SEBI Online Mock Test 4, SEBI Online Test in English Series 4
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SEBI Online Mock Test 4, SEBI Online Test in English Series 4, SEBI Free Online Test Series 4. SEBI Exam Online Test 2019, SEBI Free Mock Test Exam 2019. SEBI Exam Free Online Quiz 2019, SEBI Full Online Mock Test Series 4th in English. RRB Online Test for All Subjects, SEBI Free Mock Test Series in English. SEBI Free Mock Test Series 4. SEBI English Language Online Test in English Series 4th. SEBI Quantitative Aptitude Quiz 2019, SEBI Reasoning Ability Free Online Test. Take SEBI Online Quiz. The SEBI Full online mock test paper is free for all students. SEBI Question and Answers in English and Hindi Series 4. Here we are providing SEBI Full Mock Test Paper in English. SEBI Mock Test Series 4th 2019. Now Test your self for SEBI Exam by using below quiz…
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Question 1 of 50
1. Question
P alone can complete a piece of work in 6 days. Work done by Q alone in one day is equal to onethird of the work done by P alone in one day. In how many days can the work be completed if P and Q work together?
Correct
Work done by P alone in one day = 1/6th of the total work done by Q alone in one day = 1/3(of that done by P in one day) = 1/3(1/6 of the total) = 1/18 of the total.
Work done by P and Q, working together in one day = 1/6 + 1/18 = 4/18 = 2/9 of the total
They would take 9/2 days = 4 (1/2) days to complete the work working together.Incorrect
Work done by P alone in one day = 1/6th of the total work done by Q alone in one day = 1/3(of that done by P in one day) = 1/3(1/6 of the total) = 1/18 of the total.
Work done by P and Q, working together in one day = 1/6 + 1/18 = 4/18 = 2/9 of the total
They would take 9/2 days = 4 (1/2) days to complete the work working together. 
Question 2 of 50
2. Question
The sum of five numbers is 655. The average of the first two numbers is 85 and the third number is 125. Find the average of the two numbers?
Correct
Let the five numbers be P, Q, R, S and T.
=> P + Q + R + S + T = 655.
(P + Q)/2 = 85 and R = 125
P + Q = 170 and R = 125
P + Q + R = 295
S + T = 655 – (P + Q + R) = 360
Average of the last two numbers = (S + T)/2 = 180.Incorrect
Let the five numbers be P, Q, R, S and T.
=> P + Q + R + S + T = 655.
(P + Q)/2 = 85 and R = 125
P + Q = 170 and R = 125
P + Q + R = 295
S + T = 655 – (P + Q + R) = 360
Average of the last two numbers = (S + T)/2 = 180. 
Question 3 of 50
3. Question
Find the one which does not belong to that group ?
Correct
Except in 862, in all other numbers sum of first two digits is same as the last digit.
Incorrect
Except in 862, in all other numbers sum of first two digits is same as the last digit.

Question 4 of 50
4. Question
The diameters of two spheres are in the ratio 1:2 what is the ratio of their surface area?
Correct
Incorrect

Question 5 of 50
5. Question
Sum of two numbers is 80. Greater number exceeds by 5 from four times of the smaller. Find the numbers?
Correct
x + y = 80
x – 4y = 5
x = 65 y = 15Incorrect
x + y = 80
x – 4y = 5
x = 65 y = 15 
Question 6 of 50
6. Question
At what rate percent on simple interest will a sum of money double itself in 30 years?
Correct
P = (P*30*R)/100
R = 3 1/3%Incorrect
P = (P*30*R)/100
R = 3 1/3% 
Question 7 of 50
7. Question
A is a working partner and B is a sleeping partner in the business. A puts in Rs.15000 and B Rs.25000, A receives 10% of the profit for managing the business the rest being divided in proportion of their capitals. Out of a total profit of Rs.9600, money received by A is?
