RRB NTPC Online Test in English Series 1, RRB NTPC Mock Test
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RRB NTPC Online Test in English Series 1, RRB NTPC Mock Test Series 1, RRB NTPC Free Online Test Series 1. RRB Exam Online Test 2019, RRB NTPC Free Mock Test Exam 2019. RRB NTPC Exam Free Online Quiz 2019, RRB NTPC Full Online Mock Test Series 1st in English. RRB Online Test for All Subjects, RRB NTPC Free Mock Test Series in English. RRB NTPC Free Mock Test Series 1. RRB NTPC English Language Online Test in English Series 1st. RRB NTPC Quantitative Aptitude Quiz 2019, RRB NTPC Reasoning Ability Free Online Test. Take RRB NTPC Online Quiz. The RRB NTPC Full online mock test paper is free for all students. RRB NTPC Question and Answers in English and Hindi Series 1. Here we are providing RRB NTPC Full Mock Test Paper in English. RRB NTPC Mock Test Series 1st 2019. Now Test your self for RRB NTPC Exam by using below quiz…
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Question 1 of 50
1. Question
Two men A and B start from place X walking at 4 ½ kmph and 5 ¾ kmph respectively. How many km apart they are at the end of 3 ½ hours if they are walking in the same direction?
Correct
RS = 5 ¾ – 4 ½ = 1 ¼
T = 3 ½ h.
D = 5/4 * 7/2 = 35/8 = 4 3/8 kmIncorrect
RS = 5 ¾ – 4 ½ = 1 ¼
T = 3 ½ h.
D = 5/4 * 7/2 = 35/8 = 4 3/8 km 
Question 2 of 50
2. Question
Two pipes A and B together can fill a cistern in 4 hours. Had they been opened separately, then B would have taken 6 hours more than A to fill cistern. How much time will be taken by A to fill the cistern separately?
Correct
Let the cistern be filled by pipe A alone in x hours.
Then, pipe B will fill it in (x + 6) hours.1/x + 1/(x + 6) = 1/4x^{2} – 2x – 24 = 0(x – 6)(x + 4) = 0 => x = 6.Incorrect
Let the cistern be filled by pipe A alone in x hours.
Then, pipe B will fill it in (x + 6) hours.1/x + 1/(x + 6) = 1/4x^{2} – 2x – 24 = 0(x – 6)(x + 4) = 0 => x = 6. 
Question 3 of 50
3. Question
If a and b are the roots of the equation x^{2} – 9x + 20 = 0, find the value of a^{2} + b^{2} + ab?
Correct
a^{2} + b^{2} + ab = a^{2} + b^{2} + 2ab – ab
i.e., (a + b)^{2} – ab
from x^{2} – 9x + 20 = 0, we have
a + b = 9 and ab = 20. Hence the value of required expression (9)^{2} – 20 = 61.Incorrect
a^{2} + b^{2} + ab = a^{2} + b^{2} + 2ab – ab
i.e., (a + b)^{2} – ab
from x^{2} – 9x + 20 = 0, we have
a + b = 9 and ab = 20. Hence the value of required expression (9)^{2} – 20 = 61. 
Question 4 of 50
4. Question
1: 3 = 1 2/3: x. The value of x is?
Correct
x * 1 = 3 * 5/3
x = 5Incorrect
x * 1 = 3 * 5/3
x = 5 
Question 5 of 50
5. Question
If a man can cover 12 metres in one second, how many kilometres can he cover in 3 hours 45 minutes?
Correct
12 m/s = 12 * 18/5 kmph
3 hours 45 minutes = 3 3/4 hours = 15/4 hours
Distance = speed * time = 12 * 18/5 * 15/4 km = 162 km.Incorrect
12 m/s = 12 * 18/5 kmph
3 hours 45 minutes = 3 3/4 hours = 15/4 hours
Distance = speed * time = 12 * 18/5 * 15/4 km = 162 km. 
Question 6 of 50
6. Question
√3584 * 52.034 = ?
Correct
√3600 * 52 = ?
=> ? = 60 * 52 = 3120Incorrect
√3600 * 52 = ?
