CAT Online Test Series 2, CAT Free Mock Test  Free CAT Quiz series 2
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CAT Online Test Series 2, CAT Free Mock Test  Free CAT Quiz series 2. Common Admission Test (CAT) is one of the most challenging and competitive MBA entrance test in our country. Check your level of preparation for CAT with free All India Mock test 2019. CAT Exam Online Test 2019, CAT Free Mock Test Exam 2019. CAT Exam Free Online Quiz 2019, CAT Full Online Mock Test Series 2nd in English. CAT Online Test for All Subjects, CAT Free Mock Test Series in English. CAT Free Mock Test Series 2. CAT English Language Online Test in English Series 2nd. Here we are providing CAT Full Mock Test Paper in English. CAT Mock Test Series 2nd 2019. Now Test your self for CAT Exam by using below quiz…
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Question 1 of 50
1. Question
Two pipes A and B can fill a tank in 4 and 5 hours respectively. If they are turned up alternately for one hour each, the time taken to fill the tank is?
Correct
1/4 + 1/5 = 9/20
20/9 = 2 2/9
9/20 * 2 = 9/10 — 4 hours
WR = 1 – 9/10 = 1/10
1 h — 1/4
? —– 1/10
2/5 * 60 = 24 = 4 hrs 24 minIncorrect
1/4 + 1/5 = 9/20
20/9 = 2 2/9
9/20 * 2 = 9/10 — 4 hours
WR = 1 – 9/10 = 1/10
1 h — 1/4
? —– 1/10
2/5 * 60 = 24 = 4 hrs 24 min 
Question 2 of 50
2. Question
Simple interest on a sum at 4% per annum for 2 years is Rs.80. The C.I. on the same sum for the same period is?
Correct
SI = 40 + 40
CI = 40 + 40 + 1.6 = 81.6Incorrect
SI = 40 + 40
CI = 40 + 40 + 1.6 = 81.6 
Question 3 of 50
3. Question
There are two circles of different radii. The are of a square is 784 sq cm and its side is twice the radius of the larger circle. The radius of the larger circle is seven – third that of the smaller circle. Find the circumference of the smaller circle.
Correct
Let the radii of the larger and the smaller circles be l cm and s cm respectively. Let the side of the square be a cm.
a^{2} = 784 = (4)(196) = (2^{2}).(14^{2})
a = (2)(14) = 28
a = 2l, l = a/2 = 14
l = (7/3)s
Therefore s = (3/7)(l) = 6 Circumference of the smaller circle = 2∏s = 12∏ cm.Incorrect
Let the radii of the larger and the smaller circles be l cm and s cm respectively. Let the side of the square be a cm.
a^{2} = 784 = (4)(196) = (2^{2}).(14^{2})
a = (2)(14) = 28
a = 2l, l = a/2 = 14
l = (7/3)s
Therefore s = (3/7)(l) = 6 Circumference of the smaller circle = 2∏s = 12∏ cm. 
Question 4 of 50
4. Question
32% of 425 – ?% of 250 = 36
Correct
32/100 * 425 – x/100 * 250 = 36
=> x/100 * 250 = 136 – 36 = 100
=> x = (100 * 100)/250 = 40Incorrect
32/100 * 425 – x/100 * 250 = 36
=> x/100 * 250 = 136 – 36 = 100
=> x = (100 * 100)/250 = 40 
Question 5 of 50
5. Question
A question paper consists of five problems, each problem having three internal choices. In how many ways can a candidate attempt one or more problems?
Correct
Given that, the question paper consists of five problems. For each problem, one or two or three or none of the choices can be attempted.
Hence, the required number of ways = 4^{5} – 1.
= 2^{10} – 1 = 1024 – 1 = 1023Incorrect
Given that, the question paper consists of five problems. For each problem, one or two or three or none of the choices can be attempted.
Hence, the required number of ways = 4^{5} – 1.
= 2^{10} – 1 = 1024 – 1 = 1023 
Question 6 of 50
6. Question
In an exam, Amar scored 64 percent, Bhavan scored 36 percent and Chetan 44 percent. The maximum score awarded in the exam is 800. Find the average mark scored by all the three boys?