Correct
15:25 => 3:5
9600*10/100 = 960
9600 – 960 = 8640
8640*3/8 = 3240 + 960
= 4200Incorrect
15:25 => 3:5
9600*10/100 = 960
9600 – 960 = 8640
8640*3/8 = 3240 + 960
= 4200 
Question 8 of 50
8. Question
Two men A and B start from place X walking at 4 ½ kmph and 5 ¾ kmph respectively. How many km apart they are at the end of 3 ½ hours if they are walking in the same direction?
Correct
RS = 5 ¾ – 4 ½ = 1 ¼
T = 3 ½ h.
D = 5/4 * 7/2 = 35/8 = 4 3/8 kmIncorrect
RS = 5 ¾ – 4 ½ = 1 ¼
T = 3 ½ h.
D = 5/4 * 7/2 = 35/8 = 4 3/8 km 
Question 9 of 50
9. Question
A number when, 28 subtracted from it reduces to its one third. What is the value of 50% of that number?
Correct
2/3 x = 28 => x = 42
42 * 1/2 = 21Incorrect
2/3 x = 28 => x = 42
42 * 1/2 = 21 
Question 10 of 50
10. Question
A train running at the speed of 60 km/hr crosses a pole in 9 seconds. Find the length of the train.
Correct
Speed = 60*(5/18) m/sec = 50/3 m/sec
Length of Train (Distance) = Speed * Time
(50/3) * 9 = 150 meterIncorrect
Speed = 60*(5/18) m/sec = 50/3 m/sec
Length of Train (Distance) = Speed * Time
(50/3) * 9 = 150 meter 
Question 11 of 50
11. Question
Rs. 6000 is lent out in two parts. One part is lent at 7% p.a simple interest and the other is lent at 10% p.a simple interest. The total interest at the end of one year was Rs. 450. Find the ratio of the amounts lent at the lower rate and higher rate of interest?
Correct
Let the amount lent at 7% be Rs. x
Amount lent at 10% is Rs. (6000 – x)
Total interest for one year on the two sums lent
= 7/100 x + 10/100 (6000 – x) = 600 – 3x/100
=> 600 – 3/100 x = 450 => x = 5000
Amount lent at 10% = 1000
Required ratio = 5000 : 1000 = 5 : 1
Learn more problems on : AveragesIncorrect
Let the amount lent at 7% be Rs. x
Amount lent at 10% is Rs. (6000 – x)
Total interest for one year on the two sums lent
= 7/100 x + 10/100 (6000 – x) = 600 – 3x/100
=> 600 – 3/100 x = 450 => x = 5000
Amount lent at 10% = 1000
Required ratio = 5000 : 1000 = 5 : 1
Learn more problems on : Averages 
Question 12 of 50
12. Question
1/3 of 2/6 of 1/7 of 2/28 of 2140 = ?
Correct
1/3 * 1/3 * 1/7 * 1/9 * 2140 = ?
? = 3.77Incorrect
1/3 * 1/3 * 1/7 * 1/9 * 2140 = ?
? = 3.77 
Question 13 of 50
13. Question
At what rate percent of simple interest will a sum of money double itself in 12 years?
Correct
Let sum = x. Then, S.I. = x.
Rate = (100 * S.I.) / (P * T) = (100 * x) / (x * 12)
= 25/3 = 8 1/3 %Incorrect
Let sum = x. Then, S.I. = x.
Rate = (100 * S.I.) / (P * T) = (100 * x) / (x * 12)
= 25/3 = 8 1/3 % 
Question 14 of 50
14. Question
Anand and Deepak started a business investing Rs. 22,500 and Rs. 35,000 respectively. Out of a total profit of Rs. 13,800, Deepak’s share is:
Correct
Ratio of their shares = 22500 : 35000 = 9:14
Deepak’s share = 13800 * 14/23 = Rs. 8400.Incorrect
Ratio of their shares = 22500 : 35000 = 9:14
Deepak’s share = 13800 * 14/23 = Rs. 8400. 
