IPPB Pre Online Test Series 3rd, IPPB Pre Mock Test Series 3
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IPPB Pre Online Test Series 3rd, IPPB Pre Mock Test Series 3. IPPB Prelims Free Mock Test Exam 2019. IPPB Prelims Exam Free Online Quiz 2019, IPPB Prelims Full Online Mock Test Series 3rd in English. Prepare Online test series for IPPB officer scale I with Top rankers Practice Test Papers designed by the subject experts as per latest exam pattern and syllabus.. The IPPB Prelims Full online mock test paper is free for all students. IPPB Prelims Question and Answers in English and Hindi Series 3. Here we are providing IPPB Prelims Full Mock Test Paper in English. IPPB Prelims Mock Test Series 3rd 2019. Now Test your self for IPPB Prelims Exam by using below quiz…
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Question 1 of 50
1. Question
The subduplicate ratio of 1:4 is
Correct
√1 : √4 = 1 : 2
Incorrect
√1 : √4 = 1 : 2

Question 2 of 50
2. Question
A train speeds past a pole in 15 seconds and a platform 100 m long in 25 seconds. Its length is:
Correct
Let the length of the train be x meters and its speed be y m/sec.
They, x / y = 15 => y = x/15
x + 100 / 25 = x / 15
x = 150 m.Incorrect
Let the length of the train be x meters and its speed be y m/sec.
They, x / y = 15 => y = x/15
x + 100 / 25 = x / 15
x = 150 m. 
Question 3 of 50
3. Question
0.003 * ? * 0.0003 = 0.00000027
Correct
0.003 * ? * 0.0003 = 0.00000027
3/1000 * ? * 3/10000 = 3/1000 * 3/1000 * 3/100
? = 3/10 = 0.3Incorrect
0.003 * ? * 0.0003 = 0.00000027
3/1000 * ? * 3/10000 = 3/1000 * 3/1000 * 3/100
? = 3/10 = 0.3 
Question 4 of 50
4. Question
How many figures are required to number the pages the pages of a book containing 365 pages?
Correct
1 to 9 = 9 * 1 = 9
10 to 99 = 90 * 2 = 180
100 to 365 = 266 * 3 = 798
= ———–
= 987Incorrect
1 to 9 = 9 * 1 = 9
10 to 99 = 90 * 2 = 180
100 to 365 = 266 * 3 = 798
= ———–
= 987 
Question 5 of 50
5. Question
Krishan and Nandan jointly started a business. Krishan invested three times as Nandan did and invested his money for double time as compared to Nandan. Nandan earned Rs. 4000. If the gain is proportional to the money invested and the time for which the money is invested then the total gain was?
Correct
3:1
2:1
——
6:1
1 —– 4000
7 —– ? => Rs.28,000Incorrect
3:1
2:1
——
6:1
1 —– 4000
7 —– ? => Rs.28,000 
Question 6 of 50
6. Question
Sides of a rectangular park are in the ratio 3: 2 and its area is 3750 sq m, the cost of fencing it at 50 ps per meter is?
Correct
3x * 2x = 3750 => x = 25
2(75 + 50) = 250 m
250 * 1/2 = Rs.125Incorrect
3x * 2x = 3750 => x = 25
2(75 + 50) = 250 m
250 * 1/2 = Rs.125 
Question 7 of 50
7. Question
A certain amount earns simple interest of Rs. 1750 after 7 years. Had the interest been 2% more, how much more interest would it have earned?
Correct
We need to know the S.I., principal and time to find the rate. Since the principal is not given, so data is inadequate.
Incorrect
We need to know the S.I., principal and time to find the rate. Since the principal is not given, so data is inadequate.

Question 8 of 50
8. Question
A water tank is twofifth full. Pipe A can fill a tank in 10 minutes and pipe B can empty it in 6 minutes. If both the pipes are open, how long will it take to empty or fill the tank completely?
