RBI Assistant Online Test, RBI Assistant Mains Online Test Series 4
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RBI Assistant Online Test, RBI Assistant Mains Online Test Series 4. RBI Exam Online Test 2019. CAknowledge RBI Assistant Mains Free Mock Test Exam 2019. RBI Assistant Mains Exam Free Online Quiz 2019, RBI Assistant Mains Full Online Mock Test Series 4th in English.To Analyse your preparation, one should attempt the test series on a regular basis to score more in the examination. Start FREE mock test and get top rank among all applicants whoever are participating in the exam. RBI Assistant Mains Question and Answers in English and Hindi Series 4. Here we are providing RBI Assistant Mains Full Mock Test Paper in English. RBI Assistant Mains Mock Test Series 4th 2019. Now Test your self for RBI Assistant Mains Exam by using below quiz…
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Question 1 of 50
1. Question
43% of 784 = ?
Correct
? = 43/100 * 784 = 337.12
Incorrect
? = 43/100 * 784 = 337.12

Question 2 of 50
2. Question
The H.C.F of two numbers is 11 and their L.C.M is 7700. If one of the numbers is 275, then the other is:
Correct
Other number = (11 * 7700)/275 = 308.
Incorrect
Other number = (11 * 7700)/275 = 308.

Question 3 of 50
3. Question
A is twice as fast as B. If B alone can do a piece of work in 30 days, in what time can A and B together complete the work?
Correct
A can do the work in 30/2 i.e., 15 days.
A and B’s one day’s work = 1/15 + 1/30 = (2 + 1)/30 = 1/10
So A and B together can do the work in 10 days.Incorrect
A can do the work in 30/2 i.e., 15 days.
A and B’s one day’s work = 1/15 + 1/30 = (2 + 1)/30 = 1/10
So A and B together can do the work in 10 days. 
Question 4 of 50
4. Question
Divide Rs.118000 among three persons A, B and C such that the ratio of the shares of A and B is 3:4 and that of B:C is 5:6?
Correct
Compound ratio of A:B:C
A:B = 3:4
B:C = 5:6
———
A:B:C = 15:20:24
We can divide Rs.118000 in this ratio.
Share of A = 15/59 * 118000 = 30000
Share of B = 20/59 * 118000 = 40000
Share of C = 24/59 * 118000 = 48000Incorrect
Compound ratio of A:B:C
A:B = 3:4
B:C = 5:6
———
A:B:C = 15:20:24
We can divide Rs.118000 in this ratio.
Share of A = 15/59 * 118000 = 30000
Share of B = 20/59 * 118000 = 40000
Share of C = 24/59 * 118000 = 48000 
Question 5 of 50
5. Question
The wheels revolve round a common horizontal axis. They make 15, 20 and 48 revolutions in a minute respectively. Starting with a certain point on the circumference down wards. After what interval of time will they come together in the same position?
Correct
Time for one revolution = 60/15 = 4
60/ 20 = 3
60/48 = 5/4
LCM of 4, 3, 5/4
LCM of Numerators/HCF of Denominators =
60/1 = 60Incorrect
Time for one revolution = 60/15 = 4
60/ 20 = 3
60/48 = 5/4
LCM of 4, 3, 5/4
LCM of Numerators/HCF of Denominators =
60/1 = 60 
Question 6 of 50
6. Question
What is the least number, which is perfect square but contains 2700 as its factor?
Correct
900 * 3 * 3 = 8100
Incorrect
900 * 3 * 3 = 8100

Question 7 of 50
7. Question
Nitin borrowed some money at the rate of 6% p.a. for the first three years, 9% p.a. for the next five years and 13% p.a. for the period beyond eight years. If the total interest paid by him at the end of eleven years is Rs. 8160, how much money did he borrow?
Correct
Let the sum be Rs. x. Then,
[(x * 6 * 3)/100] + [(x * 9 * 5)/100] + [(x * 13 * 3)/100] = 8160
18x + 45x + 39x = (8160 * 100)
102x = 816000 => x = 8000.Incorrect
Let the sum be Rs. x. Then,
[(x * 6 * 3)/100] + [(x * 9 * 5)/100] + [(x * 13 * 3)/100] = 8160
18x + 45x + 39x = (8160 * 100)
102x = 816000 => x = 8000. 