Correct
Average mark scored by all the three boys =
[64/100 (800) + 36/100 (800) + 44/100 (800)] / 3 = 384Incorrect
Average mark scored by all the three boys =
[64/100 (800) + 36/100 (800) + 44/100 (800)] / 3 = 384 
Question 7 of 50
7. Question
Anil spends 40% of his income on rent, 30% of the remaining on medicines and 20% of the remaining on education. If he saves Rs. 840 every month, then find his monthly salary?
Correct
Let’s Anil’s salary be Rs. 100.
Money spent on Rent = 40% of 100 = Rs. 40.
Money spent on medical grounds = 30% of (100 – 40) = 3/10 * 60 = Rs. 18.
Money spent on education = 20% of (60 – 18) = 1/5 * 42 = Rs. 8.40
Anil saves 100 – (40 + 18 + 8.40) i.e., Rs. 33.60
for 33.6 —> 100 ; 840 —> ?
Required salary = 840/33.6 * 100 = Rs. 2500Incorrect
Let’s Anil’s salary be Rs. 100.
Money spent on Rent = 40% of 100 = Rs. 40.
Money spent on medical grounds = 30% of (100 – 40) = 3/10 * 60 = Rs. 18.
Money spent on education = 20% of (60 – 18) = 1/5 * 42 = Rs. 8.40
Anil saves 100 – (40 + 18 + 8.40) i.e., Rs. 33.60
for 33.6 —> 100 ; 840 —> ?
Required salary = 840/33.6 * 100 = Rs. 2500 
Question 8 of 50
8. Question
There were two candidates in an election. Winner candidate received 62% of votes and won the election by 288 votes. Find the number of votes casted to the winning candidate?
Correct
W = 62% L = 38%
62% – 38% = 24%
24% ——– 288
62% ——– ? => 744Incorrect
W = 62% L = 38%
62% – 38% = 24%
24% ——– 288
62% ——– ? => 744 
Question 9 of 50
9. Question
What is the difference between the local values of 3 in the number 53403?
Correct
3000 – 3 = 2997
Incorrect
3000 – 3 = 2997

Question 10 of 50
10. Question
A 70 cm long wire is to be cut into two pieces so that one piece will be 2/5th of the other, how many centimeters will the shorter piece be?
Correct
1: 2/5 = 5: 2
2/7 * 70 = 20Incorrect
1: 2/5 = 5: 2
2/7 * 70 = 20 
Question 11 of 50
11. Question
A can do a piece of work in 30 days. He works at it for 5 days and then B finishes it in 20 days. In what time can A and B together it?
Correct
5/30 + 20/x = 1
x = 24
1/30 + 1/24 = 3/40
40/3 = 13 1/3 daysIncorrect
5/30 + 20/x = 1
x = 24
1/30 + 1/24 = 3/40
40/3 = 13 1/3 days 
Question 12 of 50
12. Question
If onethird of one fourth of a number is 15, then threetenth of that number is:
Correct
Let the number be x. Then,
1/3 of 1/4 of x = 15
x = 15 * 12 = 180
So, required number = (3/10 * 180) = 54.Incorrect
Let the number be x. Then,
1/3 of 1/4 of x = 15
x = 15 * 12 = 180
So, required number = (3/10 * 180) = 54. 
Question 13 of 50
13. Question
Find the roots of quadratic equation: 3x^{2} – 7x – 6 = 0?
Correct
3x^{2} – 9x + 2x – 6 = 0
3x(x – 3) + 2(x – 3) = 0
(x – 3)(3x + 2) = 0 => x = 3, 2/3Incorrect
3x^{2} – 9x + 2x – 6 = 0
3x(x – 3) + 2(x – 3) = 0
(x – 3)(3x + 2) = 0 => x = 3, 2/3 
Question 14 of 50
14. Question
The average weight of a group of boys is 30 kg. After a boy of weight 35 kg joins the group, the average weight of the group goes up by 1 kg. Find the number of boys in the group originally ?
Correct
Let the number off boys in the group originally be x.