Correct
Clearly, pipe B is faster than pipe A and so, the tank will be emptied.
Part to be emptied = 2/5
Part emptied by (A + B) in 1 minute = (1/6 – 1/10) = 1/15
1/15 : 2/5 :: 1 : x
x = (2/5 * 1 * 15) = 6 min.
So, the tank will be emptied in 6 min.Incorrect
Clearly, pipe B is faster than pipe A and so, the tank will be emptied.
Part to be emptied = 2/5
Part emptied by (A + B) in 1 minute = (1/6 – 1/10) = 1/15
1/15 : 2/5 :: 1 : x
x = (2/5 * 1 * 15) = 6 min.
So, the tank will be emptied in 6 min. 
Question 9 of 50
9. Question
A can do a piece of work in 4 days. B can do it in 5 days. With the assistance of C they completed the work in 2 days. Find in how many days can C alone do it?
Correct
C = 1/2 – 1/4 – 1/5 = 1/20 => 20 days
Incorrect
C = 1/2 – 1/4 – 1/5 = 1/20 => 20 days

Question 10 of 50
10. Question
If A:B = 1/2: 1/3 B:C = 1/2:1/3 then A:B:C?
Correct
A:B = 1/2:1/3 = 3:2
B:C = 1/2:1/3 = 3:2
= ——————–
= A:B:C = 9:6:4Incorrect
A:B = 1/2:1/3 = 3:2
B:C = 1/2:1/3 = 3:2
= ——————–
= A:B:C = 9:6:4 
Question 11 of 50
11. Question
The radius of a wheel is 22.4 cm. What is the distance covered by the wheel in making 500 resolutions.
Correct
In one resolution, the distance covered by the wheel is its own circumference. Distance covered in 500 resolutions.
= 500 * 2 * 22/7 * 22.4 = 70400 cm = 704 mIncorrect
In one resolution, the distance covered by the wheel is its own circumference. Distance covered in 500 resolutions.
= 500 * 2 * 22/7 * 22.4 = 70400 cm = 704 m 
Question 12 of 50
12. Question
Sonika deposited Rs.8000 which amounted to Rs.9200 after 3 years at simple interest. Had the interest been 2% more. She would get how much?
Correct
(8000*3*2)/100 = 480
= 9200
= ——–
= 9680Incorrect
(8000*3*2)/100 = 480
= 9200
= ——–
= 9680 
Question 13 of 50
13. Question
Calculate the number of bricks, each measuring 25 cm * 15 cm * 8 cm required to construct a wall of dimensions 10 m * 4 m * 5 m when 10% of its volume is occupied by mortar?
Correct
10 * 4/100 * 5 * 90/100 = 25/100 * 15/100 * 8/100 * x
10 * 20 * 90 = 15 * 2 * x => x = 6000Incorrect
10 * 4/100 * 5 * 90/100 = 25/100 * 15/100 * 8/100 * x
10 * 20 * 90 = 15 * 2 * x => x = 6000 
Question 14 of 50
14. Question
The length of a rectangle is increased by 25% and its breadth is decreased by 20%. What is the effect on its area?
Correct
100 * 100 = 10000
125 * 80 = 10000
No changeIncorrect
100 * 100 = 10000
125 * 80 = 10000
No change 
Question 15 of 50
15. Question
Excluding stoppages, the speed of a bus is 54 km/hr and including stoppages, it is 45 km/hr. For how many minutes does the bus stop per hour?
Correct
Due to stoppages, it covers 9 km less.
Time taken to cover 9 km = 9/54 * 60 = 10 min.Incorrect
Due to stoppages, it covers 9 km less.
Time taken to cover 9 km = 9/54 * 60 = 10 min. 
Question 16 of 50
16. Question
Thirty men can do a work in 24 days. In how many days can 20 men can do the work, given that the time spent per day is increased by onethird of the previous time?