Question 8 of 50
8. Question
A man gets a simple interest of Rs.500 on a certain principal at the rate of 5% p.a in two years. Find the compound interest the man will get on twice the principal in two years at the same rate.
Correct
Let the principal be Rs.P
S.I at 5% p.a in 8 years on Rs.P = Rs.500
(P)(8)(5)/100 = 500
P = 1250
C.I on Rs.2P i.e., Rs.2500 at 5% p.a in two years
=2500{ [1 + 5/100]^{2} – 1} = 2500{ 21^{2} – 20^{2} /20^{2}}
= 2500/400(441 – 400)
= 25/4(41) = 1025/4 = Rs.256.25Incorrect
Let the principal be Rs.P
S.I at 5% p.a in 8 years on Rs.P = Rs.500
(P)(8)(5)/100 = 500
P = 1250
C.I on Rs.2P i.e., Rs.2500 at 5% p.a in two years
=2500{ [1 + 5/100]^{2} – 1} = 2500{ 21^{2} – 20^{2} /20^{2}}
= 2500/400(441 – 400)
= 25/4(41) = 1025/4 = Rs.256.25 
Question 9 of 50
9. Question
What is the probability that a leap year has 53 Sundays and 52 Mondays?
Correct
A leap year has 52 weeks and two days
Total number of cases = 7
Number of favourable cases = 1
i.e., {Saturday, Sunday}
Required Probability = 1/7Incorrect
A leap year has 52 weeks and two days
Total number of cases = 7
Number of favourable cases = 1
i.e., {Saturday, Sunday}
Required Probability = 1/7 
Question 10 of 50
10. Question
Find the least number of five digits which is exactly divisible by 12, 15 and 18?
Correct
LCM = 180
180) 10000 (55
9900
———
100
10000 + 180 – 100 = 10080Incorrect
LCM = 180
180) 10000 (55
9900
———
100
10000 + 180 – 100 = 10080 
Question 11 of 50
11. Question
A shopkeeper sold an article offering a discount of 5% and earned a profit of 23.5%. What would have been the percentage of profit earned if no discount was offered?
Correct
Let C.P. be Rs. 100.
Then, S.P. = Rs. 123.50
Let marked price be Rs. x. Then, 95/100 x = 123.50
x = 12350/95 = Rs. 130
Now, S.P. = Rs. 130, C.P. = Rs. 100
Profit % = 30%.Incorrect
Let C.P. be Rs. 100.
Then, S.P. = Rs. 123.50
Let marked price be Rs. x. Then, 95/100 x = 123.50
x = 12350/95 = Rs. 130
Now, S.P. = Rs. 130, C.P. = Rs. 100
Profit % = 30%. 
Question 12 of 50
12. Question
31.2 * 14.5 * 9.6 = ?
Correct
Incorrect

Question 13 of 50
13. Question
A man can row 6 kmph in still water. When the river is running at 1.2 kmph, it takes him 1 hour to row to a place and black. How far is the place?
Correct
M = 6
S = 1.2
DS = 6 + 1.2 = 7.2
US = 6 – 1.2 = 4.8
x/7.2 + x/4.8 = 1
x = 2.88Incorrect
M = 6
S = 1.2
DS = 6 + 1.2 = 7.2
US = 6 – 1.2 = 4.8
x/7.2 + x/4.8 = 1
x = 2.88 
Question 14 of 50
14. Question
If population of certain city increases at the rate of 5%. If population in 1981 was 138915, then population in 1978 was?
Correct
X * (105/100) * (105/100) * (105/100) = 138915
X = 138915/1.157625
X = 120000Incorrect
X * (105/100) * (105/100) * (105/100) = 138915
X = 138915/1.157625
X = 120000 
Question 15 of 50
15. Question
Two pipes A and B can fill a tank in 4 and 5 hours respectively. If they are turned up alternately for one hour each, the time taken to fill the tank is?
Correct
1/4 + 1/5 = 9/20
20/9 = 2 2/9
9/20 * 2 = 9/10 — 4 hours
WR = 1 – 9/10 = 1/10
1 h — 1/4
? —– 1/10
2/5 * 60 = 24 = 4 hrs 24 minIncorrect
1/4 + 1/5 = 9/20
20/9 = 2 2/9
9/20 * 2 = 9/10 — 4 hours
WR = 1 – 9/10 = 1/10
1 h — 1/4
? —– 1/10
2/5 * 60 = 24 = 4 hrs 24 min 
Question 16 of 50
16. Question
An amount of Rs. 3000 becomes Rs. 3600 in four years at simple interest. If the rate of interest was 1% more, then what was be the total amount?