Total weight of the boys = 30x
After the boy weighing 35 kg joins the group, total weight of boys = 30x + 35
So 30x + 35 + 31(x + 1) = > x = 4.Incorrect
Let the number off boys in the group originally be x.
Total weight of the boys = 30x
After the boy weighing 35 kg joins the group, total weight of boys = 30x + 35
So 30x + 35 + 31(x + 1) = > x = 4. 
Question 15 of 50
15. Question
A pump can fill a tank with water in 2 hours. Because of a leak, it took 2 1/3 hours to fill the tank. The leak can drain all the water of the tank in?
Correct
Work done by the tank in 1 hour = (1/2 – 1/3) = 1/14 Leak will empty the tank in 14 hrs.
Incorrect
Work done by the tank in 1 hour = (1/2 – 1/3) = 1/14 Leak will empty the tank in 14 hrs.

Question 16 of 50
16. Question
150 men consume 1050 kg of rice in 30 days. In how many days will 70 men consume 980 kg of rice?
Correct
Rate of consumption of each man = 1050/(150 * 30) = 7/30 kg/day
Let us say 70 men take x days to consume 150 kg.
Quantity consumed by each item in x days = (7x/30) kg
Quantity consumed by 70 men in x days = (7/30 x)(70) kg
= (7/30 x) * (70) = 960
x = 60 days.Incorrect
Rate of consumption of each man = 1050/(150 * 30) = 7/30 kg/day
Let us say 70 men take x days to consume 150 kg.
Quantity consumed by each item in x days = (7x/30) kg
Quantity consumed by 70 men in x days = (7/30 x)(70) kg
= (7/30 x) * (70) = 960
x = 60 days. 
Question 17 of 50
17. Question
The fourth proportional to 5, 8, 15 is:
Correct
Let the fourth proportional to 5, 8, 15 be x.
Then, 5:8 :: 15:x
x = (8 * 15)/5 = 24.Incorrect
Let the fourth proportional to 5, 8, 15 be x.
Then, 5:8 :: 15:x
x = (8 * 15)/5 = 24. 
Question 18 of 50
18. Question
The probability that a number selected at random from the first 50 natural numbers is a composite number is .
Correct
The number of exhaustive events = ⁵⁰C₁ = 50.
We have 15 primes from 1 to 50.
Number of favourable cases are 34.
Required probability = 34/50 = 17/25.Incorrect
The number of exhaustive events = ⁵⁰C₁ = 50.
We have 15 primes from 1 to 50.
Number of favourable cases are 34.
Required probability = 34/50 = 17/25. 
Question 19 of 50
19. Question
The edges of three iron cubes are 6cm; 8cm; 10cm respectively. A new cube was made by melting them. Find the edge of the new cube?
Correct
6^{3} + 8^{3} + 10^{3} = a^{3} => a = 12
Incorrect
6^{3} + 8^{3} + 10^{3} = a^{3} => a = 12

Question 20 of 50
20. Question
If the sum of a number and its square is 182, what is the number?
Correct
Let the number be x. Then,
x + x^{2} = 182
(x + 14)(x – 13) = 0
x = 13Incorrect
Let the number be x. Then,
x + x^{2} = 182
(x + 14)(x – 13) = 0
x = 13 
Question 21 of 50
21. Question
By selling 50 meters of cloth. I gain the selling price of 15 meters. Find the gain percent?
Correct
SP = CP + g
50 SP = 50 CP + 15 SP
35 SP = 50 CP
35 — 15 CP gain
100 — ? => 42 6/7%Incorrect
SP = CP + g
50 SP = 50 CP + 15 SP
35 SP = 50 CP
35 — 15 CP gain
100 — ? => 42 6/7% 
Question 22 of 50
22. Question
Find the average of the first 20 natural numbers?
Correct
Average of the first ‘n’ natural numbers = (n + 1)/2
We get (20 + 1)/2 = 10.5Incorrect
Average of the first ‘n’ natural numbers = (n + 1)/2
We get (20 + 1)/2 = 10.5 
Question 23 of 50
23. Question
Pipes A and B can fill a tank in 5 and 6 hours respectively. Pipe C can empty it in 12 hours. If all the three pipes are opened together, then the tank will be filled in?