Correct
Let the number of hours working per day initially be x. we have M_{1} D_{1} H_{1}= M_{2} D_{2} H_{2}
30 * 24 * x = 20 * d_{2} * (4x)/3 => d_{2} = (30 * 24 * 3)/(24 * 4) = 27 days.Incorrect
Let the number of hours working per day initially be x. we have M_{1} D_{1} H_{1}= M_{2} D_{2} H_{2}
30 * 24 * x = 20 * d_{2} * (4x)/3 => d_{2} = (30 * 24 * 3)/(24 * 4) = 27 days. 
Question 17 of 50
17. Question
³√?/9261 = 11/21
Correct
?/9261 = (11/21)^{3} = 1331/9261
=> ? = 1331Incorrect
?/9261 = (11/21)^{3} = 1331/9261
=> ? = 1331 
Question 18 of 50
18. Question
The difference between C.I. and S.I. on an amount of Rs. 15,000 for 2 years is Rs. 96. What is the rate of interest per annum?
Correct
[15000 * (1 + R/100)^{2} – 15000] – (15000 * R * 2)/100 = 96
15000[(1 + R/100)^{2} – 1 – 2R/100] = 96
15000[(100 + R)^{2} – 10000 – 200R]/10000 = 96
R^{2} = (96 * 2)/3 = 64 => R = 8
Rate = 8%Incorrect
[15000 * (1 + R/100)^{2} – 15000] – (15000 * R * 2)/100 = 96
15000[(1 + R/100)^{2} – 1 – 2R/100] = 96
15000[(100 + R)^{2} – 10000 – 200R]/10000 = 96
R^{2} = (96 * 2)/3 = 64 => R = 8
Rate = 8% 
Question 19 of 50
19. Question
Manoj borrowed Rs.3450 from Anwar at 6% p.a. simple interest for three years. He then added some more money to the borrowed sum and lent it to Ramu for the same time at 9% p.a. simple interest. If Manoj gains Rs.824.85 by way of interest on the borrowed sum as well as his own amount from the whole transaction, then what is the sum lent by him to Ramu?
Correct
Let the sum lent by Manoj to Ramu be Rs.P.
Amount gained by Manoj = P. 3.9 /100 = 3450.3.6/100 = Rs.824.85
27P = 62100 = 82485
P = (82485 + 62100)/27 = 3055 + 2300 = Rs.5355Incorrect
Let the sum lent by Manoj to Ramu be Rs.P.
Amount gained by Manoj = P. 3.9 /100 = 3450.3.6/100 = Rs.824.85
27P = 62100 = 82485
P = (82485 + 62100)/27 = 3055 + 2300 = Rs.5355 
Question 20 of 50
20. Question
A group of 10 representatives is to be selected out of 12 seniors and 10 juniors. In how many different ways can the group be selected if it should have at least one senior?
Correct
The total number of ways of forming the group of ten representatives is ²²C₁₀.
The total number of ways of forming the group that consists of no seniors is ¹⁰C₁₀ = 1 way
The required number of ways = ²²C₁₀ – 1Incorrect
The total number of ways of forming the group of ten representatives is ²²C₁₀.
The total number of ways of forming the group that consists of no seniors is ¹⁰C₁₀ = 1 way
The required number of ways = ²²C₁₀ – 1 
Question 21 of 50
21. Question
The simple form of the ratio 2/3:2/5 is?
Correct
2/3 : 2/5 = 10:6 = 5:3
Incorrect
2/3 : 2/5 = 10:6 = 5:3

Question 22 of 50
22. Question
Twenty times a positive integer is less than its square by 96. What is the integer?
Correct
Let the integer be x. Then,
x^{2} – 20x = 96
(x + 4)(x – 24) = 0
x = 24Incorrect
Let the integer be x. Then,
x^{2} – 20x = 96
(x + 4)(x – 24) = 0
x = 24 
Question 23 of 50
23. Question
The product of two successive numbers is 4556. Which of the following is the larger of the two numbers?