Question 15 of 50
15. Question
What will be the difference between simple and compound interest at 10% per annum on a sum of Rs. 1000 after 4 years?
Correct
S.I. = (1000 * 10 * 4)/100 = Rs. 400
C.I. = [1000 * (1 + 10/100)^{4} – 1000] = Rs. 464.10 Difference = (464.10 – 400) = Rs. 64.10Incorrect
S.I. = (1000 * 10 * 4)/100 = Rs. 400
C.I. = [1000 * (1 + 10/100)^{4} – 1000] = Rs. 464.10 Difference = (464.10 – 400) = Rs. 64.10 
Question 16 of 50
16. Question
The area of a square is equal to five times the area of a rectangle of dimensions 125 cm * 64 cm. What is the perimeter of the square?
Correct
Area of the square = s * s = 5(125 * 64)
=> s = 25 * 8 = 200 cm
Perimeter of the square = 4 * 200 = 800 cm.Incorrect
Area of the square = s * s = 5(125 * 64)
=> s = 25 * 8 = 200 cm
Perimeter of the square = 4 * 200 = 800 cm. 
Question 17 of 50
17. Question
A sum of money at simple interest amounts to Rs. 815 in 3 years and to Rs. 854 in 4 years. The sum is?
Correct
S.I. for 1 year = (854 – 815) = Rs. 39
S.I. for 3 years = 39 * 3 = Rs. 117
Principal = (815 – 117) = Rs. 698.Incorrect
S.I. for 1 year = (854 – 815) = Rs. 39
S.I. for 3 years = 39 * 3 = Rs. 117
Principal = (815 – 117) = Rs. 698. 
Question 18 of 50
18. Question
Rajan got married 8 years ago. His present age is 6/5 times his age at the time of his marriage. Rajan’s sister was 10 years younger to him at the time of his marriage. The age of Rajan’s sister is:
Correct
Let Rajan’s present age be x years.
Then, his age at the time of marriage = (x – 8) years.
x = 6/5 (x – 8)
5x = 6x – 48 => x = 48
Rajan’s sister’s age at the time of his marriage = (x – 8) – 10 = 30 years.
Rajan’s sister’s present age = (30 + 8) = 38 years.Incorrect
Let Rajan’s present age be x years.
Then, his age at the time of marriage = (x – 8) years.
x = 6/5 (x – 8)
5x = 6x – 48 => x = 48
Rajan’s sister’s age at the time of his marriage = (x – 8) – 10 = 30 years.
Rajan’s sister’s present age = (30 + 8) = 38 years. 
Question 19 of 50
19. Question
Twelve men can complete a piece of work in 32 days. The same work can be completed by 16 women in 36 days and by 48 boys in 16 days. Find the time taken by one man, one woman and one boy working together to complete the work?
Correct
12 men take 32 days to complete the work.
One man will take (12 * 32) days to complete it.
Similarly one woman will take (16 * 36) days to complete it and one boy will take (48 * 16) days to complete it.
One man, one woman and one boy working together will complete = 1/(12 * 32) + 1/(16 * 36) + 1/(48 * 16)
= 1/(4 * 3 * 16 * 2) + 1/(16 * 4 * 9) + 1/(16 * 3 * 4 * 4)
= 1/64(1/6 + 1/9 + 1/12) = 1/64 * 13/36 of the work in a day.
They will take (64 * 36)/13 days to complete the work working together.Incorrect
12 men take 32 days to complete the work.
One man will take (12 * 32) days to complete it.
Similarly one woman will take (16 * 36) days to complete it and one boy will take (48 * 16) days to complete it.
One man, one woman and one boy working together will complete = 1/(12 * 32) + 1/(16 * 36) + 1/(48 * 16)
= 1/(4 * 3 * 16 * 2) + 1/(16 * 4 * 9) + 1/(16 * 3 * 4 * 4)
= 1/64(1/6 + 1/9 + 1/12) = 1/64 * 13/36 of the work in a day.
