IPPB Prelims Online Test Series 1, IPPB Pre Mock Test Series 1
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IPPB Prelims Online Test Series 1, IPPB Pre Mock Test Series 1. Take IPPB Prelims Free Quiz 2019 Series 1st .The Indian Post Payments Bank recently released the Officer Scale I admit card.
This paper has 50 questions.
Time allowed is 50 minutes.
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Question 1 of 50
1. Question
A train passes a station platform in 36 seconds and a man standing on the platform in 20 seconds. If the speed of the train is 54 km/hr, what is the length of the platform?
Correct
Speed = [54 * 5/18] m/sec = 15 m/sec.
Length of the train = (15 * 20) m = 300 m.
Let the length of the platform be x meters.
Then, x + 300 / 36 = 15
x + 300 = 540
x = 240 m.Incorrect
Speed = [54 * 5/18] m/sec = 15 m/sec.
Length of the train = (15 * 20) m = 300 m.
Let the length of the platform be x meters.
Then, x + 300 / 36 = 15
x + 300 = 540
x = 240 m. 
Question 2 of 50
2. Question
Find the H.C.F of 12, 16, 18 and 24?
Correct
Incorrect

Question 3 of 50
3. Question
Find the least multiple of 13 which when divided by 6, 8 and 12 leaves 5, 7 and 11 as remainders respectively?
Correct
Incorrect

Question 4 of 50
4. Question
Find the sum The difference between the compound and S.I. on a certain sum of money for 2 years at 10% per annum is Rs.15of money?
Correct
P = 15(100/10)^{2 }=> P = 1500
Incorrect
P = 15(100/10)^{2 }=> P = 1500

Question 5 of 50
5. Question
A man said to his son, “I was twothird of your present age when you were born”. If the present age of the man is 48 years, find the present age of the son?
Correct
Present age of the son be P, he was born P years ago.
The age of the man was: (48 – P).
His age when the son was born should be equal to 2/3 of P.
(48 – P) = 2/3 P
5P = 144 => P = 28.8Incorrect
Present age of the son be P, he was born P years ago.
The age of the man was: (48 – P).
His age when the son was born should be equal to 2/3 of P.
(48 – P) = 2/3 P
5P = 144 => P = 28.8 
Question 6 of 50
6. Question
A and B complete a work in 6 days. A alone can do it in 10 days. If both together can do the work in how many days?
Correct
1/6 + 1/10 = 8/30 = 4/15
15/4 = 3.75 daysIncorrect
1/6 + 1/10 = 8/30 = 4/15
15/4 = 3.75 days 
Question 7 of 50
7. Question
Rahim bought 65 books for Rs.1150 from one shop and 50 books for Rs.920 from another. What is the average price he paid per book ?
Correct
Average price per book = (1150 + 920) / (65 + 50) = 2070 / 115 = Rs.18
Incorrect
Average price per book = (1150 + 920) / (65 + 50) = 2070 / 115 = Rs.18

Question 8 of 50
8. Question
If Rs. 510 be divided among A, B, C in such a way that A gets 2/3 of what B gets and B gets 1/4 of what C gets, then their shares are respectively:
Correct
(A = 2/3 B and B = 1/4 C) = A/B = 2/3 and B/C = 1/4
A:B = 2:3 and B:C = 1:4 = 3:12
A:B:C = 2:3:12
A;s share = 510 * 2/17 = Rs. 60
B’s share = 510 * 3/17 = Rs. 90
C’s share = 510 * 12/17 = Rs. 360.Incorrect
(A = 2/3 B and B = 1/4 C) = A/B = 2/3 and B/C = 1/4
A:B = 2:3 and B:C = 1:4 = 3:12
A:B:C = 2:3:12
A;s share = 510 * 2/17 = Rs. 60
B’s share = 510 * 3/17 = Rs. 90
C’s share = 510 * 12/17 = Rs. 360. 
Question 9 of 50
9. Question
If x % of 80 = 20% of y, then x = ? and y = ?