Correct
A = P(1 + TR/100)
=> 3600 = 3000[1 + (4 * R)/100] => R = 5%
Now R = 6%
=> A = 3000[1 + (4 * 6)/100] = Rs. 3720.Incorrect
A = P(1 + TR/100)
=> 3600 = 3000[1 + (4 * R)/100] => R = 5%
Now R = 6%
=> A = 3000[1 + (4 * 6)/100] = Rs. 3720. 
Question 17 of 50
17. Question
Convert the 13/36 m/s into kilometers per hour?
Correct
13/36 m/s = 13/36 * 18/5 = 13/10 = 1.3 kmph.
Incorrect
13/36 m/s = 13/36 * 18/5 = 13/10 = 1.3 kmph.

Question 18 of 50
18. Question
A began business with Rs.45000 and was joined afterwards by B with Rs.5400. When did B join if the profits at the end of the year were divided in the ratio of 2:1?
Correct
45*12 : 54*x = 2: 1
x = 5
12 5 = 7Incorrect
45*12 : 54*x = 2: 1
x = 5
12 5 = 7 
Question 19 of 50
19. Question
In how many ways can a committee consisting of three men and four women be formed from a group of six men and seven women?
Correct
The group contain six men and seven women
Three men can be selected from six men in ⁶C₃ ways.
Four women can be selected from seven women in ⁷C₄ ways.
Total number of ways = (⁷C₄)(⁶C₃).Incorrect
The group contain six men and seven women
Three men can be selected from six men in ⁶C₃ ways.
Four women can be selected from seven women in ⁷C₄ ways.
Total number of ways = (⁷C₄)(⁶C₃). 
Question 20 of 50
20. Question
Find the mean proportional of the following pairs of numbers 50 and 512.
Correct
Mean proportional of two numbers a and b is defined as √ab
a = 50, b = 512
Mean proportional = √(50)(512) = 160Incorrect
Mean proportional of two numbers a and b is defined as √ab
a = 50, b = 512
Mean proportional = √(50)(512) = 160 
Question 21 of 50
21. Question
The length of a rectangular floor is more than its breadth by 200%. If Rs. 324 is required to paint the floor at the rate of Rs. 3 per sq m, then what would be the length of the floor?
Correct
Let the length and the breadth of the floor be l m and b m respectively.
l = b + 200% of b = l + 2b = 3b
Area of the floor = 324/3 = 108 sq m
l b = 108 i.e., l * l/3 = 108
l^{2} = 324 => l = 18.Incorrect
Let the length and the breadth of the floor be l m and b m respectively.
l = b + 200% of b = l + 2b = 3b
Area of the floor = 324/3 = 108 sq m
l b = 108 i.e., l * l/3 = 108
l^{2} = 324 => l = 18. 
Question 22 of 50
22. Question
The side of a square is increased by 25% then how much % does its area increases?
Correct
a = 100 a^{2} = 10000
a = 125 a^{2} = 15625
—————
10000 ——— 5625
100 ——? => 56.25 %Incorrect
a = 100 a^{2} = 10000
a = 125 a^{2} = 15625
—————
10000 ——— 5625
100 ——? => 56.25 % 
Question 23 of 50
23. Question
What is the difference between the largest number and the least number written with the digits 7, 3, 1, 4?
Correct
1347
7431
————
6084Incorrect
1347
7431
————
6084 
Question 24 of 50
24. Question
A box contains 3 blue marbles, 4 red, 6 green marbles and 2 yellow marbles. If two marbles are drawn at random, what is the probability that at least one is green?
Correct
Given that there are three blue marbles, four red marbles, six green marbles and two yellow marbles.
Probability that at least one green marble can be picked in the random draw of two marbles = Probability that one is green + Probability that both are green
= (⁶C₁ * ⁹C₁)/¹⁵C₂ + ⁶C₂/¹⁵C₂
= (6 * 9 * 2)/(15 * 14) + (6 * 5)/(15 * 14) = 36/70 + 1/7
= 46/70 = 23/35Incorrect
Given that there are three blue marbles, four red marbles, six green marbles and two yellow marbles.