=> ? = 60 * 52 = 3120 
Question 7 of 50
7. Question
By selling an article at Rs.800, a shopkeeper makes a profit of 25%. At what price should he sell the article so as to make a loss of 25%?
Correct
SP = 800
Profit = 25%
CP = (SP)*[100/(100+P)]
= 800 * [100/125]
= 640
Loss = 25% = 25% of 640 = Rs.160
SP = CP – Loss = 640 – 160 = Rs.480Incorrect
SP = 800
Profit = 25%
CP = (SP)*[100/(100+P)]
= 800 * [100/125]
= 640
Loss = 25% = 25% of 640 = Rs.160
SP = CP – Loss = 640 – 160 = Rs.480 
Question 8 of 50
8. Question
There are two positive numbers in the ratio 5:8. If the larger number exceeds the smaller by 15, then find the smaller number?
Correct
Let the two positive numbers be 5x and 8x respectively.
8x – 5x = 15
3x = 15 => x = 5
=> Smaller number = 5x = 25.Incorrect
Let the two positive numbers be 5x and 8x respectively.
8x – 5x = 15
3x = 15 => x = 5
=> Smaller number = 5x = 25. 
Question 9 of 50
9. Question
A alone can do a piece of work in 6 days and B alone in 8 days. A and B undertook to do it for Rs. 3200. With the help of C, they completed the work in 3 days. How much is to be paid to C?
Correct
C’s 1 day’s work = 1/3 – (1/6 + 1/8) = 1/3 – 7/24 = 1/24
A’s wages : B’s wages : C’s wages
1/6 : 1/8 : 1/24 = 4:3:1
C’s share = 1/8 * 3200 = Rs. 400Incorrect
C’s 1 day’s work = 1/3 – (1/6 + 1/8) = 1/3 – 7/24 = 1/24
A’s wages : B’s wages : C’s wages
1/6 : 1/8 : 1/24 = 4:3:1
C’s share = 1/8 * 3200 = Rs. 400 
Question 10 of 50
10. Question
Three 6 faced dice are thrown together. The probability that all the three show the same number on them is .
Correct
It all 3 numbers have to be same basically we want triplets. 111, 222, 333, 444, 555 and 666. Those are six in number. Further the three dice can fall in 6 * 6 * 6 = 216 ways.
Hence the probability is 6/216 = 1/36Incorrect
It all 3 numbers have to be same basically we want triplets. 111, 222, 333, 444, 555 and 666. Those are six in number. Further the three dice can fall in 6 * 6 * 6 = 216 ways.
Hence the probability is 6/216 = 1/36 
Question 11 of 50
11. Question
12 men can complete a piece of work in 4 days, while 15 women can complete the same work in 4 days. 6 men start working on the job and after working for 2 days, all of them stopped working. How many women should be put on the job to complete the remaining work, if it so to be completed in 3 days?
Correct
1 man’s 1 day work = 1/48; 1 woman’s 1 day work = 1/60.
6 men’s 2 day’s work = 6/48 * 2 = 1/4.
Remaining work = (1 – 1/4) = 3/4
Now, 1/60 work is done in 1 day by 1 woman.
So, 3/4 work will be done in 3 days by (60 * 3/4 * 1/3) = 15 women.Incorrect
1 man’s 1 day work = 1/48; 1 woman’s 1 day work = 1/60.
6 men’s 2 day’s work = 6/48 * 2 = 1/4.
Remaining work = (1 – 1/4) = 3/4
Now, 1/60 work is done in 1 day by 1 woman.
So, 3/4 work will be done in 3 days by (60 * 3/4 * 1/3) = 15 women. 
Question 12 of 50
12. Question
A can give B 100 meters start and C 200 meters start in a kilometer race. How much start can B give C in a kilometer race?
Correct
A runs 1000 m while B runs 900 m and C runs 800 m.
The number of meters that C runs when B runs 1000 m,
= (1000 * 800)/900 = 8000/9 = 888.88 m.
B can give C = 1000 – 888.88 = 111.12 m.Incorrect
A runs 1000 m while B runs 900 m and C runs 800 m.