Correct
x % of 80 = 20 % of y => x / 100 (80) = 20 / 100 (y)
=> 4x = y
i.e x / y = ¼Incorrect
x % of 80 = 20 % of y => x / 100 (80) = 20 / 100 (y)
=> 4x = y
i.e x / y = ¼ 
Question 10 of 50
10. Question
(0.9 * 0.9 * 0.9 + 0.8 * 0.8 * 0.8) / (1.6 * 1.6 * 1.6 + 1.8 * 1.8 * 1.8) = ?
Correct
(0.9 * 0.9 * 0.9 + 0.8 * 0.8 * 0.8) / (1.6 * 1.6 * 1.6 + 1.8 * 1.8 * 1.8)
= (0.9 * 0.9 * 0.9 + 0.8 * 0.8 * 0.8) / 2^{3}(0.8 * 0.8 * 0.8 + 0.9 * 0.9 * 0.9) = 1/8 = 0.125Incorrect
(0.9 * 0.9 * 0.9 + 0.8 * 0.8 * 0.8) / (1.6 * 1.6 * 1.6 + 1.8 * 1.8 * 1.8)
= (0.9 * 0.9 * 0.9 + 0.8 * 0.8 * 0.8) / 2^{3}(0.8 * 0.8 * 0.8 + 0.9 * 0.9 * 0.9) = 1/8 = 0.125 
Question 11 of 50
11. Question
Find the area of circle whose radius is 7m?
Correct
22/7 * 7 * 7 = 154
Incorrect
22/7 * 7 * 7 = 154

Question 12 of 50
12. Question
I. a^{2} – 2a – 8 = 0,
II. b^{2} = 9 to solve both the equations to find the values of a and b?Correct
I. (a – 4)(a + 2) = 0
=> a = 4, 2
II. b^{2} = 9
=> b = ± 3
2 < 3, 2 > 3, 4 > 3, 4 > 3,
No relation can be established between a and b.Incorrect
I. (a – 4)(a + 2) = 0
=> a = 4, 2
II. b^{2} = 9
=> b = ± 3
2 < 3, 2 > 3, 4 > 3, 4 > 3,
No relation can be established between a and b. 
Question 13 of 50
13. Question
A man goes from A to B at a speed of 20 kmph and comes back to A at a speed of 30 kmph. Find his average speed for the entire journey?
Correct
Distance from A and B be ‘d’
Average Speed = total distance/total time
Average Speed = (2d)/[(d/20) + (d/30)]
= (2d)/[5d/60) => 24 kmph.Incorrect
Distance from A and B be ‘d’
Average Speed = total distance/total time
Average Speed = (2d)/[(d/20) + (d/30)]
= (2d)/[5d/60) => 24 kmph. 
Question 14 of 50
14. Question
A can do a piece of work in 4 hours; B and C together can do it in 3 hours, which A and C together can do it in 2 hours. How long will B alone take to do it?
Correct
A’s 1 hour work = 1/4;
(B + C)’s 1 hour work = 1/3;
(A + C)’s 1 hour work = 1/2
(A + B + C)’s 1 hour work = (1/4 + 1/3) = 7/12
B’s 1 hour work = (7/12 + 1/2) = 1/12
B alone will take 12 hours to do the work.Incorrect
A’s 1 hour work = 1/4;
(B + C)’s 1 hour work = 1/3;
(A + C)’s 1 hour work = 1/2
(A + B + C)’s 1 hour work = (1/4 + 1/3) = 7/12
B’s 1 hour work = (7/12 + 1/2) = 1/12
B alone will take 12 hours to do the work. 
Question 15 of 50
15. Question
Compound interest earned on a sum for the second and the third years are Rs.1200 and Rs.1440 respectively. Find the rate of interest?
Correct
Rs.1440 – 1200 = Rs.240 is the interest on Rs.1200 for one year.
Rate of interest = (100 * 240) / (100 * 1) = 20% p.aIncorrect
Rs.1440 – 1200 = Rs.240 is the interest on Rs.1200 for one year.
Rate of interest = (100 * 240) / (100 * 1) = 20% p.a 
Question 16 of 50
16. Question
The compound interest on Rs. 30,000 at 7% per annum is Rs. 4347. The period(in years) is?