Probability that at least one green marble can be picked in the random draw of two marbles = Probability that one is green + Probability that both are green
= (⁶C₁ * ⁹C₁)/¹⁵C₂ + ⁶C₂/¹⁵C₂
= (6 * 9 * 2)/(15 * 14) + (6 * 5)/(15 * 14) = 36/70 + 1/7
= 46/70 = 23/35 
Question 25 of 50
25. Question
Find the one which does not belong to that group ?
Correct
Boxing, Chess, Wrestling and Squash are individual events, while Baseball is a team event.
Incorrect
Boxing, Chess, Wrestling and Squash are individual events, while Baseball is a team event.

Question 26 of 50
26. Question
5 * 5 ÷ 5 + 5 ÷ 5 = ?
Correct
(5 * 5)/5 + 1/5 * 5 = 5 + 1 = 6
Incorrect
(5 * 5)/5 + 1/5 * 5 = 5 + 1 = 6

Question 27 of 50
27. Question
By selling 12 toffees for a rupee, a man loses 20%. How many for a rupee should be sell to get a gain of 20%?
Correct
Let S.P. of 12 toffees be Rs. x.
Then, 80:1 = 120:x or x = 120/180 = 3/2
For Rs. 3/2, toffees sold = 12.
For Re. 1, toffees sold = 12 * 2/3 = 8Incorrect
Let S.P. of 12 toffees be Rs. x.
Then, 80:1 = 120:x or x = 120/180 = 3/2
For Rs. 3/2, toffees sold = 12.
For Re. 1, toffees sold = 12 * 2/3 = 8 
Question 28 of 50
28. Question
What sum of money put at C.I amounts in 2 years to Rs.8820 and in 3 years to Rs.9261?
Correct
8820 — 441
100 — ? => 5%
x *105/100 * 105/100 = 8820
x*1.1025=8820
x=8820/1.1025 => 8000Incorrect
8820 — 441
100 — ? => 5%
x *105/100 * 105/100 = 8820
x*1.1025=8820
x=8820/1.1025 => 8000 
Question 29 of 50
29. Question
The number obtained by interchanging the two digits of a twodigit number is less than the original number by 45. If the sum of the two digits of the number so obtained is 13, then what is the original number?
Correct
Let the number be in the form of 10a + b
Number formed by interchanging a and b = 10b + a.
a + b = 13 — (1)
10b + a = 10a + b – 45
45 = 9a – 9b => a – b = 5 — (2)
Adding (1) and (2), we get
2a = 18 => a = 9 and b = 4
The number is: 94.Incorrect
Let the number be in the form of 10a + b
Number formed by interchanging a and b = 10b + a.
a + b = 13 — (1)
10b + a = 10a + b – 45
45 = 9a – 9b => a – b = 5 — (2)
Adding (1) and (2), we get
2a = 18 => a = 9 and b = 4
The number is: 94. 
Question 30 of 50
30. Question
If onethird of one fourth of a number is 15, then threetenth of that number is:
Correct
Let the number be x. Then,
1/3 of 1/4 of x = 15
x = 15 * 12 = 180
So, required number = (3/10 * 180) = 54.Incorrect
Let the number be x. Then,
1/3 of 1/4 of x = 15
x = 15 * 12 = 180
So, required number = (3/10 * 180) = 54. 
Question 31 of 50
31. Question
LCM of 87 and 145 is:
Correct
Incorrect

Question 32 of 50
32. Question
The ratio of the length and the breadth of a rectangle is 4 : 3 and the area of the rectangle is 6912 sq cm. Find the ratio of the breadth and the area of the rectangle?
Correct
Let the length and the breadth of the rectangle be 4x cm and 3x respectively.
(4x)(3x) = 6912
12x^{2} = 6912
x^{2} = 576 = 4 * 144 = 2^{2} * 12^{2} (x > 0)
=> x = 2 * 12 = 24
Ratio of the breadth and the areas = 3x : 12x^{2} = 1 : 4x = 1: 96.Incorrect
Let the length and the breadth of the rectangle be 4x cm and 3x respectively.