The number of meters that C runs when B runs 1000 m,
= (1000 * 800)/900 = 8000/9 = 888.88 m.
B can give C = 1000 – 888.88 = 111.12 m. 
Question 13 of 50
13. Question
A and B walk around a circular track. They start at 8 a.m. from the same point in the opposite directions. A and B walk at a speed of 2 rounds per hour and 3 rounds per hour respectively. How many times shall they cross each other before 9.30 a.m. ?
Correct
Relative speed = 2 + 3 = 5 rounds per hour.
So, they cross each other 5 times in an hour and 2 times in half an hour.
Hence, they cross each other 7 times before 9.30 a.m.Incorrect
Relative speed = 2 + 3 = 5 rounds per hour.
So, they cross each other 5 times in an hour and 2 times in half an hour.
Hence, they cross each other 7 times before 9.30 a.m. 
Question 14 of 50
14. Question
Aamir saves 32% of his monthly salary. If he spends Rs. 27200, then find his savings?
Correct
Let the monthly salary of Aamir be Rs. x.
68% of x = 27200
=> x = (27200 * 100)/68 = 40000
His savings = 32/100 * 40000 = 12800.Incorrect
Let the monthly salary of Aamir be Rs. x.
68% of x = 27200
=> x = (27200 * 100)/68 = 40000
His savings = 32/100 * 40000 = 12800. 
Question 15 of 50
15. Question
Sreedhar and Sravan together can do a work in 25 days. With the help of Pavan, they completed the work in 8 days and earned Rs. 225. What is the share of Sravan, if Sreedhar alone can do the work in 75 days?
Correct
Sravan’s one day’s work = 1/25 – 1/75 = 2/75
Sravan worked for 8 days. So, his 8 days work = 8 * 2/75 = 16/75
Sravan completed 16/75th of total work.
So, his share is 16/75 * 225 = Rs. 48.Incorrect
Sravan’s one day’s work = 1/25 – 1/75 = 2/75
Sravan worked for 8 days. So, his 8 days work = 8 * 2/75 = 16/75
Sravan completed 16/75th of total work.
So, his share is 16/75 * 225 = Rs. 48. 
Question 16 of 50
16. Question
In a bag, there are coins of 25 p, 10 p and 5 p in the ratio of 1:2:3. If there are Rs. 30 in all, how many 5 p coins are there?
Correct
Let the number of 25 p, 10 p and 5 p coins be x, 2x and 3x respectively.
Then, sum of their values = [25x/100 + (10 * 2x)/100 + (5 * 3x)/100] = Rs. 60x/100
60x/100 = 30 => x = 50.
Hence, the number of 5 p coins = 3 * 50 = 150.Incorrect
Let the number of 25 p, 10 p and 5 p coins be x, 2x and 3x respectively.
Then, sum of their values = [25x/100 + (10 * 2x)/100 + (5 * 3x)/100] = Rs. 60x/100
60x/100 = 30 => x = 50.
Hence, the number of 5 p coins = 3 * 50 = 150. 
Question 17 of 50
17. Question
The average age of husband, wife and their child 3 years ago was 27 years and that of wife and the child 5 years ago was 20 years. The present age of the husband is:
Correct
Sum of the present ages of husband, wife and child = (27 * 3 + 3 * 3) = 90 years.
Sum of the present age of wife and child = (20 * 2 + 5 * 2) = 50 years.
Husband’s present age = (90 – 50) = 40 years.Incorrect
Sum of the present ages of husband, wife and child = (27 * 3 + 3 * 3) = 90 years.
Sum of the present age of wife and child = (20 * 2 + 5 * 2) = 50 years.
Husband’s present age = (90 – 50) = 40 years. 
Question 18 of 50
18. Question
Difference between two numbers is 5, six times of the smaller lacks by 6 from the four times of the greater. Find the numbers?
Correct
x – y = 5
4x – 6y = 6
x = 12 y = 7Incorrect
x – y = 5
4x – 6y = 6
x = 12 y = 7 
Question 19 of 50
19. Question
Five men and nine women can do a piece of work in 10 days. Six men and twelve women can do the same work in 8 days. In how many days can three men and three women do the work?