Correct
Amount = (30000 + 4347) = Rs. 34347
Let the time be n years. Then,
30000(1 + 7/100)^{n} = 34347
= (107/100)^{n} = 34347/30000 = (107/100)^{2}
n = 2 years.Incorrect
Amount = (30000 + 4347) = Rs. 34347
Let the time be n years. Then,
30000(1 + 7/100)^{n} = 34347
= (107/100)^{n} = 34347/30000 = (107/100)^{2}
n = 2 years. 
Question 17 of 50
17. Question
A person can swim in still water at 4 km/h. If the speed of water 2 km/h, how many hours will the man take to swim back against the current for 6km?
Correct
M = 4
S = 2
US = 4 – 2 = 2
D = 6
T = 6/2 = 3Incorrect
M = 4
S = 2
US = 4 – 2 = 2
D = 6
T = 6/2 = 3 
Question 18 of 50
18. Question
The ratio of investments of two partners P and Q is 7:5 and the ratio of their profits is 7:10. If P invested the money for 5 months, find for how much time did Q invest the money?
Correct
7*5: 5*x = 7:10
x = 10Incorrect
7*5: 5*x = 7:10
x = 10 
Question 19 of 50
19. Question
A mixture of 150 liters of wine and water contains 20% water. How much more water should be added so that water becomes 25% of the new mixture?
Correct
Number of liters of water in150 liters of the mixture = 20% of 150 = 20/100 * 150 = 30 liters.
P liters of water added to the mixture to make water 25% of the new mixture.
Total amount of water becomes (30 + P) and total volume of mixture is (150 + P).
(30 + P) = 25/100 * (150 + P)
120 + 4P = 150 + P => P = 10 liters.Incorrect
Number of liters of water in150 liters of the mixture = 20% of 150 = 20/100 * 150 = 30 liters.
P liters of water added to the mixture to make water 25% of the new mixture.
Total amount of water becomes (30 + P) and total volume of mixture is (150 + P).
(30 + P) = 25/100 * (150 + P)
120 + 4P = 150 + P => P = 10 liters. 
Question 20 of 50
20. Question
The time taken by a man to row his boat upstream is twice the time taken by him to row the same distance downstream. If the speed of the boat in still water is 42 kmph, find the speed of the stream?
Correct
The ratio of the times taken is 2:1.
The ratio of the speed of the boat in still water to the speed of the stream = (2+1)/(21) = 3/1 = 3:1
Speed of the stream = 42/3 = 14 kmph.Incorrect
The ratio of the times taken is 2:1.
The ratio of the speed of the boat in still water to the speed of the stream = (2+1)/(21) = 3/1 = 3:1
Speed of the stream = 42/3 = 14 kmph. 
Question 21 of 50
21. Question
A tank is filled in eight hours by three pipes A, B and C. Pipe A is twice as fast as pipe B, and B is twice as fast as C. How much time will pipe B alone take to fill the tank?
Correct
1/A + 1/B + 1/C = 1/8 (Given)
Also given that A = 2B and B = 2C
=> 1/2B + 1/B + 2/B = 1/8
=> (1 + 2 + 4)/2B = 1/8
=> 2B/7 = 8
=> B = 28 hours.Incorrect
1/A + 1/B + 1/C = 1/8 (Given)
Also given that A = 2B and B = 2C
=> 1/2B + 1/B + 2/B = 1/8
=> (1 + 2 + 4)/2B = 1/8
=> 2B/7 = 8
=> B = 28 hours. 
Question 22 of 50
22. Question
(17^{14} * 17^{16}) / 17^{8} = ?
Correct
? = 17^{14+168} = 17^{22}
Incorrect
? = 17^{14+168} = 17^{22}

Question 23 of 50
23. Question
What is the least number to be subtracted from 11, 15, 21 and 30 each so that the resultant numbers become proportional?
Correct
Let the least number to be subtracted be ‘x’, then 11 – x, 15 – x, 21 – x and 30 – x are in proportion.