Correct
Net part filled in 1 hour = 1/5 + 1/6 – 1/12 = 17/60
The tank will be full in 60/17 hrs, i.e., 3 9/17 hrs.Incorrect
Net part filled in 1 hour = 1/5 + 1/6 – 1/12 = 17/60
The tank will be full in 60/17 hrs, i.e., 3 9/17 hrs. 
Question 24 of 50
24. Question
If the sum of the two numbers is 22 and the sum of their squares is 404, then the product of the numbers is:
Correct
Let the numbers be x and y.
Then, (x + y) = 22 and x^{2} + y^{2} = 404
Now,
2xy = (x + y)^{2} – (x^{2} + y^{2})
2xy= 22^{2} – 404 = 484 – 404 = 80
xy = 40Incorrect
Let the numbers be x and y.
Then, (x + y) = 22 and x^{2} + y^{2} = 404
Now,
2xy = (x + y)^{2} – (x^{2} + y^{2})
2xy= 22^{2} – 404 = 484 – 404 = 80
xy = 40 
Question 25 of 50
25. Question
A started a business with an investment of Rs. 70000 and after 6 months B joined him investing Rs. 120000. If the profit at the end of a year is Rs. 52000, then the share of B is?
Correct
Ratio of investments of A and B is (70000 * 12) : (120000 * 6) = 7 : 6
Total profit = Rs. 52000
Share of B = 6/13 (52000) = Rs. 24000Incorrect
Ratio of investments of A and B is (70000 * 12) : (120000 * 6) = 7 : 6
Total profit = Rs. 52000
Share of B = 6/13 (52000) = Rs. 24000 
Question 26 of 50
26. Question
A 300 meter long train crosses a platform in 39 seconds while it crosses a signal pole in 18 seconds. What is the length of the platform?
Correct
Speed = [300 / 18] m/sec = 50/3 m/sec.
Let the length of the platform be x meters.
Then, x + 300 / 39 = 50/3
3(x + 300) = 1950 → x = 350m.Incorrect
Speed = [300 / 18] m/sec = 50/3 m/sec.
Let the length of the platform be x meters.
Then, x + 300 / 39 = 50/3
3(x + 300) = 1950 → x = 350m. 
Question 27 of 50
27. Question
The average of 10 numbers is 23. If each number is increased by 4, what will the new average be?
Correct
Sum of the 10 numbers = 230
If each number is increased by 4, the total increase =
4 * 10 = 40
The new sum = 230 + 40 = 270 The new average = 270/10 = 27.Incorrect
Sum of the 10 numbers = 230
If each number is increased by 4, the total increase =
4 * 10 = 40
The new sum = 230 + 40 = 270 The new average = 270/10 = 27. 
Question 28 of 50
28. Question
Raj invested an amount of Rs.17400 for two years. Find the rate of compound interest that will fetch him an amount of Rs.1783.50 at the end of two years?
Correct
Let the rate of interest be R% p.a.
17400[1 + R/100]^{2} = 17400 + 1783.50
[1 + R/100]^{2} = (17400 + 1783.50)/17400
= 1 + 1025/10000 = 1 + 41/400
= 441/400 = [21/20]^{2}
[1 + R/100] = 21/20
R/100 = 1/20
Therefore R = 5Incorrect
Let the rate of interest be R% p.a.
17400[1 + R/100]^{2} = 17400 + 1783.50
[1 + R/100]^{2} = (17400 + 1783.50)/17400
= 1 + 1025/10000 = 1 + 41/400
= 441/400 = [21/20]^{2}
[1 + R/100] = 21/20
R/100 = 1/20
Therefore R = 5 
Question 29 of 50
29. Question
A train of 24 carriages, each of 60 meters length, when an engine also of 60 meters length is running at a speed of 60 kmph. In what time will the train cross a bridge 1.5 km long?
Correct
D = 25 * 60 + 1500 = 3000 m
T = 3000/60 * 18/5 = 180 sec = 3 minsIncorrect
D = 25 * 60 + 1500 = 3000 m
T = 3000/60 * 18/5 = 180 sec = 3 mins 
Question 30 of 50
30. Question
A dealer purchases 15 articles for Rs. 25 and sells 12 articles for Rs. 30. Find the profit percentage?