Correct
(5m + 9w)10 = (6m + 12w)8
=> 50m + 90w = 48w + 96 w => 2m = 6w => 1m = 3w 5m + 9w = 5m + 3m = 8m
8 men can do the work in 10 days.
3m +3w = 3m + 1w = 4m
So, 4 men can do the work in (10 * 8)/4 = 20 days.Incorrect
(5m + 9w)10 = (6m + 12w)8
=> 50m + 90w = 48w + 96 w => 2m = 6w => 1m = 3w 5m + 9w = 5m + 3m = 8m
8 men can do the work in 10 days.
3m +3w = 3m + 1w = 4m
So, 4 men can do the work in (10 * 8)/4 = 20 days. 
Question 20 of 50
20. Question
Find the one which does not belong to that group ?
Correct
Except Japanian, all others are appropriate usage of citizenship.
Incorrect
Except Japanian, all others are appropriate usage of citizenship.

Question 21 of 50
21. Question
Find the one which does not belong to that group ?
Correct
27, 36, 72 and 45 are divisible by 9, but not 30.
Incorrect
27, 36, 72 and 45 are divisible by 9, but not 30.

Question 22 of 50
22. Question
What is the unit digit in 7^{105} ?
Correct
Unit digit in 7^{105} = unit digit in [(7^{4})^{26} * 7]
But, unit digit in (7^{4})^{26} = 1unit digit in 7^{105} = (1 * 7) = 7Incorrect
Unit digit in 7^{105} = unit digit in [(7^{4})^{26} * 7]
But, unit digit in (7^{4})^{26} = 1unit digit in 7^{105} = (1 * 7) = 7 
Question 23 of 50
23. Question
150 men consume 1050 kg of rice in 30 days. In how many days will 70 men consume 980 kg of rice?
Correct
Rate of consumption of each man = 1050/(150 * 30) = 7/30 kg/day
Let us say 70 men take x days to consume 150 kg.
Quantity consumed by each item in x days = (7x/30) kg
Quantity consumed by 70 men in x days = (7/30 x)(70) kg
= (7/30 x) * (70) = 960
x = 60 days.Incorrect
Rate of consumption of each man = 1050/(150 * 30) = 7/30 kg/day
Let us say 70 men take x days to consume 150 kg.
Quantity consumed by each item in x days = (7x/30) kg
Quantity consumed by 70 men in x days = (7/30 x)(70) kg
= (7/30 x) * (70) = 960
x = 60 days. 
Question 24 of 50
24. Question
A man saves Rs. 200 at the end of each year and lends the money at 5% compound interest. How much will it become at the end of 3 years?
Correct
Amount = [200(1 + 5/100)^{3} + 200(1 + 5/100)^{2} + 200(1 + 5/100)]
= [200 * 21/20(21/20 * 21/20 + 21/20 + 1)] = Rs. 662.02Incorrect
Amount = [200(1 + 5/100)^{3} + 200(1 + 5/100)^{2} + 200(1 + 5/100)]
= [200 * 21/20(21/20 * 21/20 + 21/20 + 1)] = Rs. 662.02 
Question 25 of 50
25. Question
The price of an article has been reduced by 25%. In order to restore the original price the new price must be increased by?
Correct
100
75
——
75 —— 25
100 —— ? => 33 1/3%Incorrect
100
75
——
75 —— 25
100 —— ? => 33 1/3% 
Question 26 of 50
26. Question
LCM of 87 and 145 is:
Correct
Incorrect

Question 27 of 50
27. Question
The difference between the simple interest received from two different sources on Rs. 1500 for 3 years is Rs. 13.50. The difference between their rates of interest is?