<=> (11 – x):(15 – x) = (21 – x):(30 x)(21 – x)
From the options, when x = 3
=> 8 * 27 = 12 * 18 => then x = 3. => (11 – x)(30 – x) = (15 – x)(21 – x)Incorrect
Let the least number to be subtracted be ‘x’, then 11 – x, 15 – x, 21 – x and 30 – x are in proportion.
<=> (11 – x):(15 – x) = (21 – x):(30 x)(21 – x)
From the options, when x = 3
=> 8 * 27 = 12 * 18 => then x = 3. => (11 – x)(30 – x) = (15 – x)(21 – x) 
Question 24 of 50
24. Question
Five years ago the average of the ages of A and B was 40 years and now the average of the ages of B and C is 48 years. What will be the age of the B ten years hence?
Correct
Let the present ages of A, B and C be a, b and c respectively.
Given, [(a – 5) + (b – 5)] / 2 = 40 => a + b = 90 — (1)
(b + c)/2 = 48 => b + c = 96 — (2)
From (1) and (2), we cannot find b.Incorrect
Let the present ages of A, B and C be a, b and c respectively.
Given, [(a – 5) + (b – 5)] / 2 = 40 => a + b = 90 — (1)
(b + c)/2 = 48 => b + c = 96 — (2)
From (1) and (2), we cannot find b. 
Question 25 of 50
25. Question
7589 – ? = 3434
Correct
Let 7589 – x = 3434
Then x = 7589 – 3434 = 4155Incorrect
Let 7589 – x = 3434
Then x = 7589 – 3434 = 4155 
Question 26 of 50
26. Question
A and B rent a pasture for 10 months. A put in 80 cows for 7 months. How many can B put in for the remaining 3 months, if he pays half as much again as A?
Correct
80* 7: x* 3 = 1:1 1/2
560: 3x = 2: 3
x = 280Incorrect
80* 7: x* 3 = 1:1 1/2
560: 3x = 2: 3
x = 280 
Question 27 of 50
27. Question
√3584 * 52.034 = ?
Correct
√3600 * 52 = ?
=> ? = 60 * 52 = 3120Incorrect
√3600 * 52 = ?
=> ? = 60 * 52 = 3120 
Question 28 of 50
28. Question
A, B and C are partners in a business. Their capitals are respectively, Rs.5000, Rs.6000 and Rs.4000. A gets 30% of the total profit for managing the business. The remaining profit is divided among three in the ratio of their capitals. In the end of the year, the profit of A is Rs.200 more than the sum of the profits of B and C. Find the total profit.
Correct
A:B:C = 5:6:4
Let the total profit = 100 – 30 = 70
5/15 * 70 = 70/3
A share = 70/3 + 30 = 160/3
B + C share = 100 – 160/3 = 140/3
A(B+C) = 160/3 – 140/3 = 20/3
20/3 — 200
100 — ? => 3000Incorrect
A:B:C = 5:6:4
Let the total profit = 100 – 30 = 70
5/15 * 70 = 70/3
A share = 70/3 + 30 = 160/3
B + C share = 100 – 160/3 = 140/3
A(B+C) = 160/3 – 140/3 = 20/3
20/3 — 200
100 — ? => 3000 
Question 29 of 50
29. Question
A can do a piece of work in 21 days and B in 28 days. Together they started the work and B left after 4 days. In how many days can A alone do the remaining work?
Correct
Let A worked for x days.
x/21 + 4/28 = 1 => x/21 = 6/7 => x = 18
A worked for 18 days. So, A can complete the remaining work in 18 – 4 = 14 days.Incorrect
Let A worked for x days.
x/21 + 4/28 = 1 => x/21 = 6/7 => x = 18
A worked for 18 days. So, A can complete the remaining work in 18 – 4 = 14 days. 
Question 30 of 50
30. Question
A man swims downstream 72 km and upstream 45 km taking 9 hours each time; what is the speed of the current?
Correct
72 — 9 DS = 8
? — 1
45 — 9 US = 5
? — 1 S = ?