Correct
Let the two successive numbers be n, n + 1.
It is given that n(n + 1) = 4556.
=> n^{2} + n – 4556 = 0
=> n^{2} + 68n – 67n – 4556 = 0
=> n(n + 68) – 67(n + 68) = 0
=> n = 67 and (n + 1) = 68.Incorrect
Let the two successive numbers be n, n + 1.
It is given that n(n + 1) = 4556.
=> n^{2} + n – 4556 = 0
=> n^{2} + 68n – 67n – 4556 = 0
=> n(n + 68) – 67(n + 68) = 0
=> n = 67 and (n + 1) = 68. 
Question 24 of 50
24. Question
A group consists of 4 men, 6 women and 5 children. In how many ways can 2 men , 3 women and 1 child selected from the given group?
Correct
Two men, three women and one child can be selected in ⁴C₂ * ⁶C₃ * ⁵C₁ ways
= (4 * 3)/(2 * 1) * (6 * 5 * 4)/(3 * 2) * 5
= 600 ways.Incorrect
Two men, three women and one child can be selected in ⁴C₂ * ⁶C₃ * ⁵C₁ ways
= (4 * 3)/(2 * 1) * (6 * 5 * 4)/(3 * 2) * 5
= 600 ways. 
Question 25 of 50
25. Question
Albert buys 4 horses and 9 cows for Rs. 13,400. If he sells the horses at 10% profit and the cows at 20% profit, then he earns a total profit of Rs. 1880. The cost of a horse is:
Correct
Let C.P. of each horse be Rs. x and C.P. of each cow be Rs. y.
Then, 4x + 9y = 13400 — (i)
And, 10% of 4x + 20% of 9y = 1880
2/5 x + 9/5 y = 1880 => 2x + 9y = 9400 — (ii)
Solving (i) and (ii), we get : x = 2000 and y = 600.
Cost price of each horse = Rs. 2000.Incorrect
Let C.P. of each horse be Rs. x and C.P. of each cow be Rs. y.
Then, 4x + 9y = 13400 — (i)
And, 10% of 4x + 20% of 9y = 1880
2/5 x + 9/5 y = 1880 => 2x + 9y = 9400 — (ii)
Solving (i) and (ii), we get : x = 2000 and y = 600.
Cost price of each horse = Rs. 2000. 
Question 26 of 50
26. Question
Two pipes A and B can fill a tank in 15 min and 20 min respectively. Both the pipes are opened together but after 4 min, pipe A is turned off. What is the total time required to fill the tank?
Correct
Part filled in 4 minutes = 4(1/15 + 1/20) = 7/15
Remaining part = 1 – 7/15 = 8/15
Part filled by B in 1 minute = 1/20
1/20 : 8/15 :: 1 ; x
x = 8/15 * 1 * 20 = 10 2/3 min = 10 min 40 sec.
The tank will be full in (4 min. + 10 min. 40 sec) = 14 min 40 sec.Incorrect
Part filled in 4 minutes = 4(1/15 + 1/20) = 7/15
Remaining part = 1 – 7/15 = 8/15
Part filled by B in 1 minute = 1/20
1/20 : 8/15 :: 1 ; x
x = 8/15 * 1 * 20 = 10 2/3 min = 10 min 40 sec.
The tank will be full in (4 min. + 10 min. 40 sec) = 14 min 40 sec. 
Question 27 of 50
27. Question
The cost price of an article is 64% of the marked price. Calculate the gain percent after allowing a discount of 12%?
Correct
Let marked price = Rs. 100.
Then, C.P. = RS. 64, S.P. = Rs. 88
Gain % = 24/64 * 100 = 37.5%.Incorrect
Let marked price = Rs. 100.
Then, C.P. = RS. 64, S.P. = Rs. 88
Gain % = 24/64 * 100 = 37.5%. 