(4x)(3x) = 6912
12x^{2} = 6912
x^{2} = 576 = 4 * 144 = 2^{2} * 12^{2} (x > 0)
=> x = 2 * 12 = 24
Ratio of the breadth and the areas = 3x : 12x^{2} = 1 : 4x = 1: 96. 
Question 33 of 50
33. Question
4 men and 6 women can complete a work in 8 days, while 3 men and 7 women can complete it in 10 days. In how many days will 10 women complete it?
Correct
Let 1 man’s 1 day work = x and 1 woman’s 1 day work = y.
Then, 4x + 6y = 1/8 and 3x + 7y = 1/10
Solving these two equations, we get:
x = 11/400 and y = 1/400
1 woman’s 1 day work = (1/400 * 10) = 1/40.
Hence, 10 women will complete the work in 40 days.Incorrect
Let 1 man’s 1 day work = x and 1 woman’s 1 day work = y.
Then, 4x + 6y = 1/8 and 3x + 7y = 1/10
Solving these two equations, we get:
x = 11/400 and y = 1/400
1 woman’s 1 day work = (1/400 * 10) = 1/40.
Hence, 10 women will complete the work in 40 days. 
Question 34 of 50
34. Question
Ram professes to sell his goods at the cost price but he made use of 900 grms instead of a kg, what is the gain percent?
Correct
900 — 100
100 — ? => 11 1/9%Incorrect
900 — 100
100 — ? => 11 1/9% 
Question 35 of 50
35. Question
The average monthly salary of laborers and supervisors in a factory is Rs.1250 per month; where as the average monthly salary of 6 supervisors is Rs.2450. If the average monthly salary of the laborers is Rs.950 find the number of laborers?
Correct
1 —— 6
4 ——? → 24Incorrect
1 —— 6
4 ——? → 24 
Question 36 of 50
36. Question
20 women can do a work in 9 days. After they have worked for 6 days. 6 more men join them. How many days will they take to complete the remaining work?
Correct
(20 * 16) women can complete the work in 1 day.
1 woman’s 1 day work = 1/320
(16 * 15) men can complete the work in 1 day
1 man’s 1 day work = 1/240
So, required ratio = 1/240 : 1/320 = 4:3.Incorrect
(20 * 16) women can complete the work in 1 day.
1 woman’s 1 day work = 1/320
(16 * 15) men can complete the work in 1 day
1 man’s 1 day work = 1/240
So, required ratio = 1/240 : 1/320 = 4:3. 
Question 37 of 50
37. Question
Nine men went to a hotel. Eight of them spent Rs.3 each over their meals and the ninth spent Rs.2 more than the average expenditure of all the nine. Determine the total money spent by them?
Correct
Average of 9 = x
9x = 8 * 3 + x * 2 x = 3.25
Total = 9 * 3.25 = 29.25Incorrect
Average of 9 = x
9x = 8 * 3 + x * 2 x = 3.25
Total = 9 * 3.25 = 29.25 
Question 38 of 50
38. Question
A person takes 20 minutes more to cover a certain distance by decreasing his speed by 20%. What is the time taken to cover the distance at his original speed?
Correct
Let the distance and original speed be d km and k kmph respectively.
d/0.8k – d/k = 20/60 => 5d/4k – d/k = 1/3
=> (5d – 4d)/4k = 1/3 => d = 4/3 k
Time taken to cover the distance at original speed
= d/k = 4/3 hours = 1 hour 20 minutes.Incorrect
Let the distance and original speed be d km and k kmph respectively.
d/0.8k – d/k = 20/60 => 5d/4k – d/k = 1/3
=> (5d – 4d)/4k = 1/3 => d = 4/3 k
Time taken to cover the distance at original speed
= d/k = 4/3 hours = 1 hour 20 minutes. 
Question 39 of 50
39. Question
(84 ÷ 14 ÷ 2 ÷ 9) * ? = 33⅓
Correct
(84 ÷ 14 ÷ 2 ÷ 9) * ? = 33⅓
=> (6 ÷ 2 ÷ 9) * ? = 100 / 3
=> 3 / 9 * ? = 100 / 3
=> ? = 100Incorrect
(84 ÷ 14 ÷ 2 ÷ 9) * ? = 33⅓
=> (6 ÷ 2 ÷ 9) * ? = 100 / 3
=> 3 / 9 * ? = 100 / 3
=> ? = 100 
Question 40 of 50
40. Question
The area of the cardboard(in cm^{2}) needed to make a box of size 25 cm * 15 cm * 8 cm will be?