S = (8 – 5)/2 = 1.5Incorrect
72 — 9 DS = 8
? — 1
45 — 9 US = 5
? — 1 S = ?
S = (8 – 5)/2 = 1.5 
Question 31 of 50
31. Question
How many seconds will a 500 meter long train take to cross a man walking with a speed of 3 km/hr in the direction of the moving train if the speed of the train is 63 km/hr?
Correct
Let length of tunnel is x meter
Distance = 800+x meter
Time = 1 minute = 60 seconds
Speed = 78 km/hr = 78*5/18 m/s = 65/3 m/s
Distance = Speed*Time
800+x = (65/3) * 60
800+x = 20 * 65 = 1300
x = 1300 – 800 = 500 metersIncorrect
Let length of tunnel is x meter
Distance = 800+x meter
Time = 1 minute = 60 seconds
Speed = 78 km/hr = 78*5/18 m/s = 65/3 m/s
Distance = Speed*Time
800+x = (65/3) * 60
800+x = 20 * 65 = 1300
x = 1300 – 800 = 500 meters 
Question 32 of 50
32. Question
A can do a piece of work in 10 days and B can do the same work in 12 days. A and B worked together for 2 days. How many more days are required to complete the remaining work if they work together?
Correct
A can do 1/10 of the work in a day.
B can do 1/12 of the work in a 1 day.
Both of them together can do (1/10 + 1/12) part of work in 1 day = (6 + 5)/60 = 11/60
They take 60/11 days to complete the work together.
Given that they already worked for 2 days.
The number of days required to complete remaining work => 60/11 – 2 = 38/11 = 3 (5/11) days.Incorrect
A can do 1/10 of the work in a day.
B can do 1/12 of the work in a 1 day.
Both of them together can do (1/10 + 1/12) part of work in 1 day = (6 + 5)/60 = 11/60
They take 60/11 days to complete the work together.
Given that they already worked for 2 days.
The number of days required to complete remaining work => 60/11 – 2 = 38/11 = 3 (5/11) days. 
Question 33 of 50
33. Question
A large tanker can be filled by two pipes A and B in 60 and 40 minutes respectively. How many minutes will it take to fill the tanker from empty state if B is used for half the time and A and B fill it together for the other half?
Correct
Part filled by (A + B) in 1 minute = (1/60 + 1/40) = 1/24
Suppose the tank is filled in x minutes.
Then, x/2(1/24 + 1/40) = 1
x/2 * 1/15 = 1 => x = 30 min.Incorrect
Part filled by (A + B) in 1 minute = (1/60 + 1/40) = 1/24
Suppose the tank is filled in x minutes.
Then, x/2(1/24 + 1/40) = 1
x/2 * 1/15 = 1 => x = 30 min. 
Question 34 of 50
34. Question
Aamir saves 32% of his monthly salary. If he spends Rs. 27200, then find his savings?
Correct
Let the monthly salary of Aamir be Rs. x.
68% of x = 27200
=> x = (27200 * 100)/68 = 40000
His savings = 32/100 * 40000 = 12800.Incorrect
Let the monthly salary of Aamir be Rs. x.
68% of x = 27200
=> x = (27200 * 100)/68 = 40000
His savings = 32/100 * 40000 = 12800. 
Question 35 of 50
35. Question
If 25% of x is 15 less than 15% of 1500, then x is?
Correct
25% of x = x/4 ; 15% of 1500 = 15/100 * 1500 = 225
Given that, x/4 = 225 – 15 => x/4 = 210 => x = 840.Incorrect
25% of x = x/4 ; 15% of 1500 = 15/100 * 1500 = 225
Given that, x/4 = 225 – 15 => x/4 = 210 => x = 840. 
Question 36 of 50
36. Question
Two numbers 4242 and 2903 when divided by a certain number of three digits, leave the same remainder. Find the number?
Correct
Incorrect

Question 37 of 50
37. Question
The difference between simple and compound interest on Rs. 1200 for one year at 10% per annum reckoned halfyearly is?