Correct
L.C.M of 15 and 12 = 60
CP of 60 articles = Rs. 100 (25 * 4)
SP of 60 articles = Rs. 150 (30 * 5)
Profit percentage = (150 – 100)/100 * 100 = 50%Incorrect
L.C.M of 15 and 12 = 60
CP of 60 articles = Rs. 100 (25 * 4)
SP of 60 articles = Rs. 150 (30 * 5)
Profit percentage = (150 – 100)/100 * 100 = 50% 
Question 31 of 50
31. Question
The difference between simple interest and C.I. at the same rate for Rs.5000 for 2 years in Rs.72. The rate of interest is?
Correct
5000 = 72(100/R)^{2}
5 R^{2} = 720 => R = 12Incorrect
5000 = 72(100/R)^{2}
5 R^{2} = 720 => R = 12 
Question 32 of 50
32. Question
Anna left for city A from city B at 5.20 a.m. She traveled at the speed of 80 km/hr for 2 hrs 15 min. After that the speed was reduced to 60 km/hr. If the distance between two cities is 350 kms, at what time did Anna reach city A?
Correct
Distance covered in 2 hrs 15 min i.e., 2 1/4 hrs = 80 * 9/4 = 180 hrs.
Time taken to cover remaining distance = (350 – 180)/60 = 17/6 hrs
= 2 5/6 = 2 hrs 50 min
Total time taken = (2 hrs 15 min + 2 hrs 50 min) = 5 hrs 5 min.
So, Anna reached city A at 10.25 a.m.Incorrect
Distance covered in 2 hrs 15 min i.e., 2 1/4 hrs = 80 * 9/4 = 180 hrs.
Time taken to cover remaining distance = (350 – 180)/60 = 17/6 hrs
= 2 5/6 = 2 hrs 50 min
Total time taken = (2 hrs 15 min + 2 hrs 50 min) = 5 hrs 5 min.
So, Anna reached city A at 10.25 a.m. 
Question 33 of 50
33. Question
What percent of 125 is 16?
Correct
Let the required percentage be x%.
x% of 125 = 16 => x/100 * 125 = 16
=> x = 1600/125 = 64/5 = 12 4/5Incorrect
Let the required percentage be x%.
x% of 125 = 16 => x/100 * 125 = 16
=> x = 1600/125 = 64/5 = 12 4/5 
Question 34 of 50
34. Question
Two men and three women working 7 hours a day finish a work in 5 days. Four men and four women working 3 hours a day complete the work in 7 days. The number of days in which only 7 men working 4 hours a day will finish the work is?
Correct
2M + 3W —– 35 h
4M + 4W —— 21 h
7M ——? d
70M + 105W = 84M +84M
21W = 14M => 2M = 3W
4 * 35 = 7 * x => x = 20 hours
20/4 = 5 daysIncorrect
2M + 3W —– 35 h
4M + 4W —— 21 h
7M ——? d
70M + 105W = 84M +84M
21W = 14M => 2M = 3W
4 * 35 = 7 * x => x = 20 hours
20/4 = 5 days 
Question 35 of 50
35. Question
The average age 9 members of a committee are the same as it was 2 years ago, because an old number has been replaced by a younger number. Find how much younger is the new member than the old number?
Correct
9 * 2 = 18 years
Incorrect
9 * 2 = 18 years

Question 36 of 50
36. Question
(5 – 7)^{2} * (6 – 9)^{2} / (2^{3})^{2} = ?
Correct
(5 – 7)^{2} * (6 – 9)^{2} / (2^{3})^{2} = (2)^{2} * (3)^{2} * 1/(2^{3})^{2}
= 4 * 9 * 64 = 2304.Incorrect
(5 – 7)^{2} * (6 – 9)^{2} / (2^{3})^{2} = (2)^{2} * (3)^{2} * 1/(2^{3})^{2}
= 4 * 9 * 64 = 2304. 
Question 37 of 50
37. Question
If the height of a cone is increased by 100% then its volume is increased by?