Correct
(1500 * R_{1} * 3)/100 – (1500 * R_{2} * 3)/100 = 13.50 4500(R_{1} – R_{2}) = 1350
R_{1} – R_{2} = 0.3%Incorrect
(1500 * R_{1} * 3)/100 – (1500 * R_{2} * 3)/100 = 13.50 4500(R_{1} – R_{2}) = 1350
R_{1} – R_{2} = 0.3% 
Question 28 of 50
28. Question
A 25 cm wide path is to be made around a circular garden having a diameter of 4 meters. Approximate area of the path is square meters is
Correct
Area of the path = Area of the outer circle – Area of the inner circle = ∏{4/2 + 25/100}^{2} – ∏[4/2]^{2}
= ∏[2.25^{2} – 2^{2}] = ∏(0.25)(4.25) { (a^{2} – b^{2} = (a – b)(a + b) }= (3.14)(1/4)(17/4) = 53.38/16 = 3.34 sq mIncorrect
Area of the path = Area of the outer circle – Area of the inner circle = ∏{4/2 + 25/100}^{2} – ∏[4/2]^{2}
= ∏[2.25^{2} – 2^{2}] = ∏(0.25)(4.25) { (a^{2} – b^{2} = (a – b)(a + b) }= (3.14)(1/4)(17/4) = 53.38/16 = 3.34 sq m 
Question 29 of 50
29. Question
12.5 + 10 1/4 of 100 ÷ 10% of 10 = ?
Correct
12.5 + 10 1/4 of 100 ÷ 10% of 10
= 12.5 + 41/4 of 100 ÷ 10/100 of 10= 12.5 + 41(25) ÷ 1 = 12.5 + 1025 = 1037.5Incorrect
12.5 + 10 1/4 of 100 ÷ 10% of 10
= 12.5 + 41/4 of 100 ÷ 10/100 of 10= 12.5 + 41(25) ÷ 1 = 12.5 + 1025 = 1037.5 
Question 30 of 50
30. Question
After working for 6 days, Ashok finds that only 1/3 rd of the work has been done. He employs Ravi who is 60% as efficient as Ashok. How many days more would Ravi take to complete the work?
Correct
1/3 — 6
1 ——? A = 18
R = 1/18 * 60/100 = 1/30
1 —– 1/30
2/3 —? => 20 daysIncorrect
1/3 — 6
1 ——? A = 18
R = 1/18 * 60/100 = 1/30
1 —– 1/30
2/3 —? => 20 days 
Question 31 of 50
31. Question
Mohan’s salary was first increased by 20% and then decreased by 20%. If his present salary is Rs. 7200, then what was his original salary?
Correct
Let Mohan’s salary be Rs.100.
When increased by 20%, Mohan’s salary = Rs.120
Again when decreased by 20%, Mohan’s salary = 120 – 24 = Rs. 96.
But present salary is Rs. 7200
for, 96 —> 100 ; 7200 —> ?
Required salary is 7200/96 * 100 = Rs. 7500Incorrect
Let Mohan’s salary be Rs.100.
When increased by 20%, Mohan’s salary = Rs.120
Again when decreased by 20%, Mohan’s salary = 120 – 24 = Rs. 96.
But present salary is Rs. 7200
for, 96 —> 100 ; 7200 —> ?
Required salary is 7200/96 * 100 = Rs. 7500 
Question 32 of 50
32. Question
A shopkeeper loses 15%,if an article is sold for Rs. 102. What should be the selling price of the article to gain 20%?
Correct
Given that SP = Rs. 102 and loss = 15%
CP = [100(SP)]/(100 – l%) = (100 * 102)/85 = 20 * 6 = Rs. 120.
To get 20% profit, New SP = [(100 + p%)CP]/100 = (120 * 120)/100 = Rs. 144Incorrect
Given that SP = Rs. 102 and loss = 15%
CP = [100(SP)]/(100 – l%) = (100 * 102)/85 = 20 * 6 = Rs. 120.
To get 20% profit, New SP = [(100 + p%)CP]/100 = (120 * 120)/100 = Rs. 144 
Question 33 of 50
33. Question
Find the expenditure on digging a well 14m deep and of 3m diameter at Rs.15 per cubic meter?