Correct
S.I. = (1200 * 10 * 1)/100 = Rs. 120
C.I. = [1200 * (1 + 5/100)2 – 1200] = Rs. 123 Difference = (123 – 120) = Rs. 3.Incorrect
S.I. = (1200 * 10 * 1)/100 = Rs. 120
C.I. = [1200 * (1 + 5/100)2 – 1200] = Rs. 123 Difference = (123 – 120) = Rs. 3. 
Question 38 of 50
38. Question
The area of the square formed on the diagonal of a rectangle as its side is 108 1/3 % more than the area of the rectangle. If the perimeter of the rectangle is 28 units, find the difference between the sides of the rectangle?
Correct
Let the sides of the rectangle be l and b respectively.
From the given data,
(√l^{2} + b^{2}) = (1 + 108 1/3 %)lb
=> l^{2} + b^{2} = (1 + 325/3 * 1/100)lb
= (1 + 13/12)lb
= 25/12 lb
=> (l^{2} + b^{2})/lb = 25/12
12(l^{2} + b^{2}) = 25lb
Adding 24lb on both sides
12l^{2} + 12b^{2} + 24lb = 49lb
12(l^{2} + b^{2} + 2lb) = 49lb
but 2(l + b) = 28 => l + b = 14
12(l + b)^{2} = 49lb=> 12(14)^{2} = 49lb=> lb = 48Since l + b = 14, l = 8 and b = 6l – b = 8 – 6 = 2m.Incorrect
Let the sides of the rectangle be l and b respectively.
From the given data,
(√l^{2} + b^{2}) = (1 + 108 1/3 %)lb
=> l^{2} + b^{2} = (1 + 325/3 * 1/100)lb
= (1 + 13/12)lb
= 25/12 lb
=> (l^{2} + b^{2})/lb = 25/12
12(l^{2} + b^{2}) = 25lb
Adding 24lb on both sides
12l^{2} + 12b^{2} + 24lb = 49lb
12(l^{2} + b^{2} + 2lb) = 49lb
but 2(l + b) = 28 => l + b = 14
12(l + b)^{2} = 49lb=> 12(14)^{2} = 49lb=> lb = 48Since l + b = 14, l = 8 and b = 6l – b = 8 – 6 = 2m. 
Question 39 of 50
39. Question
The triplicate ratio of 1:2 is?
Correct
1^{3}: 2^{3} = 1:8
Incorrect
1^{3}: 2^{3} = 1:8

Question 40 of 50
40. Question
A total of 3000 chocolates were distributed among 120 boys and girls such that each boy received 2 chocolates and each girl received 3 chocolates. Find the respective number of boys and girls?
Correct
Let the number of boys be x.
Number of girls is 120 – x.
Total number of chocolates received by boys and girls = 2x + 3(120 – x) = 300
=> 360 – x = 300 => x = 60.
So, the number of boys or girls is 60.Incorrect
Let the number of boys be x.
Number of girls is 120 – x.
Total number of chocolates received by boys and girls = 2x + 3(120 – x) = 300
=> 360 – x = 300 => x = 60.
So, the number of boys or girls is 60. 
Question 41 of 50
41. Question
What is the difference between the largest number and the least number written with the figures 3, 4, 7, 0, 3?
Correct
74330 Largest
30347 Smallest
————
43983Incorrect
74330 Largest
30347 Smallest
————
43983 
Question 42 of 50
42. Question
The average of first 10 even numbers is?
Correct
Sum of 10 even numbers = 10 * 11 = 110
Average = 110/10 = 11Incorrect
Sum of 10 even numbers = 10 * 11 = 110
Average = 110/10 = 11 
Question 43 of 50
43. Question
If x % of 80 = 20% of y, then x = ? and y = ?
Correct
x % of 80 = 20 % of y => x / 100 (80) = 20 / 100 (y)
=> 4x = y
i.e x / y = ¼Incorrect
x % of 80 = 20 % of y => x / 100 (80) = 20 / 100 (y)
=> 4x = y
i.e x / y = ¼ 
Question 44 of 50
44. Question
The ratio of the area of a square to that of the square drawn on its diagonal is?
