bombay to Pune, a distance of 192 kms at an average of 32 kmph speed. Another man starts from Bombay by car 2 ½ hours after the first, and reaches Pune ½ hour earlier. What is the ratio of the speed of the motorcycle and the car?
Correct
T = 192/32 = 6 h
T = 6 – 3 = 3
Time Ratio = 6:3 = 2:1
Speed Ratio = 1:2Incorrect
T = 192/32 = 6 h
T = 6 – 3 = 3
Time Ratio = 6:3 = 2:1
Speed Ratio = 1:2 
Question 27 of 50
27. Question
(180/37 of 14.8) / (17/60.1 of 180.30) = ?
Correct
(180/37 of 14.8) / (17/60.1 of 180.30) = 72/51 = 24/17 = 1.41
Incorrect
(180/37 of 14.8) / (17/60.1 of 180.30) = 72/51 = 24/17 = 1.41

Question 28 of 50
28. Question
If 5% more is gained by selling an article for Rs. 350 than by selling it for Rs. 340, the cost of the article is:
Correct
Let C.P. be Rs. x.
Then, 5% of x = 350 – 340 = 10
x/20 = 10 => x = 200Incorrect
Let C.P. be Rs. x.
Then, 5% of x = 350 – 340 = 10
x/20 = 10 => x = 200 
Question 29 of 50
29. Question
The cost price of an article is 64% of the marked price. Calculate the gain percent after allowing a discount of 12%?
Correct
Let marked price = Rs. 100.
Then, C.P. = RS. 64, S.P. = Rs. 88
Gain % = 24/64 * 100 = 37.5%.Incorrect
Let marked price = Rs. 100.
Then, C.P. = RS. 64, S.P. = Rs. 88
Gain % = 24/64 * 100 = 37.5%. 
Question 30 of 50
30. Question
Thrice the square of a natural number decreased by 4 times the number is equal to 50 more than the number. The number is:
Correct
Let the number be x. Then,
3x^{2} – 4x = x + 50
3x^{2} – 5x – 50 = 0
(3x + 10)(x – 5) = 0
x = 5Incorrect
Let the number be x. Then,
3x^{2} – 4x = x + 50
3x^{2} – 5x – 50 = 0
(3x + 10)(x – 5) = 0
x = 5 
Question 31 of 50
31. Question
A candidate got 35% of the votes polled and he lost to his rival by 2250 votes. How many votes were cast?
Correct
35%———–L
65%———–W
——————
30%———2250
100%———? => 7500Incorrect
35%———–L
65%———–W
——————
30%———2250
100%———? => 7500 
Question 32 of 50
32. Question
Two pipes A and B can separately fill a tank in 2 minutes and 15 minutes respectively. Both the pipes are opened together but 4 minutes after the start the pipe A is turned off. How much time will it take to fill the tank?
Correct
4/12 + x/15 = 1
x = 10Incorrect
4/12 + x/15 = 1
x = 10 
Question 33 of 50
33. Question
Two third of three fifth of one fourth of a number is 24, what is 30% of that number?
Correct
x * 2/3 * 3/5 * 1/4 = 24
x = 240
240 * 30/100 = 72Incorrect
x * 2/3 * 3/5 * 1/4 = 24
x = 240
240 * 30/100 = 72 
Question 34 of 50
34. Question
A cylinder and a cone have a same height and same radius of the base. The ratio between the volumes of the cylinder and cone is?
Correct
Incorrect

Question 35 of 50
35. Question
Sum of two numbers is 15. Two times of the first exceeds by 5 from the three times of the other. Then the numbers will be?
Correct
x + y = 15
2x – 3y = 5
x = 10 y = 5Incorrect
x + y = 15
2x – 3y = 5
x = 10 y = 5 
Question 36 of 50
36. Question
Find the roots of the quadratic equation: 2x^{2} + 3x – 9 = 0?
Correct
2x^{2} + 6x – 3x – 9 = 0
2x(x + 3) – 3(x + 3) = 0
(x + 3)(2x – 3) = 0
=> x = 3 or x = 3/2.Incorrect
2x^{2} + 6x – 3x – 9 = 0
2x(x + 3) – 3(x + 3) = 0
(x + 3)(2x – 3) = 0
=> x = 3 or x = 3/2. 
Question 37 of 50
37. Question
Eight years ago, Ajay’s age was 4/3 times that of Vijay. Eight years hence, Ajay’s age will be 6/5 times that of Vijay. What is the present age of Ajay?
Correct
Let the present ages of Ajay and Vijay be ‘A’ and ‘V’ years respectively.