Correct
22/7 * 14 * 3/2 * 3/2 = 99 m^{2}
99 * 15 = 1485Incorrect
22/7 * 14 * 3/2 * 3/2 = 99 m^{2}
99 * 15 = 1485 
Question 34 of 50
34. Question
Reena took a loan of Rs. 1200 with simple interest for as many years as the rate of interest. If she paid Rs. 432 as interest at the end of the loan period, what was the rate of interest?
Correct
Let rate = R% and time = R years.
Then, (1200 * R * R) / 100 = 432
12R2 = 432
R2 = 36 => R = 6.Incorrect
Let rate = R% and time = R years.
Then, (1200 * R * R) / 100 = 432
12R2 = 432
R2 = 36 => R = 6. 
Question 35 of 50
35. Question
Two pipes A and B can separately fill a cistern in 10 and 15 minutes respectively. A person opens both the pipes together when the cistern should have been was full he finds the waste pipe open. He then closes the waste pipe and in another 4 minutes the cistern was full. In what time can the waste pipe empty the cistern when fill?
Correct
1/10 + 1/15 = 1/6 * 4 = 2/3
1 – 2/3 = 1/3
1/10 + 1/15 – 1/x = 1/3
x = 8Incorrect
1/10 + 1/15 = 1/6 * 4 = 2/3
1 – 2/3 = 1/3
1/10 + 1/15 – 1/x = 1/3
x = 8 
Question 36 of 50
36. Question
A train travelled from station P to Q in 8 hours and came back from station Q to P is 6 hours. What would be the ratio of the speed of the train while traveling from station P to Q to that from station Q to P?
Correct
Since S # 1/t
S_{1} : S_{2} = 1/t_{1} : 1/t_{2} = 1/8 : 1/6 = 3 : 4Incorrect
Since S # 1/t
S_{1} : S_{2} = 1/t_{1} : 1/t_{2} = 1/8 : 1/6 = 3 : 4 
Question 37 of 50
37. Question
A and B can do a work in 4 hours and 12 hours respectively. A starts the work at 6AM and they work alternately for one hour each. When will the work be completed?
Correct
Work done by A and B in the first two hours, working alternately = First hour A + Second hour B = 1/4 + 1/12 = 1/3.
Total time required to complete the work = 2 * 3 = 6 days.Incorrect
Work done by A and B in the first two hours, working alternately = First hour A + Second hour B = 1/4 + 1/12 = 1/3.
Total time required to complete the work = 2 * 3 = 6 days. 
Question 38 of 50
38. Question
The product of two numbers is 2028 and their H.C.F is 13. The number of such pairs is:
Correct
Let the numbers be 13a and 13b.
Then, 13a * 13b = 2028 => ab = 12.
Now, coprimes with product 12 are (1, 12) and (3, 4).
So, the required numbers are (13 * 1, 13 * 12) and (13 * 3, 13 * 4).
Clearly, there are 2 such pairs.Incorrect
Let the numbers be 13a and 13b.
Then, 13a * 13b = 2028 => ab = 12.
Now, coprimes with product 12 are (1, 12) and (3, 4).
So, the required numbers are (13 * 1, 13 * 12) and (13 * 3, 13 * 4).
Clearly, there are 2 such pairs. 
Question 39 of 50
39. Question
How many meters of carpet 50cm, wide will be required to cover the floor of a room 30m * 20m?
Correct
50/100 * x = 30 * 20 => x = 1200
Incorrect
50/100 * x = 30 * 20 => x = 1200

Question 40 of 50
40. Question
Find the roots of quadratic equation: x^{2} + x – 42 = 0?
Correct
x^{2} + 7x – 6x + 42 = 0
x(x + 7) – 6(x + 7) = 0
(x + 7)(x – 6) = 0 => x = 7, 6Incorrect
x^{2} + 7x – 6x + 42 = 0
x(x + 7) – 6(x + 7) = 0
(x + 7)(x – 6) = 0 => x = 7, 6 
Question 41 of 50
41. Question
How many seconds will a train 100 meters long take to cross a bridge 150 meters long if the speed of the train is 36 kmph?