Correct
Incorrect

Question 45 of 50
45. Question
Find the one which does not belong to that group ?
Correct
30 = 3^{3} + 3, 630 = 5^{4} + 5, 10 = 2^{3} + 2, 520 = 8^{3} + 8 and 130 = 5^{3} + 5.
30, 10, 130 and 520 can be expressed as n^{3} + n but not 630.Incorrect
30 = 3^{3} + 3, 630 = 5^{4} + 5, 10 = 2^{3} + 2, 520 = 8^{3} + 8 and 130 = 5^{3} + 5.
30, 10, 130 and 520 can be expressed as n^{3} + n but not 630. 
Question 46 of 50
46. Question
Two pipes A and B can separately fill a tank in 12 and 15 minutes respectively. A third pipe C can drain off 45 liters of water per minute. If all the pipes are opened, the tank can be filled in 15 minutes. What is the capacity of the tank?
Correct
1/12 + 1/15 – 1/x = 1/15
x = 12
12 * 45 = 540Incorrect
1/12 + 1/15 – 1/x = 1/15
x = 12
12 * 45 = 540 
Question 47 of 50
47. Question
The length of the bridge, which a train 130 meters long and travelling at 45 km/hr can cross in 30 seconds, is:
Correct
Speed = (45 * 5/18) m/sec = (25/2) m/sec. Time = 30 sec. Let the length of bridge be x meters. Then, (130 + X)/30 = 25/2 ==> 2(130 + X) = 750 ==> X = 245 m.
Incorrect
Speed = (45 * 5/18) m/sec = (25/2) m/sec. Time = 30 sec. Let the length of bridge be x meters. Then, (130 + X)/30 = 25/2 ==> 2(130 + X) = 750 ==> X = 245 m.

Question 48 of 50
48. Question
Find the lowest 4digit number which when divided by 3, 4 or 5 leaves a remainder of 2 in each case?
Correct
Lowest 4digit number is 1000.
LCM of 3, 4 and 5 is 60.
Dividing 1000 by 60, we get the remainder 40. Thus, the lowest 4digit number that exactly divisible by 3, 4 and 5 is 1000 + (60 – 40) = 1020.
Now, add the remainder 2 that’s required. Thus, the answer is 1022.Incorrect
Lowest 4digit number is 1000.
LCM of 3, 4 and 5 is 60.
Dividing 1000 by 60, we get the remainder 40. Thus, the lowest 4digit number that exactly divisible by 3, 4 and 5 is 1000 + (60 – 40) = 1020.
Now, add the remainder 2 that’s required. Thus, the answer is 1022. 
Question 49 of 50
49. Question
The age of father 10 years ago was thrice the age of his son. Ten years hence, father’s age was five times the age of the son. After 6 years, son’s age will be:
Correct
Let the age of father and son 10 years ago be 3x and x years respectively.
Then, (3x + 10) + 10 = 2[(x + 10) + 10]
3x + 20 = 2x + 40 => x = 20.
Required ratio = (3x + 10):(x + 10) = 70:30 = 7:3Incorrect
Let the age of father and son 10 years ago be 3x and x years respectively.
Then, (3x + 10) + 10 = 2[(x + 10) + 10]
3x + 20 = 2x + 40 => x = 20.
Required ratio = (3x + 10):(x + 10) = 70:30 = 7:3 
Question 50 of 50
50. Question
In an election only two candidates contested. A candidate secured 70% of the valid votes and won by a majority of 172 votes. Find the total number of valid votes?
Correct
Let the total number of valid votes be x.
70% of x = 70/100 * x = 7x/10
Number of votes secured by the other candidate = x – 7x/100 = 3x/10
Given, 7x/10 – 3x/10 = 172 => 4x/10 = 172
=> 4x = 1720 => x = 430.Incorrect
Let the total number of valid votes be x.
70% of x = 70/100 * x = 7x/10
Number of votes secured by the other candidate = x – 7x/100 = 3x/10
Given, 7x/10 – 3x/10 = 172 => 4x/10 = 172
=> 4x = 1720 => x = 430.