Correct
2(25 * 15 + 15 * 8 + 25 * 8)
2(375 + 120 + 200) => 1390Incorrect
2(25 * 15 + 15 * 8 + 25 * 8)
2(375 + 120 + 200) => 1390 
Question 41 of 50
41. Question
The area of a square field 3136 sq m, if the length of cost of drawing barbed wire 3 m around the field at the rate of Rs.1.50 per meter. Two gates of 1 m width each are to be left for entrance. What is the total cost?
Correct
a^{2} = 3136 => a = 56
56 * 4 * 3 = 672 – 6 = 666 * 1.5 = 999Incorrect
a^{2} = 3136 => a = 56
56 * 4 * 3 = 672 – 6 = 666 * 1.5 = 999 
Question 42 of 50
42. Question
(0.456 * 0.456 – 0.228 * 0.228) / (0.456 + 0.228) = ?
Correct
(0.456 * 0.456 – 0.228 * 0.228) / (0.456 + 0.228)
This is the form of 7x/60 = 7 = a – b = 0.466 – 0.228 = 0.228Incorrect
(0.456 * 0.456 – 0.228 * 0.228) / (0.456 + 0.228)
This is the form of 7x/60 = 7 = a – b = 0.466 – 0.228 = 0.228 
Question 43 of 50
43. Question
The edges of a cuboid are respectively 3cm, 4cm and 12 cm. Find the length of the diagonal of cuboid.
Correct
Incorrect

Question 44 of 50
44. Question
With a uniform speed a car covers the distance in 8 hours. Had the speed been increased by 4 km/hr, the same distance could have been covered in 7 1/2 hours. What is the distance covered?
Correct
Let the distance be x km. Then,
x/(7 1/2) – x/8 = 4
2x/15 – x/8 = 4 => x = 480 km.Incorrect
Let the distance be x km. Then,
x/(7 1/2) – x/8 = 4
2x/15 – x/8 = 4 => x = 480 km. 
Question 45 of 50
45. Question
The radius of a circle is increased by 1%. Find how much % does its area increases?
Correct
r = 100 r = 101
r^{2} = 10000 r^{2} = 10201
10000 — 201
100 — ? => 2.01%Incorrect
r = 100 r = 101
r^{2} = 10000 r^{2} = 10201
10000 — 201
100 — ? => 2.01% 
Question 46 of 50
46. Question
A, B and C enter into partnership. A invests some money at the beginning, B invests double the amount after 6 months, and C invests thrice the amount after 8 months. If the annual gain be Rs.18000. A’s share is?
Correct
x* 12 : 2x* 6: 3x* 4
1:1:1
1/3 * 18000 = 6000Incorrect
x* 12 : 2x* 6: 3x* 4
1:1:1
1/3 * 18000 = 6000 
Question 47 of 50
47. Question
A reduction of 40% in the price of bananas would enable a man to obtain 64 more for Rs.40, what is reduced price per dozen?
Correct
40*(40/100) = 16 — 64
? — 12 => Rs.3Incorrect
40*(40/100) = 16 — 64
? — 12 => Rs.3 
Question 48 of 50
48. Question
25 2/5 + 8 4/5 + 4/5 = ?
Correct
25 2/5 + 8 4/5 + 4/5 = 34 4/5 ≡ 35
Incorrect
25 2/5 + 8 4/5 + 4/5 = 34 4/5 ≡ 35

Question 49 of 50
49. Question
The average monthly salary of 20 employees in an organisation is Rs. 1500. If the manager’s salary is added, then the average salary increases by Rs. 100. What is the manager’s monthly salary?
Correct
Manager’s monthly salary
= Rs. (1600 * 21 – 1500 * 20) = Rs. 3600Incorrect
Manager’s monthly salary
= Rs. (1600 * 21 – 1500 * 20) = Rs. 3600 
Question 50 of 50
50. Question
A paper is in a square form whose one side is 20 cm. Two semi circles are drawn on its opposites as diameters. If these semi circles are cut down what is the area of the remaining paper?
Correct
Incorrect