A – 8 = 4/3 (V – 8) and A + 8 = 6/5 (V + 8)
3/4(A – 8) = V – 8 and 5/6(A + 8) = V + 8
V = 3/4 (A – 8) + 8 = 5/6 (A + 8) – 8
=> 3/4 A – 6 + 8 = 5/6 A + 20/3 – 8
=> 10 – 20/3 = 10/12 A – 9/12 A
=> 10/3 = A/12 => A = 40.Incorrect
Let the present ages of Ajay and Vijay be ‘A’ and ‘V’ years respectively.
A – 8 = 4/3 (V – 8) and A + 8 = 6/5 (V + 8)
3/4(A – 8) = V – 8 and 5/6(A + 8) = V + 8
V = 3/4 (A – 8) + 8 = 5/6 (A + 8) – 8
=> 3/4 A – 6 + 8 = 5/6 A + 20/3 – 8
=> 10 – 20/3 = 10/12 A – 9/12 A
=> 10/3 = A/12 => A = 40. 
Question 38 of 50
38. Question
Two men can complete a piece of work in four days. Two women can complete the same work in eight days. Four boys can complete the same work in five days. If four men, eight women and 20 boys work together in how many days can the work be completed?
Correct
Two men take four days to complete the work four men would take (2 * 4)/4 = 2 days to complete it.
Similarly four women would take two days to complete it and 20 children would take one day to complete it.
All the three groups working togerther will complete 1/2 + 1/2 + 1/1 work in a day
= 2 times the unit work in a day.
They will take 1/2 a day to complete it working together.Incorrect
Two men take four days to complete the work four men would take (2 * 4)/4 = 2 days to complete it.
Similarly four women would take two days to complete it and 20 children would take one day to complete it.
All the three groups working togerther will complete 1/2 + 1/2 + 1/1 work in a day
= 2 times the unit work in a day.
They will take 1/2 a day to complete it working together. 
Question 39 of 50
39. Question
If Re.1 amounts to Rs.9 over a period of 20 years. What is the rate of simple interest?
Correct
8 = (1*20*R)/100
R = 40%Incorrect
8 = (1*20*R)/100
R = 40% 
Question 40 of 50
40. Question
Two men Amar and Bhuvan have the ratio of their monthly incomes as 6 : 5. The ratio of their monthly expenditures is 3 : 2. If Bhuvan saves onefourth of his income, find the ratio of their monthly savings?
Correct
Let the monthly incomes of Amar and Bhuvan be 6x and 5x respectively.
Let the monthly expenditure of Amar and Bhuvan be 3y and 2y respectively.
Savings of Bhuvan every month = 1/4(5x)
= (His income) – (His expenditure) = 5x – 2y.
=> 5x = 20x – 8y => y = 15x/8.
Ratio of savings of Amar and Bhuvan
= 6x – 3y : 1/4(5x) = 6x – 3(15x/8) : 5x/4 = 3x/8 : 5x/4
= 3 : 10.Incorrect
Let the monthly incomes of Amar and Bhuvan be 6x and 5x respectively.
Let the monthly expenditure of Amar and Bhuvan be 3y and 2y respectively.
Savings of Bhuvan every month = 1/4(5x)
= (His income) – (His expenditure) = 5x – 2y.
=> 5x = 20x – 8y => y = 15x/8.
Ratio of savings of Amar and Bhuvan
= 6x – 3y : 1/4(5x) = 6x – 3(15x/8) : 5x/4 = 3x/8 : 5x/4
= 3 : 10. 
Question 41 of 50
41. Question
A man rows his boat 85 km downstream and 45 km upstream, taking 2 1/2 hours each time. Find the speed of the stream?
Correct
Speed downstream = d/t = 85/(2 1/2) = 34 kmph
Speed upstream = d/t = 45/(2 1/2) = 18 kmph
The speed of the stream = (34 – 18)/2 = 8 kmphIncorrect
Speed downstream = d/t = 85/(2 1/2) = 34 kmph
Speed upstream = d/t = 45/(2 1/2) = 18 kmph
The speed of the stream = (34 – 18)/2 = 8 kmph 
Question 42 of 50
42. Question
A, B and C are partners in a business. Their capitals are respectively, Rs.5000, Rs.6000 and Rs.4000. A gets 30% of the total profit for managing the business. The remaining profit is divided among three in the ratio of their capitals. In the end of the year, the profit of A is Rs.200 more than the sum of the profits of B and C. Find the total profit.