Question 28 of 50
28. Question
2 1/3 + 4 1/6 – 2 2/3 – 1 1/2 = 2 ?/3
Correct
2 1/3 + 4 1/6 – 2 2/3 – 1 1/2 = 2 ?/3
= 7/3 + 25/6 – 8/3 – 3/2 = (14 + 25 – 16 – 9)/6 = 7/3 = 2 1/3
? = 1Incorrect
2 1/3 + 4 1/6 – 2 2/3 – 1 1/2 = 2 ?/3
= 7/3 + 25/6 – 8/3 – 3/2 = (14 + 25 – 16 – 9)/6 = 7/3 = 2 1/3
? = 1 
Question 29 of 50
29. Question
Ajay spends 45% of his monthly income on household items, 25% of his monthly income on buying cloths, 7.5% of his monthly income on medicines and saves the remaining amount which is Rs. 9000. Find his monthly income.
Correct
Let the monthly income of Ajay be Rs. x
Savings of Ajay = x – (45 + 25 + 7.5)/100 * x = 22.5/100 x
22.5/100 x = 9000
x = 40000.Incorrect
Let the monthly income of Ajay be Rs. x
Savings of Ajay = x – (45 + 25 + 7.5)/100 * x = 22.5/100 x
22.5/100 x = 9000
x = 40000. 
Question 30 of 50
30. Question
On dividing 2272 as well as 875 by 3digit number N, we get the same remainder. The sum of the digits of N is:
Correct
Clearly, (2272 – 875) = 1397, is exactly divisible by N.
Now. 1397 = 11 * 127
The required 3digit number is 127, the sum of whose digit is 10.Incorrect
Clearly, (2272 – 875) = 1397, is exactly divisible by N.
Now. 1397 = 11 * 127
The required 3digit number is 127, the sum of whose digit is 10. 
Question 31 of 50
31. Question
Divide Rs.32000 in the ratio 3:5?
Correct
3/8 * 32000 = 12000
5/8 * 32000 = 20000Incorrect
3/8 * 32000 = 12000
5/8 * 32000 = 20000 
Question 32 of 50
32. Question
After working for 6 days, Ashok finds that only 1/3 rd of the work has been done. He employs Ravi who is 60% as efficient as Ashok. How many days more would Ravi take to complete the work?
Correct
1/3 — 6
1 ——? A = 18
R = 1/18 * 60/100 = 1/30
1 —– 1/30
2/3 —? => 20 daysIncorrect
1/3 — 6
1 ——? A = 18
R = 1/18 * 60/100 = 1/30
1 —– 1/30
2/3 —? => 20 days 
Question 33 of 50
33. Question
Two passenger trains start at the same hour in the day from two different stations and move towards each other at the rate of 16 kmph and 21 kmph respectively. When they meet, it is found that one train has traveled 60 km more than the other one. The distance between the two stations is?
Correct
1h —– 5
? —— 60
12 h
RS = 16 + 21 = 37
T = 12
D = 37 * 12 = 444Incorrect
1h —– 5
? —— 60
12 h
RS = 16 + 21 = 37
T = 12
D = 37 * 12 = 444 
Question 34 of 50
34. Question
A salt manufacturing company produced a total of 5000 tonnes of salt in January of a particular year. Starting from February its production increased by 100 tonnes every month over the previous months until the end of the year. Find its average monthly production for that year?
Correct
Total production of salt by the company in that year = 5000 + 5100 + 5200 + …. + 6100 = 66600.
Average monthly production of salt for that year = 66600/12 = 5550.Incorrect
Total production of salt by the company in that year = 5000 + 5100 + 5200 + …. + 6100 = 66600.
Average monthly production of salt for that year = 66600/12 = 5550. 
Question 35 of 50
35. Question
Find the least number of five digits which is exactly divisible by 12, 15 and 18?