Correct
Incorrect

Question 38 of 50
38. Question
The sum of two numbers is 528 and their H.C.F is 33. The number of pairs of numbers satisfying the above conditions is:
Correct
Let the required numbers be 33a and 33b.
Then, 33a + 33b = 528 => a + b = 16.
Now, coprimes with sum 16 are (1, 15), (3, 13), (5, 11) and (7, 9).
Required numbers are (33 * 1, 33 * 15), (33 * 3, 33 * 13), (33 * 5, 33 * 11), (33 * 7, 33 * 9).
The number of such pairs is 4.Incorrect
Let the required numbers be 33a and 33b.
Then, 33a + 33b = 528 => a + b = 16.
Now, coprimes with sum 16 are (1, 15), (3, 13), (5, 11) and (7, 9).
Required numbers are (33 * 1, 33 * 15), (33 * 3, 33 * 13), (33 * 5, 33 * 11), (33 * 7, 33 * 9).
The number of such pairs is 4. 
Question 39 of 50
39. Question
I. x^{2} – x – 42 = 0,
II. y^{2} – 17y + 72 = 0 to solve both the equations to find the values of x and y?Correct
I. x^{2} – 7x + 6x – 42 = 0
=> (x – 7)(x + 6) = 0 => x = 7, 6
II. y^{2} – 8y – 9y + 72 = 0
=> (y – 8)(y – 9) = 0 => y = 8, 9
=> x < yIncorrect
I. x^{2} – 7x + 6x – 42 = 0
=> (x – 7)(x + 6) = 0 => x = 7, 6
II. y^{2} – 8y – 9y + 72 = 0
=> (y – 8)(y – 9) = 0 => y = 8, 9
=> x < y 
Question 40 of 50
40. Question
A person purchases 90 clocks and sells 40 clocks at a gain of 10% and 50 clocks at a gain of 20%. If he sold all of them at a uniform profit of 15%, then he would have got Rs. 40 less. The cost price of each clock is:
Correct
Let C.P. of clock be Rs. x.
Then, C.P. of 90 clocks = Rs. 90x.
[(110% of 40x) + (120% of 50x)] – (115% of 90x) = 40
44x + 60x – 103.5x = 40
0.5x = 40 => x = 80Incorrect
Let C.P. of clock be Rs. x.
Then, C.P. of 90 clocks = Rs. 90x.
[(110% of 40x) + (120% of 50x)] – (115% of 90x) = 40
44x + 60x – 103.5x = 40
0.5x = 40 => x = 80 
Question 41 of 50
41. Question
X men can do a work in 120 days. If there were 20 men less, the work would have taken 60 days more. What is the value of X?
Correct
We have M_{1} D_{1} = M_{2} D_{2}
120X = (X – 20)180
=> 2X = (X – 20) 3 => 2X = 3X – 60
=> X = 60Incorrect
We have M_{1} D_{1} = M_{2} D_{2}
120X = (X – 20)180
=> 2X = (X – 20) 3 => 2X = 3X – 60
=> X = 60 
Question 42 of 50
42. Question
How much is 80% of 40 is greater than 4/5 of 25?
Correct
(80/100) * 40 – (4/5) * 25
32 – 20 = 12Incorrect
(80/100) * 40 – (4/5) * 25
32 – 20 = 12 
Question 43 of 50
43. Question
In how many ways can three consonants and two vowels be selected from the letters of the word “TRIANGLE”?
Correct
The word contains five consonants. Three vowels, three consonants can be selected from five consonants in ⁵C₃ ways, two vowels can be selected from three vowels in ³C₂ ways.
3 consonants and 2 vowels can be selected in ⁵C₂ . ³C₂ ways i.e., 10 * 3 = 30 ways.Incorrect
The word contains five consonants. Three vowels, three consonants can be selected from five consonants in ⁵C₃ ways, two vowels can be selected from three vowels in ³C₂ ways.
3 consonants and 2 vowels can be selected in ⁵C₂ . ³C₂ ways i.e., 10 * 3 = 30 ways. 