Correct
A:B:C = 5:6:4
Let the total profit = 100 – 30 = 70
5/15 * 70 = 70/3
A share = 70/3 + 30 = 160/3
B + C share = 100 – 160/3 = 140/3
A(B+C) = 160/3 – 140/3 = 20/3
20/3 — 200
100 — ? => 3000Incorrect
A:B:C = 5:6:4
Let the total profit = 100 – 30 = 70
5/15 * 70 = 70/3
A share = 70/3 + 30 = 160/3
B + C share = 100 – 160/3 = 140/3
A(B+C) = 160/3 – 140/3 = 20/3
20/3 — 200
100 — ? => 3000 
Question 43 of 50
43. Question
A, B and C start at the same time in the same direction to run around a circular stadium. A completes a round in 252 seconds, B in 308 seconds and C in 198 seconds, all starting at the same point. After what time will they meet again at the starting point?
Correct
L.C.M of 252, 308 and 198 = 2772
So, A, B and C will again meet at the starting point in 2772 sec, i.e., 46 min 12 sec.Incorrect
L.C.M of 252, 308 and 198 = 2772
So, A, B and C will again meet at the starting point in 2772 sec, i.e., 46 min 12 sec. 
Question 44 of 50
44. Question
How much interest can a person get on Rs. 8200 at 17.5% p.a. simple interest for a period of two years and six months?
Correct
I = (8200 * 2.5 * 17.5)/100 = (8200 * 5 * 35)/(100 * 2 * 2) = Rs. 3587.50
Incorrect
I = (8200 * 2.5 * 17.5)/100 = (8200 * 5 * 35)/(100 * 2 * 2) = Rs. 3587.50

Question 45 of 50
45. Question
(112 * 5^{4}) = ?
Correct
(112 * 5^{4}) = 112 * (10/2)^{4}
= (112 * 10^{4})/24 = 1120000/16 = 70000Incorrect
(112 * 5^{4}) = 112 * (10/2)^{4}
= (112 * 10^{4})/24 = 1120000/16 = 70000 
Question 46 of 50
46. Question
In a pair of fractions, fraction A is twice the fraction B and the product of two fractions is 2/25. What is the value of fraction A?
Correct
A = 2B => B = 1/2 A, so, AB = 2/25
1/2 A^{2} = 2/25
A^{2} = 4/25
A = 2/5Incorrect
A = 2B => B = 1/2 A, so, AB = 2/25
1/2 A^{2} = 2/25
A^{2} = 4/25
A = 2/5 
Question 47 of 50
47. Question
The compound interest accrued on an amount of Rs.44000 at the end of two years is Rs.1193.60. What would be the simple interest accrued on the same amount at the same rate in the same period?
Correct
Let the rate of interest be R% p.a.
4400{[1 + R/100]^{2} – 1} = 11193.60
[1 + R/100]^{2} = (44000 + 11193.60)/44000
[1 + R/100]^{2} = 1 + 2544/1000 = 1 + 159/625
[1 + R/100]^{2} = 784/625 = (28/25)^{2}
1 + R/100 = 28/25
R/100 = 3/25
Therefore R = 12 SI on Rs.44000 at 12% p.a. for two years = 44000(2)(12)/100
=Rs.10560Incorrect
Let the rate of interest be R% p.a.
4400{[1 + R/100]^{2} – 1} = 11193.60
[1 + R/100]^{2} = (44000 + 11193.60)/44000
[1 + R/100]^{2} = 1 + 2544/1000 = 1 + 159/625
[1 + R/100]^{2} = 784/625 = (28/25)^{2}
1 + R/100 = 28/25
R/100 = 3/25
Therefore R = 12 SI on Rs.44000 at 12% p.a. for two years = 44000(2)(12)/100
=Rs.10560 
Question 48 of 50
48. Question
If 12 men do a work in 80 days, in how many days will 16 men do it?
Correct
12 * 80 = 16 * x
x = 60 daysIncorrect
12 * 80 = 16 * x
x = 60 days 
Question 49 of 50
49. Question
(0.9 * 0.9 – 0.8 * 0.8)/1.7 = ?
Correct
As numerator is of the form a^{2} – b^{2} = (a + b) (a – b), so the given expression simplifying becomes
(0.9^{2} – 0.8^{2})/(0.9 + 0.8) (0.9 + 0.8) (0.9 – 0.8)/0.9 + 0.8 = 0.1Incorrect
As numerator is of the form a^{2} – b^{2} = (a + b) (a – b), so the given expression simplifying becomes
(0.9^{2} – 0.8^{2})/(0.9 + 0.8) (0.9 + 0.8) (0.9 – 0.8)/0.9 + 0.8 = 0.1 
Question 50 of 50
50. Question
The average of runs of a cricket player of 10 innings was 32. How many runs must he make in his next innings so as to increase his average of runs by 4?
Correct
Average after 11 innings = 36
Required number of runs
= (36 * 11) – (32 * 10) = 396 – 320 = 76.Incorrect
Average after 11 innings = 36
Required number of runs
= (36 * 11) – (32 * 10) = 396 – 320 = 76.