Correct
LCM = 180
180) 10000 (55
9900
———
100
10000 + 180 – 100 = 10080Incorrect
LCM = 180
180) 10000 (55
9900
———
100
10000 + 180 – 100 = 10080 
Question 36 of 50
36. Question
A money lender finds that due to a fall in the annual rate of interest from 8% to 7 3/4 % his yearly income diminishes by Rs. 61.50, his capital is?
Correct
Let the capital be Rs. x. Then,
(x * 8 * 1)/100 – (x * 31/4 * 1/100) = 61.50
32x – 31x = 6150 * 4
x = 24,600.Incorrect
Let the capital be Rs. x. Then,
(x * 8 * 1)/100 – (x * 31/4 * 1/100) = 61.50
32x – 31x = 6150 * 4
x = 24,600. 
Question 37 of 50
37. Question
4 men and 6 women can complete a work in 8 days, while 3 men and 7 women can complete it in 10 days. In how many days will 10 women complete it?
Correct
Let 1 man’s 1 day work = x and 1 woman’s 1 day work = y.
Then, 4x + 6y = 1/8 and 3x + 7y = 1/10
Solving these two equations, we get:
x = 11/400 and y = 1/400
1 woman’s 1 day work = (1/400 * 10) = 1/40.
Hence, 10 women will complete the work in 40 days.Incorrect
Let 1 man’s 1 day work = x and 1 woman’s 1 day work = y.
Then, 4x + 6y = 1/8 and 3x + 7y = 1/10
Solving these two equations, we get:
x = 11/400 and y = 1/400
1 woman’s 1 day work = (1/400 * 10) = 1/40.
Hence, 10 women will complete the work in 40 days. 
Question 38 of 50
38. Question
If a : b = 4 : 1, then find (a – 3b)/(2a – b).
Correct
a : b = 4 : 1
a/b = 4/1 => a = 4b
(a – 3b)/(2a – b) = (4b – 3b)/[2(4b) – b]
= b/(8b – b) = b/7b => 1/7Incorrect
a : b = 4 : 1
a/b = 4/1 => a = 4b
(a – 3b)/(2a – b) = (4b – 3b)/[2(4b) – b]
= b/(8b – b) = b/7b => 1/7 
Question 39 of 50
39. Question
I. x^{2} – x – 42 = 0,
II. y^{2} – 17y + 72 = 0 to solve both the equations to find the values of x and y?Correct
I. x^{2} – 7x + 6x – 42 = 0
=> (x – 7)(x + 6) = 0 => x = 7, 6
II. y^{2} – 8y – 9y + 72 = 0
=> (y – 8)(y – 9) = 0 => y = 8, 9
=> x < yIncorrect
I. x^{2} – 7x + 6x – 42 = 0
=> (x – 7)(x + 6) = 0 => x = 7, 6
II. y^{2} – 8y – 9y + 72 = 0
=> (y – 8)(y – 9) = 0 => y = 8, 9
=> x < y 
Question 40 of 50
40. Question
Three 6 faced dice are thrown together. The probability that exactly two dice show the same number on them is .
Correct
Using question number 11 and 12, we get the probability as
1 – (1/36 + 5/9) = 5/12Incorrect
Using question number 11 and 12, we get the probability as
1 – (1/36 + 5/9) = 5/12 
Question 41 of 50
41. Question
Find the one which does not belong to that group ?
Correct
Except 132, other numbers are odd numbers.
Incorrect
Except 132, other numbers are odd numbers.

Question 42 of 50
42. Question
A began business with Rs.45000 and was joined afterwards by B with Rs.5400. When did B join if the profits at the end of the year were divided in the ratio of 2:1?
Correct
45*12 : 54*x = 2: 1
x = 5
12 5 = 7Incorrect
45*12 : 54*x = 2: 1
x = 5
12 5 = 7 
Question 43 of 50
43. Question
A sum of money amounts to Rs. 9800 after 5 years and Rs. 12005 after 8 years at the same rate of simple interest. The rate of interest per annum is?