They will take (64 * 36)/13 days to complete the work working together. 
Question 20 of 50
20. Question
If x = 3 – √7, then find the value of x + 1/x.
Correct
x = √7
1/x = 1/(3 – √7) = 3 + √7/(3 – √7) (3 + √7)
= (3 + √7)/2 => x + 1/x = (9 – √7)/2Incorrect
x = √7
1/x = 1/(3 – √7) = 3 + √7/(3 – √7) (3 + √7)
= (3 + √7)/2 => x + 1/x = (9 – √7)/2 
Question 21 of 50
21. Question
Two pipes A and B can separately fill a tank in 2 minutes and 15 minutes respectively. Both the pipes are opened together but 4 minutes after the start the pipe A is turned off. How much time will it take to fill the tank?
Correct
4/12 + x/15 = 1
x = 10Incorrect
4/12 + x/15 = 1
x = 10 
Question 22 of 50
22. Question
80 is what percent of 64?
Correct
Let x percent of 64 be 80.
64 * x/100 = 80 => x = (80 * 100)/64 => x = 125
80 is 125% of 64.Incorrect
Let x percent of 64 be 80.
64 * x/100 = 80 => x = (80 * 100)/64 => x = 125
80 is 125% of 64. 
Question 23 of 50
23. Question
If a: b = 3:4, b:c = 7:9, c:d = 5:7, find a:d?
Correct
a/d = (3/4)*(7/9)*(5/7) => 5/12
Incorrect
a/d = (3/4)*(7/9)*(5/7) => 5/12

Question 24 of 50
24. Question
The area of a parallelogram is 128sq m and its altitude is twice the corresponding base. Then the length of the base is?
Correct
2x * x = 128 => x= 8
Incorrect
2x * x = 128 => x= 8

Question 25 of 50
25. Question
The average of 1^{st} 3 of 4 numbers is 16 and of the last 3 are 15. If the sum of the first and the last number is 13. What is the last numbers?
Correct
A + B + C = 48
B + C + D = 45
A + D = 13
A – D = 3
A + D = 132D = 10
D = 5Incorrect
A + B + C = 48
B + C + D = 45
A + D = 13
A – D = 3
A + D = 132D = 10
D = 5 
Question 26 of 50
26. Question
A is two years older than B who is twice as old as C. If the total of the ages of A, B and C be 27, then how old is B?
Correct
Let C’s age be x years.
Then, B’s age = 2x years.
A’s age = (2x + 2) years.
(2x + 2) + 2x + x = 27
5x = 25 => x = 5
Hence, B’s age = 2x = 10 years.Incorrect
Let C’s age be x years.
Then, B’s age = 2x years.
A’s age = (2x + 2) years.
(2x + 2) + 2x + x = 27
5x = 25 => x = 5
Hence, B’s age = 2x = 10 years. 
Question 27 of 50
27. Question
The difference between C.I. and S.I. on an amount of Rs. 15,000 for 2 years is Rs. 96. What is the rate of interest per annum?
Correct
[15000 * (1 + R/100)^{2} – 15000] – (15000 * R * 2)/100 = 96
15000[(1 + R/100)^{2} – 1 – 2R/100] = 96
15000[(100 + R)^{2} – 10000 – 200R]/10000 = 96
R^{2} = (96 * 2)/3 = 64 => R = 8
Rate = 8%Incorrect
[15000 * (1 + R/100)^{2} – 15000] – (15000 * R * 2)/100 = 96
15000[(1 + R/100)^{2} – 1 – 2R/100] = 96
15000[(100 + R)^{2} – 10000 – 200R]/10000 = 96
R^{2} = (96 * 2)/3 = 64 => R = 8
Rate = 8% 
Question 28 of 50
28. Question
A sum of money is borrowed and paid back in two annual installments of Rs. 882 each allowing 5% C.I. The sum borrowed was?