Question 44 of 50
44. Question
A train moves fast a telegraph post and a bridge 264 m long in 8 sec and 20 sec respectively. What is the speed of the train?
Correct
Let the length of the train be x m and its speed be y m/sec.
Then, x/y = 8 => x = 8y
(x + 264)/20 = y
y = 22
Speed = 22 m/sec = 22 * 18/5 = 79.2 km/hr.Incorrect
Let the length of the train be x m and its speed be y m/sec.
Then, x/y = 8 => x = 8y
(x + 264)/20 = y
y = 22
Speed = 22 m/sec = 22 * 18/5 = 79.2 km/hr. 
Question 45 of 50
45. Question
Manoj borrowed Rs.3450 from Anwar at 6% p.a. simple interest for three years. He then added some more money to the borrowed sum and lent it to Ramu for the same time at 9% p.a. simple interest. If Manoj gains Rs.824.85 by way of interest on the borrowed sum as well as his own amount from the whole transaction, then what is the sum lent by him to Ramu?
Correct
Let the sum lent by Manoj to Ramu be Rs.P.
Amount gained by Manoj = P. 3.9 /100 = 3450.3.6/100 = Rs.824.85
27P = 62100 = 82485
P = (82485 + 62100)/27 = 3055 + 2300 = Rs.5355Incorrect
Let the sum lent by Manoj to Ramu be Rs.P.
Amount gained by Manoj = P. 3.9 /100 = 3450.3.6/100 = Rs.824.85
27P = 62100 = 82485
P = (82485 + 62100)/27 = 3055 + 2300 = Rs.5355 
Question 46 of 50
46. Question
A man buys two articles for Rs.1980 each and he gains 10% on the first and loses 10% on the next. Find his total gain or loss percent?
Correct
Incorrect

Question 47 of 50
47. Question
A train 110 meters long is running with a speed of 60 kmph. In what time will it pass a man who is running at 6 kmph in the direction opposite to that in which the train is going?
Correct
Speed of train relative to man = (60 + 6) km/hr = 66 km/hr
[66 * 5/18] m/sec = [55/3] m/sec.
Time taken to pass the man = [110 * 3/55] sec = 6 secIncorrect
Speed of train relative to man = (60 + 6) km/hr = 66 km/hr
[66 * 5/18] m/sec = [55/3] m/sec.
Time taken to pass the man = [110 * 3/55] sec = 6 sec 
Question 48 of 50
48. Question
150 men consume 1050 kg of rice in 30 days. In how many days will 70 men consume 980 kg of rice?
Correct
Rate of consumption of each man = 1050/(150 * 30) = 7/30 kg/day
Let us say 70 men take x days to consume 150 kg.
Quantity consumed by each item in x days = 7x/30 kg.
Quantity consumed by 70 men in x days = (7x/30)(70)kg
(7x/30)(70) = 980
x = (980 * 30)/490 => x = 60 daysIncorrect
Rate of consumption of each man = 1050/(150 * 30) = 7/30 kg/day
Let us say 70 men take x days to consume 150 kg.
Quantity consumed by each item in x days = 7x/30 kg.
Quantity consumed by 70 men in x days = (7x/30)(70)kg
(7x/30)(70) = 980
x = (980 * 30)/490 => x = 60 days 
Question 49 of 50
49. Question
Ravi invested certain amount for two rates of simple interests at 6% p.a. and 7% p.a. What is the ratio of Ravi’s investments if the interests from those investments are equal?
Correct
Let x be the investment of Ravi in 6% and y be in 7%
x(6)(n)/100 = y(7)(n)/100
=> x/y = 7/6
x : y = 7 : 6Incorrect
Let x be the investment of Ravi in 6% and y be in 7%
x(6)(n)/100 = y(7)(n)/100
=> x/y = 7/6
x : y = 7 : 6 
Question 50 of 50
50. Question
Find the one which does not belong to that group ?
Correct
Tiruvanantapuram, Hyderabad, Bangalore and Bhubaneswar are state capitals, while Calicut is not a state capital.
Incorrect
Tiruvanantapuram, Hyderabad, Bangalore and Bhubaneswar are state capitals, while Calicut is not a state capital.