Correct
S.I. for 3 years = (12005 – 9800) = Rs. 2205
S.I. for 5 years = Rs. 2205/3 * 5 = Rs. 3675.
Principal = (9800 – 3675) = Rs. 6125
Hence, rate = (100 * 3675) / (6125 * 5) = 12%Incorrect
S.I. for 3 years = (12005 – 9800) = Rs. 2205
S.I. for 5 years = Rs. 2205/3 * 5 = Rs. 3675.
Principal = (9800 – 3675) = Rs. 6125
Hence, rate = (100 * 3675) / (6125 * 5) = 12% 
Question 44 of 50
44. Question
109.13 * 34.14 – 108.12 * 33 = ?
Correct
109 * 34 – 108 * 33
= 3706 – 3564 = 142Incorrect
109 * 34 – 108 * 33
= 3706 – 3564 = 142 
Question 45 of 50
45. Question
If the price of an article went up by 20%, then by what percent should it be brought down to bring it back to its original price?
Correct
Let the price of the article be Rs. 100.
20% of 100 = 20.
New price = 100 + 20 = Rs. 120
Required percentage = (120 – 100)/120 * 100
= 20/120 * 100 = 50/3 = 16 2/3%.Incorrect
Let the price of the article be Rs. 100.
20% of 100 = 20.
New price = 100 + 20 = Rs. 120
Required percentage = (120 – 100)/120 * 100
= 20/120 * 100 = 50/3 = 16 2/3%. 
Question 46 of 50
46. Question
What number has a 5:1 ratio to the number 10?
Correct
5:1 = x: 10
x = 50Incorrect
5:1 = x: 10
x = 50 
Question 47 of 50
47. Question
Ten years ago, the age of Anand was onethird the age of Bala at that time. The present age of Bala is 12 years more than the present age of Anand. Find the present age of Anand?
Correct
Let the present ages of Anand and Bala be ‘a’ and ‘b’ respectively.
a – 10 = 1/3 (b – 10) — (1)
b = a + 12
Substituting b = a + 12 in first equation,
a – 10 = 1/3 (a + 2) => 3a – 30 = a + 2
=> 2a = 32 => a = 16.Incorrect
Let the present ages of Anand and Bala be ‘a’ and ‘b’ respectively.
a – 10 = 1/3 (b – 10) — (1)
b = a + 12
Substituting b = a + 12 in first equation,
a – 10 = 1/3 (a + 2) => 3a – 30 = a + 2
=> 2a = 32 => a = 16. 
Question 48 of 50
48. Question
The sale price of an article including the sales tax is Rs. 616. The rate of sales tax is 10%. If the shopkeeper has made a profit of 12%, then the cost price of the article is:
Correct
110% of S.P. = 616
S.P. = (616 * 100)/110 = Rs. 560
C.P = (110 * 560)/112 = Rs. 500Incorrect
110% of S.P. = 616
S.P. = (616 * 100)/110 = Rs. 560
C.P = (110 * 560)/112 = Rs. 500 
Question 49 of 50
49. Question
The curved surface of a sphere is 64 π cm^{2}. Find its radius?
Correct
4 πr^{2 }= 64 => r = 4
Incorrect
4 πr^{2 }= 64 => r = 4

Question 50 of 50
50. Question
In a flight of 600 km, an aircraft was slowed down due to bad weather. Its average speed for the trip was reduced by 200 km/hr and the time of flight increased by 30 minutes. The duration of the flight is?
Correct
Let the duration of the flight be x hours. Then,
600/x – 600/(x + 1/2) = 200
x(2x + 1) = 3 2x^{2} + x – 3 = 0
(2x + 3)(x – 1) = 0
x = 1 hr.Incorrect
Let the duration of the flight be x hours. Then,
600/x – 600/(x + 1/2) = 200
x(2x + 1) = 3 2x^{2} + x – 3 = 0
(2x + 3)(x – 1) = 0
x = 1 hr.