Correct
Principal = (P.W. of Rs. 882 due 1 year hence) + (P.W. of Rs. 882 due 2 years hence)
= [882/(1 + 5/100) + 882/(1 + 5/100)^{2}]
= (882 * 20)/21 + (882 * 400)/441 = Rs. 1640.Incorrect
Principal = (P.W. of Rs. 882 due 1 year hence) + (P.W. of Rs. 882 due 2 years hence)
= [882/(1 + 5/100) + 882/(1 + 5/100)^{2}]
= (882 * 20)/21 + (882 * 400)/441 = Rs. 1640. 
Question 29 of 50
29. Question
What amount does Kiran get if he invests Rs. 18000 at 15% p.a. simple interest for four years?
Correct
Simple interest = (18000 * 4 * 15)/100 = Rs. 10800
Amount = P + I = 18000 + 10800 = Rs. 28800Incorrect
Simple interest = (18000 * 4 * 15)/100 = Rs. 10800
Amount = P + I = 18000 + 10800 = Rs. 28800 
Question 30 of 50
30. Question
The sum of two numbers is 22. Five times one number is equal to 6 times the other. The bigger of the two numbers is:
Correct
Let the numbers be x and (22 – x). Then,
5x = 6(22 – x)
11x = 132 => x = 12
So, the numbers are 12 and 10.Incorrect
Let the numbers be x and (22 – x). Then,
5x = 6(22 – x)
11x = 132 => x = 12
So, the numbers are 12 and 10. 
Question 31 of 50
31. Question
A man can row 30 km downstream and 20 km upstream in 4 hours. He can row 45 km downstream and 40 km upstream in 7 hours. Find the speed of man in still water?
Correct
Let the speed of the man in still water be a kmph and let the speed of the stream be b kmph.
Now 30/(a + b) + 20/(a – b) = 4 and 45/(a + b) + 40/(a – b) = 7
Solving the equation, the speed of man in still water is 12.5 kmph.Incorrect
Let the speed of the man in still water be a kmph and let the speed of the stream be b kmph.
Now 30/(a + b) + 20/(a – b) = 4 and 45/(a + b) + 40/(a – b) = 7
Solving the equation, the speed of man in still water is 12.5 kmph. 
Question 32 of 50
32. Question
If the wheel is 14 cm then the number of revolutions to cover a distance of 1056 cm is?
Correct
2 * 22/7 * 14 * x = 1056 => x = 12
Incorrect
2 * 22/7 * 14 * x = 1056 => x = 12

Question 33 of 50
33. Question
A and B can do a piece of work in 7 days. With the help of C they finish the work in 5 days. C alone can do that piece of work in?
Correct
C = 1/5 – 1/6 = 1/30 => 30 days
Incorrect
C = 1/5 – 1/6 = 1/30 => 30 days

Question 34 of 50
34. Question
The S.I. on a certain sum of money for 3 years at 8% per annum is half the C.I. on Rs. 4000 for 2 years at 10% per annum. The sum placed on S.I. is?
Correct
C.I. = [4000 * (1 + 10/100)^{2} – 4000]
= (4000 * 11/10 * 11/10 – 4000) = Rs. 840.
Sum = (420 * 100)/(3 * 8) = Rs. 1750Incorrect
C.I. = [4000 * (1 + 10/100)^{2} – 4000]
= (4000 * 11/10 * 11/10 – 4000) = Rs. 840.
Sum = (420 * 100)/(3 * 8) = Rs. 1750 
Question 35 of 50
35. Question
If the price of an article went up by 20%, then by what percent should it be brought down to bring it back to its original price?
Correct
Let the price of the article be Rs. 100.
20% of 100 = 20.