Correct
D = 100 + 150 = 250
S = 36 * 5/18 = 10 mps
T = 250/10 = 25 secIncorrect
D = 100 + 150 = 250
S = 36 * 5/18 = 10 mps
T = 250/10 = 25 sec 
Question 42 of 50
42. Question
Find the mean proportional of the following pairs of numbers 50 and 512.
Correct
Incorrect

Question 43 of 50
43. Question
A and B start a business with Rs.6000 and Rs.8000 respectively. Hoe should they share their profits at the end of one year?
Correct
They should share the profits in the ratio of their investments.
The ratio of the investments made by A and B =
6000 : 8000 => 3:4Incorrect
They should share the profits in the ratio of their investments.
The ratio of the investments made by A and B =
6000 : 8000 => 3:4 
Question 44 of 50
44. Question
Find the one which does not belong to that group ?
Correct
A, E, I and O are vowels, while R is a consonant.
Incorrect
A, E, I and O are vowels, while R is a consonant.

Question 45 of 50
45. Question
If Re.1 amounts to Rs.9 over a period of 20 years. What is the rate of simple interest?
Correct
8 = (1*20*R)/100
R = 40%Incorrect
8 = (1*20*R)/100
R = 40% 
Question 46 of 50
46. Question
Two trains 140 m and 160 m long run at the speed of 60 km/hr and 40 km/hr respectively in opposite directions on parallel tracks. The time which they take to cross each other is?
Correct
Relative speed = 60 + 40 = 100 km/hr.
= 100 * 5/18 = 250/9 m/sec.
Distance covered in crossing each other = 140 + 160 = 300 m.
Required time = 300 * 9/250 = 54/5 = 10.8 sec.Incorrect
Relative speed = 60 + 40 = 100 km/hr.
= 100 * 5/18 = 250/9 m/sec.
Distance covered in crossing each other = 140 + 160 = 300 m.
Required time = 300 * 9/250 = 54/5 = 10.8 sec. 
Question 47 of 50
47. Question
The volume of a cube is 1728 cc. Find its surface.
Correct
a^{3} = 1728 => a = 12
6a^{2} = 6 * 12 * 12 = 864Incorrect
a^{3} = 1728 => a = 12
6a^{2} = 6 * 12 * 12 = 864 
Question 48 of 50
48. Question
Manoj borrowed Rs.3450 from Anwar at 6% p.a. simple interest for three years. He then added some more money to the borrowed sum and lent it to Ramu for the same time at 9% p.a. simple interest. If Manoj gains Rs.824.85 by way of interest on the borrowed sum as well as his own amount from the whole transaction, then what is the sum lent by him to Ramu?
Correct
Let the sum lent by Manoj to Ramu be Rs.P.
Amount gained by Manoj = P. 3.9 /100 = 3450.3.6/100 = Rs.824.85
27P = 62100 = 82485
P = (82485 + 62100)/27 = 3055 + 2300 = Rs.5355Incorrect
Let the sum lent by Manoj to Ramu be Rs.P.
Amount gained by Manoj = P. 3.9 /100 = 3450.3.6/100 = Rs.824.85
27P = 62100 = 82485
P = (82485 + 62100)/27 = 3055 + 2300 = Rs.5355 
Question 49 of 50
49. Question
Walking with 4/5 of my usual speed, I miss the bus by 5 minutes. What is my usual time?
Correct
Speed Ratio = 1:4/5 = 5:4Time Ratio = 4:51 ——– 5 4 ——— ? è 20
Incorrect
Speed Ratio = 1:4/5 = 5:4Time Ratio = 4:51 ——– 5 4 ——— ? è 20

Question 50 of 50
50. Question
[(7 * 9) + (2 * 12) + 3]/[(12 * 3) + (81/9)] = ?
Correct
[(7 * 9) + (2 * 12) + 3]/[(12 * 3) + (81/9)] = (63 + 24 + 3)/(36 + 9) = 90/45 = 2
Incorrect
[(7 * 9) + (2 * 12) + 3]/[(12 * 3) + (81/9)] = (63 + 24 + 3)/(36 + 9) = 90/45 = 2