New price = 100 + 20 = Rs. 120
Required percentage = (120 – 100)/120 * 100
= 20/120 * 100 = 50/3 = 16 2/3%.Incorrect
Let the price of the article be Rs. 100.
20% of 100 = 20.
New price = 100 + 20 = Rs. 120
Required percentage = (120 – 100)/120 * 100
= 20/120 * 100 = 50/3 = 16 2/3%. 
Question 36 of 50
36. Question
How many shots of 1cm radius can be prepared from a sphere of 3cm radius?
Correct
4/3 π * 3 * 3 * 3 = 4/3 π * 1 * 1 * 1 * x
x = 27Incorrect
4/3 π * 3 * 3 * 3 = 4/3 π * 1 * 1 * 1 * x
x = 27 
Question 37 of 50
37. Question
The cost price of a radio is Rs.1500 and it was sold for Rs.1230, find the loss %?
Correct
1500 — 270
100 — ? => 18%Incorrect
1500 — 270
100 — ? => 18% 
Question 38 of 50
38. Question
A room is 4 meters 37 cm long and 3 meters 23cm broad. It is required to pave the floor with minimum square slabs. Find the number of slabs required for this purpose?
Correct
HCF of 323, 437 = 19
323 * 437 = 19 * 19 * x
x = 391Incorrect
HCF of 323, 437 = 19
323 * 437 = 19 * 19 * x
x = 391 
Question 39 of 50
39. Question
Kiran travels from A to B by car and returns from B to A by cycle in 7 hours. If he travels both ways by car he saves 3 hours. What is the time taken to cover both ways by cycle?
Correct
Let the time taken to cover from A to B in car and cycle be x hours and y hours respectively.
x + y = 7 — (1) ; 2x = 4 — (2)
solving both the equations, we get y = 5
So, time taken to cover both ways by cycle = 2y hours = 10 hours.Incorrect
Let the time taken to cover from A to B in car and cycle be x hours and y hours respectively.
x + y = 7 — (1) ; 2x = 4 — (2)
solving both the equations, we get y = 5
So, time taken to cover both ways by cycle = 2y hours = 10 hours. 
Question 40 of 50
40. Question
Simran started a software business by investing Rs. 50,000. After six months, Nanda joined her with a capital of Rs. 80,000. After 3 years, they earned a profit of Rs. 24,500. What was Simran’s share in the profit?
Correct
Simran : Nanda = (50000 * 36) : (80000 * 30) = 3:4
Simran’s share = 24500 * 3/7 = Rs. 10500Incorrect
Simran : Nanda = (50000 * 36) : (80000 * 30) = 3:4
Simran’s share = 24500 * 3/7 = Rs. 10500 
Question 41 of 50
41. Question
The smallest number when increased by ” 1 ” is exactly divisible by 12, 18, 24, 32 and 40 is:
Correct
LCM = 1440
1440 – 1 = 1439Incorrect
LCM = 1440
1440 – 1 = 1439 
Question 42 of 50
42. Question
Two trains of length 120 m and 280 m are running towards each other on parallel lines at 42 kmph and 30 kmph respectively. In what time will they be clear of each other from the moment they meet?
Correct
Relative speed = (42 + 30) * 5/18 = 4 * 5 = 20 mps.
Distance covered in passing each other = 120 + 280 = 400 m.
The time required = d/s = 400/20 = 20 sec.Incorrect
Relative speed = (42 + 30) * 5/18 = 4 * 5 = 20 mps.
Distance covered in passing each other = 120 + 280 = 400 m.
The time required = d/s = 400/20 = 20 sec. 
Question 43 of 50
43. Question
Find the one which does not belong to that group ?
Correct
Except Austriala : Pound, all others are correction combination of country and its currency.
Incorrect
Except Austriala : Pound, all others are correction combination of country and its currency.

Question 44 of 50
44. Question
Tanya’s grandfather was 8 times older to her 16 years ago. He would be 3 times of her age 8 years from now. Eight years ago, what was the ratio of Tanya’s age to that of her grandfather?
Correct
16 years ago, let T = x years and G = 8x years. After 8 years from now, T = (x + 16 + 8) years and G = (8x + 16 + 8) years.
8x + 24 = 3(x + 24) => 5x = 48
8 years ago, T/G = (x + 8)/(8x + 8) = (48/5 + 8) / (8 * 48/5 + 8) = 88/424 = 11/53Incorrect
16 years ago, let T = x years and G = 8x years. After 8 years from now, T = (x + 16 + 8) years and G = (8x + 16 + 8) years.
8x + 24 = 3(x + 24) => 5x = 48
8 years ago, T/G = (x + 8)/(8x + 8) = (48/5 + 8) / (8 * 48/5 + 8) = 88/424 = 11/53 
Question 45 of 50
45. Question
A pump can fill a tank with water in 2 hours. Because of a leak, it took 2 1/3 hours to fill the tank. The leak can drain all the water of the tank in?
Correct
Work done by the tank in 1 hour = (1/2 – 1/3) = 1/14 Leak will empty the tank in 14 hrs.
Incorrect
Work done by the tank in 1 hour = (1/2 – 1/3) = 1/14 Leak will empty the tank in 14 hrs.

Question 46 of 50
46. Question
Two trains of equal are running on parallel lines in the same direction at 46 km/hr and 36 km/hr. The faster train passes the slower train in 36 sec. The length of each train is?
Correct
Let the length of each train be x m.
Then, distance covered = 2x m.
Relative speed = 46 – 36 = 10 km/hr.
= 10 * 5/18 = 25/9 m/sec.
2x/36 = 25/9 => x = 50.Incorrect
Let the length of each train be x m.
Then, distance covered = 2x m.
Relative speed = 46 – 36 = 10 km/hr.
= 10 * 5/18 = 25/9 m/sec.
2x/36 = 25/9 => x = 50. 
Question 47 of 50
47. Question
The curved surface of a sphere is 64 π cm^{2}. Find its radius?
Correct
4 πr^{2 }= 64 => r = 4
Incorrect
4 πr^{2 }= 64 => r = 4

Question 48 of 50
48. Question
Kim can do a work in 3 days while David can do the same work in 2 days. Both of them finish the work together and get Rs. 150. What is the share of Kim?
Correct
Kim’s wages : David’s wages = Kim’s 1 day work : David’s 1 day work = 1/3 : 1/2 = 2:3
Kim’s share = 2/5 * 150 = Rs. 60Incorrect
Kim’s wages : David’s wages = Kim’s 1 day work : David’s 1 day work = 1/3 : 1/2 = 2:3
Kim’s share = 2/5 * 150 = Rs. 60 
Question 49 of 50
49. Question
2003 * 2004 – 2001 * 2002 = ?
Correct
(2000 + 3)(2000 + 4) – (2000 + 1)(2000 + 2) = ?
Since (2000 * 2000) – (2000 * 2000) is equal to zero. ?
= (8000 + 6000 + 12) – (4000 + 2000 + 2)
=> ? = 14012 – 6002 = 8010Incorrect
(2000 + 3)(2000 + 4) – (2000 + 1)(2000 + 2) = ?
Since (2000 * 2000) – (2000 * 2000) is equal to zero. ?
= (8000 + 6000 + 12) – (4000 + 2000 + 2)
=> ? = 14012 – 6002 = 8010 
Question 50 of 50
50. Question
0.003 * ? * 0.0003 = 0.00000027
Correct
0.003 * ? * 0.0003 = 0.00000027
3/1000 * ? * 3/10000 = 3/1000 * 3/1000 * 3/100
? = 3/10 = 0.3Incorrect
0.003 * ? * 0.0003 = 0.00000027
3/1000 * ? * 3/10000 = 3/1000 * 3/1000 * 3/100
? = 3/10